Answer:
[tex]\begin{array}{ccc}{Industry} & {Frequency} & {RF}& {Bank} & {26} & {13\%}& {Cable} & {44} &{22\%} & {Car} & {42} & {21\%} &{Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} &{Total} & {200} & {100\%}\ \end{array}[/tex]
Step-by-step explanation:
Given
[tex]n =200[/tex]
[tex]Bank = 26; Cable = 44; Car = 42; Cell = 60; Collection = 28[/tex]
Required
The frequency relative frequency table
The frequency table is as follows:
[tex]\begin{array}{cc}{Industry} & {Frequency} & {Bank} & {26} & {Cable} & {44} & {Car} & {42} & {Cell} & {60} & {Collection} & {28} & {Total} & {200} \ \end{array}[/tex]
Relative frequency (RF) is calculated using:'
[tex]RF = \frac{Frequency}{Total} * 100\%[/tex]
So, we have:
[tex]Bank = \frac{26}{200} * 100\% = 13\%[/tex]
[tex]Cable = \frac{44}{200} * 100\% = 22\%[/tex]
[tex]Car = \frac{42}{200} * 100\% = 21\%[/tex]
[tex]Cell = \frac{60}{200} * 100\% = 30\%[/tex]
[tex]Collection = \frac{28}{200} * 100\% = 14\%[/tex]
So, we have:
[tex]\begin{array}{ccc}{Industry} & {Frequency} & {RF}& {Bank} & {26} & {13\%}& {Cable} & {44} &{22\%} & {Car} & {42} & {21\%} &{Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} &{Total} & {200} & {100\%}\ \end{array}[/tex]
A roundabout is a one-way circular intersection.
About how many feet would a car travel if it drove
once around the roundabout? Round to the
nearest foot.
Answer:
[tex]471\:\mathrm{ft}[/tex]
Step-by-step explanation:
In one full rotation around the roundabout, the car is travelling a distance equal to the circumference, or the perimeter, of the circle. The circumference of a circle with radius [tex]r[/tex] is given by [tex]C=2r\pi[/tex]. In the diagram, the diameter is labelled 150 feet. By definition, the radius of a circle is exactly half of the diameter of the circle. Therefore, the radius must be [tex]\frac{150}{2}=75[/tex] feet. Thus, the car would travel [tex]2\cdot 75\cdot \pi=471.238898038=\boxed{471\:\mathrm{ft}}[/tex]
Find the distance between the points (6,5) and (4,-2). use of the graph is optional
Answer ? Anyone
Answer:
√53
Step-by-step explanation:
Distance between two points =
√(4−6)^2+(−2−5)^2
√(−2)^2+(−7)^2
= √4+49
=√53
= 7.2801
Hope this helps uwu
9514 1404 393
Answer:
option 2: √53
Step-by-step explanation:
The distance formula is useful for this:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((4-6)² +(-2-5)²) = √((-2)² +(-7)²) = √(4+49)
d = √53
The distance between the given points is √53.
The nth term of a sequence is 5n.
Work out the 10th term of this sequence.
Answer:
The 10th term is 50
Step-by-step explanation:
5(10) = 50
The rectangular ground floor of a building has a perimeter of 780 ft. The length is 200 ft more than the width. Find the length and the width.
The length is ___ and the width is ___
Answer:
perimeter of the rectangular ground floor
=2(length+width)
length=X+200
width=X
=2(X+200+X)
=4x+400
4x+400 =780
4x =780-400
4x =380
x =95
width=95 feet
length=95+200
=295 feet
HELP PLSS I WILL GIVE BRAINLYEST
I SUCK AT MATH
Answer:
W=11
Step-by-step explanation:
Just trust me with this one :3
I need help please asp !!!!
Simply the following ratio 1000:540:780
a + b = 300 pls help i cant find out the answer
Answer:
a= 250
b= 50
250 + 50 = 300
Step-by-step explanation:
There's many solutions but this was the first one I could come up with.
Answer:
my opinion is seince a+b=300 then the sqaure of 300= 17.3?
Step-by-step explanation:
−8x − 6y = 24
Find the x−and y−intercepts.
Answer:
y = − 4 + 4 x 3
x = − 3 − 3 y 4
Question attached please answer brainliest to best answer
Answer:
B
Step-by-step explanation:
Have a nice day :)
What is the volume of a rectangular prism
8 inches long, 3 inches wide, and 5 inches high?
