Answer:
a y = 2
b.y = 14
c. y =56
Step-by-step explanation:
a .6 (1)- 4=2
y=2
b. 6 (3)- 4
=18-4
y=14
c. 6 (10) - 4
= 60 - 4 =56
(a) Use appropriate algebra and Theorem to find the given inverse Laplace transform. (Write your answer as a function of t.)
L−1 {3s − 10/ s2 + 25}
(b) Use the Laplace transform to solve the given initial-value problem.
y' + 3y = e6t, y(0) = 2
(a) Expand the given expression as
[tex]\dfrac{3s-10}{s^2+25}=3\cdot\dfrac s{s^2+25}-2\cdot\dfrac5{s^2+25}[/tex]
You should recognize the Laplace transform of sine and cosine:
[tex]L[\cos(at)]=\dfrac s{s^2+a^2}[/tex]
[tex]L[\sin(at)]=\dfrac a{s^2+a^2}[/tex]
So we have
[tex]L^{-1}\left[\dfrac{3s-10}{s^2+25}\right]=3\cos(5t)-2\sin(5t)[/tex]
(b) Take the Laplace transform of both sides:
[tex]y'(t)+3y(t)=e^{6t}\implies (sY(s)-y(0))+3Y(s)=\dfrac1{s-6}[/tex]
Solve for [tex]Y(s)[/tex]:
[tex](s+3)Y(s)-2=\dfrac1{s-6}\implies Y(s)=\dfrac{2s-11}{(s-6)(s+3)}[/tex]
Decompose the right side into partial fractions:
[tex]\dfrac{2s-11}{(s-6)(s+3)}=\dfrac{\theta_1}{s-6}+\dfrac{\theta_2}{s+3}[/tex]
[tex]2s-11=\theta_1(s+3)+\theta_2(s-6)[/tex]
[tex]2s-11=(\theta_1+\theta_2)s+(3\theta_1-6\theta_2)[/tex]
[tex]\begin{cases}\theta_1+\theta_2=2\\3\theta_1-6\theta_2=-11\end{cases}\implies\theta_1=\dfrac19,\theta_2=\dfrac{17}9[/tex]
So we have
[tex]Y(s)=\dfrac19\cdot\dfrac1{s-6}+\dfrac{17}9\cdot\dfrac1{s+3}[/tex]
and taking the inverse transforms of both sides gives
[tex]y(t)=\dfrac19e^{6t}+\dfrac{17}9e^{-3t}[/tex]
Round 1, 165.492 to the nearest hundredth.
Answer:
1, 165.500
Step-by-step explanation:
1, 165.492 rounded to the nearest hundredth is 1, 165.500 because the hundredth space in the decimal is 5 or above, so the whole decimal gets rounded to the nearest hundred, which in this case, would be .500.
165.492 is the correct answer
c. What is f (-5)?
When the function is f(x) =-3x+7
Answer:
f(-5) = 22
Step-by-step explanation:
f(x) =-3x+7
Let x = -5
f(-5) =-3*-5+7
= 15 +7
=22
Write each expression in a simpler form that is equivalent to the given expression. Let g be a nonzero number. 1/g^1 or 1/g-1
Answer:
[tex]\boxed{\mathrm{view \: explanation}}[/tex]
Step-by-step explanation:
Apply rule : [tex]a^1 =a[/tex]
[tex]\displaystyle \frac{1}{g^1 } =\frac{1}{g}[/tex]
[tex]\displaystyle \frac{1}{g^{-1}}[/tex]
Apply rule : [tex]\displaystyle a^{-b}=\frac{1}{a^b}[/tex]
[tex]\displaystyle \frac{1}{\frac{1}{g^1 } }[/tex]
Apply rule : [tex]\displaystyle \frac{1}{\frac{1}{a} } =a[/tex]
[tex]\displaystyle \frac{1}{\frac{1}{g^1 } }=g[/tex]
Answer:
[tex]\frac{1}{g^1}[/tex]
= [tex]\frac{1}{g}[/tex]
[tex]\frac{1}{g - 1}[/tex]
= [tex]\frac{g^1}{1}[/tex]
= [tex]\frac{g}{1}[/tex]
= g
Hope this helps!
An amusement park is open 7 days a week. The park has 8 ticket booths, and each booth has a ticket seller from 10am to 6pm. On average, ticket sellers work 30 hours per week. Write and equation that can be used to find "t", the minimum number of ticket sellers the park needs. show work if possible.
