Calculate the pressure using the formula P=1.03+ mass on syringe/area of top of syringe

Answer:

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

Explanation:

The balanced oxidation half equation is;

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

A redox reaction is actually an acronym for oxidation-reducation reaction. Since the both reactions are complementary, there can't be oxidation without reduction and there can't be reduction without oxidation.

The main characteristic of redox reactions is that electrons are transferred in the process. The number of electrons transferred is usually deduced from the balanced reaction equation. For this reaction, the balanced overall reaction equation is;

Cr2O7^2–(aq) + 6Fe^2+(aq) +14H^+(aq)→ 2Cr^3+(aq) + 6Fe^3+ (aq) + 7H2O(l)

It is clear from the equation above that six electrons were transferred. Thus six Fe^2+ ions lost one electron each in the oxidation half equation as shown in the balanced oxidation half equation above.

Answer:

c,density is the measure of compactness in a substance. Liquid particles are close together however they aren't as close as the particles in solids.

Answer

False

Explanation:

Answer:

mass ( g ) = 348 g

Explanation:

First you know : M = mole / volume (L)

in question you have the M and V and the formula of SUBSTANCE ( KF )

first you get the number of mole from equation above

so 3 = no of mole / 2

no of mole = 3 × 2 = 6 moles

and the moles equation is no of moles = mass ( g ) / molecular weight ( g/mole )

so you have already calculate the moles and you can know the MW from the Question

Mw of KF = 39 + 19 = 58

so n = mass / MW

so 6 = mass / 58

mass ( g ) = 348 g

GOOD LUCK

Answer:

38g of Cr

Explanation:

Step 1:

The balanced equation for the reaction:

2K + CrBr2 —> 2KBr + Cr

Step 2:

Determination of the masses of K and CrBr2 that reacted and the mass of Cr produced from the balanced equation.

This is illustrated below:

Molar mass of K = 39g/mol

Mass of K from the balanced equation = 2 x 39 = 78g

Molar Mass of CrBr2 = 52 + (80x2) = 212g

Mass of CrBr2 from the balanced equation = 1 x 212 = 212g

Molar Mass of Cr = 52g/mol

Mass of Cr from the balanced equation = 1 x 52 = 52g

From the balanced equation above,

78g of K reacted with 212g of CrBr2 to produce 52g of Cr.

Step 3:

Determination of the limiting reactant.

This is illustrated below:

From the balanced equation above,

78g of K reacted with 212g of CrBr2.

Therefore, 57g of K will react with = (57 x 212)/78 = 154.92g of CrBr2.

From the above calculation, we can see that a lesser mass (i.e 154.92g) than what was given ( i.e 199g) of CrBr2 is needed to react completely with 57g of K. Therefore, K is the limiting reactant and CrBr2 is the excess reactant.

Step 4:

Determination of the mass of Cr produced by the reaction.

In this case, the limiting reactant will be use because it will give the maximum yield of Cr as all of it is used up in the reaction process. The limiting reactant is K and the mass of Cr produced is obtained as follow:

From the balanced equation above,

78g of K reacted to produce 52g of Cr.

Therefore, 57g of K will produce = (57 x 52)/78 = 38g of Cr.

Therefore, 38g of Cr is produced from the reaction.

Answer:

Chemical properties can be tested without changing the substance

Explanation:

Answer: 179 of [tex]H_2O[/tex] will be produced.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} H_2=\frac{20.0g}{2.01g/mol}=9.95moles[/tex]

[tex]2H_2+O_2(g)\rightarrow 2H_2O[/tex]

According to stoichiometry :

2 moles of [tex]H_2[/tex] give =  2 moles of [tex]H_2O[/tex]

Thus 9.95 moles of [tex]H_2[/tex] will require=[tex]\frac{2}{2}\times 9.95=9.95moles[/tex]  of [tex]H_2O[/tex]

Mass of [tex]H_2O=moles\times {\text {Molar mass}}=9.95moles\times 18g/mol=179g[/tex]

Thus 179 of [tex]H_2O[/tex] will be produced.

