The ethylenediaminetetraacetic acid (EDTA) is an effective antidote for heavy metal poisoning (e.g., Pb²⁺ and Hg²⁺ ).
The ethylenediaminetetraacetic acid is also known as EDTA is very helpful in the treatment of chronic and the acute lead poisoning . it pull out the toxins , the heavy metals like as lead , mercury, cadmium from the blood stream. The ethylenediaminetetraacetic acid is used as a chelating agent . the ethylenediaminetetraacetic acid has the claw like structure which binds the heavy metals and the other toxins also. the claw means chelate.
Thus, an effective antidote for heavy metal poisoning is the ethylenediaminetetraacetic acid.
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Based on your data and using deductive reasoning, what can you conclude about the trends in the solubilities of the compounds of the alkaline earth metals?
onclude about the trends in the solubilities of the compounds of the alkaline earth metals
The solubility or, as we can say, the activity of the chemical, increases as one moves down the group. Since barium is more active
Chemical element barium (Ba), an alkaline-earth metal belonging to Group 2 (IIa) of the periodic chart. The substance is utilized in metallurgy, and pyrotechnics, petroleum production, and radiology all make use of its constituents.What is the purpose of barium?
Barium is solely utilized for GI tract imaging tests. An upper GI series may include a barium swallow test in addition to or instead of it. In this series, the esophagus, stomach, and first segment of the small intestine are examined (duodenum). During a barium swallow test, fluoroscopy is frequently employed.
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which of the following concerning molecular geometry and dipole moments is correct? all molecules with polar bonds have a permanent dipole moment. all square planar molecules are nonpolar. all linear molecules are nonpolar. only molecules with polar bonds may have a permanent dipole moment. a molecule with nonpolar bonds could have a permanent dipole moment, depending on the molecular geometry.
Answer:
only molecules with polar bonds may have a permanent dipole moment.
Explanation:
On a hot afternoon (311 K) a party balloon was filled with 2.07 L of helium. That evening the temperature dropped to 295 K. What is the
new volumen of the balloon?
Answer:
2.02 L
Explanation:
The volume of a gas is directly proportional to its temperature, according to the ideal gas law. This means that as the temperature of a gas decreases, its volume will also decrease.
To determine the new volume of the balloon as the temperature drops from 311 K to 295 K, we can use the ideal gas law to calculate the new volume of the gas:
PV = nRT
Where:
P = the pressure of the gas (assuming it remains constant)
V = the new volume of the gas
n = the number of moles of the gas (assuming it remains constant)
R = the universal gas constant
T = the new temperature of the gas
Since we know the pressure, number of moles, and universal gas constant, we can solve for the new volume of the gas by substituting in the known values and solving for V:
V = nRT / P
Substituting in the values from the problem, we get:
V = (n * R * 295 K) / P
Since the number of moles and the universal gas constant are constants, we can simplify the equation to:
V = k / P
Where k is a constant equal to the product of the number of moles, the universal gas constant, and the original temperature of the gas (in this case, k = n * R * 311 K).
Since we know the value of k and the pressure of the gas, we can solve for the new volume of the gas by substituting in the known values:
V = (k / P)
= (n * R * 311 K) / P
= (2.07 L * 8.31 L * atm / mol * K * 311 K) / P
= 2.02 L
Therefore, the new volume of the balloon is approximately 2.02 L.
An organism with the genotype of AaXx can produce gametes containing _________ if the two genes are unlinked.
a. either Aa or Xx
b. either AX, Ax, aX, ax
c. AaXx
d. AX or ax
e. None of the above.
An organism with the genotype of AaXx can produce gametes containing either AX, Ax, aX, ax if the two genes are unlinked .
An organism's genotype is the complete set of its genetic material. [1] Genotype can also be used to refer to the alleles or variants that an individual has at a particular gene or locus. The number of alleles an individual can have for a particular gene depends on the number of copies of each chromosome (also called polyploidy) found in that species. Diploid species like humans have two complete sets of chromosomes. This means that each individual has her two alleles for a particular gene. If both alleles are the same, the genotype is said to be homozygous. If the alleles are different, the genotype is called heterozygous.
