A single age distribution graph comparing males and females of a given population can provide a wealth of information. Three of the most important measures that can be obtained from such a graph are the population size, the age structure, and the gender ratio.
What is the way to measure the population size ?The population size can be determined by adding the total number of males and females represented in the graph. This is an important measure of the overall population size, and can be used to compare the population size of different countries or regions.
The age structure of the population can be determined by looking at the distribution of males and females across different age groups. This is an important measure of the demographic makeup of a population, and can be used to identify trends in population growth or decline.
Finally, the gender ratio of the population can be determined by comparing the number of males and females in each age group. This is an important measure of the overall gender balance in a population, and can be used to identify areas where there is a need for greater gender equality.
In conclusion, a single age distribution graph comparing males and females of a given population can provide a wealth of information. Three of the most important measures that can be obtained from such a graph are the population size, the age structure, and the gender ratio.
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Please help me with this.
Answer:
D
Explanation:
Gene pool is the total genetic diversity within a population or species
Answer:
D
Explanation:
hope it helps.
GOLGI APPARATUS IS THE IMPORTANT SITE OF FORMATION OF____________& ______________
GOLGI APPARATUS IS THE IMPORTANT SITE OF FORMATION OF GLYCOPROTEINS & GLYCOLIPIDS.
Transfusion of type AB blood would introduce both A and B ______________ which would be ______________ monosaccharides type
Answer: hello your question is poorly written below is the question
answer:
Tetrasaccharides, Recognized, Triggers, Type B, Type A, Type O, Not recognize, TetrasaccharidesExplanation:
Both A and B Tetrasaccharides which would be Recognized as foreign and Triggers an immune reaction in recipients lacking either the A saccharide Type B or B Type A or both Type O . meanwhile the type AB blood would contain both A and B and would Not recognize those Tetrasaccharides as foreign
the different between microspores and pollen grain
The key difference between microspore and pollen grain is that microspore is the small spore that develops into the male gametophyte in plants while pollen grain is the small grain that contains the male gametophyte.
what are three characteristics of life that archaea bacteria have?
Answer:
The common characteristics of Archaebacteria known to date are these:
(1) the presence of characteristic tRNAs and ribosomal RNAs.
(2) the absence of peptidoglycan cell walls, with in many cases, replacement by a largely proteinaceous coat.
(3) the occurrence of ether linked lipids built from phytanyl chains.
Exchange of gases in plants occur through:
(A): Stomata.
(B):Lenticels.
(C):Root surface.
(D):Choloroplast.
(1)A,B and D
(2)A,B,CandD
(3)AandC
(4)A,BandC
Answer:
(A): through the stomata
As with most fluid samples sent for microbiological analysis, Mandy starts her investigation with a Gram stain.
Gram Stain Analysis Classify the infectious agent based on the Gram staining.
Hi. Unfortunately your question is incomplete and you have not shown any photos of the sample that Mandy must identify by Gram stain. However, after researching her question on the internet, I was able to find another question exactly like this one, which showed the microorganism that should be analyzed. This image is attached below. In that case, I hope the answer below can help you.
Answer:
Gram-positive cocci
Explanation:
It is possible to identify that the microorganism presented is a bacteria due to the application of the test known as Gram stain, which allows the identification of gram positive and gram negative bacteria. This test allows the bacteria to be subjected to a specific dye that reacts with the chemical composition of the bacteria, modifying its color. Gram positive bacteria show a blue color after the test, while gram negative bacteria show a red color after the test.
As we can see in the attached image, the bacteria that Mandy is analyzing shows a blue color, after being submitted to Gram stain, being then a gram positive bacteria.
We can also see that the colonies of this bacterium have formed round, similar to a coconut and for this reason, we can conclude that the bacterium has the shape known as cocci.
Therefore, we can classify the microorganism as a Gram-positive cocci.
discuss the reaction in tricarboxylic acid cycle
The tricarboxylic acid cycle also known as the Kreb's cycle consists of eight cycle wherein a molecule of acetylCoA is used to produce three NADH, one FADH2 and one GTP/ATP molecule.