Answer:
t = (448 hrs/ week) / (30 hrs / week)
Step-by-step explanation:
Number of times park opens in a week = 7
Number of ticket booth = 8
Opening hours = 10am - 6pm = 8 hours per day
Max working hours per ticket seller per week = 30 hours
Therefore each booth works for 8 hours per day,
Then ( 8 * 7) = 56 hours per week.
All 8 booths work for (56 * 8) = 448 hours per week
If Max working hours per ticket seller per week = 30 hours,
Then muninim number of workers required (t) :
Total working hours of all booth / maximum number of working hours per worker per week
t = (448 hrs/ week) / (30 hrs / week)
Perimeter =68 Length (L) is 4 less than twice the width (W)
Answer:
Length = 21.3333333333; Width: 12.6666666667
Step-by-step explanation:
Perimeter = 68
Perimeter of a rectangle:
2 (L +W)
Length (L) = 2W - 4
Width = W
2 ( 2W -4 +W) = 68
=> 2 (3W - 4) = 68
=> 6w -8 = 68
=> 6w = 76
=> w = 12.6666666667
Length = (12.6666666667 X 2) - 4
=> 21.3333333333
An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and its color is recorded.
a. Let B1 W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced before the second ball is drawn, the outcomes of the experiment are equally likely. List all 25 possible outcomes of the experiment.
b. Consider the event that the first ball that is drawn is blue. List all outcomes in the event. What is the probability of the event?
c. Consider the event that only white balls are drawn. List all outcomes in the event. What is the probability of the event?
Answer:
(a) Shown below.
(b) The probability that the first ball drawn is blue is 0.40.
(c) The probability that only white balls are drawn is 0.36.
Step-by-step explanation:
The balls in the urn are as follows:
Blue balls: B₁ and B₂
White balls: W₁, W₂ and W₃
It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.
(a)
The possible outcomes of selecting two balls are as follows:
B₁B₁ B₂B₁ W₁B₁ W₂B₁ W₃B₁
B₁B₂ B₂B₂ W₁B₂ W₂B₂ W₃B₂
B₁W₁ B₂W₁ W₁W₁ W₂W₁ W₃W₁
B₁W₂ B₂W₂ W₁W₂ W₂W₂ W₃W₂
B₁W₃ B₂W₃ W₁W₃ W₂W₃ W₃W₃
There are a total of N = 25 possible outcomes.
(b)
The sample space for selecting a blue ball first is:
S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}
n (S) = 10
Compute the probability that the first ball drawn is blue as follows:
[tex]P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40[/tex]
Thus, the probability that the first ball drawn is blue is 0.40.
(c)
The sample space for selecting only white balls is:
X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}
n (X) = 9
Compute the probability that only white balls are drawn as follows:
[tex]P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36[/tex]
Thus, the probability that only white balls are drawn is 0.36.
How many months does it take for $700 to double at simple interest of 14%?
• It will take
number.
months to double $700, at simple interest of 14%.
For this year's fundraiser, students at a certain school who sell at least 75 magazine subscriptions win a prize. If the fourth grade students at this school sell an average (arithmetic mean) of 47 subscriptions per student, the sales are normally distributed, and have a standard deviation of 14, then approximately what percent of the fourth grade students receive a prize
Answer:
The percentage is k = 2.3%
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 47[/tex]
The standard deviation is [tex]\sigma = 14[/tex]
Given that the sales are normally distributed and that students at a certain school who sell at least 75 magazine subscriptions win a prize then the percent of the fourth grade students receive a prize is mathematically represented as
[tex]P(X > 75) = P(\frac{X - \mu }{\sigma } > \frac{75 - \mu }{\sigma })[/tex]
Generally
[tex]\frac{X - \mu }{\sigma } = Z (The \ standardized \ value \ of \ X )[/tex]
So
[tex]P(X > 75) = P(Z > \frac{75 - 47 }{14 })[/tex]
[tex]P(X > 75) = P(Z > 2)[/tex]
From the standardized normal distribution table
[tex]P(Z > 2) =0.023[/tex]
=> [tex]P(X > 75) = 0.023[/tex]
The percentage of the fourth grade students receive a prize is
k = 0.023 * 100
k = 2.3%
Simplify 3 x times the fraction 1 over x to the power of negative 4 times x to the power of negative 3.
