Answer:
0.000256
Explanation:
Formula:
Divide the value volume by 1e+6
1 kl equal to 1000000ml
describe the formation of ionic bonds in potassium chloride compound (5 marks)
Answer:
When the two atoms are in contact, potassium readily transfers its outer electron to chlorine which readily accepts it, resulting in both atoms achieving a state of eight outermost electrons. With this electron transfer, the ionic bond in KCl is formed.
Trends in the periodic table indicate that the element with the greatest ionization energy is in which of the following periods and groups?
a
Period 2, Group 1
b
Period 7, Group 2
c
Period 6, Group 17
d
Period 1, Group 18
Answer:
D Period 1, Group 18
Explanation:
it's helium
it's top right corner of the periodic table
The general shape that an electron is located within an energy level_____
Answer:
Concentric circles
Explanation:
The energy levels are shown as concentric circles around the central nucleus, and the electrons are placed from the inside out. The first two electrons are found in the first energy level, and the third electron is found in the second energy level.
I need answers to question 1,2,3
Answer:
1. 0.125 mole
2. 42.5 g
3. 0.61 mole
Explanation:
1. Determination of the number of mole of NaOH.
Mass of NaOH = 5 g
Molar mass of NaOH = 23 + 16 + 1
= 40 g/mol
Mole of NaOH =?
Mole = mass /molar mass
Mole of NaOH = 5/40
Mole NaOH = 0.125 mole
2. Determination of the mass of NH₃.
Mole of NH₃ = 2.5 moles
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 2.5 × 17
Mass of NH₃ = 42.5 g
3. Determination of the number of mole of Ca(NO₃)₂.
Mass of Ca(NO₃)₂ = 100 g
Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]
= 40 + 2[14 + 48]
= 40 + 2[62]
= 40 + 124
= 164 g/mol
Mole of Ca(NO₃)₂ =?
Mole = mass /molar mass
Mole of Ca(NO₃)₂ = 100 / 164
Mole of Ca(NO₃)₂ = 0.61 mole
Explain how carbon’s bonding ability makes it unique.
[tex]\huge\fcolorbox{red}{pink}{Answer ♥}[/tex]
The carbon atom is unique among elements in its tendency to form extensive networks of covalent bonds not only with other elements but also with itself. ... Moreover, of all the elements in the second row, carbon has the maximum number of outer shell electrons (four) capable of forming covalent bonds.
Hope it helps uh ✌️✌️✌️
Gud mrng
3) The spectrum of the unknown mixture is a mixture of two substances among the five. What are these two substances
Answer:
a. H + d. Na
Explanation:
This is Mixture of H and Na. Because of H and in the emission and Absorption spectrum of H Total 5 lines [Red, Green, Blue and Purple (2)) are present and in the spectrum of Na Two yellow lines are present. In the mixture all this lines are are also 5 + Present. Total lines are 5+2= 7 (H+ Na)
Therefore, the answer is a. H + d. Na
Balancing equations
1. __Na + __Oz -> __Na2O
Answer:
Balancing equations
1
[tex]4Na + O_{2} -> 2Na_{2}O[/tex]
PLS HELP!!
Compare and contrast an electrolytic cell with a voltaic cell. Provide one example where both are present in daily life.
Answer:
See explanation
Explanation:
An electrolytic cell functions by a non spontaneous chemical process. Energy is supplied in the form of electricity through a battery to drive the electrochemical process.
A voltaic cell functions by a spontaneous chemical process. Energy or work can be derived from a voltaic cell.
When iron is rusting, a natural voltaic cell is set and the iron is converted to hydrated iron III hydroxide. The set up used for the extraction of sodium metal from brine functions on the basis of electrolysis.
An empirical research method in which data are gathered from observations of phenomena, hypothesis are formulated and tested, and conclusions are drawn that validate or modify the original hypothesis is known as the: Group of answer choices Gotham theory Scientific Method Niels-Bohr hypothesis Entropy theory
Answer:
Scientific Method
Explanation:
Science is empirical in nature. The entire purpose of science is to discover new knowledge.
