EH is a diameter of D. The measure of ef is (10x+ 8) and the measure of gh is (11x). Determine the values

Answer:

122

Step-by-step explanation:

The exterior angle of a triangle is the sum of the opposite interior agnles

32+90 =x

122 =x

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

[tex] \bf \large \hookrightarrow \: \: x \: = \: 32 \degree \: + \: 90 \degree [/tex]

[tex]\bf \large \hookrightarrow \: \: x \: = \: 122 \degree[/tex]

Answer:

4 TOPPING WITH 5 CENTS LEFT

Step-by-step explanation:

A AND B ARE CORRECT ok so $6.50 to spend take out $3 for the cost of a plain hamburger which would leave you with $3.50 to spend on toppings alone so

3.5-0.75=2.75 (1 topping

2.75-0.75=2 (2 topping

2-0.75=1.25 (3 topping

1.25-0.75=0.5 (4 topping

there for you can get 4 toppings with 5 cents left over

Use the Pythagorean theorem

? = sqrt(52^2 + 19^2)

? = sqrt(2704 + 361)

? = sqrt(3065)

Answer: sqrt(3065)

Answer:

45 degrees

Step-by-step explanation:

the 2 angles are supplementary (add up to 180 degrees)

180-135=45

Answer:

(4x4) + (6x11) = 82 for area

4+4+10+11+7+6= 42

Step-by-step explanation:

You can calculate this by calculating the two squares separately, and on the bottom line, it is 10, so just subtract 4 to make the rectangle on the right, separate from the square on the left. (for area)

Answer:

1 / 5

Step-by-step explanation:

Given the outcome of number cube spin : 2, 5, 3, 5, 1, 2, 3, 3, 4, 6

The experimental probability of an event, A is given as :

P(A) = number of times A occurs / total number of trials

Therefore, the experimental probability of getting 2 ;

P(getting 2) = Number of times 2 occurs / total number of trials

P(getting 2) = 2 / 10 = 1/5

The order of Rotational symmetry is 2 (option B) for the given figure.

It is basically the number of times we obtain the initial(or same) figure in a single rotation of 360°.

The rotational symmetry of a shape demonstrates that when an object is rotated on its axis, the form of the object examines the same. Many geometrical shapes emerge to be symmetrical when they exist rotated 180 degrees or with some angles, clockwise or anticlockwise. Some of the examples exist as squares, circles, hexagons, etc.

If we rotate the picture by 90°or 270°, then it wont match the initial figure.

If we rotate the picture by 180° from initial, it will match the figure.

If we further rotate it by 180°( full 360° completed) , it will again match.

Hence, it matches 2 times in a single rotation.

Therefore it has rotational symmetry of order 2.

To solve more questions about rotational symmetry refer:

https://brainly.com/question/16883531

#SPJ2

Answer: The graph DOES represent a function.

Explanation: If you use a vertical line in the function and it only intersects once, that means it is a function. If it intersects twice, it is not a function.

See examples:

Answer:

m=4

Step-by-step explanation:

m = y2 - y1/x2 - x1

(y2=8, y1=0, x2= 2, x1=0)

m = y2 -y1/x2 - x1

= 8 - 0/2 - 0

= 8/2

=4

find the square root and of 1+i√3​  

Answer:

Y = 8 + 2d

Step-by-step explanation:

Y = 8 + 2d where d is miles traveled

Answer:

y = 2d + 8

Brainliest, please!

Step-by-step explanation:

y = mx + b

m = slope, b = y-intercept

The flat rate of $8 is the y-intercept, and the slope is $2.

y = 2x + 8

We can change x to d to match the context of this problem.

y = 2d + 8

Answer:

100000 = 8 (4) ^t

Step-by-step explanation:

We are multiplying by 4 each time

y = a (4)^t

The initial amount is 8

y = 8 (4)^t

We want to get to 100000

100000 = 8 (4) ^t

Answer:

B

8 ⋅ 4^t  = 100,000

Step-by-step explanation:

Answer:

cos(pi/2) + i sin (pi/2)

Step-by-step explanation:

(1+i)/ (1-i)

Multiply top and bottom by (1+i)

(1+i) (1+i)/ (1-i)(1+i)

Foil the top (1+i)(1+i) = 1 +2i +i^2 = 1 +2i -1 = 2i

Foil the bottom ( 1+i)(1-i) = 1 - i^2 = 1 - (-1) =2

2i/2 = i

the magnitude is (0^2+1^2) = 1

The angle is tan^-1( 1/0) = pi/2

cos(pi/2) + i sin (pi/2)

Answer:

4/8= 2/4=1/2= 50%

Step-by-step explanation:

4 out of the 8 new cars have a fuel efficiency of less than 27 mpg. that is is 50%

Answer:

Does the answer help you?

