Answer:
double helix
two
wound
Explanation:
DNA is referred to as double helix, meaning it has two strands that are wound together.
how are traits which are not beneficial to a living organism removed from its gene pool
Answer:
recessive traits is the answer
What is Anatomy and physiology
Answer:
Anatomy: The branch of science concerned with the bodily structure of humans, animals, and other living organisms, especially as revealed by dissection and the separation of parts.
Physiology: The branch of biology that deals with the normal functions of living organisms and their parts.
Explanation:
Anatomy = The science that deals with the form and structure of organic bodies; anatomical structure or organization is Anatomy.
Physiology = A branch of biology that deals with the functions and activities of life or of living matter (as organs, tissues, or cells) and of the physical and chemical phenomena involved is Physiology.
Hope it will help:)❤️
Considering your knowledge of carbohydrates, evaluate the use of chitin as a component of health foods.
Answer:
Carbohydrates may be defined as energy-rich foods such as sugars and starches. if consumed in excess or not properly metabolized in the body, carbohydrates may lead to obesity and which may also lead a person to severe number of diseases.
Chitins are components of the exoskeletons of foods such as shrimps, crabs and snails, and insects.
Chitin's use as a component in healthy foods is based on its health benefits.
For example it promotes weight loss , prevents obesity, relieving constipation and preventing inflammation associated with refined carbohydrates, cookies and candies
geosphere burying organisms
hydrosphere respiration of marine life
biosphere photosynthesis atmosphere burning things
Answer:
This question is incomplete, the question is asking to match each activity with the sphere to which it adds carbon or CO2.
ANSWERS:
Geosphere = burying organisms
hydrosphere = respiration of marine life
biosphere = photosynthesis atmosphere = burning things
Explanation:
This question describes the types of spheres we have. The respective activities that occur in each sphere that adds CO2 or carbon are as follows:
- Geosphere: This refers to the solid part of the Earth. Dead organisms are buried in the geosphere (soil) where their carbon remains can be deposited.
- Hydrosphere: This constitutes all of the water bodies (sea, river, stream, ocean) on the Earth. When marine organisms respire in water, carbon dioxide (CO2) is released.
- Biosphere: A sphere consisting of all living things (plant, animal, microbes etc.) on Earth. Plants as a living organisms photosynthesize and make use of carbon dioxide to produce glucose, which stores in the plant.
Atmosphere: The gaseous component of the Earth. Burning substances release carbon based gases into the atmosphere.
Which statement is not true about the field of science?
it is based on observations and explanations of the natural world.
You are right with your answer please
Actual Question:
Which statement about the purpose of the field of science is false? (1 point)
Science is used to investigate the natural world.
Events of the natural world can be explained by science.
Science works to establish a collection of unchanging truths.
Useful predictions come from derived explanations of science.
Answer:
Science works to establish a collection of unchanging truths.
Explanation:
I took the test
Issued in 1974, 45 CFR 46 raised to regulatory status:
A) The 1974 National Research Act
B) The Nuremberg Code
C) Kefauver-Harris Drug Amendments to the Federal Food, Drug & Cosmetics Act
D) US Public Health Service Policy
Hello!
The answer is D, The U.S Public Health Service Policy. Its main purpose was providing protection for human subjects for research work which was conducted by federal agencies. You can read more about it on HHS.gov, as it is a very interesting regulation.
I hope this helps! :)
Issued in 1974, 45 CFR 46 raised to regulatory status US Public Health Service Policy. Option D
What is the regulatory status?The restrictions known as the Common Rule for the protection of human subjects in research done by or supported by federal agencies are outlined in Title 45 of the Code of Federal restrictions, Part 46. These laws define moral principles and requirements for the protection of research subjects who are being used as human subjects.
The US Public Health Service (PHS) published the policy that would eventually become 45 CFR 46 in 1974. This policy established standards for the examination and approval of research involving human subjects as well as the legal foundation for the protection of those individuals. Informed consent, weighing risks and benefits, and the creation of Institutional Review Boards (IRBs) to regulate research techniques were all adopted.
