Combine the like terms to create an equivalent expression:
-n+(-4)-(-4n)+6}

Answer:

h(4) = -1 ;   h(-5) = 1        h(0) = -9

Step-by-step explanation:

a)    h(x) = |-2x| - 9       Substitute x = 4

       h(4) = | -2 · 4| - 9

       h(x) = | -8| - 9

       h(4) = 8 - 9

       h(4) = -1

b)  h(x) = |-2x| - 9            Substitute x = -5

    h(-5) = |-2 · -5| - 9

    h(-5) = |-10| - 9

     h(-5) = 10 - 9

      h(-5) = 1

c)   h(x) = |-2x| - 9             Substitute x = 0

     h(0) = |-2 · 0| - 9

     h(0) = |0| - 9

     h(0) = 0 - 9

      h(0) = -9

Step-by-step explanation:

Write properties of function:

x intercept/zero: ; T1= -1 and T2=10

vertex form: g(t)=  (t-9/2)^2, (-121/4)

vertex: 9/2, 121/4

Explanation Write properties of function: Write properties of function:

x intercept/zero: ; t1=-1, and t2=10

vertex form: (t-9/2)^2, (-121/4)

vertex: 9/2, 121/4

hope this helped

Answer:

4900

Step-by-step explanation:

multiply all those numbers together

2x2x5x5x7x7 = 4900

Answer:

12

Step-by-step explanation:

House A is 24. So divide it by two to get 12. Which is house B

the answer is t<-48

i hope this helped you if you need the explanation lmk

Answer:

A

Step-by-step explanation:

Answer: 12 students

Step-by-step explanation:

Let X and Y stand for the number of students in each respective class.

We know:

X/Y = 2/5, and

Y = X+24

We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:

(Y-x)/(X+x) = 1

---

We can rearrange X/Y = 2/5 to:

X = 2Y/5

The use this value of X in the second equation:

Y = X+24

Y =2Y/5+24

5Y = 2Y + 120

3Y = 120

Y = 40

Since Y = X+24

40 = X + 24

X = 16

--

Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:

(Y-x)=(X+x)

(40-x)=(16+x)

24 = 2x

x = 12

12 students must transfer to the more difficult, very early morning, class.

Answer:

110 degrees I think

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

2+4 over 2

x 3

= 9

The height of the bottom of the hole after the second day is -35 11/12 feet

Given:

Day 1 height = -45 1/4 feet

Day 2 height = -45 1/4 + 9 1/3

= - 181/4 + 28/3

= (-543 + 112) / 12

= -431/12

= -35 11/12 feet

Therefore, the height of the bottom of the hole after the second day is -35 11/12 feet

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Answer:

8 batches

Step-by-step explanation:

You would have to divide 3 1/5 by 2/5, which gets you 8 batches of brownies.

Answer:

C. 97.1 should be your answer

Step-by-step explanation:

if the value of x is 1 then the y value is 6

Answer:

y = -12.35

Step-by-step explanation:

Plug in 2.65 for x giving you y = 2.65 - 15

Answer:

8 and 2

Step-by-step explanation:

Answer:

1/4 and 1/2

Step-by-step explanation:

One number is twice another number.

x and 2x

The sum of their reciprocals is 6

[tex]\frac{1}{x}[/tex] + [tex]\frac{1}{2x}[/tex] = 6

Use common denominator of 2x

[tex]\frac{2}{2x}[/tex] +  [tex]\frac{1}{2x}[/tex] = 6

[tex]\frac{3}{2x}[/tex] = 6

multiply botn sides by 2x

3 = 12x

Divide both sides by 12

1/4 = x

x = 1/4

2x = 1/2

The numbers are

1/4 and 1/2

Answer:

56

Step-by-step explanation:

54 + 4(3/4 − 1/2)2

=> 54 + 4(1/4)2

=> 54 + (1)2

=> 54 + 2

=> 56

Therefore, 56 is our answer.

Hoped this helped.

Un significant figured Volume=1099.56

3 sf = 1100.00

Answer: 90,000

To find the LCM (Least Common Multiple) of a number, list the multiples of each number.

Multiples of 900

Since they're a lot, we will extend it to the short version.

900, 2700, 9900, 37800, 85500, 90000

Multiples of 30000

30000, 60000, 90000, 120000, 150000

Looking at both multiples, the least common multiple is 90000, as it is listed in both 900 and 30000.

Hence, 90,000 is the answer.

Answer:

-2, -0.5, -.025, 0.05, 5

Answer:

a =4 and b= 3

Step-by-step explanation:

Stare at it for a bit. You have the squre of x, then(ignoring the minus sign) 2 times x times 4. What's left is the square of 4, which is 16; you have 13, you are 3 short. Let's add them to both sides:

[tex]x^2-8x+13+3=3 \rightarrow x^2-8x+16 = 3\\(x-4)^2 = 3[/tex]

so a =4 and b= 3

Answer:

no graph how am i supposed to answer

Step-by-step explanation:

DUDE PUT THE GRAPH WHERE IS iT

Answer:

For the one on the far left its 104 m2

Step-by-step explanation:

u split the shape in a square and rectangle

them u fin the area of the square by multiplying both sides. (8*8)

then u find the area of the rectangle by using the formula

2*(16+4)

when u find both areas u count them up and it'll become 104 m squared

Answer:

0, 1/18, and 1/36

Step-by-step explanation:

For i = 2, the probability it lands on 6 is 0, because you cannot sum to 2 with a 6. The same applies to i = 3 thru i = 6.