What is the tricarboxylic acid cycle?The tricarboxylic acid cycle is a sequence of reactions in which acetylCoA molecules from the glycolytic pathway are used to produce the reducing equivalents NADH ad FADH2 which are used to produce ATP in the electron transport chain.
The tricarboxylic acid cycle also known as the Kreb's cycle consists of eight cycle wherein a molecule of acetylCoA is used to produce three NADH, one FADH2 and one GTP molecule.
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Question Mode Fill in the Blank Question Fill in the blank question. In cells that contain a nucleus, the DNA is divided into multiple linear chromosomes which are organized into a complex structure called
Answer:
The correct answer is - chromatin.
Explanation:
Chromatin is a part within a chromosome consisting of DNA and protein. The DNA carries the cell's genetic instructions and these are complex structures present in multiple linear chromosomes.
The major proteins in chromatin are histones, which help package the DNA in a compact form that fits in the cell nucleus.
Which of the following is a feature of beaches?
A. Berms
B. Runnels
C. All of these
D. Shingles
Answer:
C: All of these.
Explanation:
Because there is feature
The locus B on the X chromosome of a malaria-carrying mosquito shows a 49% recombination rate with respect to the locus M. Since a recombination rate of 50% is essentially indistinguishable from independent assortment, you might be tempted to look for a locus that falls between B and M. Before you decide to do all that work, you run a chi square test to determine the P value of your experiment.
Required:
What range of P values would tell you that you should accept the conclusion that locus B and locus M are, indeed, 49mu apart and that another locus is not necessary?
Answer:
The correct answer is - P = 0.45
Explanation:
The Chi-square test is a test that determines the assorted genes independently. Here p-values used to make conclusions in significance testing.
If the p value is less than the significance level we expect or choose, then this null hypothesis is rejected in favor of the alternative hypothesis. It p value is greater than or equal to the significance level, then we fail to reject the null hypothesis.
So in this case, as the recombination rate is 49% so the p value which satisfies the conclusion will be around 0.45 and values near to it.
Lainey is looking for a new apartment and her realtor keeps calling her with new listings. The calls only take a few minutes, but a few minutes here and there are really starting to add up. She's having trouble concentrating on her work. What should Lainey do? a) Tell her realtor she can only receive text messages O b) Limit the time spent on each call O c) Turn off her phone until she is on a break O di Call her realtor back when customers won't see her on the phone
Answer:
c) Turn off her phone until she is on a break
Explanation:
If she does option "a" then her phone will still keep ringing with text message alerts. Option " b" will still be consuming her work time and option "d" can't be because it'll be too late by then so only option c makes sense.
6 points about carnivorous
Answer:
a carnivorous is a plaant and animal that eats the flesh of animal.
In eukaryotes, miR-5 is a microRNA with sequence complementarity to the 3’UTR of the mRNA transcript encoded by the UCD gene. The UCD gene encodes for a protein that acts as an allosteric activator of the protein p101. The p101 protein is a DNA methyltransferase (DNMT) which is an enzyme that methylates DNA when the protein is in its active form.
A) In a lung cancer cell line, the p101 protein is overly active leading to misregulation of gene expression. In these lung cancer cells which of the following would be a correct prediction in regards to miR-5? [choose ALL that apply, note that incorrect selections will deduct points]
A) The gene encoding miR-5 is in a region of chromatin with hypoacetylation
B) The gene encoding miR-5 is in a region of chromatin with hyperacetylation
C) The gene encoding miR-5 in a region of euchromatin
D) The gene encoding miR-5 in a region of heterochromatin
E) The miR-5 transcript is translated at high levels
F) The miR-5 transcript is activating translation of the UCD gene
B) A different lung cancer cell line is found to have significantly decreased amounts of DNA methylation. Which of the following could explain why there is decreased DNA methylation in this cell line? [choose ALL that apply, note that incorrect selections will deduct points]
A) increased amounts of the p101 protein due to low levels of miR-5
B) increased amounts of the UCD protein due to high levels of miR-5
C) decreased amounts of the UCD protein due to low levels of miR-5
D) the absence of the UCD protein due to miR-5 inhibiting translation of the UCD mRNA transcript
E) the absence of the p101 protein due to miR-5 inhibiting transcription of the p101 mRNA transcript
Answer:
A) A) The gene encoding miR-5 is in a region of chromatin with hypoacetylation.
