evaluate 2x-y when x=5 and when y=12

Answers

Answer 1

Answer:

-2

Step-by-step explanation:

GIVEN :-

x = 5 and y = 12

TO FIND :-

2x - y

SOLUTION :-

placing the values of x and y

(2 × 5) - 12

10 - 12

-2

Answer 2
Answer:

- 2

Step-by-step explanation:

2x - y
2(5) - (12)
10 - 12
- 2

Related Questions

Convert the following fraction to a decimal.
1/3
A. 0.3


B. 0.03


C. 0.303


D. 3.9

Answers

Answer:

Option A, 0.3

Step-by-step explanation:

Step 1:  Convert the fraction into a decimal

Technically, 1/3 is an irrational number meaning that it never ends.  However, if we round it, it would round to 0.3 since 1/3 = 0.3333333.....

Answer: Option A, 0.3

A 42 gallon hot water tank hose 350 pounds of water what weight of water at 53 gallon tank hold

Answers

Answer:

441.66667 pounds

Step-by-step explanation:

divide 350/42 then multiply the quotient by 53

Part C of Jim and his dad are building a rectangular flower bed.
If Jim and his dad decide to decrease the width of the flower bed from 15 feet, what happens to its length?

Answers

i gotchu

The perimeter is 35. If we were to change the width, which is one of the dimensions of the flower bed, The perimeter will change. This means that perimeter will no longer be 35. So in order to keep the perimeter as it is, if we change one dimension, we must also change the other.

Let's solve for the length, using the formula to see how much the length changes from.

p = 2l + 2w

35 = 2l + 2(15)

35 = 2l + 30

5 = 2l

2.5 = l


We must increase the length from 2.5 feet. This is because decreasing one dimension will decrease the perimeter. But if we increase the other dimension as well, it will restore the perimeter to where is was initially.

Find Y. round to the nearest tenth.

Answers

9514 1404 393

Answer:

  32.7°

Step-by-step explanation:

Solve the given equation for C, then fill in the given values and evaluate.

  C = arccos((a² +b² -c²)/(2ab))

  Y = arccos((50² +90² -55²)/(2·50·90)) = arccos(7575/9000) ≈ 32.7°

__

Y is angle A in the attached triangle solver.

Surface roughness of pipe. Refer to the Anti-corrosion Methods and Materials (Vol. 50, 2003) study of the sur- face roughness of coated interior pipe used in oil fields, Exercise 7.26 (p. 311). The data (in micrometers) for 20 sampled pipe sections are reproduced in the table on p. 391.
a. Give the null and alternative hypotheses for testing whether the mean surface roughness of coated interior pipe, H, differs from 2 micrometers.
b. The results of the test, part a, are shown in the MINITAB printout at the bottom of the page. Locate the test statistic and p-value on the printout.

Answers

The minitab report isn't given.

Answer:

H0 : μ = 2 um

H1 : μ ≠ 2 um

Step-by-step explanation:

The mean surface roughness of coated interior pipe is given as 2um.

This refers to the population mean, μ = 2 um

Therefore, the null hypothesis which usually aligns with the population mean value will be stated as :

H0 : μ = 2 um

The alternative hypothesis is used to test the claim that the mean surface roughness is different from 2 ; hence no direction is given, this is thus a 2 - tailed test

H1 : μ ≠ 2 um

Convert 0.181818 … to a fraction by writing the repeating decimal as an infinite geometric series. Show all of your work (please)

Answers

0.181818… = 18 (0.010101…)

… = 18 (0.01 + 0.0001 + 0.000001 + …)

… = 18 (1/100 + 1/100² + 1/100³ + …)

… = 18 (1 + 1/100 + 1/100² + 1/100³ + …) - 18

Then you have

[tex]0.181818\ldots = \displaystyle18\sum_{k=0}^\infty\frac1{100^k} - 18 = \frac{18}{1-\frac1{100}} - 18 = \boxed{\frac2{11}}[/tex]

Solve the equation for x: 6-(4x-2)/5=x

Answers

Probably 3 5/9 around that I’m pretty sure

Simplify[tex]\frac{9x^{16} }{6(x^{2} )^{3}x^{2} } }[/tex]

Answers

Answer:

