Explanation:
total resistance=(2×2)/(2+2)= 1ohms
60.96-mile distance in kilometers
Answer:
98.105610 Kilometers
Explanation:
Rounded to 8 digits
Answer:
98.11 km
Explanation:
60.96 mi (5280ft/mi)(12 in/ft)(2.54 cm/in)(1 m/ 100cm)(1 km/1000 m) = 98.10561024 km
however, reporting this precision to the nearest hundred millionth of a kilometer is silly as we only know the mile dimension to the nearest hundredth of a mile.
A hundredth of a mile is 5280/100 = 52.8 ft or just over 16 m
It would only be a little bit of a presumption to give our precision to the nearest 10 meters as I have done.
This also fits neatly into the significant digits rule. Both the original dimension and the converted dimension have four significant digits.
Name another way that energy is made
Answer:
The three major categories of energy for electricity generation are fossil fuels (coal, natural gas, and petroleum), nuclear energy, and renewable energy sources. Most electricity is generated with steam turbines using fossil fuels, nuclear, biomass, geothermal, and solar thermal energy.
Explanation:
Solar
Wind
Geothermal
Hydrogen
TidaWave
Hydroelectric
Biomass
What is the amount of force exerted by gas particles?
Answer:
Pressure is the force divided by the area on which the force is exerted, and temperature is measured with a thermometer. We gain a better understanding of pressure and temperature from the kinetic theory of gases, which assumes that atoms and molecules are in continuous random motion.
9.1 x 105 – 7.2 x 105
=
Answer:
1.9 x 10⁵
Explanation:
I ASSUME your question is supposed to read
9.1 x 10⁵ – 7.2 x 10⁵ =
9.1 - 7.2 = 1.9 and the powers are the same so just tag them along
its the same as
910000 - 720000 = 190000
1.9 x 105 could be another possibility if the question is actually posed correctly.
Driving home from school one day, you spot a ball rolling out into the street . (See the figure below) You brake for 1.50 s , slowing your 950-kg car from 16.0 m/s to 9.50 m/s.
a)What was the magnitude of the average force exerted on your car during braking?
b)What was the direction of the average force exerted on your car during braking?
c)How far did you travel while braking?
Answer:
a) 4116.67 N
b) negative (assuming car is traveling in positive direction)
c) 19.125 m
Explanation:
Part A)We can find the average force exerted on the car by using Newton's 2nd Law: F = ma.
We have the mass (950 kg) but we do not have the acceleration. Let's solve for this using kinematics.
We have the time during braking, the initial and final velocity, and we need to find the acceleration. To do this, we can use the following equation: v = v₀ + at.
v (final velocity) = 9.50 m/sv₀ (initial velocity) = 16.0 m/st (time) = 1.50 s a = ?Substitute these values into the equation.
v = v₀ + at9.50 m/s = 16.0 m/s + a (1.50 s) 9.50 = 16.0 + 1.50a -6.50 = 1.50a a = -4.333333... m/s²The car's acceleration during the braking period is -4.33 m/s², assuming the car is traveling in the positive direction.
Now, we can use this to plug into Newton's 2nd Law to find the force exerted on the car.
F = maF = (950 kg) (-4.33...) F = -4116.666667 NThe magnitude of the average force exerted on the car while braking is the absolute value, so it is 4116.67 N.
Part B)The direction of the average force is denoted in the negative sign. It is opposite the direction of the car's motion. Assuming that the car is traveling in the positive direction, the direction of the average force exerted on the car is in the negative direction since this force is slowing the car down while braking.
Part C)We can find the distance traveled during the braking period by using another kinematic equation.
We have the initial and final velocity, and the time traveled, so we can use this equation: Δx = v_avg · t.
Note that v_avg is the same thing as (v + v₀) / 2.Substitute the known values into the equation.
Δx = [(9.50 + 16.0)/2] · 1.50 Δx = 12.75 · 1.50Δx = 19.125 mThe car traveled 19.125 m while braking.
