Answer:
El valor máximo de los platos a ordenar en el almuerzo es de $ 20.32.
Step-by-step explanation:
Sea [tex]c[/tex] el coste máximo que puede asumir el comensal, medido en pesos, el cual es representada por la siguiente suma:
[tex]c = c_{o} + c_{i} + c_{ii}[/tex]
Donde:
[tex]c_{o}[/tex] - Coste del consumo, medido en pesos.
[tex]c_{i}[/tex] - Coste del impuesto en el condado, medido en pesos.
[tex]c_{ii}[/tex] - Coste de la propina, medido en pesos.
Ahora, los costes por impuesto y por propina se determinan en función del coste de consumo:
Coste del impuesto en el condado
[tex]c_{i} = r_{i}\cdot c_{o}[/tex]
Donde [tex]r_{i}[/tex] es la razón entre el coste del impuesto en el condado y el coste del consumo, adimensional.
Coste de la propina
[tex]c_{ii} = r_{ii}\cdot (c_{o}+c_{i})[/tex]
[tex]c_{ii} = r_{ii}\cdot (c_{o}+r_{i}\cdot c_{o})[/tex]
[tex]c_{ii} = r_{ii}\cdot (1 + r_{i})\cdot c_{o}[/tex]
Donde [tex]r_{ii}[/tex] es la razón entre el coste de la propina y la suma de los costes de consumo y del impuesto del condado, adimensional.
Entonces, la suma completa queda representada por:
[tex]c = c_{o} + r_{i}\cdot c_{o}+r_{ii}\cdot (1+r_{i})\cdot c_{o}[/tex]
[tex]c = [1+r_{i}+r_{ii}\cdot (1+r_{i})]\cdot c_{o}[/tex]
A continuación, se despeja el coste de consumo (valor máximo de los platos):
[tex]c_{o} = \frac{c}{1 +r_{i}+r_{ii}\cdot (1+r_{i})}[/tex]
Si [tex]c = \$\,25[/tex], [tex]r_{i} = 0.07[/tex] y [tex]r_{ii} = 0.15[/tex], entonces:
[tex]c_{o} = \frac{\$\,25}{1+0.07+0.15\cdot (1+0.07)}[/tex]
[tex]c_{o} = \$\,20.32[/tex]
El valor máximo de los platos a ordenar en el almuerzo es de $ 20.32.
A triangle has vertices at (-4,-6),(3,3),(7,2). Rounded to two decimal places, which of the following is closest aporoximation of the perimeter of the triangle
Answer:
Perimeter= 29.12 unit
Step-by-step explanation:
Perimeter of the triangle is the length of the three sides if the triangle summef up together
Let's calculate the length of each side.
For (-4,-6),(3,3)
Length= √((3+4)²+(3+6)²)
Length= √((7)²+(9)²)
Length= √(49+81)
Length= √130
Length= 11.40
For (-4,-6),(7,2)
Length= √((7+4)²+(2+6)²)
Length= √((11)²+(8)²)
Length= √(121+64)
Length= √185
Length= 13.60
For (3,3),(7,2)
Length=√( (7-3)²+(2-3)²)
Length= √((4)²+(-1)²)
Length= √(16+1)
Length= √17
Length= 4.12
Perimeter= 4.12+13.60+11.40
Perimeter= 29.12 unit
Identify which equations have one solution, infinitely many solutions, or no solution. No solution: One solution: Infinitely solution:
Answer:
Top left: no
Top middle: one
Top right: no
Bottom left: infinite
Bottom middle: one
Bottom right: one
Step-by-step explanation:
Top left: no
Top middle: one
Top right: no
Bottom left: infinite
Bottom middle: one
Bottom right: one
In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal places.)
