Answer:
x = 41 degrees
Step-by-step explanation:
Since two of the sides are shown as being congruent, the base angles are the same. We are given the top angle, which is 98 degrees. All the angles of a triangle add up to 180. We can subtract 98 from 180, giving us 82, and divide that by two (since the base angles are congruent), giving us a measure of 41 degrees for each of the bottom angles of the isosceles triangle.
A right rectangular prism is 5 inches long, 12 inches wide, and 8 inches tall. The diagonal of the base is 13 inches.
The area of the cross section that is perpendicular to the base and created by a plane that slices the prism through the diagonals of the base and its opposite face is
square inches.
Answer:
Step-by-step explanation:
The cross-section is an 8”×13” rectangle.
Area = 104 square inches
Decide !!!!!!!!!!!!!!!!!!!!!!!!
Answer:
[tex]\displaystyle [CQF]=5[/tex]
Step-by-step explanation:
Note that [tex][n][/tex] refers to the area of some polygon [tex]n[/tex].
Diagonal [tex]\overline{AC}[/tex] forms two triangles, [tex]\triangle ABC[/tex] and [tex]\triangle ADC[/tex]. Both of these triangles have an equal area, and since the area of parallelogram [tex]ABCD[/tex] is given as [tex]210[/tex], each triangle must have an area of [tex]105[/tex].
Furthermore, [tex]\triangle ADC[/tex] is broken up into two smaller triangles, [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex]. We're given that [tex]\frac{DF}{FC}=2[/tex]. Since [tex]DF[/tex] and [tex]FC[/tex] represent bases of [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex] respectively and both triangles extend to point [tex]A[/tex], both triangles must have the same height and hence the ratio of the areas of [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex] must be [tex]2:1[/tex] (recall [tex]A=\frac{1}{2}bh[/tex]).
Therefore, the area of each of these triangles is:
[tex][ACF]+[ADF]=105,\\[][ACF]+2[ACF]=105,\\3[ACF]=105,\\[][ACF]=35 \implies [ADF]=70[/tex]
With the same concept, the ratio of the areas of [tex]\triangle AQE[/tex] and [tex]\triangle DQE[/tex] must be [tex]2:1[/tex] respectively, from [tex]\frac{AE}{ED}=2[/tex], and the ratio of the areas of [tex]\triangle DQF[/tex] and [tex]\triangle CQF[/tex] is also [tex]2:1[/tex], from [tex]\frac{DF}{FC}=2[/tex].
Let [tex][DQE]=y[/tex] and [tex][CQF]=x[/tex] (refer to the picture attached). We have the following system of equations:
[tex]\displaystyle \begin{cases}2y+y+2x=70,\\y+2x+x=35\end{cases}[/tex]
Combine like terms:
[tex]\displaystyle \begin{cases}3y+2x=70,\\y+3x=35\end{cases}[/tex]
Multiply the second equation by [tex]-3[/tex], then add both equations:
[tex]\displaystyle \begin{cases}3y+2x=70,\\-3y-9x=-105\end{cases}\\\\\rightarrow 3y-3y+2x-9x=70-105,\\-7x=-35,\\x=[CQF]=\frac{-35}{-7}=\boxed{5}[/tex]
please help me to solve this
Answer:
Step-by-step explanation:
a) 3x^2
b) (512)^-2/3=2^n
1/64=2^n
n=-6
Ferris started to bike the 4 1/3 miles to school. After 3/5 mile, he stoppedto talk to a friend. How mush farther did he have to go to get to school?
Answer:
3 11/15 miles
Step-by-step explanation:
4 1/3 - 3/5
4 5/15 - 9/15
3 20/15 - 9/15
3 11/15 miles
a. IfA= {a, b} and B = {p, q, r}, find A x B and B x A using tree diagram.
Answer:
Step-by-step explanation:
instructions find the value of x
Answer:
Given two equal chords. Since the line from the centre is always equal, thus the lines that bisect the two chords are also equal. X=5
There is a $30 fee to rent a tool from the local hardware store plus $6 per day. If Joe rents a jackhammer for 5 days, what is his total bill? The correct function for this situation is f(x) = 30x + 6.
