During what intervals was Jenny positively accelerating?

During What Intervals Was Jenny Positively Accelerating?

Answers

Answer 1

Answer:

3:00 - 3:02 and 3:07 - 3:08

Explanation:

Those are the only intervals in which Jenny's speed increased.

Answer 2

Answer and Explanation:

To know where Jenny was positively accelerating, we have to find where the slopes on the graph are increasing (in the positive direction).

By looking at the graph, we can see that at the intervals:

3:00 to 3:02 and 3:07 to 3:08

Jenny was positively accelerating, as there is an increase in speed during these time intervals.

#teamtrees #PAW (Plant And Water)

I hope this helps!


Related Questions

Logam P dan Q sejenis. Logam P yang memiliki panjang 1 meter dipanaskan hingga mengalami kenaikan suhu 12ºC, akibatnya logam bertambah panjang 0,2 cm. Logam Q juga dipanaskan hingga mengalami kenaikan suhu 10°C dan panjangnya bertambah 0,1 cm. Tentukanlah panjang mula-mula logam Q!​

Answers

Answer:

I don't know ???

sorry

Name the type of relationship between current and potential difference for a resistor at constant temperature. [

Answers

The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it. This is called Ohm's law

A apartie undergoes two displacement.The one has amagnitude of 150cm and makes an angle of 120 degrees with that positive x-axis.The resultant of the two displacement is 140cm at 35 degrees to the positive x-axis .Find the magnitude and direction of second displacement

Answers

Answer:

A = 150 cm at 120 degc

Where A + B = C       find B

B = C - A          add -A to both sides

Ax = 150 cos 60 = -75

Ay = 150 sin 60 = 129.9

Likewise

Cx = 114.7

Cy = 80.3

Bx = Cx - Ax = 114.7 + 75 = 189.7

By = Cy - Ay = 80.3 -129.9 = -49.6

B = (189.7^2 + 49.6^2)^1/2 = 196.7       length of B vector

tan B = By / Bx = -49.6 / 189.7       B = -14.65 deg

Also

sin B = By / B = -49.6 / 196.1 = -14.65 deg

So B is 196.1 cm at -14.65 deg

The number of windings on the primary coil of a transformer
is 1.5 times greater than on the secondary coil. The primary
coil has a current of 3.0 A and a voltage of 12.0 V. Determine
the voltage and current on the secondary coil.

Answers

Answer:

I. Vs = 8.0 Volts.

II. Is = 4.5 Amperes.

Explanation:

Given the following data;

Np = 1.5Ns = [tex] \frac {N_{P}}{N_{S}} = 1.5 [/tex]  ..... equation 1

Ip = 3.0 A

Vp = 12 V

To find the voltage and current on the secondary coil;

I. For the voltage in the secondary coil (Vs), we would use the following formula;

[tex] \frac {V_{P}}{V_{S}} = \frac {N_{P}}{N_{S}} [/tex]  ...... equation 2.

Substituting eqn 1 into eqn 2, we have;

[tex] \frac {V_{P}}{V_{S}} = 1.5 [/tex]

[tex] \frac {12}{V_{S}} = 1.5 [/tex]

Cross-multiplying, we have;

[tex] V_{S} * 1.5 = 12 [/tex]

[tex] V_{S} = \frac {12}{1.5} [/tex]

Vs = 8.0 V

II. For the current in the secondary coil (Is), we would use the following formula;

[tex] \frac {I_{S}}{I_{P}} = \frac {N_{P}}{N_{S}} [/tex]  .... equation 3

Substituting eqn 1 into eqn 3, we have;

[tex] \frac {I_{S}}{I_{P}} = 1.5 [/tex]

[tex] \frac {I_{S}}{3.0} = 1.5 [/tex]

Cross-multiplying, we have;

[tex] I_{S} = 1.5 * 3.0 [/tex]

Is = 4.5 A

Ag,Au and Cu are called coinage metals why plzzzz hurry its urgent plzzz​

Answers

Answer:

This is because these metals are used for minting (making) coins.

