Answer: $15927.183
Step-by-step explanation:
Price of good= $29,000
Trade discount = 40½ 20¼/5
The first discount will be:
= 40½ × $29000
= $11745
Then, the price after the first discount will be:
= $29000 - $11475
= $17255
Then, the second discount will be:
= $17255 × 20¼%
= $3494.14
Then, the price after the second discount will be:
= $17255 - $3494.14
= $13760.86
The third discount will be:
= $13760.86 × 5%
= $688.043
Then, the total discount will be:
= $11745 + $3494.14 + $688.043
= $15927.183
Therefore, the trade discount is $15927.183.
Angles of triangle are in the ratio of 23:5. What is the Size of the smallest angle?
Answer:
ratio 2 : 3 : 5
size of smallest angle
[tex]180 \times \frac{2}{10} \\ = 36[/tex]
Answer:
The smallest angle of a triangle is 36°.
Step-by-step explanation:
Given, the ratio of angles of a triangle is 2 : 3 : 5
Let the angles of a triangle be ∠A, ∠B and ∠C.
∠A = 2x, ∠B = 3x, ∠C = 5x
∠A+∠B + ∠C= 180°
[sum of all the angles of a triangle is 180°]
2x + 3x + 5x = 180°
10x = 180°
x=180°/10 =18°
∠A=2x=2 x 18° = 36°
∠B = 3x = 3 x 18° = 54°
∠C = 5x = 5 x 18° = 90°
Hence, the smallest angle of a triangle is 36°.
HOPE IT HELPS!!!
Solve for x.
x – 42 = 98 – 9x
X = [?]
Answer:
x = 14
Step-by-step explanation:
x - 42 = 98 - 9x
+42 +42
x = 140 - 9x
+9x +9x
10x = 140
/10 /10
x = 14
25)
Jackson's current salary is $36,000 per year. Each year his salary is 1.04 times the previous yeal's salary. What
will his salary be in his 5th year?
OA) $42,214.92
OB) $42,114.91
Answer:
$43,799.50
Step-by-step explanation:
USing the formula:
A = P(1+r)ⁿ
n is the time = 5
1 + r = 1.04
P = 36,000
Substitute the values into the formula
A = 36000(1.04)⁵
A = 36,000(1.2166529024)
A = 43,799.50
Hence the value in the fifth year will e $43,799.50
El periodo de un movimiento circular uniforme es de
8 segundos. ¿Cuál es su velocidad angular?
Answer: I dont understand what your saying im sorry, I'd really like to help but I cant :(
HELPPPP MEEEE OUTTTT!!!
Answer:
Solution given:
Relationship between base and hypotenuse is given by Cos angle
Cos Angle(?)=base/hypotenuse
Angle{?}=Cos-¹(40/58)
Angle{?}=46°
The indicated angle is 46°
Find x in the right triangle (not drawn to scale):
Which of the following statements does not prove that ABCD is a parallelogram.
Given: A(-4, 7), B(3,0), C(2,-5) and D(-5, 2).
Answer:
answer A
Step-by-step explanation:
A=(-4,7)
C=(2,-5)
midpoint = U=((-4+2)/2, (7+(-5))/2)=(-1,1))
B=(3,0)
D=(-5,2)
midpoint = V=((3+(-5))/2,(0+2)/2)=( -1,1)
Diagonals have the same middle, the quadrilater is a parallogram.
Dividing with powers of 10
write 2^60 as an exponent with a base of 16
Recall that 2⁴ = 16. So you have
2⁶⁰ = 2⁴ˣ¹⁵ = (2⁴)¹⁵ = 16¹⁵
6. Which of the following equations has a slope of -2 and passes
through the point (3,-4).