Genotypes contribute to the phenotype, observable traits and characteristics of an individual or organism. The extent to which genotype influences phenotype depends on the trait.
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Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.
The energy required to bring 120 g of acetic acid (HCH3CO2) to a boil at a starting temperature of 16.7 °C is 72.2116 kJ.
Given that ;
mass of acetic acid = 120.0 g
initial temperatureT₁ = 16.7 °C = (16.7 + 273.15 ) K = 298.85 K
standard molar mass of acetic acid = 60.052 g/mol
The number of moles of acetic acid can therefore be calculated as follows: number of moles of acetic acid = mass of acetic acid/molar mass of acetic acid
number of moles of acetic acid = 120.0 g/ 60.052 g/mol
number of moles of acetic acid = 1.998 moles
For acetic acid:
standard boiling point T₂ = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K
enthalpy of vaporization of acetic acid ΔH[tex]_{vap}[/tex] = 23.7 kJ/mol
heat capacity of acetic acid c = 2.043 J/g.K
change in temperature Δ T = T₂ - T₁
Δ T = (391.25 - 289.85)K
Δ T = 101.4 K
The heat required to raise the liquid acetic acid's temperature from 16.7°C to its boiling point is;
q = mcΔT
From our values above;
q = 120 g × 2.043 J/g.K × 101.4 K
q = 24859.2 J
q = 24859 /1000 kJ
q = 24.859 kJ
We already determined that we have 1.998 moles of acetic acid;
Thus;
the needed amount of heat = Δ[tex]_{vap}[/tex]*number of moles
The needed amount of heat = 47.3526 kJ
Hence;
The total amount of heat needed = 24.859 kJ + 47.3526 kJ
The total amount of heat needed = 72.2116 kJ
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part a: identification of a hydrocarbon write out a balanced chemical reaction for 1-hexene with br2 using structural formulae for reactants and products g
The chemical reaction and its components are as follows -
Firstly writing the balanced chemical reaction for 1-hexene and bromine gas -
1-hexene -- [tex] Br_{2}[/tex]/[tex] CH_{3}[/tex]OH--> 1,2-dibromohexane + 1-bromo-2-methoxyhexane
The structural formula of each compound is -
1-hexene: [tex] C_{6}[/tex][tex] H_{12}[/tex]
1,2-dibromohexane: [tex] C_{6}[/tex][tex] H_{12}[/tex][tex] Br_{2}[/tex]
1-bromo-2-methoxyhexane: [tex] C_{7}[/tex][tex] H_{15}[/tex]BrO
Containing alkene group, 1-hexene finds application in Linear Low Density Polyethylene. The products are used in research processes. Reaction involves incorporation of bromine atoms and methyl alcohol group on the hexene.
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The density of an unknown element in the gaseous state is 1.60 g at 300 K and 1 atm. Which of the following could be the element?
a. He
b. Ne
c. Ar
d.O2
e. Cl2
the first 32 amino acids from the N terminus of the protein bovine angiogenin were determined by edman degradation and have the sequence: AQDDYRYIHFLTQHYDAKPKGRNDEYCFNMMK (a) Identify the sites of cleavage during trypsin-catalyzed hydrolysis of this protein. (b) What are the cleavage sites using chymotrypsin?
The first 32 amino acids from the N terminus of the protein bovine angiogenin were determined by edman degradation. (a) The cleavage sites for the trypsin-catalyzed hydrolysis are, AQDDYRYIHFLTQHYDAKPKGRNDEYCFNMMK.
