Answer:
Saprobionts eat by secreting enzymes through the cell membrane onto their food, a process known as extracellular phototropic digestion. The enzymes catalyze the breakdown of food into molecules small enough to be absorbed by passive diffusion, transport, osmotrophy, or phagocytosis.
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Answer: External digestion is when the bacteria secretes digestive enzymes to break down the food outside of the "body" and then it sucks it up!
Explanation: her ya go
All of the following are true of spermatogenesis EXCEPT: Question 18 options: DNA replicates once, but cells divide twice. The products are spermatozoa that each have a head, midpiece and tail. Spermatids containing 23 chromosomes (1n) are produced. One spermatogonium produces 4 spermatids Genetically diverse spermatids are created.
Answer:
One spermatogonium produces 4 spermatids FALSE. One primary spermatocyte produces 4 spermatids.Explanation:
Germ cells are diploid reproductive cells in charge of gamete production. Germ cells divide by mitosis and meiosis. Through mitosis, they originate more sexual cells, but through meiosis, they produce gametes -sperm and egg cells-. This process is known as gametogenesis.
Gametes´destiny is to merge during fecundation, and a new diploid cell called zygote emerges through fertilization. The zygote is a complete cell and suffers successive mitosis to form the new organism.
Spermatogenesis is the process of production and maturation of sperm cells. Spermatogonia are the masculine diploid germ cells, carrying 46 chromosomes. These germ cells suffer mitosis to reproduce. Some of them stay as spermatogonia, and some others become primary spermatocytes, which are in charge of gamete production. Primary spermatocytes are also diploid cells, meaning that they still carry 46 chromosomes.
Each primary spermatocyte replicates its genetic material and then goes through meiosis I to produce two daughter haploid cells called secondary spermatocytes, each of them carrying 23 chromosomes. Each secondary spermatocyte will produce two other haploid daughter cells by meiosis II.
The total result from the two cellular divisions of each primary spermatocyte is four haploid daughter cells called spermatids.
During spermiogenesis, spermatids mature into spermatozoa or sperm cells. Each sperm cell characterizes by being composed of a head, midpiece, and tail.
DNA replicates once, but cells divide twice TRUE The products are spermatozoa that each have a head, midpiece, and tail TRUE Spermatids containing 23 chromosomes (1n) are produced TRUE One spermatogonium produces 4 spermatids FALSE. One primary spermatocyte produces 4 spermatids.Genetically diverse spermatids are created TRUEwhat are applied areas of mycology?
Answer:
Applied Mycology deals with fungal organisms and their application in the field of agriculture, food production and environmental sciences. Novel application of fungi in fermentation, association of fungal organisms in agriculture and forestry and in pharmaceutical industry.
Given that the intracellular concentration of potassium is 150 mEq/L, how would the potassium equilibrium potential be affected if the extracellular concentration of potassium is changed from 5.0 to 3.5 mEq/L
Answer:
The potassium equilibrium potential would increase, meaning that more K+ would be leaving the cell.
Explanation:
Let us assume that the only ion transported through the cell membrane is K+. We need to use the Nernst equation to know the destiny of the ion.
Nernst equation:
E = 58 millivolts/z. [Log₁₀ (C-out/C- in)
Where,
• E = Equilibrium potential
• 58 millivolts/z = Constant
• z = Ion charge + positive or negative symbol
• C-out = Ion concentration out of the cell
• C-In = Ion concentration inside the cell
By convenience, in the Nerts equation, the bigger concentration value corresponds to the numerator and the smaller concentration value to the denominator.
Now let us see the provided values,
• z = Ion charge + positive or negative symbol ⇒ +1 ⇒ K+
• C-out = Ion concentration out of the cell ⇒ 5 mEq/L
• C-In = Ion concentration inside the cell ⇒ 150 mEq/L
E = 58 millivolts/z. [Log₁₀ (Ion in/Ion out)
E = 58 millivolts/+1. [Log₁₀ (150 mEq/L / 5 mEq/L)
E = 58 millivolts (Log₁₀ 30)
E = 58 millivolts (1.477)
E = 85.67 millivolts
85.7 mV is the absolute value of equilibrium potential.