[tex]\displaystyle \frac{3x^8}{2}[/tex]

General Formulas and Concepts:

Algebra I

Exponential Rule [Multiplying]:                                                                            [tex]\displaystyle b^m \cdot b^n = b^{m + n}[/tex] Exponential Rule [Dividing]:                                                                                [tex]\displaystyle \frac{b^m}{b^n} = b^{m - n}[/tex]Exponential Rule [Powering]:                                                                              [tex]\displaystyle (b^m)^n = b^{m \cdot n}[/tex] Exponential Rule [Rewrite]:                                                                                 [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \frac{9x^{16}}{6(x^2)^3x^2}[/tex]

Step 2: Simplify

Exponential Rule [Powering]:                                                                           [tex]\displaystyle \frac{9x^{16}}{6x^6x^2}[/tex]Exponential Rule [Multiplying]:                                                                        [tex]\displaystyle \frac{9x^{16}}{6x^8}[/tex]Exponential Rule [Dividing]:                                                                             [tex]\displaystyle \frac{9x^8}{6}[/tex]Simplify:                                                                                                             [tex]\displaystyle \frac{3x^8}{2}[/tex]

Problem
Combine the like terms to create an equivalent expression:

y−(−3y)
please someone explain to me how to do this?

Answers

y-(-3y)= 4y
Because you have two negative signs, 3y becomes positive. This makes the expression y+3y, which is 4y.

Figure out the pattern, and write the next number.
2,6,21,88

Answers

Answer:
a5=445

Explanation:
a of n=(a+1)*n
a1=2
I found the pattern to add 1 to the previous number and then multiply it by its number in the sequence. Apologies for the terrible format of my recursive formula.
Proof of pattern:
(2+1)*2=6
(6+1)*3=21
(21+1)*4=88
a5=(88+1)*5=445

A sales firm receives an average of three calls per hour on its toll-free number. For any given hour, find the probability that it will receive at least three calls. Use the Poisson distribution.

Answers

Answer:

At most 3 calls: 64.7%

At least 3 calls: 57.7%

5 or more calls: 18.5%

Step-by-step explanation:

Find the area of the shaded regions.
QUICKLY PLEASE

Answers

Answer:

the answer is 270° on this

Answer:

84.78

Step-by-step explanation:

Area of a circle is pi(radius)^2

In this case it would be (pi(radius)^2)270/360 since it's 3/4 of a circle.

So we replace the values and solve:

3.14(36)(270/360)= 84.78 square centimeters.

2 2/3 +2 2/3 + 2 2/3 +2 2/3

Answers

Answer:

10.6666666667 is your answer

just round this to the nearest tenth

9514 1404 393

Answer:

  10 2/3

Step-by-step explanation:

Multiplication works nicely on problems involving repeated addition:

  2 2/3 +2 2/3 + 2 2/3 +2 2/3 = 4 × (2 2/3) = 4×2 +4×2/3 = 8 +8/3

  = 8 + 2 2/3 = 10 2/3

PLEASE HELP ME IM HAVING TROUBLE WITH IT

Answers

Answer:

True

False

Step-by-step explanation:

BC are on the same line so, the new [tex]B^{1}[/tex][tex]C^{1}[/tex] will also be on the same. Just a different line than the original. The both move the same distance when dilated.

CD and the new [tex]C^{1}[/tex][tex]D^{1}[/tex] cannot be the same length. The dilation will increase their length by 1[tex]\frac{2}{3}[/tex]

MFP15017010 2021 Question 2 2.1 Calculate the following 2- and 3-digit numbers using strategic doubling: 34 2.1.2 340 2.13 277 214 00 (10) 2.15 500

Answers

Answer:

plz check ur school solution down.

Step-by-step explanation:

Which one correct answer??

Answers

What is the question of it ?

Number 4 is the correct one

What is the length of PO

Answers

These are similar triangles, therefore their sides are proportional.

36 / 24 = PO / 36

24PO = 1296

PO = 54

Hope this helps!

find all the missing measurement​

Answers

Answer:

find all the missing measurement

A man invested N80 at a certain rate of simple interest. If at the end of 5 years the money amounted to N88, what was the rate of simple interest paid?

