In this equilibrium, the chemical system will shift to the right in order to produce more NH₃.
The equilibrium constant of a reaction is defined as:
"The ratio between equilibrium concentrations of products powered to their reaction quotient and equilibrium concentration of reactants powered to thier reaction quotient".
The reaction quotient, Q, has the same algebraic expressions but use the actual concentrations of reactants.
To solve this question we need this additional information:
For this reaction, K = 6.0x10⁻² and the initial concentrations of the reactants are:
[N₂] = 4.0M; [NH₃] = 1.0x10⁻⁴M and [H₂] = 1.0x10⁻²M
Thus, for the reaction:
N₂ + 3H₂ ⇄ 2NH₃
The equilibrium constant, K, of this reaction, is defined as:
[tex]K = \frac{[NH_3]^2}{[H_2]^3[N_2]}[/tex]
Where [] are concentrations in equilibrium.
And Q, is:
[tex]Q = \frac{[NH_3]^2}{[H_2]^3[N_2]}[/tex]
Where actual concentrations are:
[NH₃] = 1.0x10⁻⁴M
[N₂] = 4.0M
[H₂] = 2.5x10⁻¹M
Replacing:
Q = 1.6x10⁻⁷
As Q < K,
The chemical system will shift to the right in order to produce more NH₃
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Categorize the following reaction as an acid-base neutralization, precipitation, combination, decomposition, combustion, displacement, or disproportionation reaction.
Ba(C2H3O2)2(aq) + Na2CO3(aq) → BaCO3(s) + 2 NaC2H3O2(aq)
Answer:
Precipitation
Explanation:
Let's consider the balanced chemical equation between barium acetate and sodium carbonate to form barium carbonate and sodium acetate.
Ba(C₂H₃O₂)₂(aq) + Na₂CO₃(aq) → BaCO₃(s) + 2 NaC₂H₃O₂(aq)
Both products and reactants are salts. But, among the products, barium carbonate is solid. This allows us to classify it as a precipitation reaction.
NEED HELP ASAP!!!! PLEASE DONT COMMENT IF YOU DONT KNOW. I WIILL REPORT YOU.
Answer:
is C the Ch because is look 99% the answer pls don't report if I'm wrong it took me a long time to answer it
Water put into a freezer compartment in the same refrigerator goes into a state of less molecular disorder when it freezes. Is this an exception to the entropy principle
Answer:
No it is not an exception to this principle
Explanation:
Work was carried out by this compressor to reduce the entropy of ice. What this means is that the ice gave out heat which is as a result of the work that the compressor was putting in. there are violations of this principle
the entropy principle has that the entropy of the universe is always going to be more than 0 (system + surrounding). in this question, the that of the system is negative while that of the surrounding is positive. As the refrigerator was cooling the water, the air outside was getting heated. Outside this refrigerator, the gain in entropy is more than the entropy that was lost in the water.
the entropy of the universe once again is more than 0.
Explain how the existence of isotopes relates to the number of neutrons within the nuclei of an element.
Answer:
because of it less attraction and its neutral position
Answer:
The existence of isotopes relates to the number of neutrons within the nuclei of an element because isotopes contain the same amount of protons (based on what element they are) but different number of neutrons in their nuclei. Because they have a different amount of neutrons, than the original element
,they also have a different atomic mass.
Explanation:
hope it helps!
I place 3 moles of N2 and 4 moles of O2 in a 35 L container at ta temperature of 25 degree Celsius, what will the pressure (in atm) of the resulting mixture of gases be?
Answer:
The pressure of the resulting mixture of gases will be 4.89 atm.
Explanation:
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P*V = n*R*T
where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances. The numerical value of R will depend on the units in which the other properties are worked.
In this case:
P= ?V= 35 Ln= 3 moles of N₂ + 4 moles of O₂= 7 molesR= 0.082 [tex]\frac{atm*L}{mol*K}[/tex]T= 25 C= 298 K (being 0 C= 273 K)Replacing:
P* 35 L= 7 moles* 0.082 [tex]\frac{atm*L}{mol*K}[/tex] * 298 K
Solving:
[tex]P=\frac{ 7 moles* 0.082 \frac{atm*L}{mol*K} * 298 K}{35 L}[/tex]
P= 4.89 atm
The pressure of the resulting mixture of gases will be 4.89 atm.
