Draw the structure of 2 methyl,but-3-ene

Answers

Answer 1

Answer:

Please find the structure attached as an image

Explanation:

Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.

- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.

- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).

N.B: In the structure attached below, the counting is from the left to right (→).

Draw The Structure Of 2 Methyl,but-3-ene

Related Questions

How many protons are in iron (Fe)?
A. 30
B. 82
C. 26
D. 56

Answers

Answer:

26 protons

make sure its write answer

A reaction is thermodynamically unstable (spontaneous) but no change is observed. The reaction is probably Select the correct answer below: kinetically unstable. kinetically stable. thermodynamically stable but kinetically unstable. None of the above

Answers

Answer:

kinetically stable.

Explanation:

When we say that a system is thermodynamically unstable, it means that there is still a state in which the system is expected to have lower energy than it currently has. A thermodynamically unstable system is yet to attain equilibrium hence it can still undergo further chemical processes in order to attain thermodynamic stability.

When we say that a system is kinetically stable, it means that the activation energy or energy barrier for the reaction system is high. Thus reactants are not easily converted into products. The reaction system remains the same for a long while without change.

Finally, when a reaction is thermodynamically unstable (spontaneous) but no change is observed, the reaction is kinetically stable.

what are the products in a chemical equation located?

Answers

Answer:

they are the end results so they are after the yields symbol

Explanation:

Which type of element is almost always found as a single atom in nature?
O A. Alkaline earth metal
O B. Halogen
c. Noble gas
D. Oxygen family element

Answers

Noble gas elements are almost always found as a single atom in nature.

What is inert gas?

An inert gas is a gas that does not undergo chemical reactions under a set of given conditions. The noble gases often do not react with many substances and were historically referred to as inert gases.

All noble gases have the maximum number of electrons in their outer shell; i.e. 2 electrons for helium and 8 for the other five.

Noble gases are monoatomic, which means they exist as single atoms. This is because of their electronic stability.

Thus, noble gas elements are almost always found as a single atom in nature. Hence, option C is correct.

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Using the law of conservation of energy what is the kinetic energy at D

Answers

Answer:

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another.

Explanation:

This means that a system always has the same amount of energy, unless it's added from the outside.

Identify effective techniques for accurate pipet use. Select all that apply. Select one or more: Measure liquid by aligning the meniscus with the volume line. Leave any air bubbles in a pipet that occur after drawing up liquid. Do not let liquid enter the pipet bulb or pump. Use the pipet bulb to force the last drop out of the tip.

Answers

Answer:

Measure liquid by aligning the meniscus with the volume line.

Explanation:

A pipette is an instrument specially made for measuring a small volume of liquid.

The pipette comes in various sizes to be used in measuring various volumes of liquid. Generally, the pipette has a volume line which helps us to measure a liquid.

A liquid is measured by aligning the meniscus with the volume line.

QUICK I JUST NEED THE ANSWER!!!
What's the hybridization of the central atom in OF2?

Answers

Answer:

sp3 hybridization

Explanation:

High-pressure liquid chromatography (HPLC) is a method used in chemistry and biochemistry to purify chemical substances. The pressures used in this procedure range from around 500 kilopascals (500,000 Pa) to about 60,000 kPa (60,000,000 Pa). It is often convenient to know the pressure in torr. If an HPLC procedure is running at a pressure of 6.50×106 Pa , what is its running pressure in torr?

Answers

Answer:

1 kpa = 7.5 torr

1.75*10^7 pa = 1.75*10^4 Kpa = (1.75/7.5)*10^4 torr = 2333 torr

Explanation:

which of the following kb values represents the weakest base?

Answers

Answer:

the weakest base will have a higher Kb value since it will be closer to an acid than a base

7 kb values represents the weakest base.

What is kb value?

Kb is the base dissociation constant which is a measure of how completely a base dissociates into its component ions in water. pKb is define as the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.

Ka is define as the acid dissociation constant while pKa is the -log of this constant. Kb is define as the base dissociation constant, while pKb is the -log of the constant.

