Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations.

using the t statistic.

With another study, where you also plan on evaluating a mean using the t statistic, you have a sample of n = 21 that has an SS of 500. What is the variance for the sample?

A. 5.00

B. 22. 36

C. 25

D. 250,000

Answer:

The distance is 87.5 miles

Step-by-step explanation:

We can use a ratio to solve

1 in              3.5 inches

-----------  = ----------------

25 miles          x miles

Using cross products

1x = 3.5 * 25

x =87.5

The distance is 87.5 miles

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▹ Answer

87.5 miles

▹ Step-by-Step Explanation

[tex]\frac{1}{25} * \frac{3.5}{x} \\\\1 * 3.5 = 3.5\\25 * 3.5 = 87.5 \\\\Actual Distance = 87.5 miles[/tex]

Hope this helps!

CloutAnswers ❁

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Answer:

The two numbers are 1 and 2.

Step-by-step explanation:

Let the two numbers be a and b.

One number is twice another, so let's let b=2a.

Their reciprocals are 3/2. Thus:

[tex]\frac{1}{a}+\frac{1}{b} =\frac{3}{2}[/tex]

Substitute and solve for a:

[tex]\frac{1}{a}+\frac{1}{2a} =\frac{3}{2}\\[/tex]

Combine the fractions by forming a common denominator by multiplying the left term by 2:

[tex]\frac{2}{2a} +\frac{1}{2a}=\frac{3}{2}[/tex]

Combine and cross-multiply:

[tex]3/2a=3/2\\6a=6\\a=1\\b=2(1)=2[/tex]

Thus, the two numbers are 1 and 2.

Answer:

Step-by-step explanation:

Given that

sin(2θ)+sinθ=0

We know that

sin(2θ)=2 sinθ x cosθ

Therefore

2 sinθ x cosθ + sinθ=0

sinθ(2 cosθ+1)=0

sinθ= 0

θ=0

2 cosθ+1=0

cosθ= - 1/2

θ=120°

_______________________________________________________

[tex]sin 2\theta=\sqrt{3cos\theta}[/tex]

By squaring both sides

[tex]sin^2 2\theta={3cos\theta}[/tex]

4 sin²θ x cos²θ=3 cosθ

4 sin²θ x cos²θ - 3 cosθ=0

cos θ = 0

θ= 90°

4 sin²θ=3

θ=60°

Answer:

the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days

Step-by-step explanation:

Given that :

Mean  = 265

standard deviation = 14

The formula for calculating the z score is [tex]z = \dfrac{x -\mu}{\sigma}[/tex]

x = μ + σz

At middle of 50% i.e 0.50

The critical value for [tex]z_{\alpha/2} = z_{0.50/2}[/tex]

From standard normal table

[tex]z_{0.25}=[/tex] + 0.67  or -0.67  

So; when z = -0.67

x = μ + σz

x = 265 + 14(-0.67)

x = 265 -9.38

x = 255.62

when z = +0.67

x = μ + σz

x = 265 + 14 (0.67)

x = 265 + 9.38

x = 274.38

the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days

Answer:

In this question, we shall be accepting the null hypothesis H0 since the critical value is greater than the test statistic value

Step-by-step explanation:

Here in this question, we want to make a conclusion about the null hypothesis H0.

To make or give the correct conclusion about the null hypothesis in this case, we shall need to compare the absolute value of the test statistic used against the value of the critical value.

Hence, we draw a conclusion if the test statistic is larger or smaller than the critical value.

From the value given in the question, we can see that the test statistic given as 1.68 is lesser in value compared to the critical value given as 1.96.

In this kind of case, the conclusion that we shall be drawing is that we will accept the null hypothesis H0 and reject the alternative hypothesis

With such a larger sample size, the margin of error lowers (grows or decreases), whereas, at a higher confidence level, it increases (increases or declines).

