csc(π/2) =__
a.0
b.-1
c.1
d.undefined​

Answer:

x + y = 30

y = 2x

Step-by-step explanation:

x = number of ounces of lemon juice

y = number of ounces of linseed oil

How much of each ingredient is needed to make 30 oz of floor wax?

x + y = 30

The amount of oil should be twice the amount of lemon juice.

y = 2x

Answer:

x + y = 30

y = 2x

Given :-

To Find :-

Answer :-

Taking the given expression,

→ 4x² - 8x + 4

→ 4x² - 4x -4x + 4

→ 4x ( x - 1 ) -4( x -1)

→ (4x - 4)(x-1)

Hence the required answer is (4x - 4)( x - 1) .

Answer:

(1) the number of liters the tank holds

Step-by-step explanation:

Answer:

A point estimate for the proportion of registered voters who wish to see Mayor Waffleskate defeated is of 0.553.

Step-by-step explanation:

Point estimate:

The point estimate of a proportion is the sample proportion(number of desired outcomes divided by the number of total outcomes).

Find a point estimate for the proportion of registered voters who wish to see Mayor Waffleskate defeated.

167 out of 302. So

[tex]p = \frac{167}{302} = 0.553[/tex]

A point estimate for the proportion of registered voters who wish to see Mayor Waffleskate defeated is of 0.553.

Answer:

angle C= 65 degree

Step-by-step explanation:

60+55+x= 180

115+x= 180

x= 180-115

x= 65

angle C= 65 degree

Please mark me as brainliest.

Answer:

The maximum value of the function = 11, at x = 3 and y = 5

The minimum value of the function = -21, at x = 3 and y = -3

Step-by-step explanation:

Given;

F = 4y - 3x

The function is subject to  y ≤ 2x - 1,

                                            y ≥ -2x + 3,

                                               x ≤ 3

           y ≤ 2x - 1  

      -  ( y ≥ -2x + 3)

        -------------------

          0 ≤ 4x - 4

           4 ≤ 4x

            1 ≤ x

thus,   1 ≤  x ≤ 3

When x = 3

y ≤ 2x - 1     ⇒     y ≤ 2(3) - 1,        ⇒ y ≤ 5

y ≥ -2x + 3,  ⇒    y ≥ -2(3) + 3,      ⇒ y ≥ - 3

thus, -3 ≤  y  ≤ 5

When x = 1

y ≤ 2x - 1     ⇒     y ≤ 2(1) - 1,        ⇒ y ≤ 1

y ≥ -2x + 3,  ⇒    y ≥ -2(1) + 3,      ⇒ y ≥ 1

when x = 1 and y = 1

F = 4(1) - 3(1)

F = 1

when y = -3, and x = 3

F = 4(-3) - 3(3)

F = -12 - 9

F = - 21

When y = 5 and x = 3

F = 4(5) - 3(3)

F = 20 - 9

F = 11

Therefore, the maximum value of the function = 11, at x = 3 and y = 5

The minimum value of the function = -21, at x = 3 and y = -3

Answer:

see below

Step-by-step explanation:

[tex] \displaystyle AB = DE[/tex]

[given]

[tex] \displaystyle \boxed{BC = EF}[/tex]

[given]

[tex] \displaystyle AB + BC = AC[/tex]

[segment addition Postulate]

[tex] \displaystyle \boxed{DE+ EF=DF}[/tex]

[segment addition Postulate]

[tex] \rm\displaystyle DE+ BC = AC \: \: \text{and} \: \: DE+ BC = DF[/tex]

[Substitution Property of Equality]

[tex] \displaystyle \boxed{AE= DE}[/tex]

[Proven]

Answer:

less than or equal to -26

Answer:

9+c < 15

OR

c < 6

Step-by-step explanation:

"the sum of 9 and c" means: 9+c

"is less than or equal to 15" means: < 15

If you need to simplify it, then subtract 9 from both sides, and you get

c < 6

Answer:

[tex]4 \sqrt{2} [/tex]

[tex] \sqrt{32} = \sqrt{16 \times 2} = 4 \sqrt{2} [/tex]

Answer:

d)6.00

d)3.00

Step-by-step explanation:

We are given that

n=4 scores

[tex]S^2_1=68[/tex]

[tex]S^2_2=76[/tex]

We have to find the  difference should be expected, on average, between the two sample means.

