Determine if a quadrilateral with the given vertices is an isosceles trapezoid. Show and explain all steps to prove or disprove.
A(3, 3) B(5, 3) C(8,1) D(1,1)

Answer:

5x^2-12x+7

Step-by-step explanation:

7x^2-5x+3-(2x^2 + 7X - 4)

Distribute the minus sign

7x^2-5x+3 - 2x^2 - 7X + 4

Combine like terms

5x^2-12x+7

Answer:

-12x + 17

Step-by-step explanation:

hope this helps!

Answer:

The choose D. 15/16

Step-by-step explanation:

[tex] 1\frac{1}{4} \times \frac{3}{4} = \frac{15}{16} [/tex]

I hope I helped you^_^

Answer:

Step-by-step explanation:

slope of line through (0,0) and (4,3) =(3-0)/(4-0)=3/4

eq. of line is y-0=3/4(x-0)

y=3/4 x

put x=4

y=2

2=3/4×4

2=3

which is true if 2<3

2<3

so y<3/4 x

Answer:

Our three numbers are 8, 48, and 16.

Step-by-step explanation:

Let the first, second, and third numbers be x, y, and z, respectively.

The sum of them is 72. In other words:

[tex]x + y + z = 72[/tex]

The second number y is three times the third number z. So:

[tex]y = 3z[/tex]

And the third number z is eight more than the first number x. So:

[tex]z = x + 8[/tex]

To find the numbers, solve for the system. We can substitute the last two equations into the first:

[tex]x + (3z) + ( x + 8) = 72[/tex]

Substitute again:

[tex]\displaystyle x + 3(x+8) + x+8 = 72[/tex]

Solve for x. Distribute:

[tex]x+3x+24+x+8=72[/tex]

Combine like term:

[tex]5x + 32 = 72[/tex]

Subtract:

[tex]5x = 40[/tex]

And divide:

[tex]x=8[/tex]

Thus, the first number is eight.

And since the third number is eight more than the first, the third number z is 16.

The second number is three times the third. Thus, the second number y is 3(16) or 48.

Our three numbers are 8, 48, and 16.

Answer:

y=3/2x+5

The slope is 3/2 and the y-intercept is 5

Step-by-step explanation:

Solving for y will give us the slope and y-intercept

Isolate y

2y/2=10+3x/2

y=5+3/2x

The slope is 3/2 and the y-intercept is 5

Graph it by graphing (0,5) and using the slope (up 3 over 2) to put other points

Step-by-step explanation:

We'll find the distance using the all-famous "Distance Formula." You'll probably come across it quite a bit, so it's best to have it written down somewhere.

The Distance Formula: [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

Our points are (8, -3) and (4, -7), so we'll plug in those numbers accordingly.

For reference:

x2 = 4

x1 = 8

y2 = -7

y1 = -3

The calculation:

(substitute)

[tex]\sqrt{(4-8)^2+((-7)-(-3))^2 }[/tex]

(simplify)

[tex]\sqrt{(-4)^2+(-4)^2 }[/tex]

(square things)

[tex]\sqrt{16+16 }[/tex]

(add)

[tex]\sqrt{32}[/tex]

Answer:

[tex]\sqrt{32}[/tex]

Answer:

[tex]\boxed {\boxed {\sf C. \sqrt{32}}}[/tex]

Step-by-step explanation:

The distance between 2 points can be determined with the following formula.

[tex]d= \sqrt{(x_2-x_1)^2+ (y_2-y_1)^2[/tex]

In this formula, (x₁, y₁) and (x₂, y₂) are the 2 points. We want to find the distance between the points (8, -3) and (4, -7). If we match the value with its corresponding variable, then we see:

Substitute the values into the formula.

[tex]d= \sqrt{(4-8)^2+(-7--3)^2[/tex]

Solve inside the parentheses.

[tex]d= \sqrt {(-4)^2+(-4)^2[/tex]

Solve the exponents.

[tex]d= \sqrt {16+16[/tex]

Add.

[tex]d= \sqrt {32}[/tex]

This radical can be simplified, but since it is an answer choice, we can leave it as is.

The distance between the points (8, -3) and (4, -7) is √32 and choice C is correct.