O) y=-2x - 4
O) y=-2x + 2
O) y = -2x+3
O) y = -2x - 1
Answer:
y=-2x+2
Step-by-step explanation:
substitute either the x or y value into the equations, if you substitute x=3 and get back y=-4, the equation is correct
A parallelogram is cut out of a 12 inch by 8 inch sheet of paper there are four right triangles remnats two have the dimensions 2 inches by 9 inches and the other two have the dimensions 3 inches by 6 inches
Answer:
96 in²
36 in²
60 in²
6.51 in
Step-by-step explanation:
Given that :
Dimension of paper = 12 in by 8 in
Dimension of right triangles :
2 in by 9 in ; 3 in by 6 in
Area of sheet of paper = 12 in * 8 in = 96 in²
Area of triangle = 1/2 base * height
Therefore, area of remnant right triangle :
2 * 1/2 * 2 * 9 = 18 in²
2 * 1/2 * 3 * 6 = 18 in²
Combined area of triangle left = 18in + 18in = 36 in²
Area of parallelogram = Area of sheet - Area of triangles left
Area of parallelogram = 96in² - 36in² = 60 in²
Base, b of parallelogram = 9.22 in
Area of parallelogram = base * altitude,h
60in² = 9.22h
h = 60 / 9.22 = 6.51 in
Abel bought a mini hi-fi set for S600.
He sold it to Bob at a loss of 20%.
Bob sold it to Charles and made a profit of 5%. How much did Charles pay for it?
Answer:
$504
$600* .8 = $480
$480 * 1.05 = $504
Step-by-step explanation:
Answer:
Step-by-step explanation:
Abel:
Cost price = $ 600
Loss = 20%
Selling price = [tex]\frac{100-loss}{100}*Cost \ price[/tex]
[tex]= \frac{(100-20)}{100}*600\\\\=\frac{80}{100}*600[/tex]
= 80 * 6 = $ 480
Cost price for Bob = Selling price of Abel = $ 480
Bob's cost Price = $480
Selling price = [tex]\frac{100+Profit}{100}*CP\\\\[/tex]
[tex]= \frac{100+5}{100}*480\\=\frac{105}{100}*480[/tex]
= $ 504
Amount paid by Charles =$ 504
10 fracciones que generen decimales exactos 10 fracciones que generen decimales inexactos puros y 10 fraccionarios que generen decimales periódicos mixtos
Answer:
Un número decimal exacto es algo de la forma:
3.27
Para reescribir este número como una fracción, podemos ver que tiene dos dígitos luego del punto.
Entonces podemos multiplicar y dividir por 100 (misma cantidad de ceros que dígitos luego del punto decimal)
así obtenemos:
3.27*(100)/(100) = 327/100
Entonces la fracción 327/100 genera un decimal exacto.
Así, encontrar 10 fracciones es trivial, 10 ejemplos son:
7/10 = 0.7
314/100 = 3.14
27/10 = 2.7
27/100 = 0.27
2/10 = 0.2
25/100 = 0.25
31/10 = 3.1
12/10 = 6/5 = 1.2
131/10 = 13.1
142/100 = 1.42
Ahora, un decimal inexacto puro es algo de la forma:
3.33...
donde el 3 se repite infinitamente.
Tratemos de reescribir este número como una fracción:
primero debemos ver la cantidad de dígitos que se repiten, en este caso es uno solo, el 3, entonces multiplicamos por 10:
3.33*10 = 33.33...
Ahora, podemos restar el numero original:
33.333... - 3.333... = 30
Entonces tenemos que:
3.33*9 = 30
3.33 = 30/9
La fracción:
30/9 nos da in decimal inexacto puro.
Ahora que sabemos construirlas, 10 ejemplos pueden ser:
30/9 = 3.33....
1/3 = 0.33...
40/9 = 4.44...
50/9 = 5.55...
60/9 = 6.66...
70/9 = 7.77...
20/9 = 2.22...
55/9 = 6.11...
544/99 = 5.5959...
10/9 = 1.11...
Finalmente, un periódico mixto es algo de la forma:
1.2343434...
Es decir, el 34 se repite infinitamente, pero también tenemos un 2 luego del punto decimal, por lo que este número no es puramente periódico.
Para construirlos, podemos tomar una fracción exacta, como
1.1 y una periódica, como 1.11...
Si las sumamos, obtenemos:
1.1 + 1.11... = 2.211...
donde el uno se repetirá infinitamente.
Así, simplemente sumando las fracciones del primer caso con las del segundo, obtendremos decimales periódicos mixtos, por ejemplo:
7/10 + 55/9 = 613/90 = 0.7 + 6.11... = 6.8111....
7/10 + 10/9 = 163/90 = 0.7 + 1.11... = 1.811....
31/10 + 10/9 = 379/90 = 3.1 + 1.11... = 4.2111...
31/10 + 20/9 = 479/90 = 3.1 + 2.22... = 5.322...
31/10 + 30/9 = 579/90 = 3.1 + 3.33... = 6.4333...
