Eduardo has in his pocket $1 in pennies, $1 in nickels, and $1 in dimes. If he randomly pulls out just one coin, what is the probability that he will pull out a dime?

Answer:

I think the answer is x = 2

Answer: 2

Step-by-step explanation:

-6x+5=3-5x

+5x +5x

-x +5=3

-5 -5

-x = -2

-2 -2

X=2

Answer:

The first choice.

Step-by-step explanation:

It pass through the x axis at x = 3, so a factor must be (x - 3).

Answer:

The first option is correct :)

~Hope this helps

Answer:

-3 - 16b

Step-by-step explanation:

by simply doing the multiplication and then add combinable terms.

9 - 4(3 + 4b) = 9 - 12 - 16b = -3 - 16b

Explanation:

Let's simplify step-by-step:

9-4(3 + 4b)

Distribute:

= 9 + (-4)(3) + (-4)(4b)

= 9 + (-12) + (-16b)

Combine Like Terms:

= 9 + (-12) + (-16b)

= (-16b) +(9 + (–12) )

= -16b + (-3)

Answer:

-16b + (-3)

Answer:

4,414,000,000

Step-by-step explanation:

4.414x10^9, move the decimal place 9 places to the left.

Answer:

C

Step-by-step explanation:

there are infinitely many solutions since different values of x and y will work for this simultaneous equation

Answer:

(5,2)

Step-by-step explanation:

midpoint formula for future reference

(x1+x2/2),(y1+y2/2)

(3+7/2),(-5+9/2)

(10/2),(4/2)

(5,2)

Answer:

Using the section formula, if a point (x,y) divides the line joining the points (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then

(x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

3AC=CB

CB

AC

=

3

1

Since, A(1,1) and B(2,3) & m:n=1:3

Therefore, we have

C(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

(

1+3

(1)(2)+3(1)

,

1+3

(1)(3)+3(1)

)

C→(

4

5

,

2

3

).

Answer:

y^-24, x^-2 y^-5, 1/ y^24, x^2/y^11, x^2y^-11 and 1/ x^2y^5

ok i tried searching up the problem and how to solve it but didn`t come up with much.

i don`t know if this changes anything, but I noticed that some of these answers are opposites

ex (from the sequence you gave me in the comments below)                                      : y^-24, x^-2, y^-5, y^24, x^2,  y^5

maybe thats what it meant by matching the expressions?

again, sorry if this wasnt much help i have a small brain DD::

Answer:

5x^2 +4x -6

Step-by-step explanation:

that is the answer

yep

Answer:

5x² + 4x - 6

Step-by-step explanation:

Subtract 2x² - 5x - 12 from 7x² - x - 18 , that is the opposite operation, that is

7x² - x - 18 - (2x² - 5x - 12) ← distribute parenthesis by - 1

= 7x² - x - 18 - 2x² + 5x + 12 ← collect like terms

= 5x² + 4x - 6

Step-by-step explanation:

Solution,

Let the total number of books be x, then

Books in English language=4800

40% of x=4800

40/100×x=4800

40x/100=4800

40x=4800×100

40x=480000

x=480000/40

x=12000

So the total number of books in the library is 12000.

Answer:

KL=63

Step-by-step explanation:

Answer:

Step-by-step explanation:

Kl=63

Answer:

10.6

Step-by-step explanation:

Pythagorean theorem: a² + b² = c²

Where a and b = the legs and c = hypotenuse

We are given two legs and need to find the hypotenuse

Given:

Short leg (a) = 7

Long leg (b) = 8

Hypotenuse = c

Now to find the value of c we simply plug in the values of the variables into the Pythagorean theorem and solve for c

Pythagorean theorem: a² + b² = c²

a = 7, b = 8, c = c

Plug in values

7² + 8² = c²

Now solve for c

Simplify exponents

49 + 64 = c²

Add

113 = c²

Taking the square root of both sides

c = 10.6 ( rounded to the nearest tenth )

Answer:

c = 10.6

Step-by-step explanation:

[tex]h {}^{2} = p {}^{2} + b {}^{2} \\ c {}^{2} = (8) {}^{2} + (7) {}^{2} \\ c = \sqrt{64 + 49} \\ c = \sqrt{113} \\c = 10.6[/tex]

Answer:

The second option

Step-by-step explanation:

First, simplify the bracket

[tex] \frac{4r {}^{3} s {}^{2} t {}^{4} }{2r {}^{4} st {}^{6} } [/tex]

Apply Quotient of Powers

[tex]2 {r}^{ - 1} s {t}^{ - 2} [/tex]

Which equals

[tex] \frac{2s}{rt {}^{2} } [/tex]

Raise this to the fifth power

[tex] \frac{32s {}^{5} }{ {r}^{5} t {}^{10} } [/tex]

Multiply by the outsides numbers(5^r^6 and t^4

[tex] \frac{160 {}^{} r {}^{6}s {}^{5} t {}^{4} }{r {}^{5} t {}^{10} } [/tex]