Answers

9514 1404 393

Answer:

  2%

Step-by-step explanation:

The amount of interest is the difference between the total amount and the principal amount:

  N88 -N80 = N8 . . . . the amount of interest

The interest amount is given by the formula ...

  I = Prt

Solving for r, we find ...

  r = I/(Pt) = 8/(80×5) = 1/50 = 2%

The rate of simple interest paid was 2%.

If POR ~ ASTU, what is the scale factor of APQR to ASTU?
A. 1/5
B. 1/4
C. 5
D. 4

Answers

Answer:

[tex]k = \frac{1}{5}[/tex]

Step-by-step explanation:

Given

The attached triangles

Required

The scale factor

From the attachment, we have:

[tex]TU = 4[/tex]

[tex]QR = 20[/tex]

So, the scale factor from PQR to STU is:

[tex]k = \frac{TU}{QR}[/tex]

[tex]k = \frac{4}{20}[/tex]

[tex]k = \frac{1}{5}[/tex]

Please help!

Solve for x

Answers

9514 1404 393

Answer:

  x = 1

Step-by-step explanation:

The product of lengths to the two circle intercepts are the same for each secant.

  7(7+9) = (8x)(8x+6x)

  112 = 112x² . . . simplify

  1 = x² . . . . . . divide by 112

  x = 1 . . . . . . . take the square root (segment lengths are positive)

In a sample of 56 bags of fertilizer, the average weight was found to be 17.2lb with a standard deviation of 0.7. Give a point estimate for the population standard deviation of the weight of the bags of fertilizer.

Answers

Answer:

???????????????????????

I am need help and an explanation on how to read these graphs.

Answers

Answer:

A is the answer

Step-by-step explanation:

A

plz mark it brainlist

y=5/3x + 3 in ordered pairs

Answers

These are three possible solutions to the equation. (
0
,

3
)
,
(
1
,

4
3
)
,
(
2
,
1
3
)

Answer:

(3,8) ; (-3,-2) ; (6,13)

Step-by-step explanation:

A linear equation in Slope Intercept Form is given to us and we need to write the ordered pairs for x and y . The given equation is ,

[tex]\rm\implies y =\dfrac{5}{3}x + 3 [/tex]

For finding the ordered pairs , substitute different values of x to get different values of y.

Put x = 3 :-

[tex]\rm\implies y =\dfrac{5}{3}\times 3 + 3 [/tex]

[tex]\rm\implies y = 5+ 3 [/tex]

[tex]\rm\implies y =8[/tex]

Put x = -3 :-

[tex]\rm\implies y =\dfrac{5}{3}\times -3 + 3 [/tex]

[tex]\rm\implies y = -5+ 3 [/tex]

[tex]\rm\implies y =-2[/tex]

Put x =6 :-

[tex]\rm\implies y =\dfrac{5}{3}\times 6 + 3 [/tex]

[tex]\rm\implies y = 10+ 3 [/tex]

[tex]\rm\implies y =13[/tex]

Therefore ,

[tex]\small\implies\boxed{\rm\blue{ Odered \ Pairs \ = (3,8) ; (-3,-2) ; (6,13) }}[/tex]

Suppose a + bi and c + di are complex numbers with b not equaling 0.
(a) Calculate (a + bi) + (c + di) and (a + bi)(c + di).
(b) Show that if both the sum and product are real numbers, then either the complex numbers are real numbers or conjugates.

Answers

9514 1404 393

Answer:

  (a) sum: (a+c) +(b+d)i

     product: (ac -bd) +(bc +ad)i

  (b) (b+d)=0 and (bc+ad)=0 ⇒ a=c, d=-b or b=d=0

Step-by-step explanation:

(a) Combining like terms the sum is ...

  (a +bi) +(c +di) = (a+c) +(b+d)i . . . . sum

And the product is ...

  (a+bi)(c+di) = ac +(ad+bc)i +bd·i²

Since i = √-1, i² = -1 and the product can be written as ...

  (a+bi)(c+di) = (ac-bd) +(ad+bc)i . . . . product

__

(b) If both the sum and product are real numbers, then we have ...

  b +d = 0

  ad +bc = 0

The first equation tells us d = -b. Substituting that into the second equation, we get ...

  a(-b) +b(c) = 0

  b(c -a) = 0

The zero product rule tells us this will be true if and only if b = 0 or c = a.

  if b = 0, then d = 0 and both numbers are real.

  if c = a, then c+di = a-bi and the numbers are conjugates.