(b) The following cleavage sites take place during hydrolysis that is catalyzed by chymotrypsin: AQDDYRYIHFLTQHYCFNMMK. Site-selective breakdown of extremely non-reactive peptide bonds also functions as a therapeutically helpful modulator of protein structure and function, providing essential information on the protein sequence. Regulated and selective cleavage is a challenging task and requires chemical reagents to be able to recognize or bind to one or more specific amino acid residues in the peptide chain. On the basis of this concept, we developed a technique that selectively changes the serine residue in a peptide chain using a chemical reagent, causing the peptide backbone to break at the N-terminus of the serine residue. After cleavage, modified residues can be transformed back into their original form. This method may cleave a wide variety of substrates and does so specifically for certain bioactive peptides with post-translational modifications (like N-acetylation and -methylation) and mutations (like D- and -amino acids), which are known to contribute to age-related diseases.
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a metal oxide with the formula m2o contains 11.18% oxygen by mass. in the box below, type the symbol for the element represented by m. [a]
Strontium, whose atomic symbol is Sr, is the metal that is present in the specified metal oxide.
The unit of measurement for substance is the mole. The term "mole" refers to the relationship between a substance's molar mass and its overall mass. It is defined as the molar mass (g/mol) of a material divided by the substance's mass in grams.
The following phrase can be used to determine the number of moles:
The supplied metal oxide MO has an oxygen content of 15.44%, which translates to 15.44 g of oxygen per 100 g of the metal oxide MO. According to the periodic table, strontium, which has a molar mass of roughly 87.7 g, is the metal present in 100 g of metal oxide (Sr). Therefore, strontium oxide is the metal oxide.
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Find the volume, in mL, of an object whose density is 400 g/mL and has a mass of 600
mg.
The volume of the object is 1.5ml.
What is the volume of an object?This refers to the space occupied within the boundaries of an object in three-dimensional space. It is also called the capacity of the object.
In the question:
ρ = 400 g/mL
m = 600 mg
v = ?
Formular for calculating density ρ:
ρ = m/v
Where,
ρ= Density of the object
m= Mass of the object
v = volume of the object
Were are given the values of density and mass in the question. We are to calculate the volume.
Makinig v subject of the formular we have:
v = m/ρ
v = 600 mg
400 g/mL
v = 1.5ml
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Combustion of 31.68 g of a compound containing only carbon, hydrogen, and oxygen produces 36.67 g CO2 and 15.01 gH2O. What is the empirical formula of the compound?
Combustion of 31.68 g of a compound containing only carbon, hydrogen, and oxygen produces 36.67 g CO₂ and 15.01 g H₂O. the empirical formula of the compound is CH₂O.
given that :
mass of CO₂ = 36.67 g
mass of H₂O = 15.01 g
total mass of compound = 31.68 g
moles of CO₂ = 36.67 / 44
= 0.833 mol
moles of C = 0.833 mol
moles of H₂O = 15.01 / 18
= 0.833 mol
moles of H = 2(0.833)
= 1.667 mol
mass of carbon = 0.833 × 12
= 10 g
mass of hydrogen = 1.667 × 1
= 1.667 g
mass of oxygen = 31.68 - ( 10 + 1.67 )
= 20 g
moles of Oxygen = 20 / 16
= 1.25 mol
dividing by the smallest one :
C = 0.833 / 0.833 = 1
H = 2
O = 1
The empirical formula is CH₂O.
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Compound A is an alkyne with molecular formula CsH8- When treated with aqueous sulfuric acid and mercuric sulfate, two different products with molecular formula C5H1oo are obtained in equal amounts. 0 Get help answering Molecular Drawing questions. Draw the structure of compound A. Edit 0 Get help answering Molecular Drawing questions. Draw the two products obtained in the box below Edit
Alkynes are hydrocarbons containing a carbon-carbon triple bond. Their general formula is CnH2n-2 for molecules with triple bonds.
Alkynes undergo many of the same reactions as alkenes but can react twice due to the presence of two p-bonds on the triple bond. Ethyne is commonly known by the trivial name acetylene. It is the simplest alkyne, consisting of two carbon atoms joined by a triple bond, where each carbon can bond to a hydrogen atom.