[tex]160r {}^{5} t {}^{ - 6} [/tex]

[tex] \frac{160r {}^{}s {}^{5} }{t {}^{6} } [/tex]

Answer:

Step-by-step explanation:

A rectangle has the perimeter of 66cm, and since a rectangle has 2 lengths and 2 widths, we can tell that 2 widths = 66-27*2 = 12

so 1 width is half of 12 which is 6

Population growth represents the rate at which the population changes

Given that:

[tex]r_1 = 2[/tex] ----- i.e. when the population doubles

[tex]r_2 = \frac{1}{2}[/tex] ----- i.e. when the population cut in halves

Population growth is represented as: [tex]A_n = ar^{n}[/tex]

Organism A

For the first 5 days (when it doubles) is:

[tex]A_5 = ar_1^{5[/tex]

Substitute [tex]r_1 = 2[/tex]

[tex]A_5 = a\times 2^{5[/tex]

For the next 3 days (when it cut in halves) is:

[tex]A = A_5 \times r_2^3[/tex]

Substitute [tex]A_5 = a\times 2^{5[/tex] and [tex]r_2 = \frac{1}{2}[/tex]

[tex]A= a \times 2^5 \times (\frac{1}{2})^3[/tex]

Apply law of indices

[tex]A = a \times 2^5 \times 2^{-3[/tex]

[tex]A = a \times 2^{5-3[/tex]

[tex]A = a \times 2^{2[/tex]

So, the growth factor of organism A is:

[tex]A = a \times 2^{2[/tex]

Organism B

For the 8 days, we have:

[tex]B=ar_1^8[/tex]

[tex]B=a\times 2^8[/tex]

The expression (n) for the number of times the population of B is greater than A is:

[tex]n = \frac BA[/tex]

This gives:

[tex]n = \frac{a \times 2^8}{a \times 2^2}[/tex]

[tex]n = \frac{2^8}{2^2}[/tex]

Apply law of indices

[tex]n = 2^{8-2}[/tex]

[tex]n = 2^{6}[/tex]

The expression that is not in exponential form is:

[tex]n = 2 \times 2\times 2\times 2 \times 2\times 2[/tex]

[tex]n = 64[/tex]

Hence:

Read more about population growth at:

https://brainly.com/question/17520917

Answer:

Month 1: 500 - 15 = 485

Month 2: 485 - 15 = 460

Month 3: 460 - 15 = 445

Month 4: 445 - 15 = 430

Step-by-step explanation:

Answer:

125

Brainliest, please!

Step-by-step explanation:

13x - y

x = 11, y = 18

13(11) - 18

143 - 18

125

Answer:

125

Step-by-step explanation:

13x - y

Substituting x = 11 and y = 18,

=> 13(11) - 18

=> 143 - 18

=> 125

Step-by-step explanation:

4x is the real answer of that question

Answer:

Is there supposed to be a picture?

Step-by-step explanation:

Answer:

we need the image

Step-by-step explanation:

Answer:

29° C

Step-by-step explanation:

-17(-12)

=29

Hope this helps

Answer:

29C

Step-by-step explanation:

Above zero temperature = +17C

Below zero temperature = -12C

Difference= 17 - (-12C)

                 = 17 + 12 C

                 =29C

The money belongs to Jackie, Avery, and Samantha is $10, $30, and $16 respectively.

Given that,

Avery has three times as Jackie.

Also, Jackie has $6 lower than Samantha.

Together they have $56.

Based on the above information

Let us assume the Jackie be x

So, Avery should be 3x

Samantha should be x + 6

So, the equation should be

x + 3x + x + 6 = $56

5x = $56 - $6

5x = $50

x = $10

So, Jackie has $10

Avery has $30

And, Samantha has $16

Therefore we can conclude that the money belongs to Jackie, Avery, and Samantha is $10, $30, and $16 respectively.

Learn more about the money here: brainly.com/question/10943652

Answer:

8,000 - (-400)

Step-by-step explanation:

Answer: 8,000 - (-400) =

Step-by-step explanation:

Answer:

1 rational b/c terminating decimal

2 irrational b/c non-terminating decimal

3 rational b/c non-terminating decimal

4 rational b/c it in an integer, which are part of rational numbers

5 rational b/c non-terminating decimal

6 b) 7.625

Step-by-step explanation:

Answer:

16= (x-4)^2 +(y+9)^2

Step-by-step explanation:

hey! The formula for the equation of a circle is r^2= (x-h)^2 + (y-k)^2

r= the radius (in your case you have the diameter so you do not need to square it)

(h,k)= is the center coordinates, so your center coordinate would be (4, -9). You now have your h (h=4) and your k (k=-9) so you can plug it in the formula! :)

a nice rating would help out

Answer:

3. MNP = OPN

Step-by-step explanation:

the second could be as well, but the sequence is the same for the third option, thus the second option is wrong

Answer:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]