The pressure (in atm) of the resulting mixture of the gases is 4.89 atm
From the question given above, the following data were obtained:
Mole of N₂ = 3 moles
Mole of O₂ = 4 moles
Total mole = 3 + 4 = 7 moles
Volume (V) = 35 L
Temperature (T) = 25 °C = 25 + 273 = 298 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure of mixture (P) =?The pressure of the resulting mixture of the gases can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
P × 35 = 7 × 0.0821 × 298
P × 35 = 171.2606
Divide both side by 35
P = 171.2606 / 35
P = 4.89 atmTherefore, the pressure of the resulting mixture of the gases 4.89 atm
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In Mexico, avocados are 39 pesos per kilogram. What is the cost in pesos of an
avocado that weighs 0.25 lb?
1kg = 2.201b
Answer:
The correct answer is - 4.5 pesos.
Explanation:
Given:
rate of per kg = 39 pesos
price for 0.25 lb = ?
Solution:
we know and given that,
1 kg = 2.20 lb
1 lb = 1000gm/2.20
then, the price for 0.25 lb would be:
=> (39/2.20)*0.25
= 4.4318 or 4.5 pesos
If 16 grams of O2 react with excess C2H6, how many grams of CO2 will be formed? The formula mass of O2 = 32 amu and the formula mass of CO2 = 44amu. The balanced chemical equation is 2 C2H6(g) + 7 O2(g) → 4 CO2(g) + 6 H2O(g)
Answer:5.17g of Co2
Explanation:
To conduct the synthesis of iodosalicylamide, Edward used 1.07 g of salicylamide (MW: 137.14 g/mol) and 1.68 g of sodium iodide (MW:149.89 g/mol). Assuming the reaction yield is 100%, how many grams of iodosalicylamide (MW:263.03 g/mol) would be formed
Answer:
2.05 g
Explanation:
Number of moles of salicylamide = 1.07g/137.14 g/mol = 0.0078 moles
Number of moles of NaI = 1.68 g/149.89 g/mol = 0.011 moles
Since the reaction is in a ratio of 1:1, salicylamide is the limiting reactant and 0.0078 moles of iodosalicylamide is formed.
Hence, theoretical yield of iodosalicylamide = 0.0078 moles × 263.03 g/mol = 2.05 g
Since there is 100% yield, actual yield = theoretical yield = 2.05 g
Flag A solution of the weak acid, HF, and a solution of the strong acid, HCl, have the same pH. Which solution will require the most sodium hydroxide, NaOH, to neutralize
Answer:
C) Both will require the same amount because the concentrations are equal.
Explanation:
The pH of a solution is defined as:
pH = -log [H+]
This H+ is the ion that reacts with OH- (From NaOH) as follows:
H+ + OH- → H2O
When all H+ reacts, we can say the solution was neutralized.
Now, as both, the solution with the weak acid and the solution with strong acid have the same pH, we can say that their [H+] is the same. Assuming the volume of both solutions is the same:
Both will require the same amount because the concentrations are equal.
Approximately how much energy (in kJ) would be released during the formation of the bonds in 2.00 mol of acetone molecules
Answer:
7822 kJ
Explanation:
The formula for acetone is: CH3COCH3
From the standard bond energy(enthalpy):
C - H bond = 412
C - C bond = 348
C = O bond = 743
From the structure of an acetone
C is bonded to H in six places;
so, for C- H bond = 6 × 412 = 2472
C is only bonded to two other carbon atoms
For C - C bond = 2 × 348 = 696
Carbon is only doubly bonded to an oxygen atom
For C = O bond = 1 × 743 = 743
∴
The total net energy bond in a mole = (2472 + 696 + 743) kJ/mol
= 3911 kJ/mol
Finally, in 2 moles of acetone, the required amount of energy will be:
= 3911 kJ/moles × 2 moles
= 7822 kJ
why beta carbon hydrogen is easily replaced
Answer:
γ−Hydrogen is easily replacable during bromination reaction in presence of light , because Allylic substitution is being preferred.
Explanation:
that's all
γ−Hydrogen is easily replacable during bromination reaction in presence of light , because Allylic substitution is being preferred.
Consider the reaction: CaCO3(s)CaO(s) CO2(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.58 moles of CaCO3(s) react at standard conditions.