Answer:

It is bcz it is used for making coins

why is the fuse used in a circuit called safety fuse?

Answers

Answer:

The maximum current which can flow through a fuse without melting it, is called its rating. ... If current higher than 8 A flows through the fuse, it would melt and circuit gets broken. ... Hence, fuse acts as a safety device

Answer:

The guy above me is right

Explanation:

What are the units for speed?
O A. km/s2
O B. m/s2
O C. m/s2
O D. m/s

Answers

Answer:

Explanation:

The only one that doesn't have a time unit that is squared is the one that is a label for speed or velocity. Acceleration has a label with the time unit squared, like m/s/s. Choice D is the only unit for speed/velocity.

Answer: D

Explanation: metres per second (m/s)

Convert 400 mm to m using the method of dimensional analysis

Answers

Answer:

To convert 400 mm to m you can apply the formula [m] = [mm] / 1000; use 400 for mm. Thus, the conversion 400 mm m is the result of dividing 400 by 1000. 0.4

PLEASE MARK AS BRAINLIEST ANSWER

a motorcycle covers 500 meters in 25 seconds. calculate the average velocity​

Answers

Vtb xe máy là:

v=s : t= 500 : 25=20(m/s)

which physical property of the gas molecules gives the measurement of temperature​

Answers

The temperature of a gas molecule is measured by the average translational kinetic energy

Answer:

The temperature of a gas is a measure of the average translational kinetic energy of the molecules. In a hot gas, the molecules move faster than in a cold gas; the mass remains the same, but the kinetic energy, and hence the temperature, is greater because of the increased velocity of the molecules

Explanation:

This is also from Go0gle because my explanation would've been an essay long .

but in shorter version if the gas molecules move fast it's hot an if it moves slow its cold hope this helps .

The needle in the following diagram rotates around a fixed point in the middle. Based on the information given, what way will the needle rotate when the current is applied?

Answers

Answer:

nods 40th anniversary rid off e 49en9 snns

3. Calculate the wavelength of wave that has a frequency of 4.75 x 1012Hz.
a. 1.43 x 1021 m
b. 6.31 x 105 m
1.58 x 104 m
d. 6.31 x 105 m
please help
C.

Answers

Frequency=v=4.75×10^12HzWavelength=?

We know

[tex]\boxed{\sf \lambda=\dfrac{C}{V}}[/tex]

[tex]\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{4.75\times 10^{12}s^{-1}}[/tex]

[tex]\\ \sf\longmapsto \lambda=0.631\times 10^{-4}m[/tex]

[tex]\\ \sf\longmapsto \lambda=6.31\times 10^{-5}m[/tex]

A tightrope walker is walking between two buildings holding a pole with length L=14.0 m, and mass mp=17.5 kg. The daredevil grips the pole with each hand a distance d=0.595 m from the center of the pole. A bird of mass mb=560 g lands on the very end of the left‑hand side of the pole. Assuming the daredevil applies upward forces with the left and right hands in a direction perpendicular to the pole, what magnitude of force Fleft and Fright must the left and right hand exert to counteract the torque of the bird?

Answers

Answer:

F = 32.28 N

Explanation:

For this exercise we must use the rotational equilibrium relation

          Σ τ = 0

In the initial configuration it is in equilibrium, for which all the torque and forces are compensated. By the time the payment lands on the bar, we assume that the counter-clockwise turns are positive.

          W_bird  L / 2 - F_left 0.595 - F_right 0.595 = 0

we assume that the magnitude of the forces applied by the hands is the same

          F_left = F_right = F

          W_bird L / 2 - 2 F 0.595 = 0

          F = [tex]\frac{m_{bird} \ g L} { 4 \ 0.595}[/tex]

   

we calculate

         F = 0.560 9.8 14.0 /2.38

         F = 32.28 N

Who would most likely be required to work with sodium hydroxide?

