Can someone help me with this problem?

Answer:

volume=length×width×height

v=15×20×20

v=6000

Answer:

5

Step-by-step explanation:

3-(-2) will become positive 5. so number line will go towards positive 5.

Answer:

upper bound for the error, | Error |  ≤ 0.0032

Step-by-step explanation:

Given the data in the question;

[tex]e^{0.4[/tex] < e < 3

Using Taylor's Error bound formula

| Error | ≤ ( m / ( N + 1 )! ) [tex]| x-a |^{N+1[/tex]

where m = [tex]| f^{N+1 }(x) |[/tex]

so we have

| Error |  ≤ ( 3 / ( 3 + 1 )! ) [tex]|[/tex] -0.4 [tex]|[/tex]⁴

| Error |  ≤ ( 3 / 4! ) [tex]|[/tex] -0.4 [tex]|[/tex]⁴

| Error |  ≤ ( 3 / 24 ) [tex]|[/tex] -0.4 [tex]|[/tex]⁴

| Error |  ≤ ( 0.125 ) [tex]|[/tex] -0.0256 [tex]|[/tex]

| Error |  ≤ ( 0.125 ) 0.0256

| Error |  ≤ 0.0032

Therefore, upper bound for the error, | Error |  ≤ 0.0032

Answer:

The insurance company should charge $1,873.5.

Step-by-step explanation:

Expected earnings:

1 - 0.99813 = 0.00187 probability of the company losing $1 million(if the client dies).

0.99813 probability of the company earning x(price of the insurance).

What premium would an insurance company charge to break even on a one-year $1 million term life insurance policy?

Break even means that the earnings are 0, so:

[tex]0.99813x - 0.00187(1000000) = 0[/tex]

[tex]0.99813x = 0.00187(1000000)[/tex]

[tex]x = \frac{0.00187(1000000)}{0.99813}[/tex]

[tex]x = 1873.5[/tex]

The insurance company should charge $1,873.5.

Answer:

[tex]b=h=\sqrt{6}[/tex] m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=[tex]2b^2+4bh[/tex]

[tex]2b^2+4bh=36[/tex]

[tex]b^2+2bh=18[/tex]

[tex]2bh=18-b^2[/tex]

[tex]h=\frac{18-b^2}{2b}[/tex]

Volume of box, V=[tex]b^2h[/tex]

Substitute the values

[tex]V=b^2\times \frac{18-b^2}{2b}[/tex]

[tex]V=\frac{1}{2}(18b-b^3)[/tex]

Differentiate w. r.t b

[tex]\frac{dV}{db}=\frac{1}{2}(18-3b^2)[/tex]

[tex]\frac{dV}{db}=0[/tex]

[tex]\frac{1}{2}(18-3b^2)=0[/tex]

[tex]\implies 18-3b^2=0[/tex]

[tex]\implies 3b^2=18[/tex]

[tex]b^2=6[/tex]

[tex]b=\pm \sqrt{6}[/tex]

[tex]b=\sqrt{6}[/tex]

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

[tex]\frac{d^2V}{db^2}=-3b[/tex]

At  [tex]b=\sqrt{6}[/tex]

[tex]\frac{d^2V}{db^2}=-3\sqrt{6}<0[/tex]

Hence, the volume of box is maximum at [tex]b=\sqrt{6}[/tex].

[tex]h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}[/tex]

[tex]h=\frac{18-6}{2\sqrt{6}}[/tex]

[tex]h=\frac{12}{2\sqrt{6}}[/tex]

[tex]h=\sqrt{6}[/tex]

[tex]b=h=\sqrt{6}[/tex] m

Answer:

a=1, b=9, c=-2, d=4

Step-by-step explanation:

Answer:

3 hrs

Step-by-step explanation:

5 * 24 = 120 miles

64x = 120 + 24x

40x = 120

x = 3 hrs

Answer:

66 m

Step-by-step explanation:

First, lets add up the numbers you know. It should be:

16, 8, 17, and 7.

Add them all up, and you will get:

48.

For the last two sides, subtract 7 from 16 to get 9.

For the last slide, subtract 8 from 17 to get 9.

Add them all up, and get 66.

Hey there!