Answer:
the entropy change for the system when 1.58 moles of CaCO3(s) react at standard conditions is 253.748 J/K
Explanation:
Given the data in the question;
CaCO₃(s) → CaO(s) + CO₂(g)
1.58 moles 1.58 moles 1.58 moles
Since 1 mole of CaCO₃ gives 1 mole of CaO and 1 mole of CO₂
Thus, 1.58 mole of CaCO₃ gives 1.58 moles of CaO and 1.58 moles of CO₂.
Now,
At 298 K, standard entropy values are;
ΔS° ( CaCO₃ ) = 92.9 J/mol.K
ΔS° ( CaO ) = 39.8 J/mol.K
ΔS° ( CO₂ ) = 213.7 J/mol.K
So,
ΔS°[tex]_{system[/tex] = ∑ΔS°( product ) - ∑ΔS°( reactant )
ΔS°[tex]_{system[/tex] = [ ΔS°(CaO) + ΔS°( CO₂ ) ] - ΔS°( CaCO₃ )
we substitute
ΔS°[tex]_{system[/tex] = [ 39.8 J/mol.K + 213.7 J/mol.K ] - 92.9 J/mol.K
ΔS°[tex]_{system[/tex] = 160.6 J/mol.K
i.e, for 1 mol CaCO₃, ΔS°[tex]_{system[/tex] = 160.6 J/mol.K
Now, for 1.58 mol CaCO₃,
ΔS°[tex]_{system[/tex] = 1.58 mol × 160.6 J/mol.K
ΔS°[tex]_{system[/tex] = 253.748 J/K
Therefore, the entropy change for the system when 1.58 moles of CaCO3(s) react at standard conditions is 253.748 J/K
Please help me I am so loss
Answer:
19.25g of C4H10
Explanation:
2C4H10
2×12×4+2×1×10
=116g
8CO2
=8×12+8×16×2
=352 g
116g of C4H10 produces 352 g of CO2
So, x g of C4H10 produces 58.4g of CO2
(cross multiply)
352 x=116×58.4
x=116×58.4÷352
x=19.25g of C4H10
Answer:
19.25g of C4H10
2C4H10
2×12×4+2×1×10
=116g
8CO2
=8×12+8×16×2
=352 g
116g of C4H10 produces 352 g of CO2
So, t g of C4H10 produces 58.4g of CO2
(cross multiply)
352 t=116×58.4
t=116×58.4÷352
t=19.25g of C4H10
Explanation:
Hazmat products warnings or labels allowed in fc
Answer:
The Hazmat products warnings or labels allowed in fc include:
1. Fully Regulated Aerosol Placard
2. Fully Regulated Flammable Solid Placard
3. Fully Regulated Flammable
4. Lithium-Ion/Metal Battery label
Explanation:
Hazmat products (including explosives, flammable liquids and solids, and gases, etc.) are classified as dangerous substances and materials that pose a risk to people during their storage, handling, or transportation. The requirement for this Hazmat classification is to show that the identified products require diligence, carefulness, and alertness in handling, transporting, and storing them. The reason for this is that mishaps can occur. Some of them can also cause fire outbreaks.
What is the pH of a solution prepared by mixing 100.00 mL of 0.020 M Ca(OH)2 with 50.00 mL of 0.100 M NaOH? Assume that the volumes are additive?a. 12.78.b. 13.25.c. 12.67.d. 12.95.
Answer:
The pH of the solution is 12.78.
Explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution. The pOH is defined as the negative logarithm of the activity of the hydroxide ions. That is, the concentration of OH- ions:
pOH= - log [OH-]
On the other side, Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume. Molarity is calculated as:
[tex]Molarity= \frac{number of moles}{volume}[/tex]
Molarity is expressed in units: [tex]\frac{moles}{liter}[/tex]
In this case, the solution is prepared by mixing 100 ml (equal to 0.1 L, where 1000 mL = 1 L) of Ca(OH)₂ 0.020 M with 50 ml (equal to 0.05 L) of 0.100 M NaOH. Then, Ca(OH)₂ and NaOH are strong bases, so they dissociate completely. In the case of the first hydroxide, for each mole of Ca(OH)₂,
form two moles of OH-. In the case of sodium hydroxide, for each mole of hydroxide, one mole of OH- is formed. So, taking into account the definition of molarity, the number of moles of OH- that each hydroxide contributes to the solution is calculated as:
From Ca(OH)₂: 0.1 L* 0.02 M*2 = 0.004 moles
From NaOH: 0.05 L* 0.1 M= 0.005 moles
So, the amount of total moles of OH- is the sum that each hydroxide contributes to the solution: 0.004 moles + 0.005 moles= 0.009 moles
On the other hand, volumes are additive. Then: 0.1 L + 0.05 L= 0.15 L
Replacing in the definition of molarity the number of moles and the volume:
[tex][OH-]=\frac{0.009 moles}{0.15 L}[/tex]
Solving:
[OH-]= 0.06 [tex]\frac{moles}{liter}[/tex]
Replacing in the definition of pOH:
pOH= - log 0.06
pOH= 1.22
The following relationship can be established between pH and pOH:
pH + pOH= 14
Being pOH= 1.22 and replacing:
pH + 1.22= 14
pH= 14 - 1.22
pH= 12.78
The pH of the solution is 12.78.
The substitution reaction of toluene with Br2 can, in principle, lead to the formation of three isomeric bromotoluene products. In practice, however, only o- and p-bromotoluene are formed in substantial amounts. The meta isomer is not formed. Draw the structures of the three possible carbocation intermediates, and explain why ortho and para products predominate over meta products.
Answer:
See explanation and image attached
Explanation:
Aromatic hydrocarbons undergo electrophillic substitution. Usually, substituted benzene is more or less reactive to electrophillic substitution compared to unsubstituted benzene.
Substituents on the benzene ring tend to direct the incoming electrophile during electrophillic substititution. The presence of the -CH3 group on toluene directs the incoming Br electrophile to the ortho/para position.
Where the incoming electrphile E is Bromine, we can see that in the ortho/ para product, the electron pushing -CH3 stabilizes the resonance structure formed and increases electron density at the ortho/para position via resonance compared to the meta product as we can see from the image attached. Hence, the ortho and para products predominate over meta products.
Image credit: Chemistry steps
Please help me order these bonds urgent
Answer:
From least polar covalent to most polar covalent;
S-I< Br-Cl < N-H< Te-O
From most ionic to least ionic
Cs-F> Sr-Cl> Li- N> Al-O
Explanation:
Electro negativity refers to the ability of an atom in a bond to attract the shared electrons of the bond towards itself.
Electro negativity difference between two atoms is a key player in the nature of bond that exists between any two atoms. A large difference in electron negativity leads to an ionic bond while an intermediate difference in electro negativity leads to a polar covalent bond.
Based on electro negativity differences, the bonds in the answer have been arranged in order of increasing polar covalent nature or decreasing ionic nature.
What is the fourth quantum number of the 3p electron in aluminum,
1s^2 2s^2 2p^6 3s^2 3p^1?
A. ms = -1
B. ms = +1/2
C. ms=0
D. ms = +1
Explanation:
here's the answer to your question
The quantum numbers are defined as the set of four numbers with the help of which we can get complete information about the electrons in an atom. The fourth quantum number is the spin quantum number. Here ms for 3p electron in 'Al' is ms = + 1/2. The correct option is B.
The quantum number which describes the spin orientation of the electron is defined as the spin quantum number. Since the electron can spin only in two ways, clockwise and anti-clockwise, the spin quantum number can have either the value +1/2 or -1/2 depending upon the direction of spin.
Thus for 3p electron in 'Al' ,ms is option B.
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When CH3NO2 burns in excess oxygen, it forms carbon dioxide, nitrogen dioxide and water. How many moles of oxygen are required to burn 17.10 mole(s) of CH3NO2
Explanation:
The given reaction is the combustion of CH3NO2.
The balanced chemical equation of the reaction is:
[tex]4CH_3NO_2+ 7O_2 ->4 CO_2+4NO_2+6H_2O[/tex]
So, from the balanced chemical equation, it is clear that:
4 moles of CH3NO2 --- 7 moles of oxygen gas is required.
then,
for 17.10 moles of CH3NO2 the following number of moles of oxygen is required.
[tex]The number of moles of O_2 required=17.10 mol. x \frac{7 mol}{4 mol} \\=29.925 mol[/tex]
Answer is :
29.9 mol of oxygen gas is required.