Molecules containing a triple bond between two carbon atoms are called alkynes. A triple bond consists of one σ bond and two π bonds. As for the hydrogen atoms, this compound is unsaturated, so the extra electrons are exchanged with two carbon atoms forming a double bond.
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when circuit town electronics sets its televisions at three price levels of $699, $899, and $1,099, it is most likely using .
When circuit town electronics sets its televisions at three price levels of $699, $899, and $1,099, it is most likely using product line pricing.
Product line pricing involves the separation of goods and services into cost categories in order to create various perceived quality levels in the minds of consumers. You might also hear product line pricing referred to as price lining, but they refer to the same practice.Selling a product at or below cost to lure customers in and drive other sales is an example of product-line pricing. A restaurant, for example, might offer a low-priced entrée with the purchase of a drink and dessert that have higher profit margins.A product line refers to a particular good or service that a company makes and markets to customers. A food company may extend a product line by adding various similar or related products (e.g., adding mesquite BBQ flavor to its existing potato chips line), and create a more diversified product family.Using product line pricing allows companies to target customers with low-end, mid-range and high-end budgets. By offering two, three or more product tiers, a company can reach a much larger range of customers. This grants companies the potential to attain more sales and greater brand recognition.
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What is the formula for cobalt (III) oxide?
Co3O2
Co2O3
Co3O
CoO3
Answer:Co2O3
Explanation:
look it up
Answer:
Co2O3
Explanation:
when you write any formula you apply the criss-cross method where you write the charges of each substance
Co3 and O2
applying the criss-cross method( you switch the charges number, in this case you switch the 2 and the 3) :-
Co2 and O3
so Co2O3
What is the number of atoms in a mole of any element? (3 points)
Avogadro's number
Graham's number
Its atomic number
Its mass number
Answer:
Avogadro's number
Explanation:
the hydrogen generated in this lab was a product of the reaction between magnesium and hydrochloric acid. which of the reactants is the limiting reactant?
a.) magnesium
b.) hydrochloric acid.
Suppose that when you inverted the eudiometer, a bubble of air became trapped inside it. Would this make your experimental value of R larger, smaller, or have no effect?
a.) larger
b.) smaller
c.)no effect
The limiting reagent in this reaction is HCl.
Supply and the stoichiometric equation are used to identify the limiting reactant of these reactants. So, both reactants are able to act as limited reagents according to these conditions.
They limit how far reactions can go in terms of producing products because they are reactants with a finite supply.
Hydrogen gas is created in the following manner in a reaction between magnesium and hydrochloric acid:
Mg + HCl ------------> MgCl₂ + H₂
HCl has two times the molecular weight of magnesium. As a result, no reactant will be limiting if both reactants are provided in the required proportion.
HCl will become limiting if the amount of moles supplied is not at least twice that of Mg. Furthermore, Mg will be limited if the amount supplied is not equal to half the amount HCl supplied.
Therefore, the limiting reagent in this reaction is HCl.
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this method of acquiring mw differs from sec and gives dosy nmr many advantages over sec. as stated before, molecules of specific sizes produce indi-vidual diffusion coefficients. due to low sample con-centration, the purity of polymer is not as essential compared to sec; thus, reducing preparation time. dosy also requires minimum amounts of solvent
A well-known NMR technique called diffusion ordered spectroscopy (DOSY) provides diffusion coefficients for specific resonances in NMR spectra.
The main applications of DOSY are the analysis of small molecule mixtures and the oligomeric state of biomolecules. The spreading Self-Diffusion (SD)-NMR and diffusion ordered spectroscopy are two common names for the NMR technology (DOSY). This is accomplished by fusing magnetic field gradients, which encode spatial information, with radio-frequency pulses, which are commonly employed in NMR spectroscopy. Magnetic field gradients are used by Diffusion Ordered Spectroscopy (DOSY) to examine diffusion processes in both solid and liquid materials. Liquid structure is discovered using NMR spectroscopy. It is also used to figure out how soluble chemical molecules are structured.