E = 58 millivolts/z. [Log₁₀ (Ion in/Ion out)
E = 58 millivolts/+1. [Log₁₀ (150 mEq/L / 3.5 mEq/L)
E = 58 millivolts (Log₁₀ 42.85)
E = 58 millivolts (1.63)
E = 94.65 millivolts
94.7 mV is the absolute value of equilibrium potential.
If the extracellular concentration of potassium is changed from 5.0 to 3.5 mEq/L, there will be an increase in the membrane potential from 85.7 to 94.7 mV. The increase in the equilibrium potential will result in more potassium diffusing out of the cell, turning the cell interior less positive than before.
The potassium equilibrium ability might increase, which means that greater K+ might be leaving the cell.
Let us expect that the handiest ion transported via the cell membrane is K+. We want to apply the Nernst equation to recognize the future of the ion.
Nernst equation:
[tex]E = 58 millivolts/z. [Log₁0 (C-out/ -in)[/tex]
Where,
E = Equilibrium ability.58 millivolts/z =Constant.z=lon charge + advantageous or terrible symbol. C - out = Ion awareness out of the cell. C-ln= ion awareness in the cell.For convenience, withinside the Nerts equation, the larger awareness fee corresponds to the numerator and the smaller awareness fee to the denominator. Now allow us to see the supplied values,
[tex]z=lon charge + effective or terrible ⇒+1 ⇒ K+\\C - out = lon awareness out of the cell ⇒5 mEq/L\\C-ln= lon awareness withinside the cell ⇒150 mEq/LE = 58 millivolts/+ 1.[Log 10 ( 50mEq / L / 5mEq/L)\\E = 58millivolts (Log30)\\E = 58 millivolts (1.477)[/tex][tex]E = 85.67 millivolts\\85.7 mV is absolutely the fee of equilibrium capability.\\E = 58 millivolts/z. [Log10 (lon in/lon out)\\E =58 millivolts/+1. [Log 10 (a 100and 50 mEq/L / 3.five mEq/L)\\E =58 millivolts (Log10 42.85)\\E = 58 millivolts (1.63)\\E = 94.65 millivolts94.7 mV is absolutely the fee of equilibrium capability.[/tex]
What happens if the extracellular attention of potassium is modified from 5.0 to 3.5?If the extracellular attention of potassium is modified from 5.0 to 3.5mEq/L, there can be a growth withinside the membrane capability from 85.7 to 94.7 mV. The growth withinside the equilibrium capability will bring about extra potassium diffusing out of the cell, turning the cell indoors much less high quality than before.
Thus it is clear from this that the potassium equilibrium potential is affected.
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What is the process of
evaporation?
A. The process in which plants release vapor into
the atmosphere
B. Any process that returns water from the
atmosphere to the earth
C. The process in which liquid water turns to
water vapor
I need help! Pls help!!!
(iii) Enzymes P, Q and R (choose any one)
P - pepsin / protease
Q - amylase / carbohydrase
R - lipase / trypsin / protease / amylase
(c) There are many ways in which different types of enzymes are using in preparing baby foods such as the amylase breaks down the starch and the starch breaks down to maltose or glucose. The protease breaks down protein and the protein breaks down into amino acids. The lipase breaks down fats and then the fats break down to gylcerol.
Hope it's help you.If it is right
What’s the following have contributed to historical increases in the global human population?
A.) increases in the number of deaths
B.) unavailability of clean water
C.) decreases in the birth rate
D.)Advances in hygiene
Answer:
D
Explanation:
people take it into account that the environment is fine for growing children hence giving birth
A botanist observes within a wild population of sunflowers 34 tall plants, 12 medium-height plants, and 54 short plants. Sunflower height follows incomplete dominance, where tall (H) is dominant to short (h). We can calculate that the allele frequencies are:
Answer:
f(H) = 0.4f(h) = 0.6Explanation:
Due to technical problems, you will find the complete explanation in the attached files.
part of the eye that gives people different eye colors
What bug is this please help I found it on the ground and want to make it my pet I need answers ASAP what bug is this please
The difference between active transport and passive transport is that a. concentration gradients are involved in one and not in the other. b. glycolipids play a role in one and not in the other. c. one requires expenditure of energy by the cell and the other does not. d. ions are transported into and out of the cell by one process and not by the other.