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what is uropoiesis?
Answer:
The production and excrection of urine
Answer:
The production and excretion or urine.
Most of the plant matter in ___ is sphagnum moss.
Answer:
the answer is peat
Explanation:
i did the test Hope dis help
Answer:
pease
Explanation:
I did some research
why is growth important to living things?
Answer:
However, growth in living things is because of different internal processes occurring inside the body of the living organisms mainly because of the formation of new cells. The increase in number and mass of individuals are two unique characteristics of growth. Multicellular organisms exhibit growth by cell division.
Which of the following statements about dinoflagellates is true? Select one: A. All known varieties are autotrophic. B. Their walls are usually composed of silica plates. C. Many types lack mitochondria. D. Some produce toxic agents in the water E. Their dead cells accumulate on the seafloor, and are mined to serve as a filtering material.
Answer: The correct option is D(Some produce toxic agents in the water).
Explanation:
Dinoflagellates are found in the phylum Dinoflagellata which are single celled organisms. They are mostly found in the ocean while few of them can live in streams, freshwater ponds and rivers. The following characteristics can be used to identify a Dinoflagellates, these include:
--> they are golden brown
--> they possess assimilative cell with indented waist.
--> they possess large nucleus with visible chromosomes.
It has been reported that many dinoflagellate species can produce various natural toxins. These toxins can be extremely toxic and many of them are effective at far lower dosages than conventional chemical agents. Therefore the option, Some produce toxic agents in the water, is a correct statement.
When does facilitated diffusion occur?
-When one liquid has a higher osmotic pressure than the other.
-When certain large molecules are unable to move through the membrane
without the help of channel proteins.
-When ATP is available to assist in moving molecules.
-When there's a strong membrane potential present, with the inside of the cell
being more negative than the outside of the cell.
Answer:
When certain large molecules are unable to move through the membrane without the help of channel proteins
Explanation:
Facilitated diffusion occurs when large molecules that are unable to pass through a membrane on their own make use of channel proteins to move from one side of the membrane to the other. Facilitated diffusion can occur when a liquid on one side of a membrane has a higher osmotic pressure than a liquid on the other side of the membrane, but it isn’t a required feature of facilitated diffusion. Similarly, facilitated diffusion can occur when there’s a large membrane potential present, but it isn’t a required feature of facilitated diffusion. Facilitated diffusion doesn’t require the use of energy, so the presence of ATP is irrelevant to facilitated diffusion occurring.
List five Characteristic of fruits.
Answer:
Quality factors for fruits include the following— maturity, firmness, the uniformity of size and shape, the absence of defects, skin and flesh color.
Explanation:
Hope this helps. Have a nice day.^_^
Answer:
the five characteristics of fruit are:- maturity, firmness, the uniformity of size and shape
what are amino acids used to build
EDG2021
Answer:
Alanine
Arginine
Asparagine
Aspartic Acid
Cysteine
Glutamic acid
Glutamine
Glycine
Histidine
Isoleucine
Leucine
Lysine
Methionine
Phenylalanine
Proline
Serine
Threonine
Tryptophan
Tyrosine
Valine
Selenocysteine
Pyrrolysine (not used in human protein synthesis)
Of these 20 amino acids, nine amino acids are essential:
why cells are sometimes called the building block of life?
Answer:
cell is the smallest unit of life, also called the 'building blocks of life' because cells multiply and differentiate to form a multicellular organism as well as give rise to new organism by forming gametes or reproductive spores.
The valves in the heart open and close to move blood in between heart chambers. O a) three directions O b) two directions O c) four directions d) one direction
Hi,
The valves in the heart open and close to move blood in between heart chambers.