The acid and base dissociation constants are usually expressed in terms of moles per liter (mol/L).

Thus, 7 kb values represents the weakest base.

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1.0 g of a compound A is prepared in 100 mL of water, and then extracted with 50 mL of ether. After the extraction, 0.25 g of the compound was recovered from the ether layer. What is the partitioning coefficient([A]ether/[A]water) for this compound in the system used?a. 4.0b. 3.0c. 1.5d. 0.75e. 0.25f. 0.67

Answers

Answer:

uh 2

Explanation:

Its 2 cause uh 2 sounds about right

To solve this we must know the concept behind partition coefficient. The partitioning coefficient for this compound in the system used is 0.67. Therefore, the correct option is option F.

What is partition coefficient?

The ratio of a solute's concentrations in two solids, immiscible liquids, or barely miscible liquids when they are in equilibrium throughout the interface connecting them is called partition coefficient.

In fundamental chemistry, partitioning is utilized to separate components in procedures like chromatography. Partitioning is a crucial factor in the distribution of chemicals and medications between the blood and bodily tissues in the field of pharmacology.

Mathematically,

partition coefficient= concentration of the solute in  stationary phase/concentration of the solute in mobile phase

partition coefficient={(0.25 /M)÷50}÷{(1.0/M)÷100 }

                                =0.005÷0.01

                                =0.67

Therefore, the correct option is option F.

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from where the baby plant gets nutrition while its under ground?​

Answers

Explanation:

The "baby" plant grows entirely from stored energy and food from the cotyledons until it reaches sunlight

An experimental drug, D, is known to decompose in the blood stream. Tripling the concentration of the drug increases the decomposition rate by a factor of nine. Write the rate law for decomposition of D.

Answers

Answer:

R=k[D]^2

Explanation:

Given that it is a decomposition reaction;

D--->product

Hence;

The rate law is;

R= k[D]^x ----(1)

When we triple the concentration of D we have;

[D]' = [3D]^x

Therefore;

R'= 3R

R'= k[D]'----(2)

Hence dividing (1) by (2);

R/R' = k[D]^x/k[D]'

R/9R = k[D]^x/k[3D]^x

1/9 = 1/3^x (take inverse of both sides)

9 = 3^x

3^2 = 3^x

x= 2

Hence the rate law;

R=k[D]^2

4. A salvage operator recovered coins believed to be gold. A sample weighed 385.000g and has a volume of 20.0mL. Were the coins gold (Density= 19.3g/mL) or yellow brass (Density =8.47g/mL)? Show your calculation and explain your answer.

Answers

Answer:

The coins are gold

Explanation:

To solve this question we need to find the density of the sample knowing that density is the ratio between the mass of a sample (385.000g) and the volume that is occupying (20.0mL).

Density is:

385.000g / 20.0mL = 19.3g/mL

As the density of the sample is equal to the density of gold:

The coins are gold

Physical and psychological dependence, high-risk behaviour, and chronic high blood
pressure can result from excessive use of

Answers

Answer:

Physical and psychological dependence is high, and withdrawal symptoms include watery eyes, runny nose, loss of appetite, irritability, tremors, panic, abdominal cramps and diarrhea, nausea, chills, and sweating. Use of contaminated syringes/needles to inject drugs may result in serious blood borne infections such as HIV-AIDS and hepatitis.

How many atom in protons

Answers

Answer:

Its atomic number is 14 and its atomic mass is 28. The most common isotope of uranium has 92 protons and 146 neutrons. Its atomic number is 92 and its atomic mass is 238 (92 + 146).

2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4 g. Calculate the density of the liquid in Lbs/ in3.

Answers

Answer:

[tex]d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

[tex]d=\frac{m}{V}[/tex]

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

[tex]m=552.4g-464.7g=87.7g[/tex]

So that we are now able to calculate the density in g/mL first:

[tex]d=\frac{87.7g}{27.8mL}=3.15g/mL[/tex]

Now, we proceed to the conversion to lb/in³ by using the following setup:

[tex]d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Regards!

g The rate constant for binding of P to L is 106 M-1s-1. What is the rate constant for dissociation of L from PL

Answers

Answer:

Eq 4 would predict a basal rate constant of 6 × 109 M−1s−1. ... ci(li) = Pli−1(cosδi)−Pli+1(cosδi) .