[tex]\mathsf{\dfrac{2}{9}\div\dfrac{5}{6}}[/tex]

[tex]\mathsf{= \dfrac{2\times6}{9\times5}}[/tex]

[tex]\mathsf{2\times 6 = \bf 12}[/tex]

[tex]\mathsf{9\times5 = \bf 45}[/tex]

[tex]\boxed{\mathsf{=\bf \dfrac{12}{45}}}[/tex]

[tex]\large\textsf{BOTH NUMBERS has the Greatest Common Factor (GCF) of 3}[/tex]

[tex]\mathsf{= \dfrac{12\div3}{45\div3}}[/tex]

[tex]\mathsf{12\div3=\bf 4}[/tex]

[tex]\mathsf{45\div3=\bf 15}[/tex]

[tex]\boxed{\mathsf{=\bf \dfrac{4}{15}}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf \dfrac{4}{15}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}\\\\\\~\frak{Amphitrite1040:)}}[/tex]

9514 1404 393

Answer:

  2

Step-by-step explanation:

In this expression, the terms are the parts of the sum. They are 3x and 4. There are 2 terms.

Answer:

11

Step-by-step explanation:

y-1=10

Any figure that crosses equal sign, the operational sign changes.

y=10+1

y= 11

Answer:

2

Step-by-step explanation:

Answer:

See Below.

Step-by-step explanation:

We can write a two-column proof.

Statements:                                                Reasons:

[tex]\displaystyle 1)\, \angle 4\cong \angle 2[/tex]                                                   Given

[tex]\displaystyle 2)\, \angle 3 \cong \angle 4[/tex]                                                   Vertical Angles are Congruent

[tex]\displaystyle 3) \, \angle 1 + \angle 2 = 180[/tex]                                          Linear Pair

[tex]\displaystyle 4)\, \angle 1 + \angle 4 = 180[/tex]                                          Substitution

[tex]\displaystyle 5) \, \angle 1 + \angle 3 = 180[/tex]                                          Substitution

[tex]\displaystyle 6) \, \text{$\angle 3$ and $\angle 1$ are supplementary}[/tex]                  Definition of Supplementary Angles

Answer:

.40 is the greatest .350 is the second greatest and last but not least .3456 is the lowest

Step-by-step explanation:

Evaluating the limand directly at x = 0 yields the indeterminate form 0/0. If L'Hopital's rule is known to you, you can compute the limit by applying it twice:

[tex]\displaystyle\lim_{x\to0}\frac{x\left(e^{3x}-1\right)}{2-2\cos(x)} = \lim_{x\to0}\frac{3xe^{3x}+e^{3x}-1}{2\sin(x)} \\\\\\ = \lim_{x\to0}\frac{9xe^{3x}+6e^{3x}}{2\cos(x)} = \frac62=\boxed{3}[/tex]

Answer: 5

Step-by-step explanation: I think it is 5

9514 1404 393

Answer:

  k = 2

Step-by-step explanation:

The geometric mean theorem for the altitude tells you ...

  ON = √(OL·OM)

  ON² = OL·OM . . . . . square both sides

  4² = 8·k . . . . . . . . substitute values

  k = 16/8 = 2 . . . . divide by the coefficient of k

_____

Additional comment

The geometric mean theorem for the legs tells you ...

  MN = √(MO·ML)   ⇒   l = 2√5

  LN = √(LO·LM)   ⇒   m = 4√5

These relations come from the fact that corresponding sides of the right triangles are proportional. (All of the triangles are similar.)

Answer:

The gradient is -0.25

Step-by-step explanation:

Given

[tex](x_1,y_1) = (-5,3)[/tex]

[tex](x_2,y_2) = (5,0.5)[/tex]

Required

The gradient (m)

This is calculated as:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m = \frac{0.5-3}{5--5}[/tex]

[tex]m = \frac{-2.5}{10}[/tex]

[tex]m = -0.25[/tex]

Answer:

Hence the answer is given as follows,

Step-by-step explanation:

Graph of y = f(x) given,

(a) [tex]\lim_{x\rightarrow 2^{-}}f(x)=3[/tex]

(b) [tex]\lim_{x\rightarrow 2^{+}}f(x)=1[/tex]

(c) [tex]\lim_{x\rightarrow 2}f(x)= DNE \left \{ \therefore \lim_{x\rightarrow 2^{-}} f(x)\neq \lim_{x\rightarrow 2^{+}}f(x) \right.[/tex]

(d) [tex]f(2)=3[/tex]

(e) [tex]\lim_{x\rightarrow 4}f(x) = 4[/tex]

(f) [tex]f(4)= DNE.[/tex]{ Hole in graph}

Hence solved.