O False
O True
PLSSSS HELP ME WHOEVER ANSWERS CORRECTLY GETS BRAINLIEST!!!!
1. How would we name the polynomial below? Think about degree and number of terms.
x^4 + 3x^2 - x
2. Simplify by adding
(x + 4) + (2x + 7)
3. Multiply
3x^2(5x^3)
4. Divide
8x^3y^5 / 4x^2y^3
Answer:
This is what you asked me just now.
Step-by-step explanation:
Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for several seconds. The player began counting at 0 seconds even though the video had already played 190 frames The video plays 252525 frames per second. How many frames had the video already played when the time was equal to -3 3/5
Answer:
105 frames
Step-by-step explanation:
Given that 25 frames are played per second
25 frames= 1 sec
The video already played 3 and 2/5 seconds before the player started to count 0
Write 3 and 2/5 seconds as an improper fraction
=(5*3)+2 / 5 = 17/5 seconds
Multiply by 25 frames
17/5 *25 =85 frames
So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames.Thus,to get the number of frames that were already in count you subtract 85 frames from the 190 frames.
190-85=105 frames.
Step-by-step explanation:
The temperature on a winter was -23 °F. The temerature rise by 5 °F when the sun came up. When the sun set again, the temperature dropped by. 7°F. Write and evaluate an exspression to find the temperature after the sun set.
Answer:
-25
Step-by-step explanation:
First, add 5 to -23 since the temperature is getting hotter.
so -23 +5= -18
Second, minus the answer by 7 since the temperature is now falling down after the sunset.
so -18 -7 = -25
or...
this step can be simplified as:
-23 +5 -7 =. -25
pls help graph of function
Answer:
i: -1.3
ii: 1.3
Step-by-step explanation:
You literally have it.
I hope this helps!
pls ❤ and give brainliest pls
Use the points slope formula..
Answer:
y = -5/14 -13/7
Step-by-step explanation:
First find the slope
m = (y2-y1)/(x2-x1)
m = (1 - -4)/(-8 - 6)
= (1+4)/(-8-6)
= 5/-14
=-5/14
Point slope form is
y-y1 = m(x-x1)
y - -4 = -5/14(x-6)
y+4 = -5/14(x-6)
We want the equation in slope intercept form y = mx+b
Distribute
y+4 = -5/14x + 15/7
Subtract 4 from each side
y+4 -4= -5/14x + 15/7-4
y = -5/14x +15/7 - 28/7
y = -5/14 -13/7
HELPPPP
You invest $2700 in an account at 1.5% per year simple interest. The equation
that represents this scenario is:
A(n) = 2700 + (n - 1)(0.015. 2700)
How much will you have in the account in year 5? Round your answer to the
nearest dollar.
For what values of k does the equation (2k + 1)x^2 + 2x = 10x – 6 have two
real and equal roots?
The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]
In this question, we use the concept of the solution of a quadratic equation to solve it, considering that a quadratic equation in the format:
[tex]ax^2 + bx + c = 0[/tex]
has two equal solutions if [tex]\Delta = b^2 - 4ac[/tex] is 0.
------------------------------------
In this question:
The equation is:
[tex](2k+1)x^2 + 2x = 10x - 6[/tex]
Placing in the correct format:
[tex](2k+1)x^2 + 2x - 10x + 6 = 0[/tex]
[tex](2k+1)x^2 - 8x + 6 = 0[/tex]
Thus, the coefficients are: [tex]a = 2k + 1, b = -8, c = 6[/tex]
------------------------------------
Delta:
We want it to be positive, so:
[tex]\Delta = b^2 - 4ac[/tex]
[tex]\Delta = 0[/tex]
[tex]b^2 - 4ac = 0[/tex]
[tex](-8)^2 - 4(2k+1)(6) = 0[/tex]
[tex]64 - 48k - 24 = 0[/tex]
[tex]-48k + 40 = 0[/tex]
[tex]-48k = -40[/tex]
[tex]48k = 40[/tex]
[tex]k = \frac{40}{48}[/tex]
[tex]k = \frac{5}{6}[/tex]
The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]
A similar question is found at https://brainly.com/question/12144265
plz help!! will mark brainliest!!