[tex]S_{M_1-M_2}=\sqrt{\frac{S^2_1}{n_1}+\frac{S^2_2}{n_2}}[/tex]

[tex]n_1=n_2=4[/tex]

Using the formula

[tex]S_{M_1-M_2}=\sqrt{\frac{68}{4}+\frac{76}{4}}[/tex]

[tex]S_{M_1-M_2}=\sqrt{\frac{68+76}{4}}[/tex]

[tex]S_{M_1-M_2}=\sqrt{36}=6[/tex]

Option d is correct.

Now, replace n by 16

[tex]n_1=n_2=16[/tex]

[tex]S_{M_1-M_2}=\sqrt{\frac{68}{16}+\frac{76}{16}}[/tex]

[tex]S_{M_1-M_2}=\sqrt{\frac{68+76}{16}}[/tex]

[tex]S_{M_1-M_2}=\sqrt{9}=3[/tex]

Option d is correct.

Answer:

0.015

Step-by-step explanation:

1.5% = means 1.5 per 100 or simply 1.5/100.if you divide 1.5 by 100 you will get 0.015

Answer:

SAA

Step-by-step explanation:

HOPE IT HELPS YOU IN YOUR LEARNING PROCESS.

Answer:

Yes, the assets appear to follow a normal distribution, the values are concentrated in the center and taper off towards the ends

Step-by-step explanation:

The distribution shown above is normal as it exhibits symmetry. This means thatvtge values are concentrated in the middle with the peak so situated in the middle of the distribution which is exactly what is displayed above. As we move towards either side of the center, the values begin to decrease and we have the tail at either side of the midpoint and not on one side of the distribution.

Answer: Let the number be x

3-2x is the equation.

Answer:

946 people

Step-by-step explanation:

Find how many you would predict to be satisfied by multiplying 1,100 by 0.86:

1,100(0.86)

= 946

So, you could expect 946 people to be satisfied

Hello,

if B ⊂ A then A∩B=B

So B={1,4,5}

As per the given value of sets, B is (1,4,5).

A set is a collection of one or multiple data.

Given,

B ⊂ A

[tex]A[/tex] ∩  [tex]B = (1,4,5)[/tex]

[tex]A[/tex] ∪ [tex]B = (1,2,3,4,5,6)[/tex]

As B ⊂ A, therefor, B is a subset of A.

Therefore, [tex]A[/tex] ∩ [tex]B = B[/tex] and [tex]A[/tex] ∪ [tex]B = A[/tex]

Hence, [tex]B = A[/tex] ∩ [tex]B = (1,4,5)[/tex].

Learn more about a set here:

https://brainly.com/question/20516078

#SPJ2

Answer:

(2,3) (4,2) (5,2) (1,4) (0,2)

Step-by-step explanation:

because all these points have something common to each other. Now pay attention in your class and stop cheating!!

Answer:

Step-by-step explanation:

eq. of circle is (x-2)²+(y-3)²=10²

now substitute the values of x and y

which satisfies the above eq.that point lies on the circle.

Answer:

The maximum value of the objective function is 112 when x = 0 and y = 7.

Step-by-step explanation:

Given the constraints:

5x+3y≤37, 3x+5y≤35, x≥0, y≥0

Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:

A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)

The objective function is given as E =2x+16y, therefore:

At point A(0, 7):  E = 2(0) + 16(7) = 112

At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8

At point C(5, 4): E = 2(5) + 16(4) = 74

At point D(0, 0): E = 2(0) + 16(0) = 0

Therefore the maximum value of the objective function is at A(0, 7).

The maximum value of the objective function is 112 when x = 0 and y = 7.

Answer:

17 miles.

Step-by-step explanation:

Let's define:

North as the positive y-axis

East as the positive x-axis.

We know that Laura lives 15 miles east of Kevin's place.