a. x=5
b. x <= 5
c. x>=6
Answer:
[tex]\mathbf{P(X=5) =0.0888}[/tex]
P(x ≤ 5 ) = 0.9707
P ( x ≥ 6) = 0.0293
Step-by-step explanation:
The probability of a binomial mass distribution can be expressed with the formula:
[tex]\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}[/tex]
[tex]\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}[/tex]
where;
n = 8 and π = 0.36
For x = 5
The probability [tex]\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}[/tex]
[tex]\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}[/tex]
[tex]\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}[/tex]
[tex]\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}[/tex]
[tex]\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}[/tex]
[tex]\mathtt{P(X=5) =0.0887645}[/tex]
[tex]\mathbf{P(X=5) =0.0888}[/tex] to 4 decimal places
b. x ≤ 5
The probability of P ( x ≤ 5)[tex]\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})[/tex]
[tex]{P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +[/tex][tex]\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )[/tex]
P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888
P(x ≤ 5 ) = 0.9707
c. x ≥ 6
The probability of P ( x ≥ 6) = 1 - P( x ≤ 5 )
P ( x ≥ 6) = 1 - 0.9707
P ( x ≥ 6) = 0.0293
A ball is released at a height of 16 inches to roll inside a half-cylinder. It rolls
to a height of 8 inches on the other side of the cylinder on roll 1. Each time it
rolls up a side of the cylinder, the ball reaches a point that is as high as it
had reached on the other side.
-lo
This explicit formula models the height of the ball, in inches, the nth time it
rolls up a side of the cylinder.
How high does the ball roll on its 5th time up the cylinder's side?
Answer:
Step-by-step explanation:
Using the given formula, we put n = 5
[tex]h = 8* {(\frac{1}{2}) ^{n-1}[/tex]
h = 8 / 16
h = 1 / 2 inches
the terms in this sequence increase by the same amount each time. _19_ _ 34_ a) work out the missing terms.
Answer:
The sequence is 14, 19, 24, 29, 34, 39.
Step-by-step explanation:
Let's call the common difference (the difference between two consecutive terms) as d. We see that the second term is 19 and the 5th term is 34 and since 5 - 2 = 3, we add d 3 times to 19 to get 34 so therefore:
19 + 3d = 34
3d = 15
d = 5 so the first term is 19 - 5 = 14, the third would be 19 + 5 = 24, the fourth would be 24 + 5 = 29 and the sixth would be 34 + 5 = 39.
determine the coordinator of the point
of intersection of lines
3x-2y=13 and 2y+x+1=0
Answer:
(3,-2)
Step-by-step explanation:
Given equations of line
3x-2y=13
2y+x+1=0
=> x = -1 -2y
Point of intersection will coordinates where both equation have same value of (x,y)
top get that we have to solve the both equations by using method of substitution of simultaneous equation.
using this value of x in 3x-2y=13, we have
3(-1-2y) -2y = 13
=> -3 -6y-2y = 13
=> -8y = 13+3 = 16
=> y = 16/-8 = -2
x = -1 - 2y = -1 -2(-2) = -1+4= 3
Thus, point of intersection of line is (3,-2)
PLEASE HELP ME WITH THIS QUESTION
Answer:
y-k
x-h
Step-by-step explanation:
Given E &D, F would be at (x, k).
That means E to F would be y-k.
And F to D would be x-h.
I assume you don’t need to find E to D, since that’s just r. (You could use the Distance Formula or Pythagoreans theorem to come up with and equation, but it wouldn‘t be one of those listed.)
A certain vector in the xy plane has an x component of 4 m and a y component of 10 m. It is then rotated in the xy plane so its x component is doubled. Its new y component is about:
Answer:
New length of component y' = 7.2 m (Approx)
Step-by-step explanation:
Given:
Length of component x = 4 m
Length of component y = 10 m
New length of component x' = 8 m
Find:
New length of component y' = ?
Computation:
Length vector of rotation = √x² + y²
Length vector of rotation = √4² + 10²
Length vector of rotation = √16 + 100
Length vector of rotation = √116
Length vector of rotation = √x'² + y'²
√116 = √x'² + y'²
116 = x'² + y'²
116 = 8² + y'²
New length of component y' = 7.2 m (Approx)
Write the null and alternative hypotheses you would use to answer this question. Are Americans getting fatter? Researchers interested in this question take a random sample of 500 people and record an average weight of 190 pounds. Ten years ago, the average weight was 185 pounds.
Answer:
H0: u = 185 against Ha: u > 185
or
H0: u ≤ 185 against Ha: u > 185
Step-by-step explanation:
The null and alternative hypotheses for this experiment would be
H0: u = 185 against Ha: u > 185
or
H0: u ≤ 185 against Ha: u > 185
This is a one tailed test .
If the results are such that we reject the null hypothesis and accept the alternative hypothesis it means that the Americans are getting fatter as the mean weight is increasing day by day.
The null hypothesis deals with all the values equal to or less than 185 pounds and the alternative with all the values greater than 185 pounds.
