Answer:the pairs are not a quadratic eqation
Step-by-step explanation:
The differences between the differences of the y value are not consistent
The set of ordered pairs (5,7),(7,11),(9,14),(11,18) does not represents a quadratic function
What is a function?A relation is a function if it has only One y-value for each x-value.
Given,
The set of ordered pairs
(5,7),(7,11),(9,14),(11,18)
We have to determine whether the (5,7),(7,11),(9,14),(11,18) is quadratic function or not.
Start by representing the function as an x-y table
x:- 5 || 7 || 9 || 11
y:- 7 || 11 || 14 || 18
The difference between the y values is not same
11-7=4
14-11=3
18-14=4
For the function to be quadratic, the above difference must be the same and since they are not, then the function does not represent a quadratic function.
Hence, the set of ordered pairs (5,7),(7,11),(9,14),(11,18) does not represents a quadratic function
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Two of the lights at the local stadium are flickering. They both just flickered at the same time.
One of the lights flickers every 7 seconds and the other light flickers every 8 seconds.
How many seconds until both lights will flicker at the same time again?
seconds
Answer:
56
Step-by-step explanation:
you have to find the LCM of 7 AND 8.
which is 56
Answer:
The answer is 56
Step-by-step explanation:
According to Hooke's Law, the force needed to stretch a spring varies directly to the amount the spring is stretched. If 50 pounds of force stretches a spring five inches, how much will the spring be stretched by a force of 180 pounds? inches
The length a spring stretches when subjected to the given load is required.
The spring is stretched by 18 inches.
Hooke's lawF = Force
k = Spring constant
x = Stretched length
[tex]F=50\ \text{lbf}[/tex]
[tex]x=5\ \text{inch}[/tex]
Hooke's law is given by
[tex]F=kx\\\Rightarrow 50=k5\\\Rightarrow k=\dfrac{50}{5}\\\Rightarrow k=10\ \text{lbf/inch}[/tex]
[tex]F=180\ \text{lbf}[/tex]
For the required spring
[tex]F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{180}{10}\\\Rightarrow x=18\ \text{inches}[/tex]
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how many are 1 raised to 3 ???
Answer:
1
Step-by-step explanation:
1^3
This is 1 multiplied by itself 3 times
1*1*1
1
19) Caculate the unit rate. Driving 95 miles on 3 gallons of
gas. How many miles are driven on 1 gallon of gas?
Answer:
31.6666666 miles / gallon
Step-by-step explanation:
Take the miles and divide by the gallons
95 miles / 3 gallons
31.6666666 miles / gallon
Find the quotient. (5x4 – 3x2 + 4) ÷ (x + 1)
Answer:
A
Step-by-step explanation:
The quotient is 5x³ -5x² + 2x -2.
What is Synthetic Division?Synthetic division is typically used to identify the zeroes of polynomials and is described as "a simplified method of dividing a polynomial with another polynomial equation of degree 1." This division method requires less human calculation effort than the lengthy division method.
Given:
(5[tex]x^4[/tex] – 3x² + 4) ÷ (x + 1)
So, the division is
(x+1) | (5[tex]x^4[/tex] – 3x² + 4) | 5x³ -5x² + 2x -2
5[tex]x^4[/tex] + 5x³
___________
-5x³ - 3x²
-5x³ - 5x²
____________
2x² + 4
2x² + 2x
____________
4 - 2x
-2 - 2x
_______
6
Hence, the quotient is 5x³ -5x² + 2x -2.
