Estimate the rate at which the total personal income is rising in a metropolitan area. In 1999, the population of this area was 918,000, and the population was increasing at roughly 9700 people per year. The average annual income was $34,549 per capita, and this average was increasing at about $1300 per year (a little above the national average of about $1225 yearly).

Required:
Use the Product Rule to estimate the rate at which total personal income was rising in the area in 1999.

Answer:

(a) {5}

(b) {1, 2, 5, 6}

(c) {1, 2, 5, 6}

Answer:

h(-6) = 3(-6)² - 6(-6) + 4

= 3(36) + 36 + 4

= 148

You basically just substitute x with -6 that's all

Answer:

I believe the answer is 4 37/50!

Answer:

a. P = 30

b. Y = 40

Step-by-step explanation:

Given the following data;

P = 1.2

Y = 100

First of all, we would have to determine the constant of proportionality;

P = k/Y (inverse proportion or relationship)

1.2 = k/100

k = 1.2 * 100

k = 120

a. To find the value of p when y = 4;

P = k/Y

P = 120/4

P = 30

b. To find the value of y when p = 3;​

P = k/Y

Y = k/P

Y = 120/3

Y = 40

Answer:

3 bags

Step-by-step explanation:

you can buy three, 20 kg bags

one (1) 20kg bag =  $12.8 (1)

three (3) 20 kg bags = $12.8 (3)

                                  = $38

your balance 10 dollars

Answer:

It is (B) ED2021

Explanatory variable: time spent streaming videos

Response variable: time spent exercising

Answer:

150 are unoccupied

Step-by-step explanation:

If 75% are occupied, then 100% -75% = 25% are unoccupied

600 *25%

600 *.25

150

150 are unoccupied

Answer:

150

Step-by-step explanation:

100% - 75% = 25%

25% of seats unoccupied

hence,

number of seats unoccupied = 25/100 * 600 = 150

9514 1404 393

Answer:

  d) 10.38%

Step-by-step explanation:

The multiplier for four quarters of quarterly compounding is ...

  (1 +10%/4)^4 = 1.025^4 = 1.103812890625

This is about 1 + 10.38%.

The effective rate of interest is about 10.38% per annum.

Answer:

hope. It helps. What. I Understood

What we need to memorize when finding the slope is this formula:

[tex] \displaystyle \large{m = \frac{y_2 - y_1}{x_2 - x_1} }[/tex]

m here represents the slope. I hope this does not confuse you with line m.

The problem here is that we do not have any given points, but we have a way.

If we notice on the graph, the graph contains or passes through (2,-1) and (-2,1). We can use these points to find the slope. So let these be the following:

[tex] \displaystyle \large{(x_1,y_1) = (2 ,- 1)} \\ \displaystyle \large{(x_2,y_2) = ( - 2 ,1)} [/tex]

Then we substitute these points in the formula.

[tex] \displaystyle \large{m = \frac{ 1 - ( - 1)}{ - 2 - 2} }[/tex]

negative × negative = positive.

[tex] \displaystyle \large{m = \frac{ 1 + 1}{ - 2 - 2} } \\ \displaystyle \large{m = \frac{ 2}{ - 4} } \longrightarrow \boxed{m = - \frac{1}{2} }[/tex]

Since m represents the slope. Therefore, the slope of line m is -1/2

Answer:

opposite angles

Step-by-step explanation:

They are formed in the intersection of lines AD and BD.

Answer:

opposite angles

Step-by-step explanation:

they are formed in the intersection of lines AD and BD. two figures are called similar if they have same shape however have different size.

Answer:

No, because the ratio of pay to hours is not the same for each pair of value.

Answer:

b/a = c/d    (first option)

Step-by-step explanation:

Two lines:

f(x) = a*x +b

g(x) = m*x + s

are parallel if m = a, and s ≠ b.

So the lines must have the same slope and different y-intercept.

For the graphed lines is obvious that the y-intercepts are different, so let's look at the slopes.

Remember that if a line passes through the points (x₁, y₁) and (x₂, y₂), then the slope can be written as:

slope = (y₂ - y₁)/(x₂ - x₁)

So now let's look to our lines.

The top one, passes through (-a, 0) and (0, b)

Then its slope is:

a₁ = (b - 0)/(0 - (-a)) = b/a

The bottom line passes through the points (0, -c) and (d, 0)

Then the slope will be:

m₁ = (0 - (-c))/(d - 0) = c/d

Then the lines will be only parallel if the slopes are equal, which means that we must have

b/a = c/d

The correct option is the first one.

9514 1404 393

Answer:

  -x^4/(2y)

Step-by-step explanation:

Perhaps you want to simplify ...

  [tex]-\dfrac{3x^5y^7}{6xy^8}=-\dfrac{3}{6}x^{5-1}y^{7-8}=-\dfrac{x^4y^{-1}}{2}=\boxed{-\dfrac{x^4}{2y}}[/tex]

__

The applicable rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

_____

Comment on notation

When writing a fraction in plain text, any denominator that includes an arithmetic operation must be enclosed in parentheses. Your given expression is properly written as ...