Answers

Answer:

a plumber

Explanation:

Which one of the following explains how light energy helps us see all kinds of objects around us?

a flashlight shining light on a book

Light is absorbed by the objects and does not reach our eyes.
The objects emit light that enters our eyes.
Light reflects off the objects and enters our eyes.
Light travels in a straight line until it enters our eyes.

Answers

Answer:

light reflects off the objects and enter our eyes

Un globo contiene 4 moles de un gas ideal con un volúmen de 5,0 L. Si se agregan 8 moles adicionales del gas a presión y temperatura constantes, ¿Cuál será el volumen final del globo? - ¿Cuál es la densidad (en g / L) de un gas con una masa molar de 60 g / mol a 0,75 atm y 27 ° C?

Answers

Tenemos un problema de termodinamica sobre gases ideales, los cuales pueden ser descritos por la ecuación de estado del gas ideal

[tex]P*V = n*R*T[/tex]

donde:

P = presión

V = volumen

n = número de moles

R = constante de los gases

T = temperatura.

1) Para el primer problema podemos pensar que el gas dentro del globo es un gas ideal:

Originalmente sabemos que n = 4 y V = 5.0 L

Entonces tendremos:

[tex]P*(5.0 L) = (4 moles)*R*T[/tex]

Ahora decidimos agregar 8 moles más, dejando constante la presión y la temperatura, entonces podemos reescribir la ecuación de arriba como:

(5.0L)/(4 moles) = R*T/P

Y como R, T y P son constantes, entonces:

R*T/P es una constante.

Esto quiere decir que cuando agreguemos 8 moles, para tener un total de 12 moles, tendremos que:

V'/(12 moles) = R*T/P = (5.0L)/(4 moles)

Donde V' es el nuevo volumen final del globo, y es lo que queremos obtener.

V'/(12 moles) =  (5.0L)/(4 moles)

V' =   (5.0L)*(12 moles)/(4 moles) = (5.0 L)*3 = 15.0 L

2) Queremos obtener la densidad en gramos sobre litro de un gas con una masa molar de 60g/mol, a P = 0.75 atm y T = 25°C.

Primero pasemos la temperatura a grados kelvin:

T = 25°C = (25 + 273.15)°K = 298.15°K

Planteamos la ecuación del gas ideal:

[tex]P*V = n*R*T[/tex]

reemplazando R = 0.082 (atm*L/mol*k), además de la presión y la temperatura para un solo mol de gas:

[tex](0.75 atm)*V = (1 mol)*(0.082 (atm*L/mol*k))*(298.15°K)[/tex]

Resolviendo para V obtenemos que:

 

[tex]V = (1 mol)*(0.082 (atm*L/mol*k))*(298.15°K)/(0.75 atm) = 32.597 L[/tex]

Así, vemos que un mol de este gas ocupa un volumen de  32.597 L

Y también sabemos que un mol de este gas pesa 60 gramos.

Recordando que la densidad es el cociente entre la masa y el volumen, podemos ver que la densidad del gas será:

[tex]d = 60g/(32.597 L) = 1.84 g/L[/tex]

Si deseas leer mas sobre el tema, podes ver:

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(ik it says physics but astronomy is a field of physics sooo) A recently discovered planet in a different solar system is located 1.85 x 10^15 Miles from earth. To the nearest 10th of a light year, how far is this planet from earth? ly= 8.6

Answers

The distance, to the nearest tenth, is 314.9 light-years.

The given data is:

A recently discovered planet is located 1.85*10^5 miles from Earth.

Now we want to transform this distance to light-years.

Remember that a light-year is defined as "the distance that the light would travel in one year".

using the relation:

distance = speed*time

The speed of light is:

speed = 6.706*10^8 mi/h

And in one year has 8760 hours, then we have:

time = 8760 h

replacing these in the equation we get:

distance = speed*time

distance = (6.706*10^8 mi/h)*(8760 h)  = 5,874,456,000,000 miles

Son one light-year is equivalent to 5,874,456,000,000 miles

1 light-year = 5,874,456,000,000 miles

So to transform a distance in miles to light-years, we just need to divide that distance by 5,874,456,000,000 miles:

The distance between the new planet and Earth was:

D = 1.85*10^15 mi = ( 1.85*10^15)/(5,874,456,000,000) = 314.9 light-years.

if you want to learn more about this, you can read:

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Those of you who have recently finished high school physics-did you struggle? If you did, where did you most struggle in? Was it the tests? Or a specific topic?
Thank you!