Answer:
d) one direction
For each of the following structures, first indicate its function in the fetus; then, note its fate (what happens to it or what it is converted to after birth).
a. Umbilical artery
b. Umbilical vein
c. Ductus venosus
d. Ductus arterious
e. Foramen ovale
Answer:
1. Functions:
a. Umbilical artery >> carries deoxygenated blood from the fetus to the placenta
b. Umbilical vein >> transports oxygenated blood from the placenta to the fetus
c. Ductus venosus >> allows oxygenated blood from the placenta to bypass the liver
d. Ductus arterious >> allows most of the blood from the right ventricle to bypass the fetus's non-functioning lungs
e. Foramen ovale >> oxygenated blood from the umbilical vein to bypass the pulmonary circulation
2. After the bird:
1. Umbilical artery >> medial umbilical ligament
2. Umbilical vein >> round ligament of the liver
3. Ductus venosus >> ligamentum venosum
4. Ductus arteriosus >> ligamentum arteriosum
5. Foramen ovale >> fossa ovalis
Explanation:
The umbilical artery is a paired artery localized in the abdominal and pelvic regions, which carries deoxygenated blood from the fetus to the placenta through the umbilical cord. The medial umbilical ligament is the obliterated part of the umbilical artery that arises from the internal iliac arteries. In utero, the umbilical arteries carry waste products back to the placenta, whereas the umbilical vein carries oxygenated blood from the placenta to the fetus. The round ligament of the liver (also known as ligamentum teres hepatis) is a remnant of the umbilical vein that exists in the embryonic stage, it connects the left lobe of the liver to the umbilicus. The ductus venosus is a slender shunt that allows oxygenated blood from the placenta to bypass the liver, it connects the intra-hepatic portion of the umbilical vein to the inferior vena cava. The ligamentum venosum is an extrahepatic, slender, and fibrous remnant of the fetal ductus venosus that travels between the left portal vein and the inferior vena cava. The ductus arteriosus is a fetal artery that connects the aorta to the pulmonary artery. The ligamentum arteriosum is a nonfunctional vestige of the ductus arteriosus, it is attached to the superior surface of the pulmonary trunk. The foramen ovale is an oval-shaped, small, opening in the wall (septum) between the two upper chambers of the heart. The fossa ovalis is a vestige stricture of the foramen ovale of the embryonic heart, which forms a depression in the right atrium of the heart.
Which of the following are parts of the cardiovascular system? |a) Blood O b) Heart c) Lungs O d) Blood vessels
Which of the following are parts of the cardiovascular system?
a) Blood
b) Heart
d) Blood vessels
Choose: a); b); d)
Answer:
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The second generation of purebred cross of -hom-ozygo us recessive organism, with a —hom-ozygous dominant organism, contain a ratio of approximately _______ expressed dominant traits to recessive traits.
A. 2:1
B. 1:1
C. 1:3
D. 3:1
Answer:
D. 3:1
Explanation:
Gregor Mendel, in one of his numerous studies, performed a cross between purebred dominant (TT) pea plants and purebred recessive (tt) pea plants. All the offsprings of this cross appeared heterozygous tall (Tt) in the F1 generation.
However, when he self-crossed the F1 generation i.e. Tt × Tt, Mendel obtained a phenotypic ratio of 3 tall plants (dominant traits) : 1 short plant (recessive). This showed that the masked gene (recessive) was still present.
¿Porque las vitaminas, las sales minarales y el agua se consideran reguladores?
Answer:
Vitamins and minerals boost the immune system, support normal growth and development, and help cells and organs do their jobs. For example, you've probably heard that carrots are good for your eyes. It's true! Carrots are full of substances called carotenoids (pronounced: kuh-RAH-teh-noydz) that your body converts into vitamin A, which helps prevent eye problems.
Vitamin K helps blood to clot, so cuts and scrapes stop bleeding quickly. You'll find vitamin K in green leafy vegetables, broccoli, and soybeans. And to have strong bones, you need to eat foods such as milk, yogurt, and green leafy vegetables, which are rich in the mineral calcium.
HELP!!!
1. In a parent pea plant with the allele pair Gg, what is the probability that one gamete will contain the G allele? Why?
2. In a parent pea plant with the allele pair GG, what is the probability that one gamete will contain the g allele? Why?
3. In a parent pea plant with the allele pair gg, what is the probability that one gamete will contain the g allele? Why?