  -3x^5y/(6xy^8)

Without the parentheses, the product xy^8 is in the numerator. This is demanded by the order of operations, which requires you evaluate your expression as (-3x^5y^7/6)·xy^8

Answer:

The answer is (B) 1/2=12

Answer:

12

Step-by-step explanation:

Given the data :

X : 10,8,18,17,7

The mean value of scores obtained can be obtained thus :

Mean = ΣX / n

n = sample size = 5

Mean = ΣX / n = (10+8+18+17+7) / 5

Mean = 60 / 5 = 12

Answer:

A. 1 + 3x = -89

B. x = -30

Step-by-step explanation:

Let the unknown variable be x.

A. Translating the word problem into an algebraic expression, we have;

1 + 3x = -89

B. To solve for the unknown variable;

1 + 3x = -89

3x = -89 -1

3x = -90

x = -90/3

x = -30

Check:

1 + 3x = -89

Substituting the value of x;

1 + 3(-30) = -89

1 + (-90) = -89

1 - 90 = -89

-89 = -89

[tex]\\ \sf\longmapsto 112^2[/tex]

[tex]\\ \sf\longmapsto (100+12)^2[/tex]

[tex]\\ \sf\longmapsto 100^2+2(100)(12)+12^2[/tex]

[tex]\\ \sf\longmapsto 10000+2400+144[/tex]

[tex]\\ \sf\longmapsto 12400+144[/tex]

[tex]\\ \sf\longmapsto 12544[/tex]

112²

(a + b)² = (a² + 2ab + b²)

⇛112²

⇛(100 + 12)²

⇛(100)² + 2 × 100 × 12 + (12)²

⇛10000 + 2400 + 144

⇛12400 + 144

⇛12544

Answer:

A. Q1 = 4.6; Q2 = 5.5; Q3 = 5.95

Step-by-step explanation:

{4.3, 4.5, 4.7, 5, 5.5, 5.7, 5.9, 6, 6.1}

First find the median or the 2nd quartile

There are 9 data points so the middle is the 5th

4.3, 4.5, 4.7, 5,     5.5,     5.7, 5.9, 6, 6.1}

Q2 = 5.5

Now looking at the data on the left, we need to find the middle, which is Q1 or the first quartile

4.3, 4.5     , 4.7, 5,

It is between 4.5 and 4.7 so we average

(4.5+4.7)/2 = 9.2/2 = 4.6

Q1 is 4.6

We do the same for the data on the right, which is the third quartile or Q3

5.7, 5.9,  6, 6.1

(5.9+6)/2 = 11.9/2 = 5.95

Q3 = 5.95

Answer: IT'S A !!

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

[tex] \Large \mathbb{SOLUTION:} [/tex]

[tex] \begin{array}{l} \text{Let }r\text{ be the rate of the boat in still water and} \\ c\text{ be the rate of the current.} \\ \\ \text{So } \\ \begin{aligned} \quad&\bullet\:\text{Rate Upstream}= r - c \\ &\bullet\:\text{Rate Downstream}= r - c\end{aligned} \\ \\ \text{We know that }\text{Rate} = \dfrac{\text{Distance}}{\text{Time}}. \end{array} [/tex]

[tex] \begin{array}{l} \bold{Equations:} \\ \\ \begin{aligned} &\quad\quad \quad r - c = \dfrac{104}{4} = 26\quad (1) \\ \\ & \quad \quad \quad r + c = \dfrac{200}{4} = 50\quad (2)\\ \\ & \text{Adding (1) and (2), we get} \\ \\ &\quad\quad 2r = 76 \implies \boxed{r = 38\ \text{kph}} \\ \\ &\text{Using (2), it follows that} \\ \\ & \quad \quad c = 50 - r \implies \boxed{c = 12\ \text{kph}} \end{aligned} \end{array} [/tex]

Answer:

16cm

Step-by-step explanation:

Area is A = bh

to find a base, b = A/h

A=80

h=5

so then we have b = 80/5 = 16

Answer:

3/6=?/10

Step-by-step explanation:

multiply by together. ?=5

Answer:

A. Men had less distress from nausea on average than women but we can not determine if this is a significant difference.

Step-by-step explanation:

Working based on the information given, the mean values of each group with with men having an average score of 1.02 and women have an average of 1.79 this reveals that distressing nausea on average is higher in women than in men . However, to test if there is a significant difference would be challenging as the information given isn't enough to make proceed with the test as the standard deviations of the two groups aren't given and no accompanying sample data is given.

Answer:

THE ANSWER IS

Answer:

undersea trench

Step-by-step explanation:

Absolute value is the distance from zero

The highest mountain trench is |29028| or 29028 ft from zero

The lowest under sea trench is | -35840| of 35840 ft from zero

The highest absolute value is the undersea trench

Height always be positive .

Absolute value:-

[tex]\\ \sf\longmapsto |29028|=29028ft[/tex]

Absolute value:-

[tex]\\ \sf\longmapsto |-35840|=35840ft[/tex]