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cold water can hold more dissolved oxygen than warm water because the solubility of oxygen decreases as temperature increases. T/F
The solubility of oxygen reduces with increasing temperature, hence cold water can store more dissolved oxygen than warm water. The chemical element with the letters O.
And the atomic number 8 is called oxygen. It belongs to the chalcogen group of the periodic table and is a highly reactive nonmetal that rapidly forms oxides with most elements as well as with other compounds. Understanding the makeup of matter developed together with the creation of the concepts of the elements. The substance has been viewed as either continuous or discontinuous at various points throughout history. It is possible to hypothesise that continuous substance is homogenous, infinitely divisible, and has parts that are all the same size.
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Consider the following reaction at 276 K.
1 A + 2 B → C + D
where rate = rate=k[A][B]2. An experiment was performed for a certain number of seconds where [A]o = 0.000847 M and [B]o = 1.11 M. A plot of ln[A] vs time had a slope of -9.43. What will the rate of this reaction be if a new experiment is preformed when [A] = [B] = 0.779 M?
1 A + two C and d → C + S t where rate=k[A][B][rate] 2. An experiment with [A]o = 0.000847 T s as well as [B]o = 1.11 M was run for a predefined number of seconds. The slope of a ln[A] vs. grown steadily was -9.43. rate of reaction is 3.62m/s
Slope and slant both refer to an incline up from a reference surface or line that is generally straight. The ground slopes (either upward or straight down) sharply here. To slope is to slope vertically in an ambiguous path A line's steepness could be determined by looking at its slope. Altitude is calculated mathematically as "rise over run."
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most to least concentration in the troposphere: carbon monoxide, carbon dioxide, ozone, and hydroxyl radical
The correct arrangement on the basis of most to least concentration in troposphere will be: Cardon dioxide > Ozone > Carbon mono oxide > Hydroxyl radical.
In this lowest layer, the air is the densest. In actuality, the troposphere makes about 75 percent of the total weight of the atmosphere. The two most common gases are nitrogen (78%) and oxygen (21%), with argon (.9%) and a trace amount of hydrogen ozone (a kind of oxygen) making up the remaining 1% of all gases. The troposphere's temperature and water vapor concentration drop sharply with altitude.
Carbon monoxide background levels across the world vary from 0.06 to [tex]0.14 mg/m^3[/tex] (0.05– 0.12 ppm).
About 3 billion metric tons of ozone are present in the atmosphere as a whole. Even while that may seem like a lot, the atmosphere only makes up 0.00006 percent of it.
The concentration of hydroxyl radical is the minimum.
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When some of the sugar added to iced tea remains undissolved at the bottom of the glass, the solution is Most studied answer a) dilute b) unsaturated c) saturated d) polar e) nonpolar
When some of the sugar added to iced tea remains undissolved at the bottom of the glass, the solution is Saturated.
Solution is saturated which means no more solute can be dissolved in the solvent at the given/present temperature and pressure conditions. To dissolve more sugar in the tea we need to increase the temperature of the tea so that the tea becomes unsaturated, for the given conditions also the solubility of the solids increases with the increase in the temperature, so more of the sugar can be dissolved if the temperature of the solvent is increased.
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using curved arrow notation, write lewis acid/base equations for each of the following. remember to place formal charge on the appropriate atoms. a. aici3- b. phyp: bf3 bh3
AlCl 3 is Lewis base,PH3 is Lewis base,BH3 is Lewis acid ,BF3 is Lewis acid.
