construct a quadrilateral KLMN in which KL=LM=KM=5cm,KM=8cm and LN =6 cm​

Answer:

537/100s.

Step-by-step explanation:

Answer:

10 inches

Step-by-step explanation:

radius = 5 inches

Diameter = radius x 2 = 5 x 2 = 10 inches

Answer:

TR = 23

Step-by-step explanation:

first we have to find TS, so we subtract 16 from 4 to get 12. then we can add 12 and 11 to get TR

Answer:

y-intercept is (0, -8)

Step-by-step explanation:

[tex]y = {x}^{2} + 2x - 8[/tex]

At y-intercept, x is zero

substitute x as zero:

[tex]y = {(0)}^{2} + 2(0) - 8 \\ y = 0 + 0 - 8 \\ y = - 8[/tex]

Answer:

6.3 cm

Step-by-step explanation:

The distance from each centimeter is divided into 10 parts.  Point A starts at 0 and goes until right before 6.5.  The big line between each whole number signifies that you are halfway through the centimeter.  As you can see, point B is right before a big line, so can't be bigger than 6.5 nor equal.  The only option that fits this is 6.3 cm

The answer is 6.3 cm

If helpful, brainliest please !

Answer:

After 5 seconds

Step-by-step explanation:

One is given the following expression to model to the flight path of a ball:

[tex]h=-16t^2+80t[/tex]

In this problem, one is asked to find the time at which the ball lands on the ground. The easiest way to do so is to factor the expression. Take out factors that both terms have in common. The one will set the equation equal to zero, as this is the height at which one wants to find the time for. Finally, use the zero product property to solve. The zero product property states that any number times zero equals zero. Apply these ideas to the given function:

[tex]h=-16t^2+80t[/tex]

Factor the expression; both terms have a common factor of (-16t):

[tex]h=-16t^2+80t[/tex]

[tex]h=-16t(t-5)[/tex]

Set the equation equal to zero to solve for when the ball has a height of zero or rather lands on the ground:

[tex]h=-16t(t-5)[/tex]

[tex]0=-16t(t-5)[/tex]

Now use the zero product property, this states that any number times zero equals zero. Set each of the factors equal to zero, and solve to find the value of (t) for which the factor will equal zero:

[tex]0=-16t(t-5)[/tex]

[tex]0=-16t[/tex]                          [tex]t - 5 =0[/tex]

Solve for the value (t) using inverse operations,

[tex]0=-16t[/tex]                            [tex]t - 5 =0[/tex]

(divide by (-16)                   (add (5))

[tex]0=t[/tex]                                     [tex]t=5[/tex]

As one can see, the ball started on the ground, therefore at (0) seconds, its height was (0). Then, after (5) seconds the ball landed on the ground, therefore, after (5) seconds its height was again (0).

Answer:

The united nations flag the translation can be any of the blue triangles and the reflection if the flag itself as it is symmetrical

Step-by-step explanation:

The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in opposite side of the axis as if we're seeing it in a mirror.

If we study it more, you will find that its symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

If you're reflecting a point (x,y) along x axis, then its abscissa will stay same but ordinates will negate. Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along y axis, the resultant image of the point will be (-x,y)

Therefore, The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

Learn more about reflection;

https://brainly.com/question/12950057

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Answer:

[tex] \sqrt{45 {x}^{2} } + \sqrt{5 {x}^{2} } + 4x \sqrt{5} \\ = 3 \sqrt{5} x + \sqrt{5} x + 4x \sqrt{5} \\ = 8x \sqrt{5} \\ thank \: you[/tex]

Answer:

hope it helps, appreciate if you can give brainliests

Answer:

hope this helps you

have a great day

Answer:

semoga jawapan ini dapat membantu

The Sequence:

1 , 1+2 , 1+2+3 , 1+2+3+4, ...

here, every term is an AP. finding the general formula for the sum of the elements of each term is:

Sₙ = [tex]\frac{x}{2}(2a + (x-1)d)[/tex]        [where x = number of term, a = first term and d = common difference]

here, the first term is always 1 and so is the common difference.

Sₙ = [tex]\frac{x}{2}(2 +x-1)[/tex]

Sₙ = [tex]\frac{x}{2}(1 +x)[/tex] = [tex]\frac{1}{2}(x + x^{2})[/tex]

which is the formula for a general term in our series

now, we need to find the sum of the first n terms of this series

[tex]\displaystyle\sum_{x=1}^{n} [\frac{1}{2}(x + x^{2})][/tex]

[tex]\displaystyle\frac{1}{2} [\sum_{x=1}^{n} (x) + \sum_{x=1}^{n}(x^{2})][/tex]

in this formula, for the first term, it's just an AP from x = 1 to x = n

for the second term, we have a general formula [tex]\frac{n(n+1)(2n+1)}{6}[/tex]

[tex]\frac{1}{2}[\frac{n}{2}(2a + (n-1)d)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

in this AP (first term), the first term and the common difference is 1 as well

[tex]\frac{1}{2}[\frac{n}{2}(2 + n-1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex]\frac{1}{2}[\frac{n}{2}(n+1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex][\frac{n}{4}(n+1)+ \frac{n(n+1)(2n+1)}{12} ][/tex]

[tex]\frac{n}{4}(n+1) [1+\frac{(2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(3+2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(2n+4)}{3} ][/tex]

[tex]\frac{n}{2}(n+1) [\frac{(n+2)}{3} ][/tex]

[tex]\frac{n(n+1)(n+2)}{6}[/tex]

which is the sum of n terms of the given sequence

Answer: (1, -2)

Concept:

There are three general ways to solve the system of equations:

Here, we are going to use the elimination method to solve.