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The angle of elevation of top of pole from point x to horizontal ground is 32degree. If x is 68m away from the foot. Calculate height FT
Answer:
h = 108.8 m
Step-by-step explanation:
x = tanФ h
x = 68m
Ф = 32°
h = unknown
68 = tan(32°) * h
h = 68 / tan(32°)
h = 108.8 m
1 - Os coeficientes numéricos de uma equação do 2º grau (ax² + bx + c = 0), são números reais representados pelas letras “a, b e c”. Para que uma equação do 2º grau possa existir, é necessário que o coeficiente “a” seja DIFERENTE de: * 1 ponto a) -2 b) -1 c) 0 d) 1 2) Usando o método de Tentativa e Erro, visto na aula, qual das alternativas abaixo representa uma raiz da equação: x²-5x+6=0 * 1 ponto a) x = 0 b) x = 1 c) x = 2 c) x = -2
Answer:
1) La opción correcta es;
c) 0
2) La opción correcta es;
c) x = 2
Step-by-step explanation:
1) La forma general de una ecuación cuadrática se puede escribir en la forma;
a · x² + b · x + c = 0
Dónde;
a, y b son los coeficientes de x², x y c es el término constante
Por tanto, para que exista un polinomio de 2º grado es necesario que el coeficiente a sea diferente de 0
De lo que tenemos;
(0) × x² + b · x + c = 0, lo que da;
(0) × x² + b · x + c = b · x + c = 0 que es una ecuación lineal o un polinomio de primer grado
Por tanto, la opción correcta es c) 0
2)
La ecuación dada se presenta como sigue;
f (x) = x² - 5 · x + 6 = 0
Usando el método de prueba y error, tenemos;
Cuando x = 0
f (0) = 0² - 5 · (0) + 6 = 6 que no es igual a 0 y, por lo tanto, no es una solución
Cuando x = 1
f (1) = (1) ² - 5 · (1) + 6 = 1 que no es igual a 0 y por lo tanto, no es una solución
Cuando x = 2
f (2) = (2) ² - 5 · (2) + 6 = 0 que es igual a 0 y por lo tanto, es una solución
Cuando x = -2
f (1) = (-2) ² - 5 × (-2) + 6 = 20 que no es igual a 0 y por lo tanto, no es una solución
Por tanto, la opción correcta es c) x = 2
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;if you answer and explain
The weights of cars passing over a bridge have a mean of 3,550 pounds and standard deviation of 870 pounds. Assume that the weights of the cars passing over the bridge are normally distributed. Use a calculator to find the probability that the weight of a randomly-selected car passing over the bridge is less than 3,000 pounds.
Answer:
0.24315
Step-by-step explanation:
Using the z score formula to solve this question
z = (x - μ) / σ,
Such that:
x = raw score
μ = population mean
σ = population standard deviation.
From the question:
x = 3000
μ = 3550
σ = 870
z = (3000 - 3550) / 870
z = -550/870
z = -0.6962
Using the z score table as well as probability calculator(as requested in the question to find the z score)
The probability of having less than 3000 is obtained as:
P(x<3000) = 0.24315
what is 7k+1<8. and what would it look like on a number line
_
Answer:
[tex]\huge \boxed{k<1}[/tex]
Step-by-step explanation:
[tex]7k+1<8[/tex]
Subtract 1 from both sides.
[tex]7k+1-1<8-1[/tex]
[tex]7k<7[/tex]
Divide both sides by 7.
[tex]\displaystyle \frac{7k}{7} <\frac{7}{7}[/tex]
[tex]k<1[/tex]
*PLEASE ANSWER* What is the value of d if the volume of Prism f is 99 cubic units?
Answer:
d = 3.46 units
Step-by-step explanation:
The diagram is a rectangular prism.
volume of a rectangular prism = Length × width × height
height = 5.2 units
volume = 99 units³
length = 5.5 units
width = d
Now we need to find the width which is d
volume = L × w × h
99= 5.5 × d × 5.2
99 = 28.6d
then u divide both sides by 28.6
d = 99/28.6
d = 3.4615384615
d = 3.46 units
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Work out the circumference of a circle with diameter 1.8 cm.
Take a to be 3.142 and give your answer to 1 decimal place.
Answer:
The answer is
5.6 cmStep-by-step explanation:
Circumference of a circle( C) = πd
where d is the diameter
π = 3.142
From the question
d = 1.8cm
Substitute d = 1.8 into the above formula
Circumference of the circle is
3.142 × 1.8
= 5.6556
We have the final answer as
C = 5.6 cm to one decimal placeHope this helps you
Which measurement is equal to 6 kilograms?
Answer:
6000 metres is equal to 6 kilograms
What is the argument of -1 + √3 i?
30°
60°
120°
150°
Answer:30
Step-by-step explanation:
Based on the dots below, which of the following is a true statement
Answer:
Is there supposed to be some "dots" or something
Given b(x)=√3x+3 evaluate f(11) I really need help with this.
Step-by-step explanation:
[tex]\huge{\purple{\underline{\underline{\bf{\pink{Answer}}}}}}[/tex]
in we have x = 11
put the value of x in equation
[tex]b(11) = \sqrt{3} (11) + 3[/tex]
[tex]b(11) = 11 \sqrt{3} + 3[/tex]
so x = 11√3
Hope it helps
Use the least common denominator of 10 and 15 to solve 2/10+7/15 .