The crucial step is AlCl 3 accepting a chloride ion lone-pair to generate AlCl 4 and the highly acidic, or electrophilic, carbonium ion. Lewis bases: RCl +AlCl 3 → R + + AlCl 4−, etc. [ edit] The highest occupied molecular orbital (HOMO) of an atomic or molecular species that is strongly localised is known as a Lewis base.Lewis acid borane (BH3) has three hydrogen atoms and one boron atom in its molecule. The Lewis structure of borane features a single connection connecting each hydrogen atom to boron (BH3). Only three bonds surround the boron atom, and there are no lone pairs on the atom itself. We will learn how to draw the BH3 Lewis structure in this lesson.Only six electrons orbit the boron atom, according the Lewis structure of BF3. As a result, the boron atom's octal is incomplete. Borane BF3 is therefore regarded as a Lewis acid.A highly poisonous gaseous chemical is phosphorus. Three sigma bonds and one lone pair are present around the phosphorus atom in the Lewis structure of phosphine (PH3). Hydrogen and phosphorous atoms have no charges. The trigonal pyramidal shape of PH3 is a fundamental shape.
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Write the overall balanced cell reaction for the following voltaic cell Fe(s) | Fe2+ (aq) || Ag + (aq) | Ag(s) (Ctrl).
the overall balanced cell reaction for the following voltaic cell
Hg2Cl2(s) + Cu(s) ® 2Hg(l) + Cu2+(aq) + 2Cl-(aq)
The cell reaction, also known as the total reaction, is the reaction that occurs within the cell as a whole and is expressed under the assumption that the right electrode is the cathode and that the spontaneous reaction is the one in which reduction takes place in the right-hand compartment.Galvanic, also known as Voltaic, and electrolytic cells are the two varieties of electrochemical cells. While electrolytic cells utilize non-spontaneous reactions and therefore need an external electron source, such as a DC battery or an AC power source, galvanic cells get their energy from spontaneous redox reactions.
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The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row You will find it useful to keep in mind that NH3 is a weak base. acids ,口, 1.3 mol of HNO3 is added to 1.0 L of a 1.3 MNH, solution bases: other acids: bases: - 0.57 mol of KOH is added to 1.0 L of a solution that is 1.2 M in both NH3 and NH4CI. other:
a) NaFi is formed when 1 mol of NaOH is oriented to 1.0 L of a 0.5 M HF mixture.
b) To 1.0 L of a solution that is 0.8 M in both HF & KF-producing KF, 0.3 mol of KOH is added.
An acid generates the hydronium ions H3O+ in an aqueous solution, whereas a base creates the hydroxide ions OH. Water and salt are the byproducts of the neutralization process that occurs when an acid and a base interact.
A) 1 mol of NaOH is counted to 1.0 L of a 0.5 M HF resolution.
The reaction involved in this is:
NaOH + HF → NaF + H2O
acid: HF
base: NaOH
species that neither creates an acid and neither a base nor a salt NaF
b) To 1.0 L of a mixture that seems to be 0.8 M in both HF as well as KF, 0.3 mol of KOH is added.
The reaction involved in this is:
KOH + HF → KF + H2O
acid: HF
base: KOH
the mixture that could be neither an acid nor a base or salt delivered: KF
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The question is -
The preparations of two aqueous solutions are described below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself.
For each of the questions, write the chemical formulas of the species that will act as acids, the formulas of the species that will act as bases, and the formulas of the species that will act as neither acids nor bases. Note that HF is a weak acid.
A) 1 mol of NaOH is added to 1.0 L of a 0.5 M HF solution.
B) 0.3 mol of KOH is added to 1.0 L of a solution that is 0.8 M in both HF and KF.
What come first egg or hen?
Hen because who makes the egg?
draw the structure or structures produced by the catalytic reduction of the given compound, in which h2 is in excess.
Structures produced by catalytic reduction of certain compounds where H2 is H2. 1-Ethylcyclohexa-1,4-diene and excess hydrogen-ethyl-2-methylcyclohexane are formed.
Specific compound 1-Ethylcyclohexa-1,4-diene and excess hydrogen-ethyl-2-methylcyclohexane are formed. One compound has the R, S configuration and the other has the S, R configuration. Using the CIP rule, preference is given to groups attached to chiral carbons.