Answer:

the answer is A heterogeneous solutions

Explanation:

Mixtures in two or more phases are heterogeneous mixtures. Examples include ice cubes in a drink, sand and water, and salt and oil. The liquid that is immiscible form heterogeneous mixtures. A good example is a mixture of oil and water.Jun 26, 2019

Answer:

The ISS provides a location in the relative safety of low Earth orbit to test spacecraft systems that will be required for long-duration missions to the Moon and Mars.

Explanation:

Answer:

An antioxidant helps in the mopping up and elimination of free radicals and a common example is Glutathione. Oxidation reactions Involves the transfer of electrons or addition of oxygen to a substance.

Antioxidants help in decreasing or prevention of the oxidation of the molecules due to free radicals being formed which causes damage in the cells of animals.

Answer:

Fusion doesn't produce runway chain reactions the way fission can, so there's no need to worry about meltdowns.

Answer:

18.0 g

Explanation:

M(H2) = 2.0 g/mol

32.0g * 1 mol/2 g= 16 mol H2

M(O2) = 32 g/mol

16.0 g * 1mol/32 g= 0.5 mol O2

                                      2H2 + O2 ---> 2H2O

from reaction              2 mol    1 mol

given                         16 mol     0.5 mol

We see that O2 is a limiting reactant.

                                    2H2 + O2 +-------> 2H2O

from reaction                         1 mol            2 mol

given                                      0.5 mol        x mol

x =(0.5*2)/1= 1 mol H2O

M(H2O)= 18 g/mol

18 g/mol* 1 mol = 18 g H2O

Answer:

I would say that the mutation has no effect on the organism, as it doesn't help or harm it.

hope this helps :)

Explanation:

Answer:

its a neutral

Explanation:

i did the test

Answer:  A basic solution is defined as a solution which has more hydroxide (OH-) ions than hydronium ions (H+)

Answer: PtF6

Explanation:  is one of seventeen known binary hexafluorides.

Answer:

nickel 48.1063%

Phosphorus 16.9245%

Oxygen 34.9692%

The percent composition of each element like nitrogen, oxygen and phosphorous in Ni₃(PO₄)₂ are 48.03%, 34.97% and 16.93% respectively.

Percent composition of any element present in any compound will be calculated as:
% comosition = (Mass of element / Mass of compound)×100%

Mass of Ni₃(PO₄)₂ compound = 366.02 g/mol

Molar mass of 3 Nitrogen atoms = 3×58.6 = 175.8 g/mol

Moar mass of 2 Phosphorous atoms = 2×31 = 62 g/mol

Moar mass of 8 Oxygen atoms = 8×16 = 128 g/mol

% comosition of Nitrogen = (175.8/366.02)×100% = 48.03%

% comosition of Oxygen = (128/366.02)×100% = 34.97%

% comosition of Phosphorous = (62/366.02)×100% = 16.93%

Hence % composition of nitrogen, oxygen and phosphorous is 48.03%, 34.97% and 16.93% respectively.

To know more about percent composition, visit the below link:

https://brainly.com/question/21044245

Answer:

4NO + 6H2O = 4NH3 + 5O2

Explanation:

Think about it this way: there are 4N's 4O's and 12H's and 10O's on both sides that's what makes it balanced

Hope this helps :)

Answer:

D

Explanation:

Answer:

[tex]m_{H_2}=0.504gH_2[/tex]

Explanation:

Hello,

In this case, since the reaction is:

[tex]2 Na + 2 H_2O \rightarrow 2 NaOH + H_2[/tex]

We notice that since there is an excess of water, we can directly compute the yielded grams of hydrogen by using the following stoichiometric procedure, considering the 2:1 molar ratio between sodium and hydrogen (notice the 2 before the sodium and the 1 before the hydrogen at the chemical reaction) and that gaseous hydrogen has a molar mass of 2 g/mol:

[tex]m_{H_2}=11.50gNa*\frac{1molNa}{22.98gNa} *\frac{1molH_2}{2.02molNa} *\frac{2gH_2}{1molH_2} \\\\m_{H_2}=0.504gH_2[/tex]

Best regards.