The empirical research method in science all begins with gathering observations from phenomena. After that, the researcher formulates appropriate hypothesis which are rigorously tested.
The conclusions drawn from testing the original hypothesis validate or modify the original hypothesis.
How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen atoms and 2 oxygen atoms
Answer:
What period is the atom in?
1.
What group is the atom in?
What is the name of this atom?
What other atom would have similar
properties to the atom?
Will this atom conduct electricity well
Explanation:
How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen
and 2 oxygen atoms
What is the frequency of a wave that has a wavelength of 28 m? c = λυ where c = 2.998 x 108 m/s
a. 1.07 x 107 Hz
b. 2.3 x 107 Hz
c. 10 Hz
d. 10.7 Hz
Answer:
The frequency of a wave that has a wavelength of 28 m is 1.07*10⁷ Hz.
Explanation:
Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
The propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave's disturbance propagates along its displacement. Relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f * λ.
Being:
v= 2.998*10⁸ m/sf= ?λ= 28 mReplacing:
2.998*10⁸ m/s= f* 28 m
Solving:
[tex]f=\frac{2.998*10^{8}m/s }{28m}[/tex]
f= 1.07*10⁷ Hz
The frequency of a wave that has a wavelength of 28 m is 1.07*10⁷ Hz.
define hydroscopy in chemistry
Answer: A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption
Explanation:
what are the six chemicals in production of liquid soaps
1. Sodium triphosphate ·
2. Sodium hydroxide ·
3. potassium hydroxide
4. Sodium Lauryl Sulfate · 5.Hydroxyethylcellulose ·
6. Sodium carbonate
Si se analizan muestras de Al2O3 en diversos laboratorios se encuentra que todas tienen 52,94% de aluminio (Al) y 47,06% de oxígeno (O). Este dato experimental corresponde a lo expresado por la ley de:
A) La ley de las proporciones definidas
B) La ley de las proporciones múltiples
C) La ley de la conservación de la masa
D) La ley de la conservación de la energía
If 46.3 grams of acetylene are required to run a carbide lamp for 8 hours, how many moles of water are required
Answer:
1.78 mol
Explanation:
Step 1: Write the balanced equation
CaC₂ + H₂O ⇒ C₂H₂ + CaO
Step 2: Calculate the moles corresponding to 46.3 g of C₂H₂
The molar mass of C₂H₂ is 26.04 g/mol.
46.3 g × 1 mol/26.04 g = 1.78 mol
Step 3: Calculate the moles of H₂O required to form 1.78 moles of C₂H₂.
The molar ratio of H₂O to C₂H₂ is 1:1. The moles of H₂O required are 1/1 × 1.78 mol = 1.78 mol.
What are the effects of acid precipitation in city centers
Answer:
Answer to the following question is as follows.
Explanation:
Acid rain causes harm to houses and buildings by dissolving stone or corroding metal exposed to the elements. Acid rain can degrade calcium carbonate or calcium-based chemicals found in some of these products.
The acidic particles damage metal and accelerate the deterioration of paint and stone. They also make buildings and other structures, like as monuments, filthy.
need help asap!!!
so i don’t necessarily need an answer just how to solve everything.
this is the first one:
calcium hydroxide + ammonium chloride
the instructions are attached to this question. i’m just not sure how to do everything. it doesn’t give me the products side only the reactants so how am i supposed to write and balance the equation?
Explanation:
とおふぉくぉをえおろとようおいおぽあおそ・
'」*とまっぉのもヴぉこぉぞぽ、こ、
Answer:
Ca(OH)2 + 2NH4Cl .................. CaCl2 + 2NH3 + 2H2O
1 x 10^-3 m is the same as which of the following? Select all that apply.
a
10000 m
b
1/1000 m
c
1/0.1 m
d
0.001 m
e
100 m
Answer: b and d
Explanation:
1×10^-3=1×1/10³=1×1/1000=1/1000 so b is correct
1×10^-3=1/1000=0.001
so d is correct
In which of the following will the density increase?
Group of answer choices
An iron bar is heated.
A lead weight is moved from sea level to the top of a high mountain.