Answer:
correct me if I'm but i think the net cash flow is 3,790 because 2,040 a month income and 1,750 a month for other stuff. 2,040+1,750=3,790
Step-by-step explanation:
Rectangle ABCD is similar to rectangle JKLM. AB = 12, BC = 8, CD = 12, DA = 8, and JK = 15. What is the scale factor from JKLM to ABCD? Reduce all answers.
Answer:
4/5 or 0.8
Step-by-step explanation:
this problem description is not very precise. it leaves out the definition what corners or sides of JKLM correspond to corners and sides of ABCD.
I assume J and K correlate to A and B, and JK is a long side of JKLM.
so, we are going from JKLM to ABCD.
that means we are going from larger to smaller (as JK = 15 and therefore larger than AB = 12).
what is the scale factor to go from 15 to 12 ?
15 × x = 12
x = 12/15 = 4/5 or 0.8
The length, breadth and thickness of a brick is 18 cm, 8 cm, and 5 cm respectively. Find the area of the widest part of the brick. Also find the volume of the brick.
Answer:
area = 8 × 18 = 144 cm^2
volume 8×18×5 = 720cm^3
Find the volume of each figure. Round your answers to the nearest tenth, if necessary
Answer:
1.92 m³
hopefully this answer can help you to answer the next question.
Ive never really understood 8th-9th grade volume, could use some help
The answer is B
Eplanation:
V = pi * r² * (h/3)
Then from here you just make h the subject of the formula:
h = (V * 3)/(pi * r²)
h = (393*3)/[3.14* (10/2)²]
h = 15.01910828 ft
which is rounded to 15 ft...B
:)
Find the area of the triangle.
Answer:
B
Step-by-step explanation:
area=1/2×32×6.1=16×6.1=97.6 yd²
Answer:
Choice B. 97.6 yd^2
Step-by-step explanation:
B×W×.5= A
Please help me
A person starts walking from home and walks: 6 miles East 6 miles Southeast 3 miles South 5 miles Southwest 2 miles East This person has walked a total of 22Correct miles Find the total displacement vector for this walk: If this person walked straight home, they'd have to walk miles
Answer:
1) The total displacement vector is ((16 + √2)/2, -(6+11·√2)/2)
2) The number of miles they'd have to walk is approximately 13.856 miles
Step-by-step explanation:
1) The distance, direction, and location of the path of the walk the person takes, are listed as follows;
Start location, (0, 0)
6 miles East walk to location, (6, 0)
6 miles Southeast to location, (6 + 3·√2, -3·√2)
3 miles South to location, (6 + 3·√2, -3·√2 - 3)
5 miles Southwest to location, (6 + 3·√2 - 2.5·√2, -3·√2 - 3 - 2.5·√2)
2 miles East to location, (6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2)
(6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2) = ((16 + √2)/2, -(6+11·√2)/2)
Therefore the destination coordinates is ((16 + √2)/2, -(6+11·√2)/2)
The total displacement vector, [tex]\underset{d}{\rightarrow}[/tex] = ((16 + √2)/2, -(6+11·√2)/2)
d = (16 + √2)/2)·i - (6+11·√2)/2)·j
2) If the person walked straight home, the number of miles they'd have to walk, [tex]\left | \underset{d}{\rightarrow} \right |[/tex], is given as follows;
[tex]\left | \underset{d}{\rightarrow} \right | = \sqrt{\left(\dfrac{16 +\sqrt{2} }{2} \right)^2 + \left(-\dfrac{6 + 11 \cdot \sqrt{2} }{2} \right)^2 } = \sqrt{134 + 41 \cdot \sqrt{2} }[/tex]
Therefore;
If the person walked straight home, the number of miles they'd have to walk [tex]\left | \underset{d}{\rightarrow} \right | \approx 13.856 \ miles[/tex]
BRAINLIEST Which equation could be solved using this application of the quadratic formula?
A.
x2 + 1 = 2x − 3
B.
x2 – 2x − 1 = 3
C.
x2 + 2x − 1 = 3
D.
x2 + 2x − 1 = -3
The quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.