Use the graph of f to estimate the local maximum and local minimum. Local maximum: (0,1); local minimum: three pi over two, negative 1 and negative pi, negative 1 Local maximum: (0,0) and approx (0,1); local minimum: negative three pi over two, negative 1 Local maximum: (0,0); local minimum: three pi over two, negative 1 Local maximum: (0,1); local minimum: approx. (0,0) and three pi over two, negative 1
Answer:
The answer is A.
Step-by-step explanation:
Local maximums are whenever the graph reaches it's highest y value.
Local minimums are whenever the graph reaches it's lowest y value.
From the graph, we can see that the maximum y-value the graph reaches is y=1. And this happens when x=0.
This only happens once (from the graph shown). Thus, the local maximum would be:
[tex](0,1)[/tex]
The minimum values we can see from the graph is at y=-1. This happens twice from the graph, once at -π and again at 3π/2.
Thus, the local minimums are:
[tex](-\pi,-1), (3\pi/2,-1)[/tex]
isted below are amounts (in millions of dollars) collected from parking meters by a security service company and other companies during similar time periods. Do the limited data listed here show evidence of stealing by the security service company's employees? Security Service Company: 1.5 1.7 1.6 1.4 1.7 1.5 1.8 1.4 1.4 1.5 Other Companies: 1.8 1.9 1.6 1.7 1.8 1.9 1.6 1.5 1.7 1.8 Find the coefficient of variation for each of the two samples, then compare the variation. The coefficient of variation for the amount collected by the security service company is nothing%. (Round to one decimal place as needed.)
Answer:
Means:
1.55
1.73
Standard Deviation:
0.1434
0.1338
Coefficient of variation:
9.2
7.7
the limited data listed here shows evidence of stealing by the security service company's employees.
Step-by-step explanation:
Given data:
security Service Company Other Companies
x₁ x₂
1.5 1.8
1.7 1.9
1.6 1.6
1.4 1.7
1.7 1.8
1.5 1.9
1.8 1.6
1.4 1.5
1.4 1.7
1.5 1.8
n₁ = 10 n₂ = 10
To find:
coefficient of variation for each of the two samples
Solution:
The formula for calculating coefficient of variation of sample is:
Coefficient of Variation (CV) = (Standard Deviation / Mean) * 100%
Calculate Mean for Security Service Company data:
Mean = (Σ x₁) / n₁
= (1.5 + 1.7 + 1.6 + 1.4 + 1.7 + 1.5 + 1.8 + 1.4 + 1.4 + 1.5) / 10
= 15.5 / 10
Mean = 1.55
Calculate Standard Deviation for Security Service Company data:
Standard Deviation = √∑(x₁ - Mean)²/n₁-1
= √∑(1.5-1.55)² + (1.7-1.55)² + (1.6-1.55)² + (1.4-1.55)² + (1.7-1.55)² + (1.5-1.55)² + (1.8-1.55)² + (1.4-1.55)² + (1.4-1.55)² + (1.5-1.55)² / 10-1
=√∑ (−0.05)² + (0.15)² + (0.05)² + (−0.15)² + (0.15)² + (−0.05)² + (0.25)² + (−0.15)² + (−0.15)² + (−0.05)² / 10 - 1
= √∑0.0025 + 0.0225 + 0.0025 + 0.0225 + 0.0225 + 0.0025 + 0.0625 + 0.0225 + 0.0225 + 0.0025 / 9
= √0.185 / 9
= √0.020555555555556
= 0.14337208778404
= 0.143374
Standard Deviation = 0.143374
Coefficient of Variation for Security Service Company:
CV = (Standard Deviation / Mean) * 100%
= (0.143374 / 1.55) * 100
= 0.09249935 * 100
= 9.249935
CV = 9.2
CV = 9.2%
Calculate Mean for Other Companies data:
Mean = (Σ x₂) / n₂
= (1.8 + 1.9 + 1.6 + 1.7 + 1.8 + 1.9 + 1.6 + 1.5 + 1.7 + 1.8) / 10
= 17.3 / 10
Mean = 1.73
Calculate Standard Deviation for Other Companies data:
Standard Deviation = √∑(x₂-Mean)²/n₂-1
= √∑[(1.8-1.73)² + (1.9-1.73)² + (1.6-1.73)² + (1.7-1.73)² + (1.8-1.73)² + (1.9-1.73)² + (1.6-1.73)² + (1.5-1.73)² + (1.7-1.73)² + (1.8-1.73)²] / 10 - 1
= √∑ [(0.07)² + (0.17)² + (-0.13)² + (-0.03)² + (0.07)² + (0.17)² + (-0.13)² + (-0.23)² + (-0.03)² + (0.07)²] / 9
= √∑ (0.0049 + 0.0289 + 0.0169 + 0.0009 + 0.0049 + 0.0289 + 0.0169 + 0.0529 + 0.0009 + 0.0049) / 9
= √(0.161 / 9)
= √0.017888888888889
= 0.13374935098493
= 0.13375
Standard Deviation = 0.13375
Coefficient of Variation for Other Companies:
CV = (Standard Deviation / Mean) * 100%
= (0.13375 / 1.73) * 100
= 0.077312 * 100
= 7.7312
CV = 7.7
CV = 7.7%
Yes, the limited data listed here shows evidence of stealing by the security service company's employees because there is a significant difference in the variation.