27/10 + 20/9 = 443/90 = 2.7 + 2.22... = 4.922...
37/10 + 20/9 = 533/90 = 3.7 + 2.22... = 5.922...
4/10 + 10/9 = 136/90 = 0.4 + 1.11... = 1.511....
3/100 + 10/9 = 1027/900 = 0.03 + 1.11... = 1.14111...
4/10 + 20/9 = 236/90 = 0.4 + 2.22... = 2.622....
plz help me to do this
A 90 ° angle is divided into 2 angles.
Find the size of the angles.
5x+10 and 6x-41
Answer:
So required ans is 5*11+10=65 6x-41=25
Step-by-step explanation:
You can do as,
5x+10+6x-41=90
11x-31=90
11x=31+90
11x=121
x=121/11
x=11
Can someone help me with this math homework please!
Answer:
10
Step-by-step explanation:
f ( 1 ) = 18
First term ( a ) = 18
f ( n + 1 ) = f ( n ) - 2
When, n = 1
f ( 1 + 1 ) = f ( 1 ) - 2
f ( 2 ) = 18 - 2
f ( 2 ) = 16
f ( 2 ) - f ( 1 )
= 16 - 18
= - 2
Common difference ( d ) = - 2
f ( 5 )
= a + 4d
= 18 + 4 ( - 2 )
= 18 - 8
= 10
Over what interval is the function in this graph constant?
Answer:
hjjjnnnhjjjjj
Step-by-step explanation:
answer is d
The graph of $y=ax^2+bx+c$ passes through points $(0,5)$, $(1,10)$, and $(2,19)$. Find $a+b+c$.
Answer:
[tex]a+b+c=10[/tex]
Step-by-step explanation:
We are given that the graph of the equation:
[tex]y=ax^2+bx+c[/tex]
Passes through the three points (0, 5), (1, 10), and (2, 19).
And we want to find the value of (a + b + c).
First, since the graph passes through (0, 5), its y-intercept or c is 5. Hence:
[tex]y=ax^2+bx+5[/tex]
Next, since the graph passes through (1, 10), when x = 1, y = 10. Substitute:
[tex](10)=a(1)^2+b(1)+5[/tex]
Simplify:
[tex]5=a+b[/tex]
The point (2, 19) tells us that when x = 2, y = 19. Substitute:
[tex](19)=a(2)^2+b(2)+5[/tex]
Simplify:
[tex]14=4a+2b[/tex]
This yields a system of equations:
[tex]\begin{cases} 5 = a + b \\ 14 = 4a + 2b\end{cases}[/tex]
Solve the system. We can do so using elimination (or any other method you prefer). Multiply the first equation by negative two:
[tex]-10=-2a-2b[/tex]
Add the two equations together:
[tex](-10)+(14)=(-2a+4a)+(-2b+2b)[/tex]
Combine like terms:
[tex]4 = 2a[/tex]
Hence:
[tex]a=2[/tex]
Using the first equation:
[tex]5=(2)+b\Rightarrow b=3[/tex]
Therefore, our equation is:
[tex]y=2x^2+3x+5[/tex]
Thus, the value of (a + b + c) will be:
[tex]a+b+c = (2) + (3) + (5) = 10[/tex]
Now that you know the vertex, find the y-values that pair with a few x-values that are less than 2 and a few that are greater than 2.
Plsssss help!!!!!!!
What is the slope-intercept form is?
please help
yuffytdgtutidrysryrdf
Answer:
19 + 1 + 9 + 1
put any of those in the slots
Answer:
19 + 1 + 9 + 1
peace
A random sample of 13 teenagers were surveyed for a hypothesis test about the mean weekly amount spent on convenience goods. Researchers conduct a one-mean hypothesis test, at the 1% significance level, to test whether the average spent per week on convenience goods is greater than 50 dollars.
Answer:
Please find the complete question and the graph in the attached file.