Answer: 2/3
Step-by-step explanation: As you can see, the denominators are different so we need to find a common denominator to add these 2 fractions.
We find the common denominator by finding
the common multiple for these 2 denominators.
Multiples of 10
1 x 10 = 10
2 x 10 = 20
3 x 10 = 30
Multiples of 15
1 x 15 = 15
2 x 15 = 30
As you can see, we have a common multiple of 30.
To get 30 in the denominator of 2/10, multiply top and bottom by 3.
To get 30 in the denominator of 7/15, multiply top and bottom by 2.
So we have 6/30 + 14/30 which is 20/30.
20/30 can be reduced to 2/3.
Please answer this question now
Answer:
70 degrees
Step-by-step explanation:
Measure of arc ABC is 128 degrees, so measure of arc BC is 128-90 = 38 degrees.
Meausure of arc BCD is 102 + 38 = 140 degrees, so measure of angle A is 140/2 = 70 degrees
Answer:
70°
Step-by-step explanation:
64 * 2 = 128
Inscribed angle is half the arc, so arc BC is 128-90 = 38
A is half of arc BCD, which is 102 + 38 = 140
so m<A = 70°
The value of x in this system of equations is 1. 3x + y = 9 y = –4x + 10 Substitute the value of y in the first equation: Combine like terms: Apply the subtraction property of equality: Apply the division property of equality:
Answer:
X = 1
Step-by-step explanation:
To solve the system of equation by susbtitution:
3x + y = 9
y = –4x + 10
We can follow the steps thus:
Substitute the value of y in the first equation:
As in the second equation y = -4x + 10 we can substitute in the first equation as follows:
3x + y = 9
3x + -4x + 10 = 9
Combine like terms:
3x + -4x + 10 = 9
Like therms are the therms with X (3x - 4x = -1x):
-1x + 10 = 9
Apply the subtraction property of equality:
-1x + 10 = 9
As 10 is suming, it passes to subtracting the 9:
-1x = 9 - 10
-1x = -1
Apply the division property of equality:
-1x = -1
Dividing in -1:
x = -1 / -1
X = 1Answer:
b
Step-by-step explanation:
The value of x in this system of equations is 1.
3x + y = 9
y = –4x + 10
Substitute the value of y in the first equation:
Combine like terms:
Apply the subtraction property of equality:
Apply the division property of equality:
3x + (–4x + 10) = 9
–x + 10 = 9
–x = –1
x = 1
What is the value of y?
y =
A bag of chocolates weighs 70 grams. If the weight of the bag increases by 25% find the new weight of the bag.
PLEASE HELP!! URGENT!! i will mark brainliest if its right!! In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and DF ≅ BD. Point C is the point of intersection between AG and BD while point E is the point of intersection between AG and DF. Prove ΔABC ≅ ΔGFE.
Answer:
See below.
Step-by-step explanation:
This is how you prove it.
<B and <F are given as congruent.
This is 1 pair of congruent angles for triangles ABC and GFE.
<DEC and <DCE are given as congruent.
Using vertical angles and substitution of transitivity of congruence of angles, show that angles ACB and GEF are congruent.
This is 1 pair of congruent angles for triangles ABC and GFE.
Now you need another side to do either AAS or ASA.
Look at triangle DCE. Using the fact that angles DEC and DCE are congruent, opposite sides are congruent, so segments DC and DE are congruent. You are told segments DF and BD are congruent. Using segment addition postulate and substitution, show that segments CB and EF are congruent.
Now you have 1 pair of included sides congruent ABC and GFE.
Now using ASA, you prove triangles ABC and GFE congruent.
I NEED HELP PLEASE I GIVE 5 STARS !
Answer:
I'm pretty sure 8 is the correct answer
Step-by-step explanation:
(-1)^(3/7) x 128^(3/7)
-1 x 128^3/7
128^(3/7) = 8
= 8
The expression (x-6)^2 is equivalent to
Answer:
2−12x+36
Step-by-step explanation:
Answer:
(x-6)² = (x-6)(x-6) = x² - 12x + 36
Step-by-step explanation:
What is the slope of the line between (3, −4) and (−2, 1)?
Answer:
Slope = -1
Step-by-step explanation:
To find the slope of the line between two points, we simply need to take the difference of the y-coordinates over the difference of the x-coordinates.