Answer:
If the gamete will get either G or g, the probability will be 1/2 of getting G.
Explanation:
all question 3 answer is that. Because all 3 of question are same. only repeated three times
In a parent pea plant with the allele pair Gg, the probability that one gamete will contain the G allele is 0.5. This is because there are two possible outcomes in which one must definitely fall. So, it is 1/2.
What is Allele?Alleles may be characterized as the alternative form or versions of a gene that are responsible for particular traits in living organisms. They carry a code of genetic sequences within generations.
In a parent pea plant with the allele pair GG, the probability that the gamete will contain the g allele is zero. This is because there is no presence of allele g that can be determined within any gametes. So, it is not possible to get g in the pair allele of GG.
In a parent pea plant with the allele pair gg, the probability that one gamete will contain the g allele is 1 or 100%. This is because both carry g alleles. So, the probability is 100%.
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4. What is the best type of graph to show the proportion of dogs that are poodles, labs,
golden retrievers, and beagles.
A. Pie graph
B. Bar graph
C. Line graph
D. Histogram
Answer:
I think a bar graph or a pie graph
The MN blood group in humans is under the control of a pair of co-dominant alleles, M (we will call the frequency of M, p) and N (we will call the frequency of N, q). In a group of 556 individuals, the following numbers of individuals are found for each of the genotypes:
167 MM
280 MN
109 NN
Required:
a. What is the frequency of each allele?
b. What is the value of the Chi-square statistic test to find if in this particular case the genotypic frequencies conform to the Hardy-Weinberg distribution.
c. What is the probability associated with you chi square statistic calculated above?
Answer:
do you know some people have golden blood
which of the following is a density- independent factor?
1 mate availability
2 parasitic infestation
3 disease transmission
4 lack of rainfall
Answer:
4. Lack of Rainfall
Explanation:
A new mammal has been discovered in the thickly-forested mountains of Papua New Guinea. The squirrel-like animal lives in the canopy of the forest and has a diet rich in leaves. On occasion, however, the animal drops to the ground to quickly fill its cheeks with its own fecal droppings, for ingestion once it is safely back in the trees. The GI tract of this animal would most likely include ________. a simple stomach and a large cecum a simple stomach, a short small intestine and colon, and a small cecum a four-chambered stomach and long intestines a long small intestine with abundant villi and an appendix at the beginning of the large intestine a short intestine and no cecum
Answer:
a simple stomach and a large cecum
Explanation:
Some small animals whose diet is prominent in vegetable matter, have an elongated cecum.
This segment of the digestive tract might be considered the first portion of the large intestine. It receives undigested material, and through the action of bacterial flora, is able to ferment this material and mix its contents with mucous substances to facilitate absorption. Through the walls, the organ can absorb fluids, salts, and nutrients.
The cecum size varies according to the animals. In small organisms, such as the new squirrel-like herbivore animal from the example, the cecum is enlarged. An elongated surface is useful for better digestion and absorption.
You are part of a research group that is attempting to improve on the beneficial genetic modification of golden rice, to further reduce
global hunger issues. Which of the following difficulties will you NOT encounter?
A. The genes could transfer into local wild plants
B. The seeds could be expensive,
C. The modified crops could make people very sick.
D. Biodiversity could be reduced,
Answer:
C.
sorry if this is wrong
If I were a part of a research group that is attempting to improve on the beneficial genetic modification of golden rice, to further reduce global hunger issues, then I would not encounter that the seeds could be expensive.
What is golden rice?Golden rice is genetically modified rice that contains provitamin A. This compound is responsible for the yellow-orange color of the rice, hence the name golden rice.
Golden rice can prevent vitamin A deficiency.The crop is available in countries such as Indonesia, Bangladesh, and the Philippines.It is much cheaper than the normal white rice available in the market.Golden rice is the modified version of normal rice which no additional cost and with enriched nutrients.Hence, option B is the right answer.
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Lymph ______ are found throughout the body and are a signal of a disease, infection, or problem if they become and remain swollen for long periods of time.