Name the functional group in the
following molecule:
Answer:
B. Aromatic
Explanation:
Functional groups are groups that differentiate a specific organic compound from others. A functional group determines the chemical property of the compound that possesses it.
For example, just like alkene and alcohol functional groups have characteristics double bond (=) and hydroxyl (OH) group respectively, the image in the attachment of this question has a BENZENE RING at the core of its structure, hence, the organic compound can be regarded to have an AROMATIC FUNCTIONAL GROUP.
Answer:
(B) aromatic
Explanation:
A step by step explanation
In a first order reaction 40% of reactant gets converted into product in 30 minutes. What time would it require to convert 75% into product?
In a first order reaction 40% of reactant gets converted into product in 30 minutes. The time would it require to convert 75% into product is 81.57 minutes.
What is first order reaction?First order reaction is defined as a chemical reaction in which the concentration of just one ingredient directly affects the pace of the reaction. If the first-order reactant concentration is doubled in these reactions, the reaction rate will likewise double. Chemical reactions classified as first order kinetics have rates of reaction that depend on the molar concentration of one component.
First order reaction = 2.303 / t log a / (a-x)
k = 2.303 / 30 log 100 (100 - 40)
k = 0.0767 log 1.66
k = 0.017 min⁻¹
The time required to convert 75 % product
t = 2.303 / 0.017 log 100 (100 - 75)
t = 135.5 log 4
t = 135.5 x 0.602
t = 81.57 minutes
Thus, in a first order reaction 40% of reactant gets converted into product in 30 minutes. The time would it require to convert 75% into product is 81.57 minutes.
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Hydrogen cyanide gas can be made by a two stepprocess. First, ammonia is reacted with oxygen gas to give nitrogen monoxide and water vapor. In the next step, nitrogen monoxide is reacted with methane (CH4) to give hydrogen cyanide gas. The by-products are water and hydrogen gas. A) Write the balanced equation for the two reactions.
B) When 24.2 g of ammonia and 25.1 g of methane are used, how many grams of hydrogen cyanide can be produced?
Answer:
38.34 g of HCN are produced
Explanation:
Our reactants for the first reaction are:
NH₃ and O₂
Products are: H₂O and NO
Our reactants for the second reaction are:
NO and CH₄
Producs are: H₂, H₂O and HCN
The reactions are:
4NH₃ and 5O₂ → 6H₂O + 4NO
2NO and 2CH₄ → 2HCN + H₂ + 2H₂O
In the first step 4 moles of ammonia can produce 4 moles of NO, so ratio is 1:1
24.2 g . 1mol / 17 g = 1.42 moles of ammonia
We have produced 1.42 moles of NO.
25.1 g . 1 mol / 16 g = 1.57 moles of methane.
Ratio is 2:2. So, for 1.57 moles of methane, we need 1.57 moles of NO.
Moles are the same. As there is no enough NO, this is the limiting reactant.
Ratio with product is also 2:2.
Our 1.42 moles of NO have produced 1.42 moles of HCN.
We convert moles to mass: 1.42 mol . 27 g/mol = 38.34 g
The burning of paper is an example of which type of change?
A. An atomic change
B. A chemical change
C. A physical change
D. A phase change
Answer: B. A chemical Change
Explanation:
The Burning of paper changes the paper into a new substance (ash). So the ashes cannot be reversed into paper, therefore it is a chemical change.
Determine the molecular formula of a compound if it is composed of 40.92% carbon, 4.58% hydrogen, and 54.50% oxygen. The molar mass is 176.12 g/mol.
A) C3H8O3.
B) CH2O.
C) C2H3O2.
D) C3H4O3.
Answer:
No correct answer listed. See explanation for defense.