Answer:
3x^2
Step-by-step explanation:
3 x times the fraction 1 over x to the power of negative 4 => 3x * 1/x^-4
= 3x *x^4 = 3x^5
times x to the power of negative 3 => x^-3
3x^5 * x^-3 = 3x^2
Answer:
3x^2
Step-by-step explanation:
i got it right on the test on god!
Which expression is equivalent to 2(5)^4
Answer:
2·5·5·5·5
Step-by-step explanation:
2(5)^4 is equivalent to 2·5·5·5·5; 2 is used as a multiplicand just once, but 5 is used four times.
20,000 is 10 times as much as
Answer:
2000
Step-by-step explanation:
20,000 is 2000 times the number 10.
What is an expression?Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
Given numbers are 20000 and 10. The number 20000 is how many times the number 10 will be calculated by dividing the number 20000 by 10.
E = 20000 / 10 = 2000
Therefore, the number 20,000 is 2000 times the number 10.
To know more about an expression follow
https://brainly.com/question/20066515
#SPJ2
The function fix) = (x - 4)(x - 2) is shown.
What is the range of the function?
8
all real numbers less than or equal to 3
all real numbers less than or equal to -1
all real numbers greater than or equal to 3
all real numbers greater than or equal to - 1
6
2
16
2
14
COL
40
8
G D
Answer:
The range of the function f(x)= (x-4)(x-2) is all real numbers greater than or equal to -1
Step-by-step explanation:
Hello there are two questions in the link's if both were solved that would be awesome.
Answer:
[tex]\frac{x^{\frac{5}{6}} }{x^{\frac{1}{6}} } = x^{(\frac{5}{6} -\frac{1}{6}) }= x^{\frac{4}{6} }\\\sqrt{x} . \sqrt[4]{x} = x^{\frac{1}{2} } . x^{\frac{1}{4} } = x^{(\frac{1}{2} +\frac{1}{4}) } = x^{\frac{3}{4}[/tex]
There are 4 roads leading from Bluffton to Hardeeville, 10 roads leading from Hardeeville to Savannah, and 5 roads leading from Savannah to Macon. How many ways are there to get from Bluffton to Macon
Answer: 200 ways
Step-by-step explanation:
From the given information:
Total number of roads leading from Bluffton to Hardeeville = 4
Total number of roads leading from Hardeeville to Savannah = 10
Total number of roads leading from Savannah to Macon = 5
We need to find the total number of ways to get from Bluffton to Macon.
Total number of ways to get from Bluffton to Macon = 4 * 10 * 5
= 200
Therefore, there are 200 required number of ways to get from Bluffton to Macon.
How many ways can you arrange your 3 statistics books, 2 math books, and 1 computer science book on your bookshelf if (a) the books can be arranged in any order
Answer:
720 different ways.
Step-by-step explanation:
Permutation has to do with arrangement. For example, in order to arrange 'n' objects in any order, this can only be done in n! ways since there is no condition or restriction on how to arrange the objects.
n! = n(n-1)(n-2)... (n-r)!
If there are 3 statistics books, 2 math books, and 1 computer science book on your bookshelf, the total number of books altogether is 3 + 2 + 1 = 6 books.
The number of ways that 6 books can be arranged in any order is 6!.
6! = 6(6-1)(6-2)(6-3)(6-4)(6-5)
6! = 6*5*4*3*2*1
6! = 120*6
6!= 720 different ways.
Hence, the books on your shelf can be arranged in 720 different ways.
A machine fills boxes weighing Y lb with X lb of salt, where X and Y are normal with mean 100 lb and 5 lb and standard deviation 1 lb and 0.5 lb, respectively. What percent of filled boxes weighing between 104 lb and 106 lb are to be expected?
a. 67%
b. None
c. 37%
d. 57%
Answer:
Option b. None is the correct option.
The Answer is 63%
Step-by-step explanation:
To solve for this question, we would be using the z score formula
The formula for calculating a z-score is given as:
z = (x-μ)/σ,
where
x is the raw score
μ is the population mean
σ is the population standard deviation.
