Consider the function f(x) = x2 and the function g(x) = 3x2. How will the graph of g(x) differ from the graph of f(x)?

Select the correct answer

The graph of g(x) is the graph of f(x) shifted to the left 3 units.

The graph of g(x) is the graph of f(x) stretched vertically by a factor of 3.

The graph of g(x) is the graph of f(x) compressed vertically by a factor of

The graph of g(x) is the graph of f(x) shifted up 3 units. ​

Answers

Answer 1

Answer:

Third Choice - The graph of g(x) is the graph of f(x) compressed vertically by a factor of 3

Step-by-step explanation:

x^2 is the the parent function, so it opens up with a normal compression.

Any number > (greater than) 1 as a coefficient of x will lead to a vertical compression (narrower parabola), while any number < (less than) 1 as a coefficient of x will lead to a vertical stretch (wider parabola).

So, 3x^2 would have to have to be a compressed parabola.

I hope this helps!

Answer 2

Answer:

The graph of g(x) is the graph of f(x) stretched vertically by a factor of 3.

Step-by-step explanation:

A vertical stretch or shrink of a function, kf(x), results from multiplying the entire function by a constant, k.

In this case, g(x) equals 3 times f(x). If k > 1, then the graph will be stretched vertically (along the direction of the y-axis) by a factor of k.

So, the graph of g(x) is the graph of f(x) stretched vertically by a factor of 3.


Related Questions

So for this problem I got the scientific notation however I can not seem to figure out the standard notation. I thought it is the same answer but it is not. Can someone please help me out here please?

Answers

Answer:

567000000

Step-by-step explanation:

Standard is the actual number. Multiply 5.67 and 10^8.

Each side of a square is increasing at a rate of 4 cm/s. At what rate (in cm2/s) is the area of the square increasing when the area of the square is 25 cm2

Answers

Answer:

The area of the square is increasing at a rate of 40 square centimeters per second.

Step-by-step explanation:

The area of the square ([tex]A[/tex]), in square centimeters, is represented by the following function:

[tex]A = l^{2}[/tex] (1)

Where [tex]l[/tex] is the side length, in centimeters.

Then, we derive (1) in time to calculate the rate of change of the area of the square ([tex]\frac{dA}{dt}[/tex]), in square centimeters per second:

[tex]\frac{dA}{dt} = 2\cdot l \cdot \frac{dl}{dt}[/tex]

[tex]\frac{dA}{dt} = 2\cdot \sqrt{A}\cdot \frac{dl}{dt}[/tex] (2)

Where [tex]\frac{dl}{dt}[/tex] is the rate of change of the side length, in centimeters per second.

If we know that [tex]A = 25\,cm^{2}[/tex] and [tex]\frac{dl}{dt} = 4\,\frac{cm}{s}[/tex], then the rate of change of the area of the square is:

[tex]\frac{dA}{dt} = 2\cdot \sqrt{25\,cm^{2}}\cdot \left(4\,\frac{cm}{s} \right)[/tex]

[tex]\frac{dA}{dt} = 40\,\frac{cm^{2}}{s}[/tex]

The area of the square is increasing at a rate of 40 square centimeters per second.

Solve by graphing. Round each answer to the nearest tenth.

6x2 = −19x − 15
a: −2, 1.7
b: −1.7, −1.5
c: −1.5, 1.5
d: −1.5, 1.7

Answers

9514 1404 393

Answer:

  b:  -1.7, -1.5

Step-by-step explanation:

The graph is shown below. We have annotated the x-intercepts for the equivalent equation ...

  6x^2 +19x +15 = 0

Based on the graph, find the set of all x-values for which the points P(x,y) are on the graph y>0. Enter your answer using interval notation

Answers

Answer:

The solution set is: (-1,3)

We want to find the set of the x-values of the points that belong to the given graph and have an y-value larger than zero.

The set is: s = (-1, 3)

To find the set, we need to see the x-values of the points on the graph such that y > 0.

y > 0 means that we only look at the region of the graph that is above the x-axis.

We can see that this region goes from x =-1 to x = 3

Then for all the x-values between x = -1 and x = 3 the points p(x, y) on the graph have an y-value larger than zero.