nd the measure of angle m
2. Find the length of sie
m
18.2m
61°
15:1m
х
105mm
Answer:
1). m° = 56.1°
2). X= 91.8 mm
Step-by-step explanation:
For angle m°
Using the sine rule
15.1/sin m= 18.2/sin 90
But Sin 90= 1
15.1/sin m= 18.2
15.1= 18.2*sin m
Sin m = 15.1/18.2
Sin m=0.8297
m= sin^-1(0.8297)
m= 56.06°
m° = 56.1°
For length of side x
Using sine rule
X/sin 61= 105/sin 90
But sin 90= 1
X/sin 61= 105
X = sin61 *105
X=0.8746*105
X= 91.833 mm
X= 91.8 mm
These two triangles are congruent by the Hypotenuse-Leg Theorem.
Answer:
[tex] y = - 2 [/tex]
Step-by-step explanation:
Given that the 2 triangles are congruent based on the Hypotenuse-leg theorem, this implies that:
[tex] x - y = x + 2 [/tex] , and [tex] 2x - y = 4x + 2y [/tex]
Using the expression, [tex] x - y = x + 2 [/tex], solve for y:
[tex] x - y - x = x + 2 - x [/tex]
[tex] - y = 2 [/tex]
[tex] y = - 2 [/tex]
for the functions f(x) = 4x^4+4x^3-8x^2-13x-5 and g(x) = x+1, find (f/g)(x) and (f/g)(2)
Answer:
(f/g)(x) = 4x³ - 8x - 5(f/g)(2) = 11Step-by-step explanation:
f(x) = 4x⁴ + 4x³ - 8x² - 13x - 5
g(x) = x + 1
To find (f/g)(2) first find (f/g)(x)
To find (f/g)(x) factorize f(x) first
That's
f(x) = 4x⁴ + 4x³ - 8x² - 13x - 5
f(x) = ( x + 1)( 4x³ - 8x - 5)
So we have
[tex] (f/g)(x) = \frac{( x + 1)( 4x³ - 8x - 5)}{x + 1} [/tex]
Simplify
We have
(f/g)(x) = 4x³ - 8x - 5To find (f/g)(2) substitute 2 into (f/g)(x)
That's
(f/g)(2) = 4(2)³ - 8(2) - 5
= 4(8) - 16 - 5
= 32 - 16 - 5
= 11
(f/g)(2) = 11Hope this helps you
how many solutions are there to this non-linear systems/graph a. one solution,b.two solutions,c.no solutions
in the diagram, POS,QOT and UOR are straight lines. Find the value of y.
Answer:
y = 15°
Step-by-step explanation:
Since ∠QOR and ∠UOT are vertical, they are congruent so ∠UOT = 5y. Since POS is a straight line (which has a measure of 180°) and ∠POS = ∠POU + ∠UOT + ∠TOS, we can write:
5y + 5y + 2y = 180
12y = 180
y = 15°
Explain how to solve the inequality (x + 1)(x – 2) ∙ (x – 3) > 0. Explain in your own words, each step necessary to solve the inequality, making sure to follow the proper order of operations. Is this inequality accurate? Explain why or why not.