We have boxes X and Y. So we will be combining both boxes
Mean of X = 100 lb
Mean of Y = 5 lb
Total mean = 100 + 5 = 105lb
Standard deviation for X = 1 lb
Standard deviation for Y = 0.5 lb
Remember Variance = Standard deviation ²
Variance for X = 1lb² = 1
Variance for Y = 0.5² = 0.25
Total variance = 1 + 0.25 = 1.25
Total standard deviation = √Total variance
= √1.25
Solving our question, we were asked to find the percent of filled boxes weighing between 104 lb and 106 lb are to be expected. Hence,
For 104lb
z = (x-μ)/σ,
z = 104 - 105 / √25
z = -0.89443
Using z score table ,
P( x = z)
P ( x = 104) = P( z = -0.89443) = 0.18555
For 1061b
z = (x-μ)/σ,
z = 106 - 105 / √25
z = 0.89443
Using z score table ,
P( x = z)
P ( x = 106) = P( z = 0.89443) = 0.81445
P(104 ≤ Z ≤ 106) = 0.81445 - 0.18555
= 0.6289
Converting to percentage, we have :
0.6289 × 100 = 62.89%
Approximately = 63 %
Therefore, the percent of filled boxes weighing between 104 lb and 106 lb that are to be expected is 63%
Since there is no 63% in the option, the correct answer is Option b. None.
The percent of filled boxes weighing between 104 lb and 106 lb is to be expected will be 63%.
What is a normal distribution?It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.
The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.
A machine fills boxes weighing Y lb with X lb of salt, where X and Y are normal with a mean of 100 lb and 5 lb and standard deviation of 1 lb and 0.5 lb, respectively.
The percent of filled boxes weighing between 104 lb and 106 lb is to be expected will be
Then the Variance will be
[tex]Var = \sigma ^2[/tex]
Then for X, we have
[tex]Var (X) = 1^2 = 1[/tex]
Then for Y, we have
[tex]Var (Y) = 0.5^2 = 0.25[/tex]
Then the total variance will be
[tex]Total \ Var (X+Y) = 1 + 0.25 = 1.25[/tex]
The total standard deviation will be
[tex]\sigma _T = \sqrt{Var(X+Y)}\\\\\sigma _T = \sqrt{1.25}[/tex]
For 104 lb, then
[tex]z = \dfrac{104-105}{\sqrt{25}} = -0.89443\\\\P(x = 104) = 0.18555[/tex]
For 106 lb, then
[tex]z = \dfrac{106-105}{\sqrt{25}} = 0.89443\\\\P(x = 106) = 0.81445[/tex]
Then
[tex]P(104 \leq Z \leq 106) = 0.81445 - 0.18555 = 0.6289 \ or \ 62.89\%[/tex]
Approximately, 63%.
More about the normal distribution link is given below.
https://brainly.com/question/12421652
Solve for x² in x²-3x+2=0
[tex]x^2-3x+2=0\\x^2-x-2x+2=0\\x(x-1)-2(x-1)=0\\(x-2)(x-1)=0\\x=2 \vee x=1\\\\x^2=4 \vee x^2=1[/tex]
Answer:
Step-by-step explanation:
First we try to factor x²-3x+2.
We have to look for two numbers that multiply to 2 and add -3.
The two numbers are -1 and -2.
(x-1)(x-2) = 0
x-1 = 0 -> x = 1
x-2 = -> x = 2
Now we find x^2.
(1)^2 = 1
(2)^2 =4
Select the best answer for the question . 7. At a public swimming pool , the probability that an employee is a lifeguard is P(L) = 0.85 , and the probability that an employee is a teenager is P(T) = 0.58 . What's the probability that an employee is a lifeguard , given that the employee is a teenager ? O A. There isn't enough information given. O B. 1.47 OC. 0.68 O D.0.49
Answer:
D) 0.49
Step-by-step explanation:
0.85 * 0.58 = 0.49
The probability is:
D 0.49
Help I’m really bad at this
Answer:
72
Step-by-step explanation:
The formula for surface area is SA = 2lw + 2wh + 2lh
W = width
L= length
H = height
A = 2(wl + hl + hw)
2·(6·3+2·3+2·6)
Simplify that down to get the answer 72
A local statistician is interested in the proportion of high school students that drink coffee. Suppose that 20% of all high school students drink coffee.
What is the probability that out of these 75 people, 14 or more drink coffee?