A sample of water is frozen.
A diamond is submerged in water.
A sample of chlorine gas is compressed.
What is the balance equation for
_AI+_Pb(NO3)2—__Pb+__Ca(NO3)2
Answer:
2 Al + 3 Pb(NO3)2 > 2 Al(NO3)3 + 3 Pb
Explanation:
Los 4 números cuánticos del oxígeno
How does fluorine (F)differ from iodine(I)
A. Fluorine (F) has 3 more energy shells than iodine (I).
B. Fluorine (F) has 1 less energy shell than iodine (I).
C. Fluorine (F) has 1 more energy shell than iodine (I).
D. Fluorine (F) has 3 less energy shells than iodine (I).
Fluorine (F) and iodine(I) are the halogen elements that belong to group 17. They differ from each other as fluorine has 3 fewer energy shells than iodine. Thus, option D is correct.
What are halogen groups?Halogen is a nonmetallic element that belongs to group 17 and consists of six elements namely fluorine, bromine, tennessine, chlorine, astatine, and iodine.
They are diatomic and have 7 valence electrons in the outer shell, which makes them highly reactive and electronegative. The shielding effect is less in F than I due to the closer placement and attraction of the valence electron to the nucleus.
Fluorine differs from iodine as it has a smaller size with fewer energy shells than iodine. Iodine has five energy shells, whereas fluorine has two energy shells that make the difference of three shells between them.
Therefore, F and I differ from each other.
Learn more about fluorine and iodine here:
https://brainly.com/question/2005537
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Give structural formula of ethylene. What type of bond is found in between carbon and hydrogen? Why is the bond between carbon and carbon weak in it?
Answer:
See explanation
Explanation:
The structure of ethylene is shown in the image attached. The two carbon atoms have a double covalent bond between them.
The two carbon atoms are sp2 hybridized. The bond between them is a covalent bond, there is one pi bond and one sigma bond between the carbon atoms. Between carbon and hydrogen, there are covalent bonds also. The covalent bonds are sigma bonds.
The pi bonds between carbon atoms is weaker than the sigma bonds between the carbon atoms. This is because, the side-by-side overlap the p orbitals in a pi bond is less effective than the end-to-end overlap of a sigma bond.
A 80°C la presion de vapor del benceno (C6H6) es de 1 atm. Calcula la cantidad de hexano (C6H14) que debemos añadir a 200g de benceno para que su presion de vapor sea de 700mm de Hg
Answer:
18,9g de hexano son necesarios
Explanation:
Basados en la ley de Raoult, la presión de vapor ejercida por una solución es:
P = P°*Xsolvente
Donde P es la presión de la solución deseada = 700mmHg, P° la presión de vapor de vapor del benceno = 1atm = 760mmHg y X es la fracción molar del solvente (Benceno).
Reemplazando:
700mm Hg = 760mmHg * X(Benceno)
0.9211 = X(Benceno)
La fracción molar de benceno se define como:
X = Moles benceno / Moles benceno + Moles hexano
Moles benceno -Masa molar: 78g/mol-
200g * (1mol/78g) = 2.5641 moles benceno
X = Moles benceno / Moles benceno + Moles hexano
0.9211 = 2.5641 moles benceno / 2.5641 moles benceno + Moles hexano
0.9211moles Hexano + 2.3618 = 2.5641
0.9211*Moles Hexano = 0.2023
Moles hexano = 0.2023/0.9211 = 0.2196 moles hexano.
Masa Hexano -Masa molar: 86g/mol-
0.2196 moles hexano * (86g/mol) =
18,9g de hexano son necesariosLa cantidad de hexano (C6H14) que se debe agregar a 200 g de benceno para permitir que la presión de vapor se convierta en 700 mm de Hg sería:
18.9 g
Usando la ley de Raoult, la presión de vapor que libera una solución se encuentra por:
P = P ° × X disolvente
Donde (P) denota la presión de la solución deseada
P ° denota la presión de vapor del benceno y
X denota la fracción molar del disolvente (benceno).