Answer:
[tex]x > -1[/tex] or
[tex]x > 2[/tex] or
[tex]x > 3[/tex]
Step-by-step explanation:
Given
[tex](x + 1)(x - 2) (x - 3) > 0[/tex]
Required
Solve; with steps
[tex](x + 1)(x - 2) (x - 3) > 0[/tex]
Start by splitting the inequality as follows
[tex]x + 1 > 0[/tex] or [tex]x - 2 > 0[/tex] or [tex]x - 3 > 0[/tex]
Solve the inequalities one after the other
Solving: [tex]x + 1 > 0[/tex]
Subtract 1 from both sides
[tex]x + 1 - 1 > 0 - 1[/tex]
[tex]x > -1[/tex]
Solving: [tex]x - 2 > 0[/tex]
Add 2 to both sides
[tex]x - 2 +2 > 0 +2[/tex]
[tex]x > 2[/tex]
Solving: [tex]x - 3 > 0[/tex]
Add 3 to both sides
[tex]x - 3 +3> 0+3[/tex]
[tex]x > 3[/tex]
Hence, the solution to the inequality is
[tex]x > -1[/tex] or
[tex]x > 2[/tex] or
[tex]x > 3[/tex]
HCF of x minus 2 and X square + X - 6
Answer:
[tex] \boxed{ \sf{ \bold{ \huge{ \boxed{x - 2}}}}}[/tex]Step-by-step explanation:
[tex] \sf{x - 2} \: and \: { {x}^{2} + x - 6}[/tex]
To find the H.C.F of the algebraic expressions, they are to be factorised and a common factor or the product of common factors is obtained as their H.C.F
Let's solve
First expression = x - 2
Second expression = x + x - 6
Here, we have to find the two numbers which subtracts to 1 and multiplies to 6
= x + ( 3 - 2 ) x + 6
Distribute x through the parentheses
= x + 3x - 2x + 6
Factor out x from the expression
= x ( x + 3 ) - 2x + 6
Factor out -2 from the expression
= x ( x + 3 ) - 2 ( x + 3 )
Factor out x+3 from the expression
= ( x + 3 ) ( x - 2 )
Here, x - 2 is common in both expression.
Thus, H.C.F = x - 2
Hope I helped!
Best regards!!!
Answer:
x - 2
Step-by-step explanation:
by factorization method
1) x - 2
2) x^2 + x - 6
by splitting method
x^2 + 3x - 2x - 6
taking separate common from the first two terms and last two terms
x(x + 3) - 2(x + 3)
now writing x+3 once and the other term to get the right answer
(x + 3)(x - 2)
in both parts just see the similar term and write it as HCF
HCF= x - 2
and the second method by which you can get this answer is division method
which of the following best describes the bases of a cylinder? A. Congruent B. Polygons C. Parallel D. Discs (Check All That Apply)
Answer:
A. Congruent and D. Discs
Step-by-step explanation:
You won't see a cylinder that doesn't have congruent bases
Look at the shape of the bases and look at a disc compare their shape
We can describe the bases of a cylinder as congruent.
What is the volume of cylinder?The volume of cylinder is given by -
V = πR²h
Given is to describe the bases of a cylinder.
The cylinders are uniform in cross - section. Therefore, the bases of the cylinder will have the same area. So, we can conclude that the given bases are congruent.
Therefore, we can describe the bases of a cylinder as congruent.
To solve more questions on cylinders, visit the link below-
https://brainly.com/question/16134180
#SPJ7
Find the reciprocal of the sum of the reciprocals of (1)/(-5) and -(1)/(6)
Answer:
-11
Step-by-step explanation:
Write out the original fractions: [tex]\frac{1}{-5} and \frac{-1}{6}[/tex] Flip the fractions around to get the reciprocal: [tex]\frac{-5}{1} + \frac{6}{-1}[/tex] Simplify: -5 and -6Add together: -5 + -6 = -11Ethan has collected 417 football cards. He shares them equally between himself and his two friends. How many will each person get
Answer:
139 cards
Step-by-step explanation:
This is basically just a division statement - we have 417 cards and want to split it with 3 people (two friends + himself = 3 people).
We can divide these using a calculator or long division, but either way you will get:
[tex]417\div3=139[/tex]
Hope this helped!
Answer: 139
Step-by-step explanation:
417 divided by 3 gives you 139.
Is 1.45 times 10 to the -7 power a scientific notation
Answer:
Yes.
It is 1.45 x 10^-7 or 0.000000145
Hope it helps!