Answer:
the probability that out of these 75 people, 14 or more drink coffee is 0.6133
Step-by-step explanation:
Given that:
sample size n = 75
proportion of high school students that drink coffee p = 20% = 0.20
The proportion of the students that did not drink coffee = 1 - p
Let X be the random variable that follows a normal distribution
X [tex]\sim[/tex] N (n, p)
X [tex]\sim[/tex] N (75, 0.20)
[tex]\mu = np[/tex] = 75 × 0.20
[tex]\mu =[/tex] 15
[tex]\sigma = \sqrt{p (1-p) n}[/tex]
[tex]\sigma = \sqrt{0.20(1-0.20) 75}[/tex]
[tex]\sigma = \sqrt{0.20*0.80* 75}[/tex]
[tex]\sigma = \sqrt{12}[/tex]
[tex]\sigma = 3.464[/tex]
Now ; if 14 or more people drank coffee ; then
[tex]P(X \geq 14) = P(\dfrac{X-\mu }{\sigma} \leq \dfrac{X-\mu}{\sigma})[/tex]
[tex]P(X \geq 14) =P(\dfrac{14-\mu }{\sigma} \leq \dfrac{14-15}{3.464})[/tex]
[tex]P(X \geq 14) = P(Z \leq \dfrac{-1}{3.464})[/tex]
[tex]P(X \geq 14) = P(Z \leq -0.28868)[/tex]
From the standard normal z tables; (-0.288)
[tex]P(X \geq 14) = P(Z \leq 0.38667)[/tex]
[tex]P(X \geq 14) = 1 - 0.38667[/tex]
[tex]P(X \geq 14) = 0.61333[/tex]
the probability that out of these 75 people, 14 or more drink coffee is 0.6133
Need Assistance
Please Show Work
Answer:
3 years
Step-by-step explanation:
Use the formula I = prt, where I is the interest money made, p is the starting amount of money, r is the interest rate as a decimal, and t is the time the money was borrowed.
Plug in the values and solve for t:
108 = (1200)(0.03)(t)
108 = 36t
3 = t
= 3 years
find the area of the figure pictured below. 3.8ft 8.3ft 7.4ft 3.9ft
The can be divided into two rectangles, one having length [tex]8.3[/tex] and width $3.8$
Another with, dimensions $7.4-3.8=3.6$ and $3.9$
Area of first rectangle=$3.8\times8.3=31.54$
Area of second rectangle =$3.6\times3.9=14.04$
Total area $=31.54+14.04=45.58$ ft²
Answer:
45.58 ft^2
Step-by-step explanation:
We can split the figure into two pieces
We have a tall rectangle that is 3.8 by 8.3
A = 3.8 * 8.3 =31.54 ft^2
We also have a small rectangle on the right
The dimensions are ( 7.4 - 3.8) by 3.9
A = 3.6*3.9 =14.04 ft^2
Add the areas together
31.54+14.04
45.58 ft^2
In a recent survey of drinking laws, a random sample of 1000 women showed that 65% were in favor of increasing the legal drinking age. In a random sample of 1000 men, 60% favored increasing the legal drinking age. Test the claim that the percentage of men and women favoring a higher legal drinking age is different at (alpha 0.05).
Answer:
Step-by-step explanation:
Given that:
Let sample size of women be [tex]n_1[/tex] = 1000
Let the proportion of the women be [tex]p_1[/tex] = 0.65
Let the sample size of the men be [tex]n_2[/tex] = 1000
Let the proportion of the mem be [tex]p_2[/tex] = 0.60
The null and the alternative hypothesis can be computed as follows:
[tex]H_0: p_1 = p_2[/tex]
[tex]H_0a: p_1 \neq p_2[/tex]
Thus from the alternative hypothesis we can realize that this is a two tailed test.
However, the pooled sample proportion p = [tex]\dfrac{p_1n_1+p_2n_2 } {n_1 +n_2}[/tex]
p =[tex]\dfrac{0.65 * 1000+0.60*1000 } {1000 +1000}[/tex]
p = [tex]\dfrac{650+600 } {2000}[/tex]
p = 0.625
The standard error of the test can be computed as follows:
[tex]SE = \sqrt{p(1-p) ( \dfrac{1} {n_1}+ \dfrac{1}{n_2} )}[/tex]
[tex]SE = \sqrt{0.625(1-0.625) ( \dfrac{1} {1000}+ \dfrac{1}{1000} )}[/tex]
[tex]SE = \sqrt{0.625(0.375) ( 0.001+0.001 )}[/tex]
[tex]SE = \sqrt{0.234375 (0.002)}[/tex]
[tex]SE = \sqrt{4.6875 * 10^{-4}}[/tex]
[tex]SE = 0.02165[/tex]
The test statistics is :
[tex]z =\dfrac{p_1-p_2}{S.E}[/tex]
[tex]z =\dfrac{0.65-0.60}{0.02165}[/tex]
[tex]z =\dfrac{0.05}{0.02165}[/tex]
[tex]z =2.31[/tex]
At level of significance of 0.05 the critical value for the z test will be in the region between - 1.96 and 1.96
Rejection region: To reject the null hypothesis if z < -1.96 or z > 1.96
Conclusion: Since the value of z is greater than 1.96, it lies in the region region. Therefore we reject the null hypothesis and we conclude that the percentage of men and women favoring a higher legal drinking age is different.