Can someone please help me!!!

Answers

sorry but I don't know so sorry

Which of the following is TRUE?
A.The equivalence point is where the amount of acid equals the amount of base during any acid-base titration.
B. At the equivalence point, the pH is always 7
C. An indicator is not pH sensitive
D.A titration curve is a plot of pH vs. the [base]/[acid] ratio
E. none of these is true

Answers

Answer:

D. a titration curve is a plot of pH vs. the [base]/[acid] ratio

You will observe a weak acid-strong base titration in this experiment. Select all statements that are true about weak acid-strong base titrations.
A. Weak acid-strong base titrations always start at a higher pH than strong acid-strong base titrations, no matter the initial concentration.
B. The pH is less than 7 at the equivalence point.
C. The pH is greater than 7 at the equivalence point.
D. Half way to the equivalence point, a buffer region is observed.

Answers

Answer:

The pH is greater than 7 at the equivalence point.

Explanation:

Equivalence point is the point where the acid reacts with the base as stipulated in the equation of the reaction.

When a weak acid and a strong base are titrated, the pH of the solution at equivalence point is actually found to be around about pH ~ 9.

Hence, for a weak acid and strong base titration, The pH is greater than 7 at the equivalence point.

A titration between a weak acid and a strong base yields a solution whose pH is greater than 7 at the equivalence point.

What are weak acids?

Weak acids are acids which only ionize partially in aqueous solutions.

When weak acids are dissolved in water, they produce only few hydrogen ions.

A strong base on the other hand ionizes completely to produce hydroxide ions in aqueous solutions.

The titration of a weak acid and a strong base gives a solution whose pH is greater than 7 at equivalence point.

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what must occur for a change to be a chemical reaction?

Answers

there must be a change in chemical properties, during a chemical reaction matter is neither created of destroyed

A compound contains only carbon, hydrogen, and oxygen. Combustion of 65.76 g of the compound yields 96.38 g of CO2 and 39.46 g of H2O.
The molar mass of the compound is 90.078 g/mol.
1. Calculate the grams of carbon (C) in 65.76 g of the compound:
2. Calculate the grams of hydrogen (H) in 65.76 g of the compound.
3. Calculate the grams of oxygen (O) in 65.76 g of the compound.

Answers

Answer:

1. 26.30 g C.

2. 4.42 g H.

3. 35.04 g O.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required as follows:

1. Here, the only source of carbon is in CO2, and thus, we calculate the grams of carbon from the produced grams of this substance:

[tex]m_C=96.38gCO_2*\frac{1molCO_2}{44.01gCO_2} *\frac{1molC}{1molO_2} *\frac{12.01gC}{1molC} =26.30g[/tex]

2. Here, the only source of hydrogen is in H2O, and thus, we calculate the grams of hydrogen from the produced grams of this substance:

[tex]m_H=39.46gH_2O*\frac{1molH_2O}{18.02gH_2O} *\frac{2molH}{1molH_2O} *\frac{1.01gH}{1molH} =4.42gH[/tex]

3. Here, we subtract the mass of H and C from the mass of the sample, to obtain the mass of oxygen:

[tex]m_O=65.76g-26.30g-4.42g\\\\m_O=35.04g[/tex]

Regards!

The standard reduction potential for O2 in acid is 1.23 V, according to Appendix E. Calculate the reduction potential for O2 at pH 7, for all other conditions being standard.
a. 0.40 V
b. 1.13 V
c. 1.23 V
d. 0.82 V
e. 1.64 V

Answers

Answer:

a. +0.40 V

Explanation:

Reduction of O2 in acid medium is +1.23 V. The reduction of O2 in basic medium will be calculated by subtracting equation of acidic medium from equation in base medium.

Kw^4 = [10^-14 ] ^ 4

solving we get -0.8274

Subtracting the value from oxygen reduction in acidic medium;

+ 1.23 - 0.8274 = +0.4026

Can you please answer the 5 attached questions?