             Margin of error [tex](E) = Z_c * {\frac{\sigma}{\sqrt{n}}}[/tex]

Find out more about the margin of error here:

brainly.com/question/10501147

Answer:

25 : 63 and 63 : 25

Step-by-step explanation:

This is a complete question

The table shows the educational attainment of the population of Country X, ages 25 and over. Use the data in the table, expressed in millions, to solve the problem. of 10 questions ge 1: Ages 25 and Over, in Miltions 4 Years igh College 4 Years High School (Less than College School Only 4years) Cor Moce) Total Male 29 19 25 89 Female 11 28 23 Total 2 57 42 50 [176 Find the odds in favor and the odds against a randomty selected person from Country X.age 25 and over, with the stated amount of education. four years (or more) of college 21:67, 67:21 63:88, 88:63 25:63, 63:25 25:88, 88:25

According to the question, the relevant data provided in the question for the solution is as follows

Four years or more of college

Number of students = 50

Total = 176 students

Number of students does not belong = 126

So odds in favor is

= 50 : 126

= 25 : 63

And automatically out against the favor is 63 : 25

Answer:

|88-x| ≤ 14

Step-by-step explanation:

their score has to be within 14 points of 88.

if their score is above 88, the number will be negative, but the absolute value makes the number positive. if that number is still within 14 of 88, they pass.

if their score is below 88, the number will be negative, and the absolute value keeps the number positive. if that number is still within 14 of 88, they pass.

Answer: A,C, and D

Step-by-step explanation:

Answer:

the answer to this question may be option B, C and D

Step-by-step explanation:

Hello, there!!

The answer would be 41/9.

The reason for above answer is to change any mixed fraction into improper fraction we should follow a simple step:

look here,

=[tex] \frac{4 \times 9 + 5}{9} [/tex]

we get 41/9.

Hope it helps...

The given fraction into the improper fraction should be [tex]\frac{41}{9}[/tex]

Given that,

[tex]= 4\frac{5}{9}\\\\ = \frac{41}{9}[/tex]

Here we multiply the 9 with the 4 it gives 36 and then add 5 so that 41 arrives.

learn more about the fraction here: https://brainly.com/question/1301963?referrer=searchResults

Answer:

3 · |x+6|

Step-by-step explanation:

Write out what you see. "Three times" is 3 · something; "the absolute value of the sum of a number and 6" is |number + 6|. We'll use x for our number. Put it all together and you get 3 · |x+6|

The expression of the statement, Three times the absolute value of the sum of a number and 6 is  [tex]\[3\left| n+6 \right|\][/tex] .

Learn more about the representation of an expression:

https://brainly.com/question/10905086?referrer=searchResults

#SPJ2

Answer: I think it is C

Step-by-step explanation:

There is no answer because A can be many solutions, B is x = -25, you just cannot solve C, and D is y = 7/6

Answer:

330

Step-by-step explanation:

If d = distance, t = time, and s = speed, then the relationship between the 3 is s * t = d.

Solve for speed by dividing the distance over the time, s = d/t. Then, plug in the speed which in this case is 55 mph and then multiply by the time of 6 hours.

Answer: 669

Step-by-step explanation:

Given, In a Gallup poll of randomly selected​ adults, 66% said that they worry about identity theft.

i.e. The proportion of adults said that they worry about identity theft. (p) = 0.66

Sample size : n= 1013

Then , Mean for the sampling distribution of sample proportion  = np

= (1013) × (0.66)

= 668.58 ≈ 669  [Round to the nearest whole number]

Hence, the mean of those who do not worry about identify theft is closest to​ 669 .

Answer:

  his path

Step-by-step explanation:

In order to determine the total distance driven from one place to another, you need to know the path taken.

Answer:

Change due is 3.50

Step-by-step explanation:

20.00-16.50 is 3.50

Answer: $3.50

Step-by-step explanation:

You subtract 20 from 16.50.

Answer:

see explanation

Step-by-step explanation:

(43)

3[tex]x^{5}[/tex] - 75x³ ← factor out 3x³ from each term

= 3x³(x² - 25) ← this is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , thus

x² - 25 = x² - 5² = (x - 5)(x + 5)

Thus

3[tex]x^{5}[/tex] - 75x³ = 3x³(x - 5)(x + 5)

(44)

81c² + 72c + 16 ← is a perfect square of the form

(ac + b)² = a²c² + 2abc + b²

Compare coefficients of like terms

a² = 81 ⇒ a = [tex]\sqrt{81}[/tex] = 9

b² = 16 ⇒ b = [tex]\sqrt{16}[/tex] = 4

and 2ab = 2 × 9 × 4 = 72

Thus

81c² + 72c + 16 = (9c + 4)²

1. 3x^5 -75x³

=3x³(x²-25)

=3x³(x²-5²)

=3x³(x-5)(x+5)

2. 81c²+72c+16

=81c²+36c+36c+16

=9c(9c+4)+4(9c+4)

=(9c+4)(9c+4)

=(9c+4)²

Answer:

csctheta= [tex]\frac{\sqrt{13} }{3}[/tex]

Step-by-step explanation:

answer is provided on top

The value of the [tex]\rm cosec \theta = \frac{\sqrt{13} }{3}[/tex]. Cosec is found as the ratio of the hypotenuse and the perpendicular.