A bag contains five white balls and four black balls. Your goal is to draw two black balls. You draw two balls at random. Once you have drawn two balls, you put back any white balls, and redraw so that you again have two drawn balls. What is the probability that you now have two black balls? (Include the probability that you chose two black balls on the first draw.)
Answer:
Probabilty of both Black
= 1/6
Step-by-step explanation:
A bag contains five white balls and four black balls.
Total number of balls= 5+4
Total number of balls= 9
Probabilty of selecting a black ball first
= 4/9
Black ball remaining= 3
Total ball remaining= 8
Probabilty of selecting another black ball without replacement
= 3/8
Probabilty of both Black
=3/8 *4/9
Probabilty of both Black
= 12/72
Probabilty of both Black
= 1/6
Compute each matrix sum or product if it is defined. If an expression is undefined. Explain why. Let A = (3 4 0 -4 -1 4), B = (8 1 -4 -5 2 -4), C = (1 -1 3 1) and D = (3 -2 4 5).
- 2A, B - 2A, AC, CD
Compute the matrix product -2A.
A. -2A =
B. The expression-2A is undefined because A is not a square matrix.
C. The expression-2A is undefined because matrices cannot be multiplied by numbers.
D. The expression 2A is undefined because matrices cannot have negative coefficients.
Answer:
-2A = (-6, -8, 0, 8, 2, -8)
B - 2A = (2, -7, -4, 3, 4, -12)
AC is undefined.
CD = (3, 2, 12, 5)
Step-by-step explanation:
Given the matrices:
A = (3 4 0 -4 -1 4)
B = (8 1 -4 -5 2 -4)
C = (1 -1 3 1)
D = (3 -2 4 5)
We are required to compute the following
-2A, B - 2A, AC, CD
For -2A:
-2(3 4 0 -4 -1 4)
= (-6, -8, 0, 8, 2, -8)
For B - 2A:
Because B - 2A = B + (-2A), we have:
(8 1 -4 -5 2 -4) + (-6, -8, 0, 8, 2, -8)
(2, -7, -4, 3, 4, -12)
For AC:
(3 4 0 -4 -1 4)(1 -1 3 1)
This is undefined.
For CD:
(1 -1 3 1)(3 -2 4 5)
= (3, 2, 12, 5)
20 POINTS! You are planning to use a ceramic tile design in your new bathroom. The tiles are equilateral triangles. You decide to arrange the tiles in a hexagonal shape as shown. If the side of each tile measures 9 centimeters, what will be the exact area of each hexagonal shape?
Answer:
210.33 cm^2
Step-by-step explanation:
We know that 6 equilateral triangles makes one hexagon.
Also, an equilateral triangle has all its sides equal.
If the tile of each side of the triangular tile measure 9 cm, then the height of the triangular tiles can be gotten using Pythagoras's Theorem.
The triangle formed by each tile can be split along its height, into two right angle triangles with base (adjacent) 4.5 cm and slant side (hypotenuse) of 9 cm. The height (opposite) is calculated as,
From Pythagoras's theorem,
[tex]hyp^{2} = adj^{2} + opp^{2}[/tex]
substituting, we have
[tex]9^{2} = 4.5^{2} + opp^{2}[/tex]
81 = 20.25 + [tex]opp^{2}[/tex]
[tex]opp^{2}[/tex] = 81 - 20.25 = 60.75
opp = [tex]\sqrt{60.75}[/tex] = 7.79 cm this is the height of the right angle triangle, and also the height of the equilateral triangular tiles.