Answer:
It is 1.45 x 10^-7 or 0.000000145
Step-by-step explanation:
A ladder 10 ft long leans against a vertical wall. If the lower end is being moved away from the wall at the rate of 6 ft/sec, how fast is the height of the top changing (this will be a negative rate) when the lower end is 6 feet from the wall?
Answer:
-4.5ft per sec
Step-by-step explanation:
Assume that vertical wall has a distance of y and the horizontal floor is x (6 ft).
This forms a triangle with the ladder as the hypothenus of length 10ft
We have dy/dt = 6ft per sec
According to Pythagoras law the relationship between x and y is
(x^2) + (y^2) = (hypothenus ^2) = 10^2
When we differentiate both sides of the equation
2x(dx/dt) + 2y(dy/dt) = 0
dy/dt = (x/y) * (dx/dt)
y= √(10^2) - (6^2) = 8ft
So dy/dt = (6/8)* (6/1)= -4.5 ft per sec
It is a negative rate
what is the difference between growth and development
Answer:
growth is usually reffered to as physical growth happening in size while development happens more gradually and happens mentally.
Step-by-step explanation:
idk if u meant pyscologically or not but that is my understanding.
i will rate you brainliest
Answer:
(3x+11)/ (5x-9)
Step-by-step explanation:
The numerator is what is on the top of the bar in the middle
(3x+11)/ (5x-9)
Answer:
[tex]\large \boxed{\mathrm{Option \ B}}[/tex]
Step-by-step explanation:
The numerator of a fraction is the top section of the fraction.
Find the missing side or angle.
Round to the nearest tenth.
Answer:
65.8
Step-by-step explanation:
Use the sin formula
100/sin (28) = x/ sin (18)
(sin (18) (100))/ sin (28) = x
x = 65.8223
x = 65.8
Answer:
65.8
Step-by-step explanation:
Accellus Correct
"Julien is trying to determine his variable type in order to select the proper statistical tests. He is measuring the height of a part. What type of variable is this"
Answer:
Quantitative
Step-by-step explanation: Quantitative or numerical variable are statistical or measured variables which involves numbers. Numerical variables allows for mathematical operations such as addition, subtraction and so on to be performed in them. Quantitative variables include height, age, weight, population and other measured variable with have numerical attributes. They can be measured on either ordinal, ratio or interval scales. Hence, since Julien is trying to determine height, the variable is a quantitative or numeric variable.
Kyle buys $30,000 of company XYZ's shares, at a share price of $50. A year later, XYZ's share price is $55, and Kyle sells all his shares. How many dollars did Kyle's investment gain
Answer:
$3,000
Step-by-step explanation:
Given that the shares are $50 per share and that Kyle buys $30,000 worth of shares,
Number of shares bought = total price of shares ÷ price per share
= $30,000 ÷ $50
= 600 shares
We are also give that a year later, the shares are worth $55
Total value of shares 1 year later = Price per share one year later x number of shares
= $55 x 600
= $33,000
Hence the investment gained $33,000 - $30,000 = $3,000
Answer:
10%
Step-by-step explanation:
x - amount of shares bought
x * 50[$] = 30000[$]
x = 30000/50 = 600
if he bought 600 shares then he sold earning in total:
600 * 55[$] = 33000[$]
that means investmant gain can be calculate as:
return on investment = (gain from investment – cost of investment) / cost of investment
return on investment = (33000 - 30000) / 30000 = 3000/30000 =0.1 = 10%
What is 4/5 to the 5th power
The head of a computer science department is interested in estimating the proportion of students entering the department who will choose the new computer engineering option. Suppose there is not information about the proportion of students who might choose the option. What size sample should the department head take if he wants to be 95% confident that the estimate is within 0.10 of the true proportion
Answer:
96
Step-by-step explanation:
From the given information:
At 95% Confidence interval level,Level of significance [tex]\alpha[/tex] 0.05, the value of Z from the standard normal tables = 1.96
Margin of Error = 0.10
Let assume that the estimated proportion = 0.5
therefore; the sample size n can be determined by using the formula: [tex]n =(\dfrac{Z}{E})^2 \times p\times (1-p)[/tex]
[tex]n =(\dfrac{1.96}{0.1})^2 \times 0.5\times (1-0.5)[/tex]
[tex]n =(19.6)^2 \times 0.5\times (0.5)[/tex]
n = 96.04
n [tex]\approx[/tex] 96