Answers

Answer:

I'm over halfway through it so don't have a complete answer but i think you just need to keep ontop of everything and write down all the key equations on flashcards or something and aim to learn them at the beginning of each topic. i found the longer questions hard so recommend practising those

Explanation:

Which statement best describes the arrangement of electrons in an atom of fluorine (F)?

(1 point) giving brainliest for sure

There are two electrons in the first energy level and seven electrons in the second energy level.

There are two electrons in the first energy level and five electrons in the second energy level.


There are five electrons in the first energy level and two electrons in the second energy level.


There are seven electrons in the first energy level and two electrons in the second energy level.

Answers

Flourine is an element which has 9 electrons. The first energy level can only hold upto 2 electrons so therefore two electrons of the fluorine element will be in the first orbital.

In the second orbital there will be seven electrons. The configuration will be as 1s2, 2s2 , 2p5 .

The first orbital has capacity of two electrons and then the remaining two electrons will be in higher second energy level.

The further 5 electrons will be in lower second energy level which is denoted by p.

Learn more at https://brainly.com/question/24373325

Answer:

#1. 5

#2.They have valence electrons in the same energy level.

#3. Helium atoms have 2 valence electrons, while atoms of the other elements in the group all have 8 valence electrons.

#4. cesium (Cs)

#5.  There are two electrons in the first energy level and seven electrons in the second energy level.

Explanation:

what can be done to increase speed of rotation of a DC motor​

Answers

Answer: There are multiple options:

By varying the supply voltage.

By varying the flux, and by varying the current through the field winding.

By varying the armature voltage, and by varying the armature resistance.

Helpful Link:

https://www.elprocus.com/what-are-the-best-ways-to-control-the-speed-of-dc-motor/

I shared a picture of the problem. It’s a basic Physics question and an Algebra question.

Answers

Hence the expression of ω in terms of m and k is

[tex]\omega = \sqrt{\frac{k}{m}[/tex]

Given the expressions;

[tex]T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}[/tex]

Equating both expressions we will have;

[tex]2 \pi \sqrt{\frac{m}{k} } = \frac{2 \pi}{\omega}[/tex]

Divide both equations by 2π

[tex]\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\[/tex]

Square both sides

[tex](\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}[/tex]

Take the square root of both sides

[tex]\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}[/tex]

Hence the expression of ω in terms of m and k is

[tex]\omega = \sqrt{\frac{k}{m}[/tex]

Learn more about subject of the formula here: https://brainly.com/question/19557491

The 11 th one please! Somebody help me:(

Answers

Answer:

203360Pa

Explanation:

Pressure= density of liquid*height*g

=1000*10*10

=100000Pa

Total pressure= water pressure + atmospheric pressure

=1000000+103360

=203360 Pascal

Does the scalar addition obey ordinary addition rules?

Answers

Explanation:

In scalar addition we have to do only the sum of magnitude as we know that the scalar quantities don't have direction.

since it is the scalar quantity the direction will be same for all the magnitudes.

Answer:

In scalar addition we have to do only the sum of magnitude as we know that the scalar quantities don't have direction...

since it is the scalar quantity the direction will be same for all the magnitudes.

on the other hand if it was a vector addition then it should be with two different directions which are considerable show the resultant vector needs to be calculated by vector addition method.