A
120 cubic inches
B
220 cubic inches
16 cubic inches
158 cubic inches
Answer:
A; 120 cubic inches
Step-by-step explanation:
Let us start with the formula of the volume of a rectangular prism,[tex]V=l*w*h[/tex], where l represents the length of the prism, w represents the width of the prism, and h represents the height of the prism. It is given to us that h =5 inches, w =3 inches, and l =8 inches. Let's plug the values in:
[tex]V= 8*3*5\\V=120[/tex]
A. The volume of the rectangular prism is 120 cubic inches.
I hope this helps! Let me know if you have any questions :)
what's the easiest way to answer how I know the answer pls?
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct
This question is incomplete, the complete question is;
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.
In other words, how many 5-tuples of integers ( h, i , j , m ), are there with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?
Answer:
the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120
Step-by-step explanation:
Given the data in the question;
Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1
this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.
So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'
Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;
[tex]\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right][/tex]
= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]
= [( n + 4 )!] / [ 5!( n-1 )! ]
= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120
Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120
how many terms are in the following expression 9c+2d-8
We want to construct a box with a square base and we currently only have 10m2 of material to use in construction of the box. Assuming that all material is used in the construction process, determine the maximum volume that the box can have.
Answer:
The maximum volume of the box is:
[tex]V =\frac{5}{3}\sqrt{\frac{5}{3}}[/tex]
Step-by-step explanation:
Given
[tex]Surface\ Area = 10m^2[/tex]
Required
The maximum volume of the box
Let
[tex]a \to base\ dimension[/tex]
[tex]b \to height[/tex]
The surface area of the box is:
[tex]Surface\ Area = 2(a*a + a*b + a*b)[/tex]
[tex]Surface\ Area = 2(a^2 + ab + ab)[/tex]
[tex]Surface\ Area = 2(a^2 + 2ab)[/tex]
So, we have:
[tex]2(a^2 + 2ab) = 10[/tex]
Divide both sides by 2
[tex]a^2 + 2ab = 5[/tex]
Make b the subject
[tex]2ab = 5 -a^2[/tex]
[tex]b = \frac{5 -a^2}{2a}[/tex]
The volume of the box is:
[tex]V = a*a*b[/tex]
[tex]V = a^2b[/tex]
Substitute: [tex]b = \frac{5 -a^2}{2a}[/tex]
[tex]V = a^2*\frac{5 - a^2}{2a}[/tex]
[tex]V = a*\frac{5 - a^2}{2}[/tex]
[tex]V = \frac{5a - a^3}{2}[/tex]
Spit
[tex]V = \frac{5a}{2} - \frac{a^3}{2}[/tex]
Differentiate V with respect to a
[tex]V' = \frac{5}{2} -3 * \frac{a^2}{2}[/tex]
[tex]V' = \frac{5}{2} -\frac{3a^2}{2}[/tex]
Set [tex]V' =0[/tex] to calculate a
[tex]0 = \frac{5}{2} -\frac{3a^2}{2}[/tex]
Collect like terms
[tex]\frac{3a^2}{2} = \frac{5}{2}[/tex]
Multiply both sides by 2
[tex]3a^2= 5[/tex]
Solve for a
[tex]a^2= \frac{5}{3}[/tex]
[tex]a= \sqrt{\frac{5}{3}}[/tex]
Recall that:
[tex]b = \frac{5 -a^2}{2a}[/tex]
[tex]b = \frac{5 -(\sqrt{\frac{5}{3}})^2}{2*\sqrt{\frac{5}{3}}}[/tex]
[tex]b = \frac{5 -\frac{5}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]
[tex]b = \frac{\frac{15 - 5}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]
[tex]b = \frac{\frac{10}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]
[tex]b = \frac{\frac{5}{3}}{\sqrt{\frac{5}{3}}}[/tex]
Apply law of indices
[tex]b = (\frac{5}{3})^{1 - \frac{1}{2}}[/tex]
[tex]b = (\frac{5}{3})^{\frac{1}{2}}[/tex]
[tex]b = \sqrt{\frac{5}{3}}[/tex]
So:
[tex]V = a^2b[/tex]
[tex]V =\sqrt{(\frac{5}{3})^2} * \sqrt{\frac{5}{3}}[/tex]
[tex]V =\frac{5}{3} * \sqrt{\frac{5}{3}}[/tex]
[tex]V =\frac{5}{3}\sqrt{\frac{5}{3}}[/tex]
The maximum volume of the box which has a 10 m² surface area is given below.