What is the quadratic formula?A standard quadratic equation of the form ax² + bx + c = 0, can be solved using the quadratic formula, which is given as:
[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
How to solve the question?In the question, we are asked for the quadratic equation, which could be solved using this application of the quadratic formula:
[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]
To find the quadratic equation for which we use the quadratic formula
[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]
we compare this equation with the standard quadratic formula,
[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
to get a = 1, b = 2, and c = -4, to get the standard quadratic equation, ax² + bx + c = 0, as (1)x² + (2)x + (-4) = 0, or x² + 2x - 4 = 0.
Now, we convert the given options in the standard form to check for the correct choice:
A. x² + 1 = 2x - 3 ⇒ x² - 2x + 4 = 0, which is not the correct choice.B . x² - 2x - 1 = 3 ⇒ x² - 2x - 4 = 0, which is not the correct choice.C. x² + 2x - 1 = 3 ⇒ x² + 2x - 4 = 0, which is the correct choice.D. x² + 2x - 1 = -3 ⇒ x² + 2x + 2 = 0, which is not the correct choice.Thus, the quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.
Learn more about the quadratic formula at
https://brainly.com/question/1214333
#SPJ2
find the missing side lengths answered in the simplest radical form with the denominator rationalized
9514 1404 393
Answer:
u = 7√2; v = 7
Step-by-step explanation:
The ratios of side lengths in an isosceles right triangle are ...
1 : 1 : √2 = 7 : v : u
Then v = 7 and u = 7√2.
Find the value of x in Circle O.
Answer:
x=8
Step-by-step explanation:
x^2+15^2=17^2, x=sqrt(64)=8
find the distance of gap d
Answer:
[tex]\displaystyle d \approx 15.8768[/tex]
Step-by-step explanation:
We want to find the distance of d or AB.
From the right triangle with a 35° angle, we know that:
[tex]\displaystyle \tan 35^\circ = \frac{50}{PB}[/tex]
And from the right triangle with a 42° angle, we know that:
[tex]\displaystyle \tan 42^\circ = \frac{50}{PA}[/tex]
AB is PA subtracted from PB. Thus:
[tex]\displaystyle d = AB = PB - PA[/tex]
From the first two equations, solve for PB and PA:
[tex]\displaystyle \frac{1}{\tan 35^\circ } = \frac{PB}{50} \Rightarrow PB = \frac{50}{\tan 35^\circ}[/tex]
And:
[tex]\displaystyle \frac{1}{\tan 42^\circ } = \frac{PA}{50} \Rightarrow PA = \frac{50}{\tan 42^\circ}[/tex]
Therefore:
[tex]\displaystyle d = AB = \frac{50}{\tan 35^\circ} - \frac{50}{\tan 42^\circ}[/tex]
Using a calculator:
[tex]\displaystyle d= AB \approx 15.8768[/tex]
What is the factored form of the expression 3x^2 + 6x – 24
Answer:
(3)(x + 4)(x-2)
Step-by-step explanation:
3x^2 + 6x – 24
3(x^2 + 2x - 8)
(3)(x + 4)(x-2)
Answer:
3(x - 2)(x + 4).
Step-by-step explanation:
3x^2 + 6x – 24
= 3(x^2 + 2x - 8)
= 3(x - 2)(x + 4).
Simplify this expression.
I need u again pls
Answer:
The answer is the Second Option
Step-by-step explanation:
Answer:
the second one sqrt(10) + sqrt(15) -sqrt(14) - sqrt(21)
Step-by-step explanation:
common ratio of the geometric sequence 6,42,294
9514 1404 393
Answer:
7
Step-by-step explanation:
If there is a common ratio, it can be found by finding the ratio of any two adjacent terms:
42/6 = 7
The common ratio is 7.
Michael has a project due in exactly 83 hours. It is currently 8:30 on a Monday morning. What time is his project due
Answer: it wll be thursday at 7:30PM
Change 400cm into mm
Answer:
4,000mm
Step-by-step explanation:
I tryed my best
Answer:
mate...
cm to mm is by multiplying 10
400 * 10 = 4000mm
brainliest l m a o