En el caso dado,
(P) = 700 mmHg,
P° = 1atm = 760mmHg
Fracción molar de benceno = 0,9211 (∵ 700/760)
La fracción molar de benceno (X) = Moles de benceno/Moles de benceno + Moles de hexano
Moles de benceno - Masa molar: 78g / mol - 200 g × (1 mol / 78 g)
= 2.5641 moles de benceno
X = Moles de benceno/Moles de benceno + Moles de hexano
0.9211 = 2.5641 moles Benceno/2.5641 moles Benceno + Moles de Hexano
⇒ 0,9211 × moles de Hexano + 2,3618 = 2,5641
⇒ 0.9211 × moles de Hexano = 0.2023
∵ Moles de Hexano = 0.2023/0.9211
[tex]= 0.2196 moles[/tex]
[tex]Hexane mass - Molar mass = 86g/mol - 0.2196 mole hexane[/tex] × [tex](86g/mole)[/tex]
[tex]= 18.9g[/tex]
Por tanto, 18,9 g es la respuesta correcta.
Learn more about "Benzene" here:
brainly.com/question/25798187
True or false, In a neutral atom of an element, the number of protons always equals the number of electrons.
Answer:
true
Explanation:
As an atom with no charge have same number of proton and electrons
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?
CSF + XeF6 → CsXeF7
Answer: A mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.
Explanation:
Given: Mass of cesium xenon heptafluoride = 73.1 g
The molar mass of cesium xenon heptafluoride is 131.3 g/mol. So, moles of [tex]CsXeF_{7}[/tex] is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{73.1 g}{131.3 g/mol}\\= 0.556 mol[/tex]
According to the given equation, 1 mole of CsF yields 1 mole of [tex]CsXeF_{7}[/tex].
Hence, moles of CsF reacting will also be equal to 0.556 mol. As molar mass of CsF is 151.9 g/mol so its mass is calculated as follows.
[tex]Moles = \frac{mass}{molarmass}\\0.556 mol = \frac{mass}{151.9 g/mol}\\mass = 84.46 g[/tex]
Thus, we can conclude that a mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.
How many liters of hydrogen can be produced at a pressure of 2 atm and a temperature of 298 K?
Answer: A volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.
Explanation:
Given: Mass of Mg = 2.3 g
Pressure = 2 atm
Temperature = 298 K
The reaction equation is as follows.
[tex]Mg + 2HCl \rightarrow MgCl_{2} + H_{2}[/tex]
This shows that 1 mole of Mg gives 1 mole of [tex]H_{2}[/tex].
Hence, moles of Mg for the given mass is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{2.3 g}{24.30 g/mol}\\= 0.095 mol[/tex]
Hence, 0.095 moles of Mg will give 0.095 moles of [tex]H_{2}[/tex].
Formula used to calculate volume is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into the above formula as follows.
[tex]PV = nRT\\2 atm \times V = 0.095 mol \times 0.0821 L atm/mol K \times 298 K\\V = \frac{0.095 mol \times 0.0821 L atm/mol K \times 298 K}{2 atm}\\= 1.16 L[/tex]
Thus, we can conclude that a volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.
Of the following transitions in the Bohr hydrogen atom, which of the following
results in the emission of the lowest-energy photon.
n = 1 ® n= 6
n=5 ® n=1
n = 6® n=1
n=3® n=5
n=1 ® n=5
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?
CSF + XeF6 → CsXeF7
Answer:
27.9 g
Explanation:
CsF + XeF₆ → CsXeF₇
First we convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles, using its molar mass:
Molar mass of CsXeF₇ = 397.193 g/mol73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇As 1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.
Now we convert 0.184 moles of CsF to moles, using the molar mass of CsF:
Molar mass of CsF = 151.9 g/mol0.184 mol * 151.9 g/mol = 27.9 gneed help w the questions in the pic! thankyouu
Answer: Here are the answers
Explanation:
7a) Calcium Chloride +water+carbon dioxide
b)Calcium Oxide +Carbon dioxide
8a) zinc + carbon monoxide
b) Aluminum + Carbon dioxide
c) Lead + carbon dioxide