Kevin lives 8 miles south of Michelle's place.

So, if we define the origin, (0, 0) as Laura's place.

From:

"that Laura lives 15 miles east of Kevin's place."

We have that the location of Kevin's house is 15 miles west from Laura's place, then Kevin's house is at:

(0, 0) + (-15mi, 0) = (-15mi, 0)

From Kevin lives 8 miles south of Michelle's place, we know that Michelle's live 8 miles north of Kevin's place.

Then the location of Michele's house is the location of Kevin's plus (0, 8mi).

Michelle's house is located at:

(-15mi, 0) + (0, 8mi)  =(-15mi, 8mi)

Now we want to find the distance between Michelle's house and Laura's house.

Michelle's house is at (-15mi, 8mi)

Laura's house is at (0mi, 0mi)

Remember that the distance between two points (a, b) and (c, d) is given by:

[tex]D = \sqrt{(a - c)^2 + (b - d)^2}[/tex]

Then the distance between  (-15mi, 8mi) and (0mi, 0mi) is:

[tex]D = \sqrt{(-15mi - 0mi)^2 + (8mi - 0mi)^2} = 17mi[/tex]

The correct option is the first one, 17 miles.

Answer:

[tex]P(head) = 0.5600[/tex]

Step-by-step explanation:

Given

[tex]n = 500[/tex] -- number of toss

[tex]head = 280[/tex] --- outcomes of head

See comment

Required

Empirical probability of head

This is calculated as:

[tex]P(head) = \frac{n(head)}{n}[/tex]

[tex]P(head) = \frac{280}{500}[/tex]

[tex]P(head) = 0.5600[/tex]

Answer:

false...

to be quadratic you need an "x^2" in the

function

(0,1)  might be 0^2 + 1

but then 1^2 + 1 = 2 than would be (1,2)  NOT (1,3)

Step-by-step explanation:

Answer:

m - 11 = 44

Step-by-step explanation:

Breaking the phrase down...

"The difference of Malik's height and 11" - this indicates subtraction.

m - 11

"is 44" - this indicates that the value of the diffrence would be '44'.

'= 44'

The equation should be:

m - 11 = 44

Hope this helps.

Answer:

13,125 ducks

Step-by-step explanation:

The ratio of ducks:geese on the first day was:

175:63

On the last day (end of migration), he counted 4,725 geese.

To find the number of ducks using the same ratio, we are first going to divide 4,725 by 63 to find what number all the ducks and geese multiplied by:

4,725/63 = 75

The geese multiplied by 75. This means the ducks also multiplied by 75:

175*75 = 13,125

Barnaby counted 13,125 ducks.

Hope it helps (●'◡'●)

Answer:

24

Step-by-step explanation:

:) im in 8th do i already know this stuff

Is this the whole question?

Step-by-step explanation:

Are you done typing or there's more to it.

Answer:

You look at your graph and or chart and start to make note

Your looking for the following tyoe data

1-5, 5-10  etc such distribution is usually done on y axes for histograms and x axes for all other graphs.

If there is a group data or frequency then you need to multiply the highest group data ie) from 0-5 it is 2.5

Then 2.5 times the actual frequency which is in the chart = say it says 4

Then 2.5 x 4 = 10

Then do the same for 5-10 = 7.5 midpoint

7.5 x frequency  of 2 = 15 and so on

Then 10-15 = 12.5 midpoint you show this by 10+15/2 = 12.5  frequency of 12.5 could be 6 as in example so 6 x 12.5 = 72  etc...

When you get all totals 10+ 15+ 72 in the fx bar you cna plot on graph and then see how many have a grade lower than 80

For histograms we dont do midpoint we do highest value then times it by frequency and so our grades for 0-5 = 5

and frequency is the number of students that got such mark so we do 5 x 4 = 20 and so on then divide this number by 5 again showing that 5 students got 5 or under

and keep adding these up, the reason we would need the fx totals ie) 20 for 0-5 is that you cna map it in a histogram by adding the number below it say its 0-5 = 5 and 5 x 4 = 20

but instead of doing separately thereafter 0-5 we just add the frequency amount to 20 so if its 5-10 = 10  then we get 10 x 2 = 20 and from 20 + 20 = 40

If no frequency was given we do 5 + 10 + 15 etc. until we get to our frequency that way.