Notice that because the value must be larger than zero, then the particular x-values:

x = -1 and x = 3 are not in the set.

So the set must be written as:

s = (-1, 3)

This is the set in the interval notation.

If you want to learn more, you can read:

https://brainly.com/question/24600195

30 students in grade 8 finished their summer packet before August 15.
This was 12% of all the students. How many students are in grade 8?

Answers

Step-by-step explanation:

12/100=30/x

12x=3000

x=250

hiii! !!

How many outcomes (sample points) for a deal of two cards from a 52-card deck are possible? Report your answer as an integer.

Answers

Answer:

1326

Step-by-step explanation:

[tex]{52\choose2}=\frac{52!}{(52-2)!2!}=\frac{52!}{50!*2!}=1326[/tex]

We deposit $12000 into an account carning 3 % interest compounded continuously, How many years will it take
for the account to grow to $16800? Round to 2 decimal places,

Answers

Answer:

The answer is 13.33 year

Step-by-step explanation:

P = $12000

Rate = 3%

Amount = $16800

so,

I = A-P

= $16800 - $12000

= $4800

So,

T = (I × 100)/P×R

= (4800×100)/P×R

= 480000/($12000×3)

= 480000/36000

= 480/36

= 13.33 year

Complete this sentence: The longest side of a triangle is always opposite the
• A. angle with the smallest measure
O B. angle with the greatest measure
O C. shortest side
D. second-longest side

Answers

Answer:

B. angle with the greatest measure

opposite the largest angle

A sociologist claims the probability that a person picked at random in Times Square in New York City is visiting the area is 0.83. You want to test to see if the claim is correct. State the null and alternative hypotheses.

Answers

Answer:

The answer is:

[tex]H_0: p=0.83\\\\H_a: p \neq 0.83[/tex]

Step-by-step explanation:

Now, we're going to test if sociologists claim to be have visited a region of 0.83 by a person picked randomly on Time In New York City.

Therefore, null or other hypotheses are:

[tex]H_0: p=0.83\\\\H_a: p \neq 0.83[/tex]

Find the distance between the two points in simplest radical form. (8,−8) and (−1,−5)

Answers

Answer:

Solution given:

[tex]x_{1},y_{1}=(8,-8)[/tex]

[tex]x_{2},y_{2}=(-1,-5)[/tex]

Now

Distance between them is:

d=[tex]\sqrt{(x_{2}-x_{1})²+(y_{2}-y_{1})²}[/tex]

d=[tex]\sqrt{(-1-8)²+(-5+8)²}=3\sqrt{10}[/tex]

Distance between them is [tex]\bold{3\sqrt{10}}[/tex]

A city has a population of 350,000 peopleSuppose that each year the population grows by 7.75%What will the population be after 6 years Use the calculator provided and round your answer to the nearest whole number

Answers

Answer:

547737

Step-by-step explanation:

So first when know that the equation for exponentinal growth is f(x)=a(1+r)^x

Then you need to substitue so it would be f(x)=350,000(1+0.0775)^6

So then you would add the 1 and 0.0775 to equal 1.0775

So now its f(x)=350,000(1.0775)^6

So after that following PEMDAS, you would basically do 1.0775 to the power of 6 and get 1.56496155465

After you would do 1.56496155465 times 350,000 and that would be 547736.544129 and since its to the nearest whole number the answer would be 547737

Hopefully, that helped. If I did end up making a mistake then just comment on my answer. :)

HELP PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS

Answers

Answer:

12

Step-by-step explanation:

10 - 1/2 x = 12-4/3x

60 - 3x = 72-2x

-12 = - x

Evaluate:

11x - 8(x - y)

Answers

Answer:

11x-8x+8y

3x+8y SEEESH IN DEEZ NU                           TS

Step-by-step explanation:


2/5 e +4 = 9

Help please

Answers

Answer:

e=12.5 or e=25/2

Step-by-step explanation:


51
What is the inverse of the function f(x) = 2x + 1?
Oh(x) =
1
2x-
o h«x)= kx +
- 3x-2
Oh(x) =
Oh(x) =
Mark this and return
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Submit
Type here to search
81
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10:49 AM
^ D 0x
mamman

Answers

Answer:

let inverse f(x) be m:

[tex]m = \frac{1}{2x + 1} \\ 2x + 1 = \frac{1}{m} \\ 2x = \frac{1 - m}{m} \\ x = \frac{1 - m}{2m} [/tex]

substitute x in place of m:

[tex]{ \bf{ {f}^{ - 1}(x) = \frac{1 - x}{2x } }}[/tex]

What is the minimum of y=1/3 x^2 + 2x + 5

Answers

Answer:

min at x = -3

Step-by-step explanation:

steps are in the pic above.