(-2, 1) and (3, -4)
Slope = (-4 - 1) / (3 - (-2) )
Slope = -5 / ( 5 )
Slope = - 1
Cheers.
Can someone help!!! And explain please
Answer:
400(π+2) feet square
Step-by-step explanation:
let x be the diagonal of the cage=40√2 at the same time it is the radius of the circle ( the tiger can go in circle)
but since the cage is part of the circle and not full turn πr²/8
area of the circleπr²+ half area square
(π(40√2)²)/8 +40²/2
3200π/8+1600/2
400π+800
400(π+2) feet square
How far are the points (6,4) and (6,-3)
Answer:
they are -7 points away. it would be a negative if you're going down and positive if going up that's how I was explained :D
Step-by-step explanation:
Vanessa owed her friend $24. She paid back $8. How much more does Vanessa need to pay before her account is at zero?
Answer:
$16
Step-by-step explanation:
$24 - $8 = $16
Answer:
$ 16
Step-by-step explanation:
$ 24 - $ 8 = $ 16
solve for r 5(r-10)= -51
Answer:
r= -1/5
Step-by-step explanation:
Step 1: Remove the parentheses (5r-10= -51)
Step 2: Move the constant to the right-hand side and change the sign (5r= -51 + 50)
Step 3: Calculate the sum of -51 +50 (5r = -1)
Last Step: Divide both sides by the equation by 5 (r = -1/5)
The solution for r in the equation is -1/5
The equation given is 5(r-10)= -51
To solve this question, use the distributive property. The distribute property entails expanding the terms in the bracket. This means multiply the terms in the bracket by 5
5(r - 10)
= 5 x (r - 10)
= 5r - 50
The equation then becomes : 5r - 50 = -51
The second step is to combine similar terms. This would be done by making use of the additive property of equalities: 50 would be added to both sides of the equation
5r = -51 + 50
5r = -1
The third step is to divide both sides of the equation by 5
(5r / 5) = (-1 /5)
r = -1/5
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20. Which of the following is not an identity?
a) sin2 a+cos2 a = 1
b) sin a = tan a * cos a
c) 1 + cot2 a = csc2 a
d) 1 - sec2 a = tan2 a
Answer: Choice D) 1 - sec^2(a) = tan^2(a) is not an identity.
================================================
Explanation:
a) is the pythagorean trig identity assuming you meant to write sin^2(a)+cos^2(a) = 1
b) is a rewritten version of tan = sin/cos. You multiply both sides by cos(a).
c) is an identity that you can find through dividing everything in equation (a) by sin^2. I'm assuming you meant to put exponent symbols before each "2".
d) is not an identity. I recommend looking at a table or graph that compares the two sides as separate functions. You should see they are not the same. The actual identity should be sec^2(a) - 1 = tan^2(a). You divide both sides of equation (a) by cos^2 and do a bit of algebra to get it into this form.
Dr. Potter provides vaccinations against polio and measles. Each polio vaccination consists of 6 doses, and each measles vaccination consists of 3 doses. Last year, Dr. Potter gave a total of 60 vaccinations that consisted of a total of 225 doses. How many more measles vaccines did Mr. Potter give than polio? Show All Work !!
Answer:
The number of measles vaccines that Dr. Potter give than polio vaccines is 30
Step-by-step explanation:
The parameters given are;
The number of doses given in a polio vaccine = 6 doses
The number of doses given in a measles vaccine = 3 doses
The number of vaccinations given by Dr. Potter last year = 60 vaccinations
The number of doses given in the 60 vaccinations = 225 doses
Let the number of polio vaccine given last year by Dr. Potter = x
Let the number of measles vaccine given last year by Dr. Potter = y
Therefore, we have;
6 × x + 3 × y = 225.......................(1)
x + y = 60.......................................(2)
From equation (2), we have;
x = 60 - y
Substituting the derived value for x in equation (1), we get;
6 × x + 3 × y = 225
6 × (60 - y) + 3 × y = 225
360 - 6·y + 3·y = 225
360 - 225 = 6·y - 3·y
135 = 3·y
y = 45
x = 60 - y = 60 - 45 = 15
Therefore;
The number of polio vaccine given last year by Dr. Potter = 15
The number of measles vaccine given last year by Dr. Potter = 45
The number of measles vaccines that Dr. Potter give than polio vaccines = 45 - 15 = 30 vaccines.
The number of measles vaccines that Dr. Potter give than polio vaccines = 30 vaccines.