Can someone please help me with this proof?!

Given: AC and BD bis, each other.

Prove: ABCD is a parallelogram

Answer:

Y is equals to negative 1.

Step-by-step explanation:

y = 2x + 3

y =2(-2)+ 3

y =-4+ 3

y=-1

Answer:

A. 61.82°;

15.64°

B. 33.37°

Step-by-step explanation:

A.

✍️Angle of elevation from 15 ft:

A right triangle is formed. Apply trigonometric ratios formula to find the angle of elevation from 15 ft.

Thus,

Length of the side Opposite to reference angle = 22 + 6 = 28 ft

Adjacent length = 15 ft

Thus, we would have:

[tex] tan(\theta) = \frac{opp}{adjacent} = \frac{28}{15} [/tex]

[tex] tan(\theta) = 1.8667 [/tex]

[tex] \theta = tan^{-1}(1.8667) [/tex]

[tex] \theta = 61.82 [/tex] (2 d.p)

✍️Angle of elevation from 100 ft:

Thus,

Length of the side Opposite to reference angle = 22 + 6 = 28 ft

Adjacent length = 100 ft

Thus, we would have:

[tex] tan(\theta) = \frac{opp}{adjacent} = \frac{28}{100} [/tex]

[tex] tan(\theta) = 0.28 [/tex]

[tex] \theta = tan^{-1}(0.28) [/tex]

[tex] \theta = 15.64 [/tex] (2 d.p)

B.

✍️Distance you'd be from the screen if you lie on the ground and make an angle of elevation of 40° to the top of the screen:

Adjacent length = your distance from the screen = x

Opposite length = 22 + 6 = 28 ft

Angle of elevation = 40°

Tge trigonometric ratios formula to use would be:

[tex] tan(\theta) = \frac{opp}{adjacent} [/tex]

Plug in the values

[tex] tan(40) = \frac{28}{x} [/tex]

Multiply both sides by x

[tex] x*tan(40) = 28 [/tex]

Divide both sides by tan(40)

[tex] x = \frac{28}{tan(40)} [/tex]

[tex] x = 33.37 [/tex] (2 d.p)