The area of a triangle = [tex]\frac{1}{2} bh[/tex]
where b is the base = 9 cm
h is the height = 7.79 cm
substituting, we have
area = [tex]\frac{1}{2}[/tex] x 9 x 7.79 = 35.055 cm^2
Area of the hexagon that will be formed = 6 x area of the triangular tiles
==> 6 x 35.055 cm^2 = 210.33 cm^2
A new soft drink is being market tested. A sample of 400 individuals participated in the taste test and 80 indicated they like the taste. At 95% confidence, test to determine if at least 22% of the population will like the new soft drink.
Required:
Determine the p-value.
Answer: p-value of the test = 0.167
Step-by-step explanation:
Given that,
sample size n = 400
sample success X = 80
confidence = 95%
significance level = 1 - (95/100) = 0.05
This is the left tailed test .
The null and alternative hypothesis is
H₀ : p = 0.22
Hₐ : p < 0.22
P = x/n = 80/400 = 0.2
Standard deviation of proportion α = √{ (p ( 1 - p ) / n }
α = √ { ( 0.22 ( 1 - 0.22 ) / 400 }
α = √ { 0.1716 / 400 }
α = √0.000429
α = 0.0207
Test statistic
z = (p - p₀) / α
z = ( 0.2 - 0.22 ) / 0.0207
z = - 0.02 / 0.0207
z = - 0.9661
fail to reject null hypothesis.
P-value Approach
P-value = 0.167
As P-value >= 0.05, fail to reject null hypothesis.
Since test is left tailed so p-value of the test is 0.167. Since p-value is greater than 0.05 so we fail to reject the null hypothesis.
Point E lies within rectangle ABCD. If AE = 6, BE = 7, and CE = 8, what is the length of DE?
Answer:
[tex]\sqrt{51}[/tex] units.
Step-by-step explanation:
Point E is inside a rectangle ABCD.
Please refer to the attached image for the given statement and dimensions.
Given that:
Sides AE = 6 units
BE = 7 units and
CE = 8 units
To find:
DE = ?
Solution:
For a point E inside the rectangle the following property hold true:
[tex]AE^2+CE^2=BE^2+DE^2[/tex]
Putting the given values to find the value of DE:
[tex]6^2+8^2=7^2+DE^2\\\Rightarrow 26+64=49+DE^2\\\Rightarrow DE^2=100-49\\\Rightarrow DE^2=51\\\Rightarrow \bold{DE = \sqrt{51}\ units}[/tex]
The graph of F(x), shown below in pink, has the same shape as the graph of
G(x) = x3, shown in gray. Which of the following is the equation for F(x)?
Greetings from Brasil...
In this problem we have 2 translations: 4 units horizontal to the left and 3 units vertical to the bottom.
The translations are established as follows:
→ Horizontal
F(X + k) ⇒ k units to the left
F(X - k) ⇒ k units to the right
→ Vertical
F(X) + k ⇒ k units up
F(X) - k ⇒ k units down
In our problem, the function shifted 4 units horizontal to the left and 3 units vertical to the bottom.
F(X) = X³
4 units horizontal to the left: F(X + 4)
3 units vertical to the bottom: F(X + 4) - 3
So,
F(X) = X³
F(X + 4) - 3 = (X + 4)³ - 3The transformed function is f ( x ) = ( x + 4 )³ - 3 and the graph is plotted
What happens when a function is transformed?Every modification may be a part of a function's transformation.
Typically, they can be stretched (by multiplying outputs or inputs) or moved horizontally (by converting inputs) or vertically (by altering output).
If the horizontal axis is the input axis and the vertical is for outputs, if the initial function is y = f(x), then:
Vertical shift, often known as phase shift:
Y=f(x+c) with a left shift of c units (same output, but c units earlier)
Y=f(x-c) with a right shift of c units (same output, but c units late)
Vertical movement:
Y = f(x) + d units higher, up
Y = f(x) - d units lower, d
Stretching:
Stretching vertically by a factor of k: y = k f (x)
Stretching horizontally by a factor of k: y = f(x/k)
Given data ,
Let the function be represented as g ( x )
Now , the value of g ( x ) = x³
And , the transformed function has coordinates as A ( -4 , -3 )
So , when function is shifted 4 units to the left , we get
g' ( x ) = ( x + 4 )³
And , when the function is shifted vertically by 3 units down , we get
f ( x ) = ( x + 4 )³ - 3
Hence , the transformed function is f ( x ) = ( x + 4 )³ - 3
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