A manufacturer of nails claims that only 4% of its nails are defective. A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective. Is it fair to reject the manufacturer's claim based on this observation?

Answers

Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

[tex]H_0: p = 0.04[/tex]

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

[tex]H_a: p > 0.04[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

4% is tested at the null hypothesis

This means that [tex]\mu = 0.04, \sigma = \sqrt{0.04*0.96}[/tex]

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that [tex]n = 20, X = 0.1[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}[/tex]

[tex]z = 1.37[/tex]

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Answer:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

The owners of a baseball team are building a new baseball field for their team and must determine the number of seats to include. The average game is attended by 6,500 fans, with a standard deviation of 450 people. Suppose a random sample of 35 games is selected to help the owners decide the number of seats to include. Identify each of the following and be sure to round to the nearest whole number:
Provide your answer below:
μ =------------
μx=-----------
σx=-----------
σ=------------
n=------------

Answers

Answer:

μ = 6500

μx= 6500

σx= 76

σ= 450

n= 35

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The average game is attended by 6,500 fans, with a standard deviation of 450 people.

This means that [tex]\mu = 6500, \sigma = 450[/tex]

35 games:

This means that [tex]n = 35[/tex]

Distribution of the sample mean:

By the Central Limit Theorem, we have [tex]\mu_x = \mu = 6500[/tex] and the standard deviation is:

[tex]\sigma_x = \frac{450}{\sqrt{35}} = 76[/tex]

you are making meat loaf with yield: 50, 4oz portions what is the total recipe cost

Answers

Answer:

[tex]200oz[/tex]

Step-by-step explanation:

The question says that there are [tex]50[/tex] portions that are [tex]4oz[/tex] each.

Write an equation

[tex](50)4oz[/tex]

Simplify

[tex]200oz[/tex]

Joe's Auto Insurance Company customers sometimes have to wait a long time to speak to a
customer service representative when they call regarding disputed claims. A random sample
of 25 such calls yielded a mean waiting time of 22 minutes with a standard deviation of 6
minutes. Construct a 95% and 99% confidence interval for the population mean of such
waiting times. Explain what these interval means.

Answers

Answer:

The 95% confidence interval for the population mean of such waiting times is between 19.5 and 24.5 minutes. This means that we are 95% sure that the true mean waiting time of all calls for this company is between 19.5 and 24.5 minutes.

The 99% confidence interval for the population mean of such waiting times is between 18.6 and 25.4 minutes. This means that we are 99% sure that the true mean waiting time of all calls for this company is between 18.6 and 25.4 minutes.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.0639

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.0639\frac{6}{\sqrt{25}} = 2.5[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 22 - 2.5 = 19.5 minutes

The upper end of the interval is the sample mean added to M. So it is 22 + 2.5 = 24.5 minutes

The 95% confidence interval for the population mean of such waiting times is between 19.5 and 24.5 minutes. This means that we are 95% sure that the true mean waiting time of all calls for this company is between 19.5 and 24.5 minutes.

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.797

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.797\frac{6}{\sqrt{25}} = 3.4[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 22 - 3.4 = 18.6 minutes

The upper end of the interval is the sample mean added to M. So it is 22 + 3.4 = 25.4 minutes

The 99% confidence interval for the population mean of such waiting times is between 18.6 and 25.4 minutes. This means that we are 99% sure that the true mean waiting time of all calls for this company is between 18.6 and 25.4 minutes.

I really need help with this problem

Answers

Step-by-step explanation:

(x)+(x+1)<832x+1<832x<83-1x<82/2x<41

hope it helps.stay safe healthy and happy....