D) The gene encoding miR-5 in a region of heterochromatin.
B) D) the absence of the UCD protein due to miR-5 inhibiting translation of the UCD mRNA transcript
Explanation:
MicroRNAs (miRNAs) are small regulatory RNA sequences (approximately 20-24 nucleotides in length) that regulate gene expression by RNA interference (RNAi) mechanisms. These sequences (miRNAs) bind by base complementarity to messenger RNAs and thus inhibit protein translation and/or trigger mRNA degradation. In this case, miR-5 binds to the 3’UTR of the mRNA transcript of the UCD gene, thereby inhibiting/slowing protein UCD synthesis. The UCD protein is an allosteric regulator that binds and activates the expression of the p101 protein, thereby the miR-5 RNAi pathway also indirectly decreases the expression of the p101 gene. Moreover, hypoacetylation is an epigenetic mark generally associated with gene silencing (heterochromatin is a transcriptionally inactive state of chromatin).
White Leaf Disease is a devastating disease that
affects sugar cane crops in Thailand and has become a
major issue for farmers. The disease starts with a white
line forming in the center of the sugar cane's leaves,
which can change in size and shape as it develops.The sugar cane's new leaves will become increasingly whiter, often having stunted growth, and resulting in the sugar cane being less productive than the non-
infected plants, Scientists are trying to determine
what organelle must be damaged to produce the
observed results,
White leaf disease is caused by phytoplasma. The disease infects the leaves and create white spots in them.
The farmers in Thailand are facing this issue with sugarcane crops. The organisms infect phloem tissues in sugar cane and cause the leaves to turn white.
The size and shape can change as sometimes there are fine white lines created while sometime there are white spots.
Scientists are trying to deal with such disease and an spray of liquid copper has been found beneficial to treat this disease. The white spot fungus stops to spread with the spray.
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Which of the following counteracts the movement of bicarbonate ions from the RBC?
A) chloride shifting
B) the Haldane effect
C) release of hydrogen ion
D) the Bohr effect
Answer:
A) chloride shifting
Explanation:
because in movement of bicarbonate ion, there. is exchange of carbonic acid and chloride ion in RBC which is called chloride shift.
Answer: A. chloride shifting
Explain how a bottleneck event can enrich recessive traits in the genetics of a population.
Answer
A bottleneck event severely reduces the fraction of a species able to pass on their genes to offspring. Any once rare recessive traits present in the surviving breeding population are passed to a larger fraction of the total population of offspring, thereby enriching those recessive traits in the total gene pool .
Bottleneck events can limit variation if the dominant allele population gets wiped out for any reason and the recessive allele can appear to be in the majority however this does not shows the actual makeup of the population.
What is bottle neck effect?The bottleneck effect is defined as a reduction and subsequent increase in a population's size affects the distribution of genetic variation among its individuals.
Examples of bottle neck effect is when the northern elephant seals have reduced genetic variation likely because of a population bottleneck humans imposed on them in the 1890s. Hunting reduced their population size to as few as 20 individuals at the end of the 19th century.