9514 1404 393

Answer:

  (a) Yes , the base is 1/e

Step-by-step explanation:

The variable is in the exponent, so this is an exponential function.

The base is the number that has the exponent. The base is (1/e).

Answer:

Step-by-step explanation:

bvxbvxbvxbvcvbbb cv

Shortest distance = Displacement

And please provide the diagram

Must click thanks and mark brainliest

Answer:

y = -7x - 16

Step-by-step explanation:

The formula for the equation of a line is y=mx+b, where m is the slope and b is the y-intercept. Since we already know the slope, all that is left is the value of b, which can be found by substituting the values of the point (-1, -9) into the equation and solving:

[tex]-9=-7(-1)+b[/tex]

[tex]-9=7+b[/tex]

[tex]b=-9-7=-16[/tex]

With this, we get the value -16, making the equation y = -7x - 16

Answer:

y = 5

Step-by-step explanation:

[tex]7y-10=25\\7y=35\\y=5[/tex]

Answer:

13 units

Step-by-step explanation:

(x₁,y₁) = (-5 , 3)   & (x₂ , y₂) = (7 ,8)

[tex]Distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}} \\[/tex]

              [tex]= \sqrt{(7-[-5])^{2}+(8-3)^{2}} \\\\= \sqrt{(7+5)^{2}+(8-3)^{2}} \\\\= \sqrt{(12)^{2}+(5)^{2}}\\\\=\sqrt{144+25}\\\\=\sqrt{169}\\\\= 13[/tex]

Answer:

2 minutes and 5 seconds

Step-by-step explanation:

60+20+15+15+15= 125 Seconds ( 2 minutes and 5 seconds )

I added three fifteens as I don't know the number of chambelanes.

Hope it helps!

The cost of each taco for the given problem is $5.

A system of linear equations can be defined as a number of equations needed to solve the equations. For n number of variables n number of equations are required.

Given that,

The cost of 2 tacos and 5 drinks cost is $20.

And, the cost of 3 tacos and 5 drinks cost is $25.

Suppose the cost of each taco and drink be x and y respectively.

Then the following equations can be written for the given case,

2x + 5y = 20         (1)

3x + 5y = 25         (2)

Subtract equation (1) from (2) to obtain,

3x + 5y - (2x + 5y) = 25 - 20

=> x = 5

Hence, the cost of a taco is $5.

To know more about linear equation click on,

https://brainly.com/question/11897796

#SPJ2

Answer: 101

Step-by-step explanation:

.

Answer:

5

Step-by-step explanation:

Subtract  

5

from  

10

.

|

5

|

The absolute value is the distance between a number and zero. The distance between  

0

and  

5

is  

5

.

5

Answer:

The (y^2 ) or (y^–2) It is not clear, I solved it in both ways (y^2) and (y^-2) .^_^

[tex] - 7 {x }^{2} - 5 + {y}^{2} \\ - 7( { - 2}^{2} ) - 5 + {4}^{2} \\ - 7( - 4) - 5 + 16 \\ 28 - 5 + 16 \\ = 39[/tex]

_______o_____o_______

[tex] - 7 {x }^{2} - 5 + {y}^{ - 2} \\ - 7( { - 2}^{2} ) - 5 + {4}^{ - 2} \\ - 7( - 4) - 5 + \frac{1}{16} \\ 28 - 5 + \frac{1}{16} \\ = 23.06[/tex]

I hope I helped you^_^

Answer:

Both are true

Step-by-step explanation:

Both are true

Answer:

y=-1/3x+7

Step-by-step explanation:

y=mx+c

m=-1/3, c=7

y=-1/3x+7

Answer:

Hello,

Step-by-step explanation:

we must first remember that:

[tex]\boxed{sin(5x)=5sin(x)-20*sin^3(x)+16*sin^5(x)}\\\\[/tex]

Let say t=sin(x)