CIP rules are based on the atomic mass of the combined groups, so the group with the highest atomic mass has the lowest number. Since it is a mixture of two enantiomers, it can be called a Rekamic mixture. Selective catalytic reduction refers to the reduction of nitrogen oxides with oxygen and selective inorganic or organic reducing agents.
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For how many electrons is the value of ml +2
Only two electrons can be filled in an orbital with a magnetic quantum number (ml) +2.
What are the quantum numbers?The set of numbers that defines the position and energy of the electron filled in a specific orbital are called quantum numbers. Four quantum numbers are principal, azimuthal quantum number, magnetic, and spin quantum numbers.
The principal quantum number (n) denotes the principal electron shell of the atom and the most probable distance between the nucleus and the electrons. The azimuthal quantum number (l) denotes the shape of an orbital in which an electron is present.
The magnetic quantum number denotes the total number of orbitals in a subshell and the orientation of these orbitals. The value of the spin quantum number (s) denotes the direction in which the electron is spinning.
For the value of n = 2, we have five values of ml which are +2, +1, 0, -1, and -2. Every value of ml represents one d-orbital. Each orbital can have two electrons.
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neutrons are useful particles for nuclear bombardment processes because they have charge and are not repelled by a target nucleus. positively charged particles must have sufficient kinetic to overcome repulsion if they are to be used in this way. this is achieved by using a particle .
Neutron is not attracted to the positively charged nucleus since it has no charge. As a result, a neutron can bombard a nucleus even if it is very weak.
As a result, a nuclear reaction can be started by even a very weak neutron bombarding a nucleus. Thus, in a nuclear reaction, a neutron is employed to bombard the nucleus. Neutrons have no charge, therefore they are neither drawn to nor repelled by atoms' nuclei and electrons. Neutron is therefore the best projectile. The connections holding the nucleus together contain enormous energy. These connections can be broken, which will release the nuclear energy. A high-energy neutron is used to start nuclear fission by bombarding a nucleus, which causes the release of further neutrons. The nucleus does not reject a neutron since it has no charge.
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Correct the volume of 2.90 L of a gas at –12 °C to the volume occupied at 25 °C. Remember to convert between °C and K.
The volume occupied at 25 °C. Remember to convert between °C and K. V2 = 3.311 L is the correct answer.
What is volume?
Volume is the measure of the amount of space occupied by an object or a substance. It is measured in three dimensions: length, width, and height. In the International System of Units (SI), it is measured in cubic meters (m3). Volume is also commonly measured in liters (L), gallons (gal), or cubic feet (ft3). Volume can also refer to the amount of a substance or object, such as the volume of a gas or the volume of a liquid.
Temperature and Volume equation
Given,
The volume at -12°C = 2.90L
Temperature, T1 = -12°C
= (-12°C + 273)
= 261K
And, Volume at 25°C = ?
(25°C + 273)K
= 298K
Now, by using this equation:-
V1/T1 = V2/T2
V2 = V1 x T2/T1
V2 = 2.90L x 298K/261K
V2 = 3.311L
Hence, The volume at 25°C will be 3.311L
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A fresh sample 1311 was left out on the benchtop for 40 days. The scientist forgot it has a half-life of 8 days. The original sample mass
was 64 g. How much of the parent isotope is left?
g
Answer:
2 g of the parent isotope is left.
Explanation:
The half-life of a radioactive isotope is the amount of time it takes for half of the isotope to decay. In this case, the half-life of the isotope is 8 days, which means that after 8 days, half of the isotope will have decayed.
To determine how much of the parent isotope is left after 40 days, we need to calculate how many half-lives have passed in that time. Since the half-life is 8 days, and 40 days have passed, we can divide 40 by 8 to find the number of half-lives that have occurred: 40 / 8 = 5
Since 5 half-lives have passed, we can calculate the amount of the parent isotope that is left by multiplying the original amount of the isotope by 1/2 to the power of the number of half-lives that have passed: 64 * (1/2)^5 = 64 * (1/32) = 2 g
Therefore, after 40 days, only 2 g of the parent isotope is left.