Answer:

0.9036

Step-by-step explanation:

Calculation to determine the probability that the proportion of Labradors

P(Proportion greater than 4%)

= P(z> 0.04 -0.05 /√0.05 * 0.95/806

= P(z > -1.30)

=0.9036

Thereforethe probability that the proportion of Labradors is =0.9036

Answer:

Part A

(1y^2+3y-6)+(4y-7+2y^2)+(3y^2-8+5y)

6y^2+12y-21

Answer:

[tex]T =56.3[/tex]

Step-by-step explanation:

Given

The attached triangle

Required

Measure of T

This is calculated as:

[tex]\cos T = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos T = \frac{5}{9}[/tex]

Take arccos

[tex]T = \cos^{-1}{(5/9)}[/tex]

[tex]T =56.3[/tex]

Answer:

9 ft^2 and 12.25 ft^2

Step-by-step explanation:

We need to figure out the area for a square with a perimeter of 12 feet and 14 feet.

A square has four sides that are all equal in length, therefore:

12/4 = 3

14/4 = 3.5

3 and 3.5 are the individual side lengths of the garden, so to find the area, we just multiply those numbers by themselves (since it is a square garden).

3*3 = 9

3.5*3.5 = 12.25

Therefore, the answer is 9 ft^2 and 12.25 ft^2

Answer:

{f, a}

Step-by-step explanation:

Given the sets:

X = {d, c, f, a}

Y = {d, e, c}

Z ={e, c, b, f, g}

U = {a, b, c, d, e, f, g}

To obtain the set X n (X - Y)

We first obtain :

(X - Y) :

The elements in X that are not in Y

(X - Y) = {f, a}

X n (X - Y) :

X = {d, c, f, a} intersection

(X - Y) = {f, a}

X n (X - Y) = elements in X and (X - Y)

X n (X - Y) = {f, a}

Answer:

3. The scale factor is 3, which means the length of the image of segment KL will be 3 times as long.

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, reflection and dilation.

Dilation is the increase or decrease in the size of a figure. If a point A(x, y) is dilated about the center of dilation located at O(a, b), the new point is at A'[k(x - a) + a, k(y - b) + b].

Quadrilateral KLMN has vertices at K(2, 1), L(-1, -5), M(6, -5) and N(6, 1). If it is dilated by 3, about the center M(6, -5), the new points are:

K' = (3(2 - 6) + 6, 3(1 - (-5)) + (-5)) = (-6, 13)

L' = (3(-1 - 6) + 6, 3(-5 - (-5)) + (-5)) = (-15, -5)

M' = (3(6 - 6) + 6, 3(-5 - (-5)) + (-5)) = (6, -5)

N' = (3(6 - 6) + 6, 3(1 - (-5)) + (-5)) = (6, 13)

Therefore the image of segment KL will be 3 times long.

Answer:

269 and 1/16 feet total (or 269.0625 feet to be precise)

Step-by-step explanation:

20 and 1/2 = 20.5

13 and 1/8 = 13.125

20.5 * 13.125 = 269.0625 feet = 269 and 1/16 feet

Answer:

0.03 more flour per cupcake

Step-by-step explanation:

3.12/8 = 0.39

2.52/7 = 0.36

0.39 - 0.36 = 0.03

Hope this helps c:

Answer:

The average value of the cost function over the interval  is of $23,500.

Step-by-step explanation:

Average value of a function:

The average value of a function, over an inteval [a,b], is given by:

[tex]A = \frac{1}{b-a} \int_{a}^{b} f(x) dx[/tex]

In this case:

Function [tex]C(x) = 20000 - 10x[/tex], interval with [tex]a = 0,b = 700[/tex]

So

[tex]A = \frac{1}{700} \int_{0}^{700} 20000+10x dx[/tex]

[tex]A = \frac{1}{700} (20000x+5x^2)|_{0}^{700}[/tex]

So

[tex]A = \frac{20000(700)+5(700)^2}{700} = 23500[/tex]

The average value of the cost function over the interval  is of $23,500.