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PLEASE HELP ASAP PLEASE FAST
Answer:
D
Explanation:
the water passes through the semi permeable membrane
What is the correct order of amino acid if the sequence of bases on DNA were as follows: C-C-T-C-G-A-T-T-C-A-T-G
glycine, alanine, lysine, tyrosine
2)
alanine, proline, lysine, tyrosine
3)
valine, aspartate, glycine, proline
4)
aspartate, glycine, serine, valine
Answer:
it should be G-G-A-G-C-T-A-A-G-T-G-C
Explanation:
A=T
C=G
think of them as opposites. invert them and you'll have the answer (its easier if you write the answer right underneath)
The amino acid sequence should be G-G-A-G-C-T-A-A-G-T-G-C
G-G-A: glycine
G-C-T: alanine
A-A-G: lysine
T-G-C: tyrosine
What are amino acids?
Amino acids are molecules that combine to form proteins. Amino acids and proteins are the building blocks of life.
The nucleotide triplet that encodes an amino acid is called a codon. Each group of three nucleotides encodes one amino acid. There are 64 combinations of 4 nucleotides taken three at a time and only 20 amino acids, the code is degenerate (more than one codon per amino acid, in most cases).
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Researchers note that a plant closes its stomata on a hot, dry, windy day. What statement describes the plant response to these
conditions?
A)
The stomatal closings and the environmental conditions are unrelated for this plant.
B)
The stomatal closings and the environmental conditions are unrelated for
this plant.
Water loss and water stress is highest on hot, dry, windy days, so the plant
closes stomata to conserve water.
Hot, dry, windy days are not conducive to pollen spread, so the plant closes
its stomata to prevent pollination.
Photosynthesis is decreased on hot, dry, windy days, so the plant closes its
stomata to prevent carbon dioxide diffusion.
a
D)
Answer:
It is B
Explanation:
i just took it
If a plant closes its stomata on a hot, dry, and windy day, the plant response to these conditions is water loss and water stress is highest on hot, dry, windy days. So, the plant closes its stomata to conserve water.
What do you mean by Stomata?Stomata are the tiny pores present on the surface of the leaves. A huge amount of gaseous exchange may take place in the leaves through these pores for the purpose of photosynthesis.
During photosynthesis, these stomatal pores take carbon dioxide and water is gradually lost, in order to prevent this water loss in hot and humid conditions, the plant closes its stomata.
Therefore, if a plant closes its stomata on a hot, dry, and windy day, the plant response to these conditions is water loss and water stress is highest on hot, dry, windy days. So, the plant closes its stomata to conserve water.
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Which of the following statements about eutrophication is TRUE?
a) Eutrophic bodies of water are characterized by clear water that is relatively free of algae. •
b) Climate change is expected to worsen eutrophication because many phytoplankton grow better in warm water
c) Eutrophication is typically driven by natural processes like rock weathering and nitrogen fixation
d) Eutrophication can harm fish and other aquatic species but does not cause health problems for humans
Answer:
c) eutrophication is typically driven by natural processes like rock weathering and nitrogen fixation.eutrophication happens when too much nitrogen enriches the soil, causing excess growth of plants and algea.
I hope this helps
When nitrogen from fertilizers seeps into soil, it frequently fosters weed growth rather than the development of native plants. The excess of nutrients caused by nitrogen washing into streams is known as eutrophication. Thus, option C is correct.
What best define about eutrophication?A surplus of nutrients in water, primarily nitrogen and phosphorus, causes a process called eutrophication. By consuming the nutrients, algae flourish, proliferate, and tint the water green.
Algae blooms can have an unpleasant odor, restrict sunlight, and in some circumstances even produce toxins.
The process of eutrophication occurs when a body of water receives an excessive amount of nutrients, which increases the growth of algae and macrophytes. It causes water bodies' dissolved oxygen levels to drop and their water quality to deteriorate.
Therefore, Eutrophication is typically driven by natural processes like rock weathering and nitrogen fixation.
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What is the metric unit for mass?
Meters
Kilograms
Pounds
Matter
Answer:
Kilograms is the metric unit for mass.
pla mark me as Brainliest !