Hence, if both the sum and product are real, both are real numbers or they are conjugates.

If Tevin has 2 times as many dimes as nickels and they have a combined value of 100 cents, how many of each coin does he have?
dimes____
nickels____

Answers

The answer would be 400 coins

Answer:

dimes- 8

nickels- 4

Step-by-step explanation:

dime=10 cents

nickels=5 cents

5 x 4 = 20

10 x 8 = 80

80 + 20 = 100

... please give brainliest ...

in order to apply the law of cosines to find the length of the side of a triangle, is it enough to know which of the following?


A. The area of a triangle

B. The lengths of two of the triangle's sides and the measure of the angle between them

C. At least two of the angles of the triangle and the length of one of its sides

Answers

9514 1404 393

Answer:

  B. The lengths of two of the triangle's sides and the measure of the angle between them

Step-by-step explanation:

The usual formulation of the law of cosines is something like this:

  c² = a² +b² -2ab·cos(C)

where 'c' is the side opposite angle C, and 'a' and 'b' are the other two sides. That is, to use this formula directly, one needs two side lengths and the measure of the included angle.

_____

Additional comment

One can use the law of cosines to solve a triangle when any two sides and one angle are known. The use of the formula will give a quadratic in the unknown side length, if it is not the side opposite the known angle. As with the law of sines, if the angle is opposite the shorter of the two given sides, there may be two solutions for the length of the third side.

Answer:

The answer is B.)

Step-by-step explanation:

Find the measure of the missing angles.
WILL GIVE BRAINLIEST

Answers

Answer:

h= 60

g= 120

m= 147

k= 33

Step-by-step explanation:

We know that all three lines are straight an continuous, so, at any given point the angles should add up to 180 degrees.

This immediately helps with angle h:

    120 + h = 180

              h = 60

As well as m:

     33 + m = 180

              m = 147

There are two ways to solve the next part:

First and most familiar way:

    h + g = 180

    60 + g = 180

             g = 120

and:

    m + k = 180

    147 + k = 180

              k = 33

The other way that I prefer is that the angles opposite of each other when two lines intersect are equal. I don't know if that makes sense, it's hard to explain in this format.

In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions. x(π/4) = 2 2 , x'(π/4) = 0

Answers

Differentiate the given solution:

[tex]x=C_1\cos(t)+C_2\sin(t) \implies x'=-C_1\sin(t)+C_2\cos(t)[/tex]

Now, given that x (π/4) = √2/2 … (I'm assuming there are symbols missing somewhere) … you have

[tex]\dfrac{\sqrt2}2=C_1\cos\left(\dfrac\pi4\right)+C_2\sin\left(\dfrac\pi4\right)[/tex]

[tex]\implies\dfrac1{\sqrt2} = \dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}[/tex]

[tex]\implies C_1+C_2=1[/tex]

Similarly, given that x' (p/4) = 0, you have

[tex]0=-C_1\sin\left(\dfrac\pi4\right)+C_2\cos\left(\dfrac\pi4\right)[/tex]

[tex]\implies 0=-\dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}[/tex]

[tex]\implies C_1=C_2[/tex]

From this result, it follows that

[tex]C_1+C_2=2C_1=1 \implies C_1=C_2=\dfrac12[/tex]

So the particular solution to the DE that satisfies the given conditions is

[tex]\boxed{x=\dfrac12\cos(t)+\dfrac12\sin(t)}[/tex]

Use all the six numerals 4, 5, 6, 7, 8 and 9 to form two 3-digit even numbers whose sum is smallest, and what is the sum? ​

Answers

Step-by-step explanation:

this Is hard to find.............

Answer:

The numbers should be even, it means the unit digits are 4, 6 or 8.

The numbers should be minimal, it means the hundred's digits are 4 and 5.

With this we have possible numbers:

4x6 and 5y8, here 6 and 8 could be exchanged.

The options are:

496 and 578 or476 and 598 or498 and 576 or478 and 596

The sum of the two numbers is:

1074
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