Chemistry help!
How much 1.50 M H3PO4, in mL, would you need to add to 50.00 mL of 3.50 M Ca(OH)2 in order to neutralize the solution?

_____ of mL of H3PO4

Answers

Answer 1

Answer:

Use the formula below

Explanation:

use the moles ratio for this by writing down the reaction and balancing the equation


Related Questions

What is the initial concentration of a solution if 40.0 mL is diluted to make 720 mL of a 0.45 M solution?

Answers

Answer:

8.1 M

Explanation:

What is the initial concentration of a solution if 40.0 mL is diluted to make 720 mL of a 0.45 M solution?

LET Y = INITIAL CONCENTRATION

SO

Y TIMES 40/720 = 0.45 m

SO

Y= (0.45) X 720/40=

0.45 X 72/4 =

0.45 X 18 =8.1 M

Concentration is related to the mass and volume. 8.1 M  initial concentration of a solution is required if 40 ml is diluted to make 720 ml of a 0.45 M solution.  

What is initial concentration ?

The first measured concentration of a compound in a substance is called as initial concentration. Initial concentration also measure with the help of molarity.

Write out the equation C = m ÷ V, where m is the mass of the solute and V is the total volume of the solution. Substitute  the values you found for the mass and volume, and divide them to find the concentration of your solution.  

Let X is the initial concentration,

so, X times 40 ÷ 720 = 0.45

X = ( 0.45 ) × ( 720÷40)

= 0.45 × 18

= 8.1 M

Hence, 8.1 M  initial concentration of a solution is required .

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Please help me ASAP I couldnt copy paste the table so I added a screenshot Please I really need help!!!

Answers

Answer:

2.04 Thermal Energy and Chemical Change Lab Report

Explanation:

element Q,X, and Z are in the same group on the periodic table and are listed in order of increasing atomic number.The melting point of element Q is -219 Celsius and the melting point of element Z is -7 celsius. Which temperature is closest to the melting point of element X

Answers

Answer:

Very low ionization energy: metal bonds easily: group 1, or maybe 2 low melting.

Explanation:

Use the choose reaction drop down menu to see other equations, and balance them. Check your answers and then write the balanced equations. AI+ HCI-> AICI3+ H2

NaCI -> Na + CI2

Na2S + HCI -> NaCI + H2S​

Answers

3 and then you do that yea

Mixture of a 25.00 mL aliquot of the sample solution with 5.00 mL of a 0.250 ppm warfarin standard yielded a solution with an intensity of 670. Calculate the percentage of warfarin in the sample.

Answers

Answer:

750

Explanation:

What happened a when you try to layer a more-dense solution on top of a less-dense solution

Answers

Answer:

the more dense solution will sink to the bottom the less dense solution will go to the top

Answer:

Explanation:The density of a liquid determines whether it will float on or sink in another liquid. A liquid will float if it is less dense than the liquid it is placed in. A liquid will sink if it is more dense than the liquid it is placed in.

Density of a liquid determines how it will layer (heaviest to lightest). If the liquid us least dense it float to the bottom. Layers will remain separated because each liquid is actually floating on top of the more dense liquid beneath it.

U ever get an answer

Answers

yesn’t. they are either wrong or links

The student burns 10 g of magnesium in air to produce magnesium oxide (MgO).
2Mg + 0 + 2MgO
Calculate the maximum mass of magnesium oxide that could be produced in the reaction.

Answers

Answer:

x=403/24,3 = 16.58 gm MgO

EXPLANATION

The student burns 10 g of magnesium in air to produce magnesium oxide (MgO)

2Mg + 0 + 2MgO

Calculate the maximum mass of magnesium oxide that could be produced in the reaction.

Oxygen exist in nature as O2, diatomic.

so

The student burns 10 g of magnesium in air to produce magnesium oxide (MgO).

2Mg + 02 + 2MgO

Calculate the maximum mass of magnesium oxide that could be produced in the reaction.

2 moles of Mg produce 2 moles of MgO

1 mole of Mg weighs 24.3 and produces 1 mole of MgO

Mg HAS AN ATOMIC MASS OF 24.3

Mg HAS A MOLAR MASS OF 24.3 +16 = 40.3gm/mole

so 24.3 gm of Mg produce 40.3 gm MgO

set up the ratio

10 gm Mg/x of MgO  = 24.3/40.3

or

10/x = 24.3/40.3

cross multiply and isolate x (use Algebra I)

24.3x =403

x=403/24,3 = 16.58 gm MgO

Which of the following is a compound? *
A. aluminum
B. carbon
C. oxygen
D. sugar

Answers

CARBON IS A COMPOUND

Answer:

C. OXYGEN

Explanation:

An exothermic reaction releases 86.5 kJ. How many kilocalories of
energy are released?