[tex]sin(x)+cos(x)=1.4\\\\t+\sqrt{1-t^2}=1.4\\\sqrt{1-t^2}=1.4-t\ we\ square\\1-t^2=1.4^2+t^2-2.8*t\\2t^2-2.8*t+0.96=0\\\Delta=2.8^2-4*2*0.96=0.16=0.4^2\\\\t=\dfrac{2.8-0.4}{4} =0.6\ or\ t=\dfrac{2.8+0.4}{4}=0.8\\\\t^3=0,216\ or\ t^3=0,512\\\\t^5=0,07776\ or\ t^5=0,32768\\\\\boxed{sin(5x)=5*0.6-20*0.216+16*0.07776=-0,07584}\\\\or\\\\\boxed{sin(5x)=5*0.8-20*0.512+16*0.32768=-0,99712}[/tex]

Answer:

A

Step-by-step explanation:

based on line p and q

Answer: p || q

Or A

Step-by-step explanation:

good luck

Answer:

$306.25

Weekly earning,

6.25×40+6.25×6×1.5

= 306.25

Answer:

y=2x+1

Step-by-step explanation:

y is directly proportional to x if it increases as x increases

Answer:

Step-by-step explanation:

perimeter=2(l+w)=2(17+14)=2(31)=62 m

cost of fencing=62×25=1550 Rs.

f is a function defined by

{(-3, 1), (-2, 2), (-1, -3), (0, -1), (1, 3), (2, -2), (3, 0)}

so f (1) = 3. Then

h (g (i (j (f (1))))) = h (g (i (j (3))))

j is defined by

{(-3, 0), (-2, 1), (-1, 2), (0, -1), (1, -2), (2, 3), (3, -3)}

so j (3) = -3, and

h (g (i (j (f (1))))) = h (g (i (-3)))

And so on. Next you have i (-3) = 2, then g (2) = 0, and finally, h (0) = 0, so your answer is correct.

Answer:

Function C is the only one that matches both definitions for the domain and range.

Step-by-step explanation:

First let's understand what the domain and range definitions mean in plain English.

The following statement means x is defined such that x can be any real number except for 1.

[tex]\{x | x \ne 1, x \epsilon R \}[/tex]

The following statement means y is defined such that y can be any real number except for 3.

[tex]\{y | y \ne 3, y \epsilon R \}[/tex]

So let's see what functions match those definitions. Take a look at the denominator of the functions in question 7, if we plug in x = 1 for any of them, we would be dividing by zero, which we know we can't do since the function would not be defined at that value. Therefore the domain definition is correct for all functions, we cannot use x = 1 for any of them.

Let's move on to the range. Our goal is to find a function where plugging in y = 3 would give us an undefined result. Simply plugin y = 3 into all of the given equations and simplify.

Therefore the function C is the only one that matches both definitions for the domain and range.

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

[tex]x= \frac{-b +- \sqrt{b^2-4ac} }{2a}[/tex]

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

[tex]x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1[/tex]

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

[tex]x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\[/tex]

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

[tex]x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2[/tex]

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

9514 1404 393

Answer:

  [165, 175) meters

Step-by-step explanation:

The rule with respect to questions like this is that the bounds are ±1/2 of the place value of the least-significant digit. Here, the integer portion of the number has trailing zeros, and there is no decimal point or fractional part. Ordinarily, this combination of characteristics would signal that the trailing zeros are not significant, so the only significant digits are 1 and 7. The place value of the least significant digit is 10, so the bounds on the measurement are this number ±1/2(10) = ±5.

Of course, 175 rounds up to 180, so the upper bound is a limit, rather than an actual value. The height should be interpreted in this context as ...

  165 m ≤ height < 175 m

The lower and upper bounds are 165 m and 175 m, respectively.

_____

Additional comment

The best way to avoid any ambiguity as to whether trailing zeros are significant is to use scientific notation. If a zero in the ones place is significant, that is conventionally indicated by a decimal point: "170.". If scientific notation is used, the number would be reported as 1.70×10² to indicate the trailing zero is significant.

For reference, Earth's tallest tree is a redwood just under 116 meters high.

Answer:

m= 0, -0.2

Step-by-step explanation:

that's what I got when I did it

Answer:

Step-by-step explanation:

200m^4 + 80m^3 + 8m^2 = 0

~Factor

8m²(5m + 1)(5m + 1) = 0

~Set everything to equal 0 and solve

8m² = 0 → m² = 0 → m = 0

5m + 1 = 0 → 5m = -1 → m = -1/5

5m + 1 = 0 → 5m = -1 → m = -1/5

Best of Luck!