Driving a car 100m requires the same amount of work as pushing it 100m by hand as the concept of work in physics refers to the transfer of energy when a force is applied over a certain distance.
When driving a car or pushing it by hand, the same amount of work is done because the distance covered is the same. However, it's important to note that the power required to accomplish this work may differ, as power is the rate at which work is done or energy is transferred. So, while the work is the same, the power required for driving a car is typically much higher than the power needed to push it by hand.
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A web browser is open on yur screen. The lengh of the monitor is x+7. The area of the browser windw is 24 inches. The dimensions of the browser window are x-2 and x. Find the length of the browser window x. Part B. The browser covers 3/13 of the screen. What are the dimensions of the screen
The length of the browser window (x) is 6. The dimensions of the screen are approximately 3 inches (width) and 18/13 inches (height).
Let's solve the equations step by step:
Part A:
The area of the browser window is given by the equation:
(x - 2) * x = 24
Expanding the equation:
[tex]x^{2}[/tex] - 2x = 24
Rearranging the equation to standard quadratic form:
[tex]x^{2}[/tex] - 2x - 24 = 0
Factoring the quadratic equation:
(x - 6)(x + 4) = 0
Setting each factor to zero:
x - 6 = 0 or x + 4 = 0
Solving for x:
x = 6 or x = -4
Since the length of the monitor cannot be negative, we discard the solution x = -4.
Therefore, the length of the browser window (x) is 6.
Part B:
The dimensions of the screen can be calculated using the length of the monitor (x+7) and the coverage ratio of the browser window (3/13).
The width of the screen is given by:
Width = (3/13) * (x + 7)
The height of the screen is given by:
Height = (3/13) * (x)
Substituting the value of x = 6:
Width = (3/13) * (6 + 7) = (3/13) * 13 = 3
Height = (3/13) * 6 = 18/13
Therefore, the dimensions of the screen are approximately 3 inches (width) and 18/13 inches (height).
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A stevedore slides a crate along a dock with a 50 kg horizontal force of 175 N. The opposing force of friction is 120 N. If started from rest, what is the crates’s final velocity after 0.5s?
To determine the crate's final velocity after 0.5 seconds, we can use the concept of Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.
In this scenario, the stevedore applies a horizontal force of 175 N to move the crate along the dock. However, there is also an opposing force of friction acting in the opposite direction, which has a magnitude of 120 N. The net force is the difference between these two forces, so we can calculate it as follows:
Net force = Applied force - Frictional force
Net force = 175 N - 120 N
Net force = 55 N
Now, using Newton's second law of motion, we can determine the acceleration of the crate. Rearranging the equation, we have:
Net force = mass * acceleration
55 N = 50 kg * acceleration
Solving for acceleration:
acceleration = 55 N / 50 kg
acceleration = 1.1 m/s²
Since we know the initial velocity of the crate is zero (as it starts from rest), and we want to find the final velocity after 0.5 seconds, we can use the equation of motion:
final velocity = initial velocity + (acceleration * time)
Plugging in the values:
final velocity = 0 + (1.1 m/s² * 0.5 s)
final velocity = 0.55 m/s
Therefore, the crate's final velocity after 0.5 seconds is 0.55 m/s. This means that after being subjected to a 175 N force and experiencing 120 N of friction, the crate gains a velocity of 0.55 m/s in the direction of the applied force.
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3. A grating with 1555 lines/cm is illuminated with light of wavelength 565 nm. What
is the highest-order number that can be observed with this grating? (Hint:
Remember that sin can never be greater than 1 for a diffraction grating. )
important!
The highest-order number that can be observed with this grating using diffraction formula is 1/1555.
It is determined using the formula for diffraction: mλ = d sinθ. Where m is the order number, λ is the wavelength of light, d is the grating spacing, and θ is the angle of diffraction. In this case, the grating has 1555 lines/cm, which means the grating spacing is 1/1555 cm.
To determine the highest-order number, calculate m × (565 × 10^-9 meters) = (1/1555 cm) × sinθ, where θ must be less than or equal to 90 degrees to satisfy sinθ ≤ 1. Given the wavelength of light as 565 nm (or 565 × 10^-9 meters), we can proceed with the calculation. Since sinθ ≤ 1, the highest-order number (m) can be determined by substituting θ = 90 degrees into the equation: m = (1/1555 cm) × sin(90 degrees).
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A 20. Kilogram rock is lifted 7. 0 meters above the ground. What is the gravitational
potential energy of the rock?
The gravitational potential energy of the rock is 1,372 Joules.
The gravitational potential energy (PE) of an object can be calculated using the formula:
PE = m * g * h, where:
m is the mass of the object,
g is the acceleration due to gravity, and
h is the height or distance above the reference point.
In this case, the mass of the rock (m) is 20 kilograms, and the height (h) is 7.0 meters.
The acceleration due to gravity (g) is approximately 9.8 m/s².
Now we can calculate the gravitational potential energy:
PE = 20 kg * 9.8 m/s² * 7.0 m
PE = 1,372 Joules
Therefore, the gravitational potential energy of the rock is 1,372 Joules.
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An elastic wire expands by 2cm when load of 40g hangs from it. What additional load will be required to cause a further extension of 4cm
Steam burns are pretty dangerous because there's often a lot of
thermal energy in the steam. When the steam hits you, it is going to
transfer some of that energy to you, cooling the steam. If a 6.4 kg cloud of
steam at 150 degrees, hits you and cools to 100 degrees, What is the loss
of heat energy? (no scientific notation)
The loss of heat energy when a 6.4 kg cloud of steam at 150 degrees Celsius hits you and cools to 100 degrees Celsius is 13,440,000 Joules.
To calculate the heat energy loss, we can use the formula:
Q = mcΔT
Where Q represents heat energy, m is the mass of the steam cloud (6.4 kg), c is the specific heat capacity of water (4,186 J/kg°C), and ΔT is the change in temperature (150°C - 100°C = 50°C).
Plugging in the values, we have:
Q = (6.4 kg) × (4,186 J/kg°C) × (50°C)
Q = 13,440,000 Joules
Therefore, the loss of heat energy when the steam cools from 150°C to 100°C is 13,440,000 Joules.
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A bookshelf is at rest in a room. A force of 35. 0 newtons is applied to a bookshelf. If the floor imparts a frictional force of 2. 90 newtons, what is the net force acting on the bookshelf?.
The net force acting on the bookshelf is 32.1 N. It is given that the net force acting on a bookshelf that is at rest in a room when a force of 35.0 N is applied to it and the floor imparts a frictional force of 2.90 N.
The force that is applied to an object minus the frictional force acting on it is called net force. This net force is responsible for causing motion in the object. Therefore, if the object is at rest, the net force is zero. If it is in motion, the net force is nonzero.
The formula for calculating net force is: Net force = Applied force - Frictional force
Given: Applied force = 35.0 N, Frictional force = 2.90 N
We know that, Net force = Applied force - Frictional force
= 35.0 N - 2.90 N
= 32.1 N
Therefore, the net force acting on the bookshelf is 32.1 N.
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