For the probability that at least one of a pair of fair dice lands on 6 for i = 7, there are only two possible ways, the first roll is a 6 and the second roll is a 7, and the first roll is a 1 and the second roll is a 6. The total amount of ways is 6 * 6 = 36, so the total probability is 1/18. This also applies to i = 8 thru i = 11.

For i = 12, there is only one way to get 12, the first dice lands on 6 and the second dice lands on 6. Assuming the dice are indistinguishable, the probability is 1/36.

The probability that at least one of a pair of fair dice lands on 6, given that the sum of the dice is i, where i ranges from 2 to 12, is 23/12.

We have,

The complementary probability of "at least one die lands on 6" is "neither of the dice lands on 6."

Therefore, you need to find the probability that neither of the dice lands on 6 for each possible sum i, and then subtract that probability from 1 to get the desired probability.

Let's go through the cases:

i = 2 (only possible sum with two dice):

In this case, both dice must show a 1.

The probability of this happening on a fair 6-sided die is

(1/6) * (1/6) = 1/36.

i = 3: The combinations are (1, 2) and (2, 1).

The probability of either happening is 2 * (1/6) * (1/6) = 1/18.

i = 4:

The combinations are (1, 3), (2, 2), and (3, 1).

The probability of any of these happening is 3 * (1/6) * (1/6) = 1/12.

i = 5:

The combinations are (1, 4), (2, 3), (3, 2), and (4, 1).

The probability of any of these happening is 4 * (1/6) * (1/6) = 1/9.

i = 6:

The combinations are (1, 5), (2, 4), (3, 3), (4, 2), and (5, 1).

The probability of any of these happening is 5 * (1/6) * (1/6) = 5/36.

i = 7:

The combinations are (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).

The probability of any of these happening is 6 * (1/6) * (1/6) = 1/6.

i = 8:

The combinations are (2, 6), (3, 5), (4, 4), (5, 3), and (6, 2).

The probability of any of these happening is 5 * (1/6) * (1/6) = 5/36.

i = 9:

The combinations are (3, 6), (4, 5), and (5, 4).

The probability of any of these happening is 3 * (1/6) * (1/6) = 1/12.

i = 10:

The combinations are (4, 6) and (6, 4).

The probability of either happening is 2 * (1/6) * (1/6) = 1/18.

i = 11:

The combinations are (5, 6) and (6, 5).

The probability of either happening is 2 * (1/6) * (1/6) = 1/18.

i = 12:

The combination is (6, 6).

The probability of this happening is (1/6) * (1/6) = 1/36.

Now, sum up the probabilities for each case:

(1/36) + (1/18) + (1/12) + (1/9) + (5/36) + (1/6) + (5/36) + (1/12) + (1/18) + (1/18) + (1/36)

This simplifies to:

69/36 = 23/12

Thus,

The probability that at least one of a pair of fair dice lands on 6, given that the sum of the dice is i, where i ranges from 2 to 12, is 23/12.

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Answer:

The answer to the is 28 and 40! hope this helps love

13. 12008.

14. 59286.

15. 21459.

16. 80478.

17. 130567.

18. 11100.

19. Seventy-two thousand, one hundred eighty.

20. Eighty thousand, seven hundred eighty-six.

Hope This Helps...:)

Answer:

There is a area of triangle and there is two trapezium so 8×17=136

Answer: a = 2.5 (an-1)

Step-by-step explanation: trust me;)

The function which is used to represent the geometric progression 8, 20, 50, 125, 312.5, ... is [tex]a_{n} = 8(2.5)^{n-1}[/tex].

sequence where each succeeding term is produced by multiplying each preceding term by a fixed number, which is called a common ratio. This progression is as a geometric sequence of  numbers.

[tex]a_{n} =ar^{n-1}[/tex]

Where,

[tex]a_{n}[/tex] is the nth term of the sequence or geometric progression

n is the total number of terms

r is the common ratio

and a is the first term

According to the given question

We have

A geometric progression

8, 20, 50, 125, 312.5

Now the common ratio for the above progression is given by

[tex]r = \frac{20}{8} = 2.5[/tex]

And the first term is

a = 8

Therefore, the function which is used to represent the above sequence is given by

[tex]a_{n} = 8(2.5)^{n-1}[/tex]

Hence, the function which is used to represent the geometric progression 8, 20, 50, 125, 312.5, ... is [tex]a_{n} = 8(2.5)^{n-1}[/tex].

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