Answer:

[tex]x<41[/tex]

Step-by-step explanation:

[tex](x)+(x+1)<83[/tex]

simplify both sides

[tex]2x+1<83[/tex]

subtract one from the both sides to isolate the variable

[tex]2x<82[/tex]

divide both sides by 2 to isolate the variable

[tex]x<41[/tex]

I need help with these questions

Answers

Answer:

1) 6m+8n

4) 21x+14y

7) 14c+16d

10) d+3e

Step-by-step explanation:

Someone please help thanks

Answers

Answer:

By similar triangles:    BE/20 = 18/25    BE 14.4

Also, (ED + 26) / 26 = 18/14.4

ED = 6.5   and AD = 32.5

Please help I’m really stuck this is my last attempt

What is the mode for the set of data?

Ages
Stem Leaves
5 0, 4, 6
6 0, 2, 3, 4, 8, 8, 9
7 0, 2, 3, 4, 4, 4, 8, 9
8 4, 5, 6, 8
5|0 = 50 years old


33
68
4
74

Answers

Answer:

I THINK IT IS 74 NOT 4

I HOPE THIS HELPS!!!!!

At a hockey game, a vender sold a combined total of 228 sodas and hot dogs. The number of sodas sold was two times the number of hot dogs sold. Find the number of sodas and the number of hot dogs sold.

Answers

9514 1404 393

Answer:

152 sodas76 hot dogs

Step-by-step explanation:

Of the items sold, sodas were 2/(2+1) = 2/3 of the total.

  (2/3)(228) = 152 . . . sodas were sold

  152/2 = 76 . . . . hot dogs were sold

Find a linear function that models the cost, C, to produce x toys given the rate of change and initial output value. The cost to produce plastic toys increases by 90 cents per toy produced. The fixed cost is 40 dollars. C(x) = dollars Write a linear model for the amount of usable fabric sheeting, F, manufactured in t minutes given the rate of change and initial output value. Fabric sheeting is manufactured on a loom at 7.25 square feet per minute. The first five square feet of the fabric is unusable. F(t) = ft^2 is the amount of usable fabric sheeting manufactured in t minutes.

Answers

Answer:

C(x) = $40 + 0.9x

F(t) = 7.25t - 5

Step-by-step explanation:

Given that :

C(x) = Cost model to produce x toys

Fixed cost of production = $40

Rate of change = 90 cent per toy produced.

A linear model will take the form :

F(x) = bx + c ;

Where ; b = rate of change or slope ; c = intercept or initial value

Therefore, a linear cost model will be :

Cost model to produce x toys = fixed cost + (rate of change * number of toys)

C(x) = $40 + 0.9x

2.)

F(t) = amount of usable factory sheets manufactured in t minutes :

Rate of production = 7.25 ft² / minute

Number of unusable fabric sheeting = 5 ft²

The function, F(t) :

F(t) = 7.25t - 5


Which point is the center of the circle?
w
Opoint w
O point X
o point Y
O point Z

Answers

Answer:

X o punto Y O punto z

Step-by-step explanation:

find from first principle the derivative of 3x+5/√x​

Answers

Answer:

[tex]\displaystyle \frac{d}{dx} = \frac{3x - 5}{2x^\bigg{\frac{3}{2}}}[/tex]

General Formulas and Concepts:

Algebra I

Exponential Rule [Powering]:                                                                          [tex]\displaystyle (b^m)^n = b^{m \cdot n}[/tex]Exponential Rule [Rewrite]:                                                                              [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex] Exponential Rule [Root Rewrite]:                                                                     [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]:                                                            [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                               [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \frac{3x + 5}{\sqrt{x}}[/tex]