Answer:

0.503g of H₂ are produced

Explanation:

Based on the chemical reaction:

2 Na + 2 H₂O → 2 NaOH + H₂

2 moles of Na react with 2 moles of water to produce 2 moles of NaOH and 1 mole of H₂

11.50g of Na -limiting reactant, molar mass 22.99g/mol- are:

11.50g× (1mol / 22.99g) = 0.500 moles of Na.

As 2 moles of Na produce 1 mole of H₂:

0.500 moles of Na × (1 mole H₂ / 2 moles Na) = 0.250 moles of H₂

As molar mass of H₂ is 2.01g/mol:

0.250 moles of H₂ × (2.01g / 1mol) = 0.503g of H₂ are produced

Answer:

I believe the answer you're looking for is DNA, not sure though

Answer:

1. carboxylic acid

2. ether

3. aldehyde

4. ketone

5. amine

6. alcohol

Explanation:

Know the functional groups. If you would like me to teach you them let me know.

- Hope that helps! Please let me know if you need further explanation.

Answer:

it should be +0.46 :)

Explanation:

I just took the test and got it right.

Answer:

I think it's +1.14 V, but don't take my word for it..

Answer:

The concentration of HA is the same as concentration of H3O+ and A- produced.

Explanation:

The dissociation equation is given below:

HA(aq) + H2O (l) —> H3O+(aq) + A-(aq)

From the reaction above, we can see that the acid is monoprotic acid i.e it has only 1 ionisable hydrogen atom.

Now, from the balanced equation, we can see that the acid produced equal concentration of H3O+ and A-.

This account for the reason why the bars for H3O+ and A- have the same height as the bar for HA.

Answer:

5) You push hard on a heavy desk and try to move it. You do work on the desk: A.- Whether you move it or not, as long as you exert a force. B.- Only if the desktop moves. C.- Only if the desktop does not move. D.- Never; the desk does work on you. E.- None of the above. CAN YOU HELP ME?

B.- Only if the desktop moves.

Explanation:

No work is done if a force is exerted but no displacement occurs. A force perpendicular to the displacement does no generate work.

Answer:

It is a typical fires that started out of a lightning strike, or people carelessly starting it, or accidentally, or even arson, that went un-noticed and got out of hand.

Answer:

Explanation:

Forest fires always start by one of two ways - naturally caused or human caused. Natural fires are generally started by lightning, with a very small percentage started by spontaneous combustion of dry fuel such as sawdust and leaves. On the other hand, human-caused fires can be due to any number of reasons.

Answer:

CuFeS2

Explanation:

Calculate the moles of each substance by doing moles= mass/relative atomic mass. you should get 0.25 moles of copper and iron and 0.5 moles of sulfur. Then divide all of those numbers by 0.25 (as its the lowest value) you should get 1 for copper and iron and 2 for sulfur. This represents the ratio that they are in within the mineral.

Answer:

[tex]\large \boxed{\text{D.) 91 kPa}}[/tex]

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 15.0 L

n = 0.55 mol

T = 300 K

Calculation:

[tex]\begin{array}{rcl}pV & =& nRT\\p \times \text{15.0 L} & = & \text{0.55 mol} \times \text{8.31 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 300 K}\\15.0p & = & \text{1370 kPa}\\p & = & \textbf{91 kPa}\end{array}\\\text{The pressure in the container is $\large \boxed{\textbf{91 kPa}}$}[/tex]

Answer : A

0,15 moles of NaOH -------in-------1000ml

x moles of NaOH ---------in-------100ml

x= 0,015 moles of NaOH

final volume =150ml

0,015 moles of NaOH -------in------150ml

x moles of NaOH ------in--------1000ml

x= 0,1 moles of NaOH