Answer:
D) ions are transported into and out of the cell by one process and not by the other
Which species of gymnosperms has reddish cones and strap like leaves that tear up from the harsh desert conditions?
A. gnetum
B. welwitschia
C. ephedra
Answer:
welwitschia
Explanation:
3. Define the following terms A) Transparent B) Translucent c) Opaque
Answer:
Transparent-->Allows all light to pass through.
Translucent-->Allows only some/partial light to pass through.
Opaque-->Allows no light to pass through.
Which of the following does NOT relate to water?
A. Dehydration damages cells.
B. 70% of the human body.
C. Controls negative feedback mechanisms.
D. Contains and moves ions in and out of cells.
The following that does not relate to water is it contains and moves ions in and out of cells. The correct option is D.
What is water?Water is a chemical compound made up of hydrogen and oxygen. It is a necessary part of life. As our body is made up of 90% of water, and without water, organisms would not survive.
The transport of ions and molecules in and out of the cell is done by the cytoplasm filling in the cell.
Thus, the correct option is D. Contains and moves ions in and out of cells.
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Hello.
All of the DNA in the nucleus of a cell can potentially be mutated?
True or false?
I will give brainly
Answer: True. Yes it could potentially be mutated.
Explanation:
hello guys, Define wave length.I think this will be easy for u guys good day thank u
Answer:
the distance between successive crests of a wave, especially points in a sound wave or electromagnetic wave.
Explanation:
Please tell me if it helps
Climate change as well as other human-driven environmental changes continue to cause loss of biodiversity in the
coming decades in addition to high rates of species extinctions. Biodiversity is a term that can be used to describe
biological diversity at a variety of different scales, but for now let's consider species diversity. Each rectangle represents a
plant community containing individuals of various species indicated by color and the total number of individuals
corresponds to the productivity of the ecosystem. Based on trends illustrated by the images, what conclusions apply?
Choose ALL that are appropriate.
-)))
A)
While species may fluctuate, biomass remains constant.
Scientific
Calc
B)
The green species increases in abundance during warm years,
C)
The productivity of the ecosystem decreases as the climate changes.
D)
Invasive species, represented by red, move in and displace native
species.
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Time
maining
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E)
Decrease in one species is compensated for by an increase in another
species.
24)
Answer:
e) decrease in one species is compensated for by an increase in another. is the answer.☺️How can algal blooms be
harmful to an aquatic
environment?
A. by blocking all sunlight and killing the bottom plants
causing no oxygen to go into the water
B. by putting oxygen up into the air for the
surrounding plants
C. by absorbing the phosphorus in the atmosphere and
having a symbiotic relationship with cyanobacteria
Answer:
(A) By blocking all sunlight and killing the bottom plants
causing no oxygen to go into the water
19. What percent of forest is found in Nepal at present? 1. 50% 2. 28% 3. 29% 4. 39%
Answer:
1. 50%
hola hai
have a great dayy
b) The chemical equation below summarizes photosynthesis.
Energy (sunlight) + 6 H20 + 6 CO2 - C6H1206 + 6 02
Write a similar chemical equation for cellular respiration. Be sure to include a
description of the form of energy that results from cellular respiration. (3 points)
Pls help me
Answer:
The chemical equation for cellular respiration would be: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O.
Explanation:
C6H12O6 (1 Glucose molecule) + 6 O2 (6 Oxygen molecules) → 6 CO2 (6 Carbon dioxide molecules) + 6 H2O (6 Water molecules)
Please I really need your help.
seventy five percent brown hair when we cross
Bb to bb
Describe ways that water pollution occurs. Describe how greenhouse gases contribute to climate change.