Step 2: Differentiate

Rewrite [Exponential Rule - Root Rewrite]:                                                     [tex]\displaystyle \frac{3x + 5}{x^\bigg{\frac{1}{2}}}[/tex]Quotient Rule:                                                                                                   [tex]\displaystyle \frac{d}{dx} = \frac{(x^\bigg{\frac{1}{2}})\frac{d}{dx}[3x + 5] - \frac{d}{dx}[x^\bigg{\frac{1}{2}}](3x + 5)}{(x^\bigg{\frac{1}{2}})^2}[/tex]Simplify [Exponential Rule - Powering]:                                                          [tex]\displaystyle \frac{d}{dx} = \frac{(x^\bigg{\frac{1}{2}})\frac{d}{dx}[3x + 5] - \frac{d}{dx}[x^\bigg{\frac{1}{2}}](3x + 5)}{x}[/tex]Basic Power Rule [Derivative Property - Addition/Subtraction]:                   [tex]\displaystyle \frac{d}{dx} = \frac{(x^\bigg{\frac{1}{2}})(3x^{1 - 1} + 0) - (\frac{1}{2}x^\bigg{\frac{1}{2} - 1})(3x + 5)}{x}[/tex]Simplify:                                                                                                             [tex]\displaystyle \frac{d}{dx} = \frac{3x^\bigg{\frac{1}{2}} - (\frac{1}{2}x^\bigg{\frac{-1}{2}})(3x + 5)}{x}[/tex]Rewrite [Exponential Rule - Rewrite]:                                                              [tex]\displaystyle \frac{d}{dx} = \frac{3x^\bigg{\frac{1}{2}} - (\frac{1}{2x^{\frac{1}{2}}})(3x + 5)}{x}[/tex]Rewrite [Exponential Rule - Root Rewrite]:                                                     [tex]\displaystyle \frac{d}{dx} = \frac{3\sqrt{x} - (\frac{1}{2\sqrt{x}})(3x + 5)}{x}[/tex]Simplify [Rationalize]:                                                                                       [tex]\displaystyle \frac{d}{dx} = \frac{3x - 5}{2x^\bigg{\frac{3}{2}}}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

The cost of renting a car is $46/week plus $0.25/mile traveled during that week. An equation to represent the cost would be y = 46 + 0.25x, where x is the number of miles traveled.

what is your cost if you travel 59 miles
cost: 60.75

if your cost Is $66.00, how many miles were you charged for traveling?

miles: ?


you have a max of $100 to spend on a car rental. what would be the maximum number of miles you could Travel?

max miles: ?​

Answers

Answer:

If your cost Is $66.00, how many miles were you charged for traveling?

y = cost = $66

[tex]66=46+0.25x\\66-46=0.25x\\20=0.25x\\x=\frac{20}{0.25} =80[/tex]80 miles

You have a max of $100 to spend on a car rental. what would be the maximum number of miles you could Travel?

y = cost = $100

[tex]100=46+0.25x\\100-46=0.25x\\54=0.25x\\x=\frac{54}{0.25} =216[/tex]216 miles

You have been doing research for your statistics class on the prevalence of severe binge drinking among teens. You have decided to use 2011 Monitoring the Future (MTF) data that have a scale (from 0 to 14) measuring the number of times teens drank 10 or more alcoholic beverages in a single sitting in the past 2 weeks.
a. According to 2011 MTF data, the average severe binge drinking score, for this sample of 914 teens, is 1.27, with a standard deviation of 0.80. Construct the 95% confidence interval for the true averse severe binge drinking score.
b. On of your classmates, who claims to be good at statistics, complains about your confidence interval calculation. She or he asserts that the severe binge drinking scores are not normally distributed, which in turn makes the confidence interval calculation meaningless. Assume that she or he is correct about the distribution of severe binge drinking scores. Does that imply that the calculation of a confidence interval is not appropriate? Why or why not?

Answers

Answer:

(1.218 ; 1.322)

the confidence interval is appropriate

Step-by-step explanation:

The confidence interval :

Mean ± margin of error

Sample mean = 1.27

Sample standard deviation, s = 0.80

Sample size, n = 914

Since we are using tbe sample standard deviation, we use the T table ;

Margin of Error = Tcritical * s/√n

Tcritical at 95% ; df = 914 - 1 = 913

Tcritical(0.05, 913) = 1.96

Margin of Error = 1.96 * 0.80/√914 = 0.05186

Mean ± margin of error

1.27 ± 0.05186

Lower boundary = 1.27 - 0.05186 = 1.218

Upper boundary = 1.27 + 0.05186 = 1.322

(1.218 ; 1.322)

According to the central limit theorem, sample means will approach a normal distribution as the sample size increases. Hence, the confidence interval is valid, the sample size of 914 gave a critical value at 0.05 which is only marginally different from that will obtained using a normal distribution table. Hence, the confidence interval is appropriate

Other Questions
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