[tex]\rm V_{max} = \dfrac{5}{3} *\sqrt{\dfrac{5}{2}}[/tex]
What is differentiation?The rate of change of a function with respect to the variable is called differentiation. It can be increasing or decreasing.
We want to construct a box with a square base and we currently only have 10 m² of material to use in the construction of the box.
The surface area = 10 m²
Let a be the base length and b be the height of the box.
Surface area = 2(a² + 2ab)
2(a² + 2ab) = 10
a² + 2ab = 5
Then the value of b will be
[tex]\rm b = \dfrac{5-a^2}{2a}[/tex]
The volume of the box is given as
V = a²b
Then we have
[tex]\rm V = \dfrac{5-a^2 }{2a}* a^2\\\\V = \dfrac{5a - a^3}{2}\\\\V = \dfrac{5a}{2} - \dfrac{a^3}{2}[/tex]
Differentiate the equation with respect to a, and put it equal to zero for the volume to be maximum.
[tex]\begin{aligned} \dfrac{dV}{da} &= \dfrac{d}{da} ( \dfrac{5a}{2} - \dfrac{a^3}{2} ) \\\\\dfrac{dV}{da} &= 0 \\\\\dfrac{5}{2} - \dfrac{3a^2 }{2} &= 0\\\\a &= \sqrt{\dfrac{5}{2}} \end{aligned}[/tex]
Then the value of b will be
[tex]b = \dfrac{5-\sqrt{\dfrac{5}{2}} }{2*\sqrt{\dfrac{5}{2}} }\\\\\\b = \sqrt{\dfrac{5}{2}}[/tex]
Then the volume will be
[tex]\rm V = (\sqrt{\dfrac{5}{2}} )^2*\sqrt{\dfrac{5}{2}} \\\\V = \dfrac{5}{3} *\sqrt{\dfrac{5}{2}}[/tex]
More about the differentiation link is given below.
https://brainly.com/question/24062595
Rewrite the quadratic equation in the form y= a(x - h)2 + k.
y = 5x2 – 30.3 + 95
Y= ?
Please can somebody help I am not very good at maths
Answer:
z = 3a + 4
Step-by-step explanation:
Add 4 to both sides
A person draws a card from a hat. Each card is one color, with the following probabilities of being drawn: 1/10 for blue, 1/20 for black, 1/15 for pink, and 1/5 for yellow. What is the probability of pulling a blue or yellow card, written as a reduced fraction?
Answer:
3/10
Step-by-step explanation:
1/10 + 1/5 = need to get common denominators to add.
1/10 + 2/10 = 3/10
The function of f(x) = 3x + 2 has a domain of -3 < x < 5. What is the domain of f-1(x)?
====================================================
Explanation:
Plug in the lower bound of the domain, which is x = -3
f(x) = 3x+2
f(-3) = 3(-3)+2
f(-3) = -9+2
f(-3) = -7
If x = -3, then the output is y = -7. Since f(x) is an increasing function (due to the positive slope), we know that y = -7 is the lower bound of the range.
If you plugged in x = 5, you should find that f(5) = 17 making this the upper bound of the range.
The range of f(x) is -7 < y < 17
Recall that the domain and range swap places when going from the original function f(x) to the inverse [tex]f^{-1}(x)[/tex]
This swap happens because how x and y change places when determining the inverse itself. In other words, you go from y = 3x+2 to x = 3y+2. Solving for y gets us y = (x-2)/3 which is the inverse.
-----------------------
In short, we found the range of f(x) is -7 < y < 17.
That means the domain of the inverse is -7 < x < 17 since the domain and range swap roles when going from original to inverse.
The domain of the resulting function exists on all real values that is the domain is -∞ < f-1(x) < ∞
How to find the domain of an inverse function?The domain of a function are the independent values of the function for Which it exists.
Given the function f(x) = 3x + 2
Find its inverse
y = 3x + 2
Replace x with y
x = 3y + 2
Make y the subject of the formula:
3y = x - 2
y = (x-2)/3
The domain of the resulting function exists on all real values that is the domain is -∞ < f-1(x) < ∞
Learn more on domain here: https://brainly.com/question/26098895
buggy’s bugs buggles buuuugles
Which point is the center of the circle that contains the vertices of a triangle?