Step-by-step explanation:

here's the answer to your question

Answer:

[tex]\frac{1}{10} * \frac{1}{100} = \frac{1}{1000}[/tex]

1000 times

Step-by-step explanation:

Answer:

0.1% = 1 spin then

100% = ( 100×1) ÷0.1 = 1000

we are using 100% because its a sure bet it will happen but not logically

the answer is 1000

1). 210m^2+156m-96=0

2). 35m^2+26x-16

3). 35m^2+40m-14m-16

4). (35m^2+40m)+(-14m-16)

5). 5m(7m+8)-2(7m+8)

6). (5m-2)(7m+8)

7.) m= 2/5, -8/7

On the 2nd step I divided 6 on both sides.

Answer:

0 is the answer . The explanation is in the attachment .

• {4, 7, 12, 19, … }

has 1st differences

7 - 4 = 3

12 - 7 = 5

19 - 12 = 7

and 2nd differences

5 - 3 = 2

7 - 5 = 2

• {-1, 2, 7, 14, …}

1st differences:

2 - (-1) = 3

7 - 2 = 5

14 - 7 = 7

2nd differences:

5 - 3 = 2

7 - 5 = 2

• {-2, -8, -18, -32, …}

1st differences:

-8 - (-2) = -6

-18 - (-8) = -10

-32 - (-18) = -14

2nd differences:

-10 - (-6) = -4

-14 - (-10) = -4

Answer:

Hello,

Step-by-step explanation:

I  am  going to explain the method with the 1th:

[tex]\begin{array}{ccccc}n & u_n&u_{n+1}-u_{n}&u_{n+2}-2u_{n+1}+u_{n}&v_{n}\\1&4&&6\\2&7&3&9\\3&12&5&2&14\\4&19&7&2&21\\...&&&\\\end{array}\\\boxed{u_{n+2}=2u_{n+1}-u_{n}+2}\\[/tex]

[tex]Let\ say\\v_{n}=u_{n}+2\\v_{n+2}=u_{n+2}+2=(2u_{n+1}-u_{n}+2)+2=2(v_{n+1}-2)-(v{n}-2)+4\\v_{n+2}=2v_{n+1}-v{n}+2\ (1)\\v_{n+3}=2v_{n+2}-v{n+1}+2\ (2)\\(2)-(1)==> \boxed{v_{n+3}=3v_{n+2}-3v_{n+1}+v_n}\\[/tex]

[tex]Caracteristic\ equation:\\P(r)=r^3-3r^2+3r-1=0\\P(r)=(r-1)^3\\v_n=\alpha+\beta*n+\gamma*n^2\\v_1=6 ==> \alpha+\beta*1+\gamma*1=6\\u_2=9 ==> \alpha+\beta*2+\gamma*4=9\\u_3=14 ==> \alpha+\beta*3+\gamma*9=14\\[/tex]

[tex]\begin{bmatrix}1&1&1\\1&2&4\\1&3&9\end{bmatrix}*\begin{bmatrix}\alpha\\\beta\\\gamma\end{bmatrix}=\begin{bmatrix}6\\9\\14 \end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\1&2&4&9\\1&3&9&14\end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\0&2&3&3\\0&2&8&8\end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\0&1&3&3\\0&1&4&4\end{bmatrix}\\\\[/tex]

[tex]\begin{bmatrix}1&1&1&6\\0&1&3&3\\0&0&1&1\end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\0&1&0&0\\0&0&1&1\end{bmatrix}\\\\\\\begin{bmatrix}1&0&0&5\\0&1&0&0\\0&0&1&1\end{bmatrix}\\[/tex]

[tex]\alpha=5\\\beta=0\\\gamma=1\\\boxed{v_n=5+0*n+1*n^2}\\\boxed{u_n=5+0*n+1*n^2-2}\\\begin{array}{ccccc}n & u_n\\1&5+1-2=4\\2&5+4-2=7\\3&5+9-2=12\\4&5+16-2=19\\...&...\\\end{array}\\[/tex]

Answer:

y=-4x+16

Step-by-step explanation:

Okay, so a perpendicular line has an opposite reciprocal slope.