Answers

Since 1 calories is 4.1858 Joules, 86.5kJ is 86.5 x (1/4.1858) = 20.66510583 kCal = 20.7 kCal (3 s.f)

How many peaks will you observe in the 13C spectrum of cyclohexane ?
1 1 - incorrect
3
6

Answers

3 peaks

Explanation:

You can do this perfectly well without referring to chemical shift tables at all. In the spectrum there are a total of three peaks - that means that there are only three different environments for the carbons, despite there being four carbon atoms.

Which of the following corresponds to an alpha particle?
A. 1/4He
B. 3/2He
C. 2/2H
D. 4/2He

Answers

Answer:

D. 4/2 He corresponds to an alpha particle.

what is the functional group and homologous series of ethyl butyrate?​

Answers

Answer:

Functional group: ROR'

Homologous series: ester [C6H12O2]

Mark brainliest please

the experimental grip


Why are coal, oil and natural gas called fossil fuels

Answers

From heat and pressure from the earth

How would you gather data to in order to determine the density of a marble

Answers

The average mass of a marble can be determined by dividing the total mass of the marbles by the total number of marbles: average mass of a marble.

To find the density of any object, you need to know the Mass (grams) of the object, and its Volume (measured in mL or cm³). Divide the mass by the volume in order to get an object's Density.

Use the formula p=m/V, or density (p) is equal to mass (m) divided by volume (V).

To determine the density of a marble, we must know its mass and volume.

In order to determine the density of any substance we need to know its mass and volume.

Let's understand "Density".

The density of a substance is its mass per unit volume. It is represented with "ρ" this symbol.It can be given by the formula which is shown below: ρ= [tex]\frac{m}{V}[/tex] where m is the mass of the substance and V is the volume.Density indicates how much of a substance occupies a specific volume at a defined temperature and pressure. The density of a substance can be used to define the substance.

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What is the mole ratio between FeCl3 and Fe(C5H7O3)3 ?

Answers

Answer:      162.2 g FeCl3. mL of soln = 0.07028 mol FeCl3x ... mol FeCl3 = mol Fe(OH)3 = 0.01291 mol ... (a) MaVa = MbVb since HCl and KOH react in a 1:1 molar ratio.

Explanation:

giving brainly for correct answer! :)

Answers

Answer:

Mass is the amount of matter in an object

Answer:

Mass

Explanation:

matter is weighed by the mass of an object

which of the following substances will cross the cell membrance through osomosis

Answers

Answer:Water, carbon dioxide, and oxygen are among the few simple molecules that can cross the cell membrane by diffusion (or a type of diffusion known as osmosis ).

Explanation:

The molarity of an aqueous solution of CaCl is defined as the

Answers

Answer:

Molarity of aqueous solution of CaCl2 can be defined as moles of CaCl2 per litre of solution

pls help i am in 8th grade k12

Answers

Answer:

zzxdczxc V

Explanation:

Convert 21 grams of radon into atoms of radon.

Answers

Answer:

The atomic mass of radon is 222.

Explanation:

. That means that one mole of radon weighs 222 grams (222 grams/moles). We can therefore make the following equation:

Grams × (1/222) = Moles of Radon

When performing an experiment, the following footwear is best

Answers

Answer:

sneakers

Explanation:

Answer:

closed toe shoe

Explanation:

becusae if a cemcal spills it cant hurt your feet

A \pu{1.60 g}1.60 g1, point, 60, space, g calcium supplement contains 37.8\%37.8%37, point, 8, percent \ce{Ca}CaC, a by mass. The calcium is present in the supplement as \ce{CaCO3}(s)CaCOX 3 ​ (s) (molar mass \pu{100.09 g/mol}100.09 g/mol100, point, 09, space, g, slash, m, o, l). How many grams of \ce{CaCO3}(s)CaCOX 3 ​ (s) are in the calcium supplement?

Answers

A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

We want to calculate the mass of CaCO₃ in a 1.60 g supplement. We need to consider the following relationships.

The mass percent of Ca is 37.8%, that is, there are 37.8 g of Ca every 100 g of supplement.The molar mass of Ca is 40.08 g/mol.The molar ratio of Ca to CaCO₃ is 1:1.The molar mass of CaCO₃ is 100.09 g/mol.

[tex]1.60gSup \times \frac{37.8gCa}{100gSup} \times \frac{1molCa}{40.08gCa} \times \frac{1molCaCO_3}{1molCa} \times \frac{100.09gCaCO_3}{1molCaCO_3} = 1.51gCaCO_3[/tex]

A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

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A 1.60 g calcium supplement contains 37.8% Ca by mass. The calcium is present in the supplement as CaCO₃(s) (molar mass 100.09 g/mol). How many grams of CaCO₃(s) are in the calcium supplement?

if 10.5 grams of liquid water is boiled how many grams of water vapor will then form ?