Answers

Answer:

10.4%

Explanation:

Recall that the formula for percent solution = mass of solute/mass of solution * 100

Mass of solute = 2.07 g

Mass of solution = 19.9 g

Hence mass percent of solute = 2.07/19.9 * 100

= 10.4%

Amines and amides are organic compounds that contain nitrogen. Amines are ammonia derivatives, in which at least one hydrogen atom is replaced by an organic substituent. Methylamine is a simple amine in which one of the hydrogen atoms of ammonia is replaced by a methyl group:

Answers

Answer:

Following are the solution to the given question:

Explanation:

Suppose that a certain atom possesses only four distinct energy levels. Assuming that all transitions between levels are possible, how many spectral lines will this atom exhibit

Answers

Answer:

Following are the response to the given question:

Explanation:

The number of shells

n = 4

Calculating the spectral line:

[tex]= \frac{n(n-1)}{2}\\\\ = \frac{4(4-1)}{2} \\\\= \frac{4\times 3}{2}\\\\ = \frac{12}{2}\\\\ = 6[/tex]

A student pours a few drops of vinegar onto limestone and it starts bubbling. What kind of reaction is this? How does it relate to chemical weathering, monuments and statues?

Answers

Answer:

The correct answer is - acid-base reaction or chemical weathering.

Explanation:

Vinegar is an acid that dissolves a material that is commonly found and known as calcium carbonate present in the limestone. When these two, vinegar mix with calcium carbonate of the limestone, the atoms in the acetic acid and the calcium carbonate come apart and rearrange in different ways to make new chemicals.

This rearrangement results in the release of carbon dioxide as a stream of bubbles. It is a form of weathering called chemical weathering and many monuments are based on rocks that have limestones in their composition and acid rain work similar to vinegar.

Oleic acid and elaidic acid are isomeric alkenes.

a. True
b. False

Answers

Answer:

False

Explanation:

Because Elaidic acid is an isomer of oleic acid. I really hope this helps you.

Complete and balance the following chemical equations. Identify the reaction type as: combination, decomposition, single replacement, double replacement, or combustion.

Products:
Magnesium Oxide + Carbon dioxide.
a) MgCO₃ (Heat is supplied to the reaction (triangle over a arrow) -> Reaction type:

Products:
Aluminum Oxide
b) Al + O₂ -> Reaction type:

Answers

Answer:

the first one is a decomposition reaction

the second one is also a synthesis reaction

Solution:-1

[tex]\boxed{\sf {MgCO_3\atop Magnesium\:Carbonate}\overset{\Delta H}{\longrightarrow}{MgO\atop Magnesium \:Oxide}+{CO_2\atop Carbon\:Dioxide}}[/tex]

It is a thermal decomposition reaction

Solution:-2:-

[tex]\boxed{\sf {4Al\atop Aluminium}+{3O_2\atop Oxygen}\longrightarrow{2Al_2O_3\atop Aluminium\:oxide}}[/tex]

It is a combination reaction.

4.If 15.00 mL of 3.00 M potassium iodide is needed to reach the equivalence point with 10.00 mL of lead (Il) nitrate, determine the molarity of the lead (Il) nitrate solution

Answers

Answer:

2.25 M

Explanation:

The reaction that takes place is:

2KI + Pb(NO₂)₃ → PbI₂ + 2KNO₃

First we calculate how many potassium iodide moles reacted, using the given volume and concentration:

15.00 mL * 3.00 M = 45 mmol KI

Then we convert 45 mmoles of KI into mmoles of Pb(NO₂)₃, using the stoichiometric coefficients of the balanced reaction:

45 mmol KI * [tex]\frac{1mmolPb(NO_3)_2}{2mmolKI}[/tex] = 22.5 mmol Pb(NO₂)₃

Finally we calculate the molarity of the Pb(NO₂)₃ solution, using the calculated number of moles and given volume:

22.5 mmol Pb(NO₂)₃ / 10.00 mL = 2.25 M
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