Solve:

Given

[tex]\left \{ {{y=-5x+3} \atop {2x-3y=8}} \right.[/tex]

Convert the first equation's arrangement to correlate with the second equation

[tex]\left \{ {{5x + y=3} \atop {2x-3y=8}} \right.[/tex]

Multiply 3 on both sides in the first equation

[tex]\left \{ {{15x + 3y=9} \atop {2x-3y=8}} \right.[/tex]

Eliminate [y] by adding the two equations

[tex]17x = 17[/tex]

Divide both sides by 17

[tex]17x / 17=17/17[/tex]

[tex]x=1[/tex]

[tex]y=-5x+3=-5(1)+3=-5+3=-2[/tex]

[tex](1, -2)[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

63

Step-by-step explanation:

6x + 3y - 9

x = 6

y = 9

6(6) + 3(9)

36 + 27

= 63

Factors for 3: 1 and 3

Factors for 5: 1 and 5

Factors for 14: 1, 2, 7, and 14

Answer:

1

Step-by-step explanation:

Factors for 3: 1 and 3  

Factors for 5: 1 and 5  

Factors for 14: 1, 2, 7, and 14

Since 1 is the greatest common factor in 3,5,14 ,

GCF = 1

Answer:

5d = 30

Step-by-step explanation:

1. first you need to add 5 to both sides

   d-4+5 = 2+5

2. then you need to combine like terms

   d+1 = 7

3. after that you have to multiply both sides by 5

   5(d+1) = 7(5)

4. simplify

   5d + 5 = 35

         -5     -5

   5d = 30

Answer:

B

Step-by-step explanation:

The correct answer is B, because you have -4 +(-6)+(-2) which is really just

-4-6-2 which is -12. Think of it as getting rid of the plus sign and just leaving the negative sign. Which this would make the answer to the equation be -12, but for the answer of the question, it would be B because it is accumulating the drops in temperatures making the numbers go down in temperature, therefore making them negative.

A is not the answer because although it is similar to letter B, the difference is the final sentence, "What was the overall change in temperature?" Since -4 is listed as the pre-existing temperature, that would make -6 - 2 be equal to negative eight (-8).

C is not the answer because it includes a temperature rising by 18 degrees.

D is not the answer either because it is saying the temperature rose, which is shouldn't have risen.

The only time C and D could be right, is if they included bigger number that equaled out to negative twelve (-12), like saying the temperature rose 18 degrees, but fell by 26 degrees by midnight, that would make the equation look like -4 + 18 - 26 = - 12

Even in that case, C and D would be wrong immediately because of the use of numbers outside of the expression given.

Hope this helps!

Step-by-step explanation:

At Bob's binders, the unit price = $4.20 ÷ 3

= $1.40

At Pam's Paper Place the unit price = $5.20 ÷ 4 = $1.30

the better buy is at Pam's Paper place

Answer:

43.4 yd

Step-by-step explanation:

[tex]45^{2}[/tex]-[tex]12^{2}[/tex]

2025-144=1881

[tex]\sqrt{1881}[/tex]

43.37049

43.4

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

The y intercept occurs when x = 0.

All you have to do is read the table until you come to x = 0.

When you do, read down to get the y value.

The answer is A (0,2)

Answer:

purple.orang.blue.yellow and green

purple.orang.blue.yellow and green

Answer: The bill with a discount is $18.59

Step-by-step explanation:

Given information

2 boxes of $3.49 cereal

3 cartons of $2.99 ice-cream

6 packs of $1.99 soda

1/3 discount off total bill

Given expression

Bill = (1 - 1/3) (2 × 3.49 + 3 × 2.99 + 6 × 1.99)

Simplify values in parentheses

Bill = (2/3) (6.98 + 8.97 + 11.94)

Simplify by addition

Bill = (2/3) (27.89)

Simplify by multiplication

Bill = $18.59 (Rounded to the nearest hundredth because the usual money ends in nearest cent)

Hope this helps!! :)

Please let me know if you have any questions

Answer:

17/30 (0.56)

Step-by-step explanation:

18/20-4/12

Reduce the fraction with 2 and 4: 9/10-1/3

Write all numerators above the least commmon denominator 30: 27-10/30

Subtract: 27-10/30 = 17/30

Answer:

56mm²

Step-by-step explanation:

i will appreciate if u give brainliests, thanks

√8 < √9 = 3

and

√42 > √36 = 6

which means the positive integers between √8 and √42 are 3, 4, 5, and 6, and their sum is 18.

Answer:

[tex]\frac{(a+b)}{a^{2} -b^{2} }[/tex] + [tex]\frac{(a-b)}{a^{2} -b^{2} }[/tex] = [tex]\frac{2a}{a^{2} -b^{2} }[/tex]

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{ \sqrt{a + b} }{ \sqrt{a - b} } + \frac{ \sqrt{a - b} }{ \sqrt{a + b} } \\ squaring \: on \: both \: sides \\ \frac{a + b}{a - b} + \frac{a - b}{a + b} \\ \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)} \\ \frac{ {(a + b)}^{2} + {(a - b)}^{2} }{ {a}^{2} - {b}^{2} } \\ remaining \: in \: attachment[/tex]

[tex]thank \: you[/tex]

Answer:

Below,...

Step-by-step explanation:

Your equation:

[tex]\frac{63}{7-(2*3)} =\frac{63}{7-6} =\frac{63}{1}=63[/tex]

Hope it helps,... Chow,...!