The field of mathematics is concerned with the relationships between triangles' sides and angles, as well as the related functions of any angle

The given data in the problem is;

[tex]\rm cot \theta = \frac{2}{3}[/tex]

The [tex]cot \theta[/tex] is found as;

[tex]\rm cot \theta = \frac{B}{P} \\\\ \rm cot \theta = \frac{2}{3} \\\\ B=2 \\\\ P=3 \\\\[/tex]

From the phythogorous theorem;

[tex]\rm H=\sqrt{P^2+B^2} \\\\ \rm H=\sqrt{2^2+3^2} \\\\ H=\sqrt{13} \\\\[/tex]

The value of the cosec is found as;

[tex]\rm cosec \theta = \frac{H}{P} \\\ \rm cosec \theta = \frac{\sqrt{13} }{3}[/tex]

Hence the value of the [tex]\rm cosec \theta = \frac{\sqrt{13} }{3}[/tex].

To learn more about the trigonometry refer to the link;

https://brainly.com/question/26719838

Answer:

The same mean  ⇒  the same symmetry axis

Bigger standard deviation major spread

Step-by-step explanation: See Annex

The annex shows two different normal curves:

1.-  N (μ₀ ; σ₁ )

2.- N (μ₀ ; σ₂ )

Where   σ₁  > σ₂

They both have the same symmetry  axis ( they have the same mean and both curves have to be symmetrically related to the mean )

Normal distribution curves spread symmetrically at both sides of the mean, but the wider curve is the one that has the bigger standard deviation.  Standard deviation is a measure of the spread of the curve.

Whenever deviation is high, the data is more dispersed than when deviation is low.

Let the mean be 2.

Let the standard deviation be 0.3 for first graph. The data is more clustered around mean.

Let the standard deviation be 0.6 for second graph. The data is less clustered more dispersed from mean.

For more information, refer this link:

https://brainly.com/question/12421652

Answer:

(a) 50%

(b) 47.5%

(c) 2.5%

Step-by-step explanation:

According to the honest coin principle, if the random variable X denotes the number of heads in n tosses of an honest coin (n ≥ 30), then X has an approximately normal distribution with mean, [tex]\mu=\frac{n}{2}[/tex] and standard deviation, [tex]\sigma=\frac{\sqrt{n}}{2}[/tex].

Here the number of tosses is, n = 2500.

Since n is too large, i.e. n = 2500 > 30, the random variable X follows a normal distribution.

The mean and standard deviation are:

[tex]\mu=\frac{n}{2}=\frac{2500}{2}=1250\\\\\sigma=\frac{\sqrt{n}}{2}=\frac{\sqrt{2500}}{2}=25[/tex]

(a)

To not lose any money the even rolls has to be 1250 or more.

Since, μ = 1250 it implies that the 50th percentile is also 1250.

Thus, the probability that by the end of the evening you will not have lost any money is 50%.

(b)

If the number of "even rolls" is 1250, it implies that the percentile of 1250 is 50th.

Then for number of "even rolls" as 1300,

1300 = 1250 + 2 × 25

        = μ + 2σ

Then P (μ + 2σ) for a normally distributed data is 0.975.

⇒ 1300 is at the 97.5th percentile.

Then the area between 1250 and 1300 is:

Area = 97.5% - 50%

        = 47.5%

Thus, the probability that the number of "even rolls" will fall between 1250 and 1300 is 47.5%.

(c)

To win $100 or more the number of even rolls has to at least 1300.

From part (b) we now 1300 is the 97.5th percentile.

Then the probability that you will win $100 or more is:

P (Win $100 or more) = 100% - 97.5%

                                   = 2.5%.

Thus, the probability that you will win $100 or more is 2.5%.

Answer:

The sample correlation coefficient r = 0.9113

Step-by-step explanation:

In this question, we are interested in calculating the sample correlation coefficient.