Explanation:
Given
C: 40.92% => 40.92g/100wt => (40.92/12)moles C = 3.41 moles O
H: 4.58% => 4.58g/100wt => (4.58/1)moles H = 4.58 moles H
O: 54.50% => 54.5g/100wt => (54.5/16)moles O = 3.41 moles O
Empirical ratio => C : H: O => (3.41/3.41) : (4.58/3.41) : (3.41/3.41) => 1 : 1.34 : 1
=> C : H : O => 3(1 : 1.34 : 1) => 3 : 4 : 3 => Empirical Formula C₃H₄O₃
Molecular Weight = Empirical Formula Wt x N
176.12 = 88 x N
N = whole number multiple of empirical formula = 176.12/88 = 2
∴ Molecular Formula => (C₃H₄O₃)₂ => C₆H₈O₆
Note => Only ionic compounds (salts) have subscripts reduced to lowest whole number ratios. Molecular compounds as C₆H₈O₆ are not reduced to lowest whole number ratios. Therefore, there is no correct answer in the answer choice list for the 'Molecular Formula'. Doc :-)
The article source and supplementary information compare p-toluenesulfonic acid and Amberlyst-15 as catalysts that can be used to synthesis Methyl Diantilis. In a paragraph please summarize and explain the differences between these two catalysts. This summary should include both differences of chemical principles and laboratory practicality.
Answer:
Following are the solution to these questions:
Explanation:
P-toluene sulfonic acid variations between Amberlyst-15
Acid p-Toluenesulfonic (PTSA)
Organic acid SimpleAquaPTSA will be removed after a reaction from a difficult workflowHard to recycleEnvironmental pollution conditionsComposite single unitToxicAmberlyst 15
Acid PolymerSolidComfortably separated by simple filtration after the reaction.Easily recycle and reuseNot environmentally damagingion exchange resin based on polystyrene.NontoxicP-toluene and Amberlyst-15 do have the same catalytic effect in the reaction as the mechanism is defined in the attached file. The Amberlyst 15 is always considered as best, given the better future for Amberlyst 15.
the -OH group cannot exhibit inductive effect? true/false, and reason for ur choice
Answer:
false
Explanation:
The inductive effects are know as the ability of the atom or a group to create polarization and electronic density long the covalent bond and it needs a higher density. The -OH group cannot exhibit the indictive effects as it becomes --O.what are the functional group
present in ch3cooh and C2h5oh
what are the angles a and b in the actual molecule of which this is a lewis structure note for advanced students give the ideal angles and don t worry about small differences from the ideal that might be caused by the fact that different electron groups may have slightly different sizes
Answer:
The answer is "120 C and 109.5 C".
Explanation:
The carbon atom is hybridized by sp2. This angle of connection thus is 120 degrees. Alkene, specifically both carbons which are in the C=C, are an instance of carbon with sp2 hybridized atom's nucleus. Those three hybridized orbits were linked to certain other atoms forming sigma connections. Its remaining 2p orbital makes a pi link with 2p orbit by the side-overlap of all the other carbon. O is hybridized inside the [-OH] Group. The optimal bond angle therefore is [tex]109.5^{\circ}[/tex].
[tex]a= 120 \ C\\\\b= 109.5 \ C[/tex]
Caffeine is a bitter stimulant drug and is found in varying quantities in seeds, leaves, and so on.
a. True
b. False
Answer:
The answer Is B.....False
For the reaction of oxygen and nitrogen to form nitric oxide, consider the following thermodynamic data :
ΔH∘rxn 180.5kJ/mol
ΔS∘rxn 24.80J/(mol⋅K)
Required:
a. Calculate the temperature in kelvins above which this reaction is spontaneous
b. Calculate the equilibrium constant for the following reaction at room temperature, 25°C
Answer:
a. 7278 K
b. Kc = 4.542 × 10⁻³¹
Explanation:
a.
The reaction is spontaneous when ΔG° < 0. We can calculate ΔG° using the following expression.
ΔG° = ΔH° - T × ΔS°
Then, the reaction will be spontaneous when,
ΔH° - T × ΔS° < 0
T > ΔH°/ΔS
T > (180.5 × 10³ J/mol)/(24.80J/mol⋅K)
T > 7278 K
b.
First, we will calculate ΔG° at 25 °C (298 K)
ΔG° = ΔH° - T × ΔS°
ΔG° = (180.5 × 10³ J/mol) - 298 K × (24.80J/mol⋅K) = 1.731 × 10⁵ J/mol
Then, we will calculate the equilibrium constant (Kc) using the following expression.
ΔG° = - R × T × ln Kc
-ΔG°/R × T = ln Kc
-(1.731 × 10⁵ J/mol)/(8.314 J/mol.K) × 298 K = ln Kc
Kc = 4.542 × 10⁻³¹