Then after adding them all up we can use this amount to get our mean etc.

and to find how many are less than 80 if histograms boxes are shown we have to distribute from how many we know as total being first one 0-5 = 5 and count 5 into the box to see the frequency there.

Say the box is 25 little boxes we know then that 25/5 = 5 so the rate of frequency is 5 for each and that each box has the same frequency or the same distribution depending if frequency is shown a different way or not.

IF its box plot then the middle line is the median and you know its exactly half of frequency and can therafter work out quartiles and count down from 80 either using the given 79 number to the set start number at start of the whiskers.

Step-by-step explanation:

Answer:

[tex]k=35[/tex]°

Step-by-step explanation:

The degree measure of a straight line is (180) degrees. Therefore, when a line intersects another line, the sum of angle measures on any one side of the line is (180). One can apply this here to find the supplement (the angle on the same side of the line) of the angle with a measure of (130) degrees, and (85) degrees.

[tex]130 + (unknown_1)=180\\unknown_1=50\\\\85+(unknown_2)=180\\unknown_2=95[/tex]

The sum of angle measures in a triangle is (180) degrees, one can apply this here by stating the following;

[tex](unknown_1)+(unknown_2)+(k)=180[/tex]

Substitute,

[tex]50+95+k=180[/tex]

Simplify,

[tex]50+95+k=180\\\\145+k=180\\\\k=35[/tex]

[tex]\sf \bf {\boxed {\mathbb {TO\:FIND :}}}[/tex]

The measure of angle [tex]k[/tex].

[tex]\sf \bf {\boxed {\mathbb {SOLUTION:}}}[/tex]

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {k\:=\:35°}}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]

We know that,

[tex]\sf\pink{Sum\:of\:angles\:on\:a\:straight\:line\:=\:180°}[/tex]

➪ [tex]x[/tex] + 85° = 180°

➪ [tex]x[/tex] = 180° - 85°

➪ [tex]x[/tex] = 95°

Also,

Exterior angle of a triangle is equal to sum of two opposite interior angles.

And so we have,

➪ 130° = [tex]k[/tex] + [tex]x[/tex]

➪ [tex]k[/tex] + 95° = 130°

➪ [tex]k[/tex] = 130°- 95°

➪ [tex]k[/tex] = 35°

Therefore, the value of [tex]k[/tex] is 35°.

[tex]\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}[/tex]

[tex]\sf\blue{Sum\:of\:angles\:of\:a\:triangle\:=\:180°}[/tex]

➪ 50° + 35° + 95° = 180°

( where 50° = 180° - 130°)

➪ 180° = 180°

➪ L. H. S. = R. H. S.

Hence verified.

(Note: Kindly refer to the attached file.)

[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{ヅ}}}}}[/tex]

Full question:

Every 5 years the Conference Board of the Mathematical Sciences surveys college math departments. In 2000 the board reported that 51% of all undergraduates taking Calculus I were in classes that used graphing calculators and 31% were in classes that used computer assignments. Suppose that 16% used both calculators and computers. a) What percent used neither kind of technology? b) What percent used calculators but not computers? c) What percent of the calculator users had computer assignments? d) Based on this survey, do calculator and computer use appear to be independent events? Explain.

Answer:

a. 34%

b. 35%

c. 31.4%

d. Independent events

Explanation:

a. To calculate percentage that used neither kind of technology, we already know those that use the technologies and total taking calculus so:

100%-51%-31%-16%= 34%

b. Percentage that used calculators but not computers.

= 51%-16%=35%

c. Percentage of the calculator users that had computer assignments?

= 16/51×100=31.4% (there are 16 people using both so that as a percentage of 51 people using calculators)

d. Independent events are events that do not affect the other, such that occurrence of one does not define occurrence of the other. Since percentage of calculator and computer assignment users is close to those who are not using any, we can say they are independent events.

Answer:

the answae is D THEN C THE. 1

Answer:

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