The circumcenter is the center of the circle that contains the vertices of a triangle
How to determine the point?When a triangle is inscribed in a circle, the vertices of the triangle touch the circumference of the circle
A line drawn through the center of the circle and passes through each of the triangle vertex is its circumcenter.
Hence, the name of the required point is the circumcenter
Read more about circumcenter at:
https://brainly.com/question/14368399
#SPJ2
Answer:
B. The point of intersection of the perpendicular bisectors of the side
Step-by-step explanation:
definition of circumcenter as the previos question answered
5/6+3/9 in the simplest form
HELP PLSS
Answer:
1 1/6
Step-by-step explanation:
5/6 + 3/9
Simplify 3/9 by dividing the top and bottom by 3
5/6 + 1/3
Get a common denominator of 6
5/6 + 1/3 *2/2
5/6 + 2/6
7/6
Rewriting
6/6 +1/6
1 1/6
What are the domain and range of this function?
Answer:
first one. domain: all real numbers, range: {y | y ≥ 0}
Answer:
The domain is all real numbers
The range is y ≥ 0
Step-by-step explanation:
The domain is the values that x can take
The domain is all real numbers
The range is the values that y can take
The range is y ≥ 0
I don’t know the answer help! ?
Answer:
m∠8=120°
Step-by-step explanation:
Given that lines L and M are parallel to each other, keep in mind that ∠1 and ∠8 are opposite exterior angles, so they will be congruent to each other. Therefore, m∠8=120°.
help plssssssssssssssssssssssssssssss
Answer:
285 mi
Step-by-step explanation:
We can see that for every gallon, Josh drives 30 more miles. This means that he will drive 30*9.5 mi.
30*9.5 = 285
find the smallest number by which 2925 should be divided to be a perfect square
Answer: 13
Step-by-step explanation:
Given
The number is 2925
The prime factorization of 2925 is
[tex]\Rightarrow 2925=3\times 3\times 5\times 5\times 13\\\Rightarrow 2925=3^2\times 5^2\times 13[/tex]
To make 2925 a perfect square, we have to eliminate 13 from it, so divide 2925 by 13 to make it a perfect square
The perfect Sqaure becomes [tex](3\times 5)^2=225[/tex]
x^(2)+y^(2)+14x+18y+114=0
i will give u brainliest and my eternal love
Answer:
(x+7)^2+(y+9)^2=16
Step-by-step explanation:
This is the equation written in standard form, I'm not sure if that's what you wanted.
I need help comment please
Answer:
41
Step-by-step explanation:
The angle were looking for is on the other side of the figure. It is also on the inside so we would divide 82 in half giving us 41.
I’ll mark brainliest
Answer:
D
Step-by-step explanation:
Hi there!
We're given the equation y=-75x-50, which represents a submarine DESCENDING towards the ocean floor, where y is the depth in feet, and x is the number of minutes the submarine is descending
Since the submarine is DESCENDING, we can immediately eliminate A and C, which talk about the submarine ASCENDING
That leaves B and D
Looking at the given equation, y=-75x-50, -75 is the slope, or rate of change, and -50 is the y intercept, or the "beginning" (where the equation will "start")
Therefore, the submarine will start at -50 feet, or 50 feet below sea level
As x is the number of minutes the submarine is descending, that means that if the submarine travels 1 minute, it will descend 75 feet (-75*1=-75), at 2 minutes, it'll descend 150 feet (-75*2=-150), and so on
So that means the submarine must be descending at a rate of 75 feet per minute
Therefore D is the correct answer
Hope this helps! Good luck on your assignment :)
A plumber and his assistant work together to replace the pipes in an old house. The plumber charges $30 an hour for his own labor and $20 an hour for his assistant's labor. The plumber works twice as long as his assistant on this job, and the labor charge on the final bill is $2000. How long did the plumber and his assistant work on this job
Answer:
The plumber worked 50 hours, and his assistant worked 25 hours.
Step-by-step explanation:
Since a plumber and his assistant work together to replace the pipes in an old house, and the plumber charges $ 30 an hour for his own labor and $ 20 an hour for his assistant's labor, and the plumber works twice as long as his assistant on this job, and the labor charge on the final bill is $ 2000, to determine how long did the plumber and his assistant work on this job the following calculation must be performed:
40 x 30 + 20 x 20 = 1200 + 400 = 1600
50 x 30 + 25 x 20 = 1500 + 500 = 2000
Therefore, the plumber worked 50 hours, and his assistant worked 25 hours.