How can a simulation study be used to learn about a planet we have never visited?
In a simulation study you imitate some conditions and characteristics of the real planet. The simulation can be used as a substitute for real data collected on the planet.
Simulation studies can be used for planets we have already visited.
In a simulation study you imitate as many conditions and characteristics as possible of the real thing, in this case the planet you have not visited. By simulating as many conditions as possible you can visualize what the planet might be like and learn things about it without actually visiting it.
Simulation studies cannot be used to learn about a planet we have never visited because we do not know anything about the planet.

Answers

Hi! I think the answer is C. as we have never visited the planet we can’t be 100% sure but we can have an idea of what the planet might me like. With experimenting with the simulation it can help you get an understanding or an idea of what the planet might be like exactly like option C. I hope this helped Goodluck :)

A simulation study that is used to learn about a planet by simulating as many conditions as possible, you can visualize what the planet might be like and learn things about it without actually visiting it. The correct option is c.

What is simulation?

A simulation is a method of simulating a process or change in the actual world to forecast future events or to explain past events and their causes. These days, simulations are frequently carried out using computers. Scientists use simulations to find answers and to test complicated systems.

A fire drill is used in this instance to get everyone ready for an impending event. In fire drills, the fire alarm is sounded even when there isn't actually a fire.

Therefore, the correct option is c.

To learn more about simulation, refer to the link:

https://brainly.com/question/16359096

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Q- Wheel of a running vehicle has which energy?
(a) Vibrational Kinetic energy
(b) Translational Kinetic energy
(c) Rotational Kinetic energy
(d) All of the above​

Answers

Answer:

Rotational kinetic energy

Explanation:

It is caused by circular motion.


Write the dirference between sl system
and cgs system

Answers

Explanation:

st system:the internationak system of measurement which i declared form internationäl convention of scientists held in france in 1960AD is Si system

CGS System:it measure in length in centimeter mass in gram time in second

derive an expression for resistivity of conductor of length l and area of cross section A​

Answers

Answer

Resistivity R = K * L / A    where resistivity is constant for material, L the length of the material and A the area of the material

K = R * A / L     where R is the resistance of the material

What is Plancks Constant? Need it ASAP

Answers

Answer:

The Planck constant, or Planck's constant, is a fundamental physical constant denoted h, and is of fundamental importance in quantum mechanics. A photon's energy is equal to its frequency multiplied by the Planck constant. Due to mass–energy equivalence, the Planck constant also relates mass to frequency.

Theory:

Planck postulated that the energy of light is proportional to the frequency, and the constant that relates them is known as Planck's constant (h). His work led to Albert Einstein determining that light exists in discrete quanta of energy, or photons.

E = hf

[tex] \sf \: h = 6.626 \times {10}^{ - 34} \: kg \: {m}^{2} {s}^{ - 1} [/tex]

Plz Help me thank uuu...
Which of these is a likely impact of the stronger than normal trade winds on the eastern Pacific ocean?

Warm surface water builds up, causing lower than average temperature.
Warm surface water builds up, causing higher than average temperature.
Warm surface water is reduced, causing colder conditions than normal.
Warm surface water is reduced, causing hotter conditions than normal.

Answers

Answer:

Jet stream would be displaced southwards causing heavy rain and flooding.

Explanation:

The other options of the question were A) Jet stream would be displaced northwards causing drought. B) Jet stream would be displaced southwards causing drought. D) Jet stream would be displaced northwards causing heavy rain and flooding,

The statement that is a likely impact of stronger than normal trade winds in the Pacific Northwest to the United States is "Jet stream would be displaced southwards causing heavy rain and flooding."

We are talking about climate or weather terminology. In this case, we are referring to the "El Niño" (the Children) effect. Its presence affects the weather in North America. This phenomenon combines with the "La Niña) effect and it presents itself every two to seven years, ad they last from 8 to 12 months, affecting the weather conditions of the region.

Answer:

jet stream should be displaced southwards which causes heavy rainfall and flood.

The law of conservation of energy states that energy cannot be created or
destroyed, only converted into other forms.
True or false

Answers

Answer:

True

Explanation:

Yes, According to law of conservation of energy, it has been said that energy cannot be created or destroyed.

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