From the question, we are given;

We are given that,

The sample standard deviation of stock X = 4.665

The sample standard deviation of stock Y = 8.427

The sample covariance = 35.826

Mathematically, the Pearson correlation coefficient "r", it is given as;

r = (co-variance of X and Y)/(standard deviation of X * Standard deviation of Y)

Inputing these values, we have;

r = (35.826)/(4.665 * 8.427) = 0.9113

Answer:

a) 0.36

b) 0.3

c) Yes

Step-by-step explanation:

Given:

Probability of no traffic delay in one period, given no traffic delay in the preceding period = P(No_Delay) = 0.9

Probability of finding a traffic delay in one period, given a delay in the preceding period = P(Delay) = 0.6

Period considered = 30 minutes

a)

Let A be the probability that for the next 60 minutes (two time periods) the system will be in the delay state:

As the Probability of finding a traffic delay in one period, given a delay in the preceding period is 0.6 and one period is considered as 30 minutes.

So probability that for the next two time periods i.e. 30*2 = 60 minutes, the system in Delay is

P(A) = P(Delay) * P(Delay) =  0.6 * 0.6 = 0.36

b)

Let B be the probability that in the long run the traffic will not be in the delay state.

This statement means that the traffic will not be in Delay state but be in No_Delay state in long run.

Let C be the probability of one period in Delay state given that preceding period in No-delay state :

P(C) =  1 - P(No_Delay)

        = 1 - 0.9

P(C) = 0.1

Now using P(C) and P(Delay) we can compute P(B) as:

P(B) = 1 - (P(Delay) + P(C))

      = 1 - ( 0.6 + 0.10 )

      = 1 - 0.7

P(B) = 0.3

c)

Yes this assumption should be questioned for this traffic problem because it implies that  traffic will be in Delay state for the 30 minutes and just after 30 minutes, it will be in No_Delay state. However, traffic does not work like this in general and it makes this scenario unrealistic. Markov process model can be improved if probabilities are modeled as a function of time instead of being presented as constant (for 30 mins).

Answer:

Student t-distribution.

Step-by-step explanation:

In this scenario, a test is being conducted to test the difference between two population "means" using data that are gathered from a matched pairs experiment. If the paired differences are normal, then the distribution used for testing is the student t-distribution.

In Statistics and probability, a student t-distribution can be defined as the probability distribution which can be used to estimate population parameters when the population variance is not known (unknown) and the sample population is relatively small. The student t-distribution is a statistical distribution which was published in 1908 by William Sealy Gosset.

A student t-distribution has a similar curve with the normal distribution curve, except that it is fatter and a little bit shorter.

Answer:

108.

Step-by-step explanation:

-7, -2, 3, 8 is an arithmetic sequence with a1 (first term) = -7 and common difference (d)  = 5.

The 24th term = a1 + (24 - 1)d

=  -7 + 23 * 5

= -7 + 115

= 108.

Answer:

1/8

Step-by-step explanation:

3/8-1/8-1/8=1/8

Work Shown:

A = P*(1+r)^t

A = 21450*(1+(-0.08))^5

A = 21450*(1-0.08)^5

A = 21450*(0.92)^5

A = 21450*0.6590815232

A = 14137.29867264

A = 14,137.30

Notice how I used a negative r value to indicate depreciation rather than growth.

Answer:

Step-by-step explanation:

Given the following logarithmic expressions [tex]log_ax = 3, log_ay = 7, log_az = -2[/tex], we are to find the value of [tex]log_a(\frac{x^3y}{z^4} )[/tex]

[tex]from\ log_ax = 3, x = a^3\\\\from\ log_ay = 7,y = a^7\\\\from\ log_az = -2, z = a^{-2}[/tex]Substituting x = a³, y = a⁷ and z = a⁻² into the log function [tex]log_a(\frac{x^3y}{z^4} )[/tex] we will have;

[tex]= log_a(\frac{x^3y}{z^4} )\\\\= log_a(\dfrac{(a^3)^3*a^7}{(a^{-2})^4} )\\\\= log_a(\dfrac{a^9*a^7}{a^{-8}} )\\\\= log_a\dfrac{a^{16}}{a^{-8}} \\\\= log_aa^{16+8}\\\\= log_aa^{24}\\\\= 24log_aa\\\\= 24* 1\\\\= 24[/tex]

Hence, the value of the logarithm expression is 24

Answer:

Point O represents the center of the circle

Step-by-step explanation:

HOPE IT HELPS. PLEASE MARK IT AS BRAINLIEST

Answer:

z = 83/( -c+6-t)

Step-by-step explanation:

-cz + 6z = tz + 83

Subtract tz from each side

-cz + 6z -tz= tz-tz + 83

-cz + 6z - tz = 83

Factor out z

z( -c+6-t) = 83

Divide each side by ( -c+6-t)

z( -c+6-t)/( -c+6-t)  = 83/( -c+6-t)

z = 83/( -c+6-t)