Step-by-step explanation:
On the basis of the data,
The level of importance is [tex]\alpha = 0.01[/tex]
Freedom levels [tex]= n -1 = 13 -1 = 12[/tex]
For the right-tailed test, the critical value is [tex]t_c = 2.681[/tex]
(Partially t-table permitted [tex]\alpha = 0.01 \ and\ df =12[/tex])
4. If 2 Cos A-1 = 0, then the value acute value A is
Answer:
[tex]A=60^{\circ}[/tex]
Step-by-step explanation:
Given [tex]2\cos A-1=0[/tex],
Add 1 to both sides:
[tex]2\cos A=1[/tex]
Divide both sides by 2:
[tex]\cos A=\frac{1}{2}[/tex]
Take the inverse cosine of each side (note that the question stipulates that A is acute):
[tex]\arccos(\cos A)=\arccos(\frac{1}{2})[/tex]
[tex]A=\arccos(\frac{1}{2}), A\in (0^{\circ}, 90^{\circ}),\\A=\boxed{60^{\circ}}[/tex]
TRIANGLES please help!! :)
Answer:
A
Step-by-step explanation:
First, the list of congruence theorems are:
SSS
SAS
ASA
AAS
HL
SSA is not on the list, so we can cross that out
Next, ASA implies that two angles are congruent, but we only know that one pair of angles (the right angles) are congruent, so we can cross that out
After that, the angle is not connecting the congruent sides, so D is not an option
Finally, we know that the longest sides (AD / AC) are congruent to each other, one other pair of legs/sides are congruent, and the triangles are both right triangles. Therefore, we can apply HL here
Help me plss I’m lost ☺️❤️
Answer:
there is only one way to to roll a 3
1/36 = .044 = 4.4%
Step-by-step explanation:
Find the general term of the ap whose 7th term is -1 and 16th term is 17? (pls Hurry up I will mark you Brainliest and don't reply in a silly way or I'll report you)
Answer:
The answer is -13.
Step-by-step explanation:
The formula of the nth term of an AP(arthimetic progression) is a+(n-1)d.
So the 7th term will be a+6d= -1 ---(1)
The 16th term will a+15d=17 ---(2)
Subtract (2) and (1)
a+15d-(a+6d)=17-(-1)
=a+15d-a-6d=17+1
9d=18
d=18/9
d=2.
Substitute d in eq (1)
a+6(2)= -1
a+12=-1
a= -1-12= -13
Thus the general term of the ap is -13
reciprocal of. 0×7/11
Answer:
it doesn't exist
Step-by-step explanation:
the expression 0×7/11 is equivalent to 0. 1/0 isn't possible, so its reciprocal doesn't exist.
Consider two parabolas: One has equation 1 ( 4)( 4) 2 y x x =−+ . The other has the same xintercepts, but goes through the point (2,−12) How far apart are the vertices of the two parabolas
Answer:
Following are the responses to the given question:
Step-by-step explanation:
[tex]\to y=(\frac{1}{2})(x-4)(x+4)\\\\\to y=(\frac{1}{2}) (x^2-16)\\\\\to y=(\frac{1}{2})(x-0)^2-8\\\\vertex \to (0,-8)[/tex]
The general x-intercept parabola equation [tex]y=k(x-4)(x+4)[/tex]
Parabola crosses the dot (2,-12)
[tex]\to k(2-4)(2+4)=-12\\\\\to k(-2)(6)=-12\\\\\to -12k=-12\\\\\to k=\frac{-12}{-12}\\\\\to k=1[/tex]
The parabolic equation which crosses the position [tex](2,-12)[/tex] is[tex]y=(x-4)(x+4)[/tex]
[tex]\to y=(x-4)(x+4)\\\\\to y=x^2-16\\\\\to y=(x-0)^2-16\\\\vertex \to (0,-16)[/tex]
The distance among the vertices of the two parabolas:
[tex]= \sqrt{(0 - 0)^2+(-8-(-16))^2}\\\\ = \sqrt{0+(-8+16))^2}\\\\ =\sqrt{0+(8)^2}\\\\=\sqrt{(8)^2}\\\\= 8\\\\[/tex]
Who know how to do this??
Answer:
Step-by-step explanation:
With some research I found that the medians (QK, RJ, and SI) are broken into 2:1 ratios.
So what this means is that QD is twice as long as DK.
QD = 2DK
QD = 2 * 6.5
QD = 13
does anyone know this?
Answer:
The volume is approximately 50 m^3
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h where r is the radius and h is the height
The radius is 1/2 of the diameter r = 8/2 = 4
V = pi ( 4)^2 (1)
V = 16 pi
Letting pi be approximated by 3.14
V = 3.14 * 16
V = 50.24
The volume is approximately 50 m^3