The slope for the first line is x/4, but I like to write it as 1/4x, since it's easier to look at.

The opposite reciprocal for 1/4x is -4x

So far, we have y=-4x+ [  ]

To find the remaining b value, we can use the given point intersection.

plug in the x and y values given (4, -1) and solve for b.

The equation for the perpendicular line is y=-4x+16

Answer:

Given, A={p,q,r}.

Now, possible subsets of A are ,{p},{q},(r) {p,q}.

(q,r) (p,r) (p,q,r)

Answer:

-80\112 = -5\7

we divided both numbers by 16

[tex]\\ \sf\longmapsto 41sin\Theta=40[/tex]

[tex]\\ \sf\longmapsto sin\Theta=\dfrac{40}{41}[/tex]

Now

[tex]\boxed{\sf cos\Theta=\sqrt{1-sin^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\left(\dfrac{40}{41}\right)^2}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\dfrac{1600}{1682}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{1681-1600}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{81}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\dfrac{9}{41}[/tex]

We know

[tex]\boxed{\sf tan\Theta=\dfrac{Sin\theta}{Cos\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{tan\Theta}{1-tan^2\Theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{sin\Theta}{cos\Theta}}{1-\dfrac{sin^2\Theta}{cos^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{\left(\dfrac{40}{41}\right)}{\left(\dfrac{9}{41}\right)}}{1-\dfrac{\left(\dfrac{40}{41}\right)^2}{\left(\dfrac{9}{41}\right)^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{{40}}{{9}}}{1-\dfrac{{40}^2}{{9}^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{9^2-40^2}{9^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{81-1600}{81}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{-1519}{81}}[/tex]

[tex]\\ \sf\longmapsto {\dfrac{40}{\cancel{9}}}\times \dfrac{\cancel{81}}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto \dfrac{40\times 9}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto - \dfrac{360}{1519}[/tex]

Answer:

804.2 km³

Step-by-step explanation:

Volume of a cylinder: πr²h

r = radius, h = height

[tex]\pi r^2h\\\pi(8)^2(4)\\\pi(64)(4)\\\pi(256)\\804.2[/tex]

Answer:

[tex]\sqrt[2]{8}[/tex]

Step-by-step explanation:

Remember the basic format of a fraction raised to a fractional exponent:

[tex]a^\frac{b}{c}=\sqrt[b]{a^c}[/tex]

Some terms to keep in mind are the following:

(a) is the base

(c) is the exponent

(b) is the index

Apply this information to the given problem:

[tex]2^\frac{3}{2}[/tex]

In this case, (2) is the base, and the index; (3) is the exponent. Apply the general format of the fraction exponent to change the expression from an exponent to a radical.

[tex]2^\frac{3}{2}=\sqrt[2]{2^3}[/tex]

Simplify the term under the radical:

[tex]\sqrt[2]{2^3}=\sqrt[2]{8}[/tex]

Answer:

[tex]58.99[/tex]

Step-by-step explanation:

[tex] \tan(61) = \frac{o}{a} \\3.74 = \frac{x}{17} \\ x = 17 \times 3.74 \\ = 58.99[/tex]

Answer:

see below

Step-by-step explanation:

y = x^2 +2x - 8

Factor

y = ( x+4)(x-2)

The zeros are

x+4 = 0  x-2 = 0    

x= -4    x= 2

(-4,0)  (2,0)

The axis of symmetry is 1/2 way between the zeros

(-4+2)/2 = -2/2 = -1

x = -1

The x coordinate of the vertex is at the axis of symmetry

The y value is found by substituting x=-1

y = (-1+4) (-1-2)= 3*-3 = -9

Vertex ( -1,-9)

The domain is all real numbers

The range is from -9 up

y≥ -9  since it opens upward

Answer:

1

Step-by-step explanation:

K(x)=5^(x+2)

Let x = -2

K(-2)=5^(-2+2)

       = 5^0

      = 1

Answer:

k(- 2) = 1

Step-by-step explanation:

Substitute x = - 2 into k(x) , that is

k(- 2) = [tex]5^{-2+2}[/tex] = [tex]5^{0}[/tex] = 1 [ [tex]a^{0}[/tex] = 1 ]