______ are pathogens that cannot be killed with antibiotics because they are non-living. They take over cellular organelles to replicate and spread.
Because they are also eukaryotes with their own cell membranes and membrane-bound organelles, ______ are often difficult to combat with medicines.
A cell signal called ______ is produced by mast cells. These molecules cause more fluid to spread to an infected area.
_______ are the types of cells that produce antibodies.
All pathogens have unique identifying molecules on their surfaces called ______. Antibodies bind to these, and targeting the pathogen to be destroyed by the immune system.
______ is a non-specific response to disease, in which the body temperature rises
Answer:
nodes
Viruses
fungi
histamine
B-cells
antigens
Fever
When a paper cut breaks the skin, it introduces outside microorganisms into the cut. The body recognizes the break in the skin. Mast cells produce histamines, which cause more blood and lymph fluid to flow to the wound. This increased flow brings phagocytic white blood cells to the area, which destroy invading organisms until the blood can clot and the skin can heal over the cut, preventing more organisms from entering the body. If a cut is too deep or too wide, special care such as stitches and antibiotics could be needed to prevent infection.
Explanation:
PENNFOSTER !
A sample from a stock of a bacterial colony in liquid media was diluted by a factor of 106, and 2 ml of this dilution was spread on a Petri dish of solidified media. 56 colonies were observed. What was the concentration of bacteria of the initial stock?
Answer:
28 × 10⁶ colonies/ml
Explanation:
Let C be the concentration of bacterial in the initial stock. When it is diluted by a factor of 10⁶, the new concentration is C' = C/10⁶.
When 2 ml of this concentration is spread on a Petri dish of solidified media, 56 colonies were produced. The number of colonies, n after spreading the 2 ml of C' is C' × 2 ml = 2C' = 2C/10⁶.
So, n = 2C/10⁶.
Since the number of colonies after spreading on a Petri dish of solidified media is 56, n = 56 colonies.
So, 2C/10⁶ = 56
Making C subject of the formula, we have
C = 56 × 10⁶/2
C = 28 × 10⁶ colonies/ml
So, the initial concentration of bacteria is 28 × 10⁶ colonies/ml
Role of mitosis in plant growth and development
Answer:
The mitosis cell division helps in vegetative growth in plants. It also helps in healing of wounds
the matter in an animal body is not capable of moving and changing without ?
Answer:
Energy
Explanation:
The matter in an animal body is not capable of moving and changing without energy.
Drag each label to the correct location.
Using the legend, arrange the minerals that you tested according to their hardness. The hardness will increase from left
to right.
Mineral Letter
Quartz
sypsum
Gy
calcite
C С
magnetite
M
graphite
Gr
feldspar microcline F
apatite
A
tale
Hardne
Nourite
Mardines - 6.5
pyrite
Q GY CM Gr.
FA
From left to right, the correct order of the minerals from the least hard to the hardest is ⇒ Graphite, Talc, Gypsum, Calcite, Fluorite, Apatite, Magnetite, Pyrithe, Feldespat, Quartz.
Theoretical frame:
Hardness is one of the physical properties of minerals and is a significant one when identifying and recognizing them.
Hardness measures the resistance level of a surface to abrasion. In the specific case of minerals, it measures how minerals resist being scratched or penetrated.
The hardness level is determined by an attempt to scratch or produce a mark on an unmarked surface using sharp elements, such as nails, copper coin, glass, or a steal knife. Notice that these elements also vary in their hardness.
There are different methods used to define hardness, and they are not comparable to each other. The Mohs hardness method defines an ordinary qualitative scale that characterizes the mineral according to their resistance to being scratched by a harder element.
According to the Mohs hardness scale, the level in which the given minerals are placed is as follows,
Graphite ⇒ 1 - 2Talc ⇒ 1Gypsum ⇒ 1.5 - 2Calcite ⇒ 3Fluorite ⇒ 4Apatite ⇒ 5 Magnetite ⇒ 5 - 6.5Pyrithe ⇒ 6Feldespat ⇒ 6 - 6.5Quartz ⇒ 7Link to a related question:
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