Answers

Answer:

It depends

Explanation:

This could vary depending on the exact temp, time and minerals. something with alot of salt boils quicker than something without it, so 10.5 grams?

The particular temperature, the passage of time, and the minerals could all affect the amount of grams of liquid water.

What are minerals?

Minerals are defined as a naturally crystallized element or chemical compound that was created through geological processes. Natural materials are those that form on their own, such as minerals. Minerals don't droop, melt, or evaporate since they are solids. In contrast to the carbon compounds found in living organisms, minerals are inorganic. Minerals are crystalline: They have a unique atomic composition and arrangement.

Temperature is defined as a measure of hotness or coldness expressed in terms of any number of arbitrary scales that shows the direction that heat energy will naturally flow, i.e., from a hotter body to a colder body. The three temperature scales that are now in use are Kelvin, Celsius, and Fahrenheit. Food, beverages, agriculture, and medical care for both people and animals all depend heavily on temperature.

Thus, the particular temperature, the passage of time, and the minerals could all affect the amount of grams of liquid water.

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The city council of a small town wanted to add fluoride to their water so that all the residents would have healthier teeth. The mayor had read that ionic compounds must be used to get the fluoride into water. He looked up fluorine-containing compounds and came up with the following list. ​
NaF NF3 SiF4 CaF2 NH4F​

Using academic vocabulary in paragraph form, discuss the following: ​

Explain which compound(s) could produce fluoride ions in the water. In your response, be sure to include: ​
° which of the listed compounds are ionic and which are covalent. ​
° how ionic and covalent compounds are different. ​
° why only ionic compounds would produce fluoride in water.​

Answers

Answer:NaF is ionic. NF3 is covalent. SiF4 is ionic. CaF2 is Ionic and  NH4F is also ionic. Ionic compounds transfer electrons whereas covalent compounds share electrons hence the word "co". Also, ionic compounds are formed with metal and nonmetal. Where a covalent is with 2 nonmetals. Only ionic compounds would produce fluoride in water because ionic compounds can dissolve in water and covalent compounds cant.

The compounds that can be used for the release of fluorine in water are NaF, [tex]\rm SiF_4[/tex], [tex]\rm CaF_2[/tex], and [tex]\rm NH_4F[/tex].

The ionic compounds are formed by the transfer of electrons between the atoms of the compounds. The ionic bonds are weaker and are easy to dissociate in the aqueous solution.

The covalent compounds are formed by the sharing of electrons between the atoms. Since there is sharing, there has been a strong bond, that has been hard to dissociate.

The Mayor has to release Fluoride in the water, thus ionic compounds are preferred that have the easy release of fluorine.

From the given compounds:

NaF = Ionic compound[tex]\rm NF_3[/tex] = Covalent compound[tex]\rm SiF_4[/tex] = Ionic compound[tex]\rm CaF_2[/tex] =  Ionic compound[tex]\rm NH_4F[/tex] =  Ionic compound

Thus the compounds that can be used for the release of fluorine in water are NaF, [tex]\rm SiF_4[/tex], [tex]\rm CaF_2[/tex], and [tex]\rm NH_4F[/tex].

For more information about ionic and covalent compounds, refer to the link:

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Calculate the number of moles in 400g of Tio2

Answers

Answer:

5.01 moles

Explanation:

Calculate the number of moles in 400g of Tio2

first, write the formulas correctly

Calculate the number of moles in 400g of TiO2

capitalize the first letter of your elements

the molar mass of TiO2 is

47.88 +2X16.00 =47.88  +32.00 = 79.88 gm/mole

(to 3 sig fig = 79.9 gm/mole

400 gm/79.9 gm/mole = 400/79.9 mole gm/gm =

400/79.9 moles = 5.01 moles

what i compound is
FeI2

Answers

Answer:

iodide

Explanation:

Answer:

Iron(II) iodide

Explanation:

Engineering chemistry

Answers

Answer:

it wont let me see it

Explanation:

what is a nucleus and what are the functions?

Answers

nucleus, in biology, a specialized structure occurring in most cells (except bacteria and blue-green algae) and separated from the rest of the cell by a double layer, the nuclear membrane. This membrane seems to be continuous with the endoplasmic reticulum (a membranous network) of the cell and has pores, which probably permit the entrance of large molecules. The nucleus controls and regulates the activities of the cell (e.g., growth and metabolism) and carries the genes, structures that contain the hereditary information

11. Which is the solubility product expression for Na3PO4(s)?

Answers

Answer: B

Explanation: the 3 in Na3PO4(s) belong to the sodium atom (Na). so in any of these equations, the 3 would have to be with Na.

A- the 3 is along w the PO4, which would make it part of that bond

C- there is no 3 at all for Na in this choice, making it incorrect

D- Again, the 3 is placed on the other half of the bond

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