Greenhouse gases are transparent to incoming (short-wave) radiation from the sun but block infrared (long-wave) radiation from leaving the earth's atmosphere. This green house effect traps radiation from the sun and the planet's surface.
which statement describes a process associated with meiosis
Answer:
homologous chromosomes pair up
Answer:
Haploid cells join to form an organism that has a complete set of chromosomes.
Explanation:
Over a long period of time the process of deposition causes the formation of
Answer:
sedimentary rock
Explanation:
the process of deposition refers to rock and soil depositing itself onto a landform and hardening into rock, specifically sedimentary rock.
ATP is considered as nature dehydrating agent.what does it means?show with the help of examples
Answer:
that man is mental
The ribosomes’s primary function in both prokaryotic cells and eukaryotic cells is to
A. Build proteins according to the cell’s DNA instruction
B. Create RNA
C. Replicate DNA and RNA
D. Produce amino acids to be used to make tissues
_________ is required so that group of cells called tissues may have different function.
A. Cell interaction
B. Cell differentiation
C. Cell Proliferation
D. Cell Movement
Answer:
first A then B
Explanation:
The ribosomes's primary function in both the prokaryotic cells and the eukaryotic cells is to build proteins according to the cell's DNA instruction. Cell differentiation is required so that groups of cells called tissues may have different function. Thus, the correct options for 1 and 2 are A and B, respectively.
What are Ribosomes?A ribosome is the cellular machinery which is responsible for the production of proteins in a cell. There are many ribosomes in each cell, each of these ribosomes are made up of two subunits- one large and one small subunit. These two subunits lock around the messenger RNA (mRNA) and then travel along the length of the messenger RNA molecule by reading each of the three-letter codons in the mRNA molecule.
Cell differentiation is the process which is required so that the group of cells called as tissues may have different functions. Cell differentiation results into formation of different cells and organs in the body.
Therefore, the correct options for 1 and 2 are A and B, respectively.
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what would happen if the diet if a chid provide enough calories but is deficient in poteinsg
very short
Answer:
Serious protein deficiency can cause swelling, fatty liver, skin degeneration, increase the severity of infections and stunt growth in children.
While true deficiency is rare in developed countries, low intake may cause muscle wasting and increase the risk of bone fracture
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The structure that hotds two chromosomes together until they separate for cett divisionois
1.chromatid .
2.cytoplasm .
3.chromatin .
4.centromere
Traditionally, the classification of fungi has been based on the nature of sexual stages of the life cycle. For Penicillium, however, no sexual stages of the life cycle have been observed. Without evidence from sexual stages, speculate about other possible sources of evidence that scientists may use in classification.
Answer:
Without the evaluation of sexual stages, fungi can be classified according to the type of colony they present, the speed of growth, the formation of pigments and the type of coloration.
Explanation:
Although the observation of sexual stages is extremely efficient for the classification of fungi in the laboratory. This type of analysis is not always possible to be carried out. In that case, scientists need to find other methods that allow for the classification of fungi. These methods are carried out with the help of a microscope, where scientists observe the morphology of the fungi and are able to classify them according to the type of colony they present, the speed of growth, the formation of pigments and the type of coloration.
A student is conducting their science experiment on the effects of sugar on bullfrogs. He has 3 groups of test subjects. 1 group of frogs that receives nothing, they are the control group. The 2nd group of frogs receives half a sugar pill each, and the 3rd group receives a whole sugar pill each. He will measure their activity levels and jump heights after giving them the pills. When he is setting up his data table, what should go in the first column?
Answer:
Group 1 of frogs.
Explanation:
It is the first thing because you have to note which of the frogs you're talking about before you start.
New world monkeys have:______.
a. None of the above
b. have short legs and no tails to help them balance on top of the branches where they walk
c. have prehensile tails to aid in their 3-D movement through the trees
d. have broad and flat bodies with the scapula on the back of the ribcage, allowing a greater range of motion in the shoulder and for them to hold their arms above their heads.
Answer:
d num have broad and flat bodies
Answer:
C. have prehensile tails to aid in their 3-D movement through the trees
Explanation:Monkeys need tails to balance themselves when walking and jumping from tree to tree