:DD have a nice day
Answer: the answer is kilo grams because people mesure the amount of mass with kilograms if you were to the amount of mass in a water bottle you would measure with kilo grams
hopefully this helps you out :) and please mark me brainiest.
OPEN ENDED QUESTION
Why should you NOT drink seawater even
in extreme survival situations? Please
use at least 3 vocabulary words from the
video.
Answer:
sea water has lot of salt which is dangerous to human health
Explanation:
i don't seem to see any video.i which I could answer your questions
1. Biochemical and differential tests can be incorporated into growth media or performed on isolated colonies after they have been cultured. Give three examples of a differential test that is incorporated into media and three examples that are applied after the colonies have been cultured.
Answer:
Biochemical and differential tests can be incorporated into growth. media or performed on isolated colonies after they have been cultured. ... Three examples of biochemical tests that are done on the colonies are catalase test, indole test, and urease test.
A geneticist finds that a strain of bacteria to produces a non-functional sigma factor. Which among the following steps in transcription would most likely be first affected?
A.Assembly of RNAP onto the DNA strand
B.Identification and binding of RNAP on to the promoter sequence
C.Conversion of open initiation complex to closed initiation complex
D.Synthesis of RNA after the formation of open initiation complex
Answer:
The correct answer is - B. Identification and binding of RNAP onto the promoter sequence.
Explanation:
Bacterial RNA polymerases have subunits known as Sigma factors responsible for the identification and specificity of promoter binding of RNAP and regulate the efficiency of RNA synthesis during transcription is initiated.
These bacteria producing the nonfunctional subunits of RNA polymerase or sigma factor will be unable to identify and tightly bind to promoter elements that are RNAP.
is the citric acid cycle the same thing as fermentation
Answer:basically
Explanation:
Suppose a researcher introduces a mutation into the glucosidase domain of the mammalian glycogen debranching enzyme. The mutation inhibits the activity of the glucosidase but does not affect the other functions of the enzyme. The researcher then introduces the mutated enzyme into mammalian cells that do not express wild type glycogen debranching enzyme. Predict the effect of the mutation on glycogen metabolism.
Answer:
cells will have glycogen molecules with branches of a single glucose residue
Explanation:
Glycogen debranching enzymes are proteins that catalyze the removal of branching from glycogen, which is a multibranched polysaccharide composed of glucose units and serves as a form of energy storage. These enzymes have two catalytic activities on a single polypeptide chain: glucosyltransferase and glucosidase activities, which are both required for glycogen breakdown. Glycogen degradation requires both glycogen phosphorylase and glycogen debranching enzymes. First, a glycogen phosphorylase acts to digest a glycogen branch down to four glucose residues. Subsequently, the debranching enzyme through its glucosyltransferase activity acts to transfer three glucose residues to a nearby branch of the glycogen chain. Finally, through its glucosidase activity, the debranching enzyme cleaves the remaining α-1,6 linkage in order to release free glucose.
hi, define chemistry and mention the three branches of chemistry answer it fast .Good night
Explanation:
Branches of inorganic chemistry include: ... Nuclear chemistry — the study of radioactive substances. Organometallic chemistry — the study of chemical compounds containing bonds between carbon and a metal. Solid-state chemistry — the study of the synthesis, structure, and properties of solid materials.
Answer:
The five primary branches of chemistry are physical chemistry, organic chemistry, inorganic chemistry, analytical chemistry, and biochemistry.
packaging methods of watermelon
Answer:
The packing process consists of:
The workers remove the watermelons from the bulk cardboard bins and place them onto the packing line.
The watermelons pass through three different brush steps (without the use of any wash water)
The watermelons are labeled and packed into large cardboard bins once again.
Explanation:
What is gylcosylation
Glycosylation is the reaction in which a carbohydrate, i.e. a glycosyl donor, is attached to a hydroxyl or other functional group of another molecule in order to form a glycoconjugate. In biology, glycosylation usually refers to an enzyme-catalysed reaction, whereas glycation may refer to a non-enzymatic reaction.
