Calculate the percent error in the atomic weight if the mass of a Zn electrode increased by 0.3681g and 6.514x10-3 moles of Zn was produced. You may assume the molar mass of elemental zinc is 65.38 g/mol.
a. -13.5%
b. 13.52%
c. -13.52%
d. 13.5%

Answer:

Solution given:

e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide

Solution given:

Balanced chemical equation:

[tex]\boxed{\bold{\green{Na_{2}CO_{2} +heat \rightarrow Na_{2}O +CO_{2}}}}[/tex]

when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide

f) chromium (III) hydroxide plus sulfuric acid

Balanced chemical equation:

[tex]\boxed{\bold{\green{2Cr(OH)_{3}+ 3H_{2}SO_{4} → Cr_{2}(SO_{4})_{3} + 6H_{2}O}}}[/tex]

When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.

g) aluminum metal plus chlorine gas

[tex]\boxed{\bold{\green{2Al(s) + 3Cl_2(g) \rightarrow 2AlCl_2 }}}[/tex]

When aluminum metal is added to chlorine gas Combination reaction takes place and forms aluminum chloride.

e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide

Solution given:

Balanced chemical equation:

[tex]\boxed{\bold{\green{Na_{2}CO_{2} +heat \rightarrow Na_{2}O +CO_{2}}}}[/tex]

when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide

f) chromium (III) hydroxide plus sulfuric acid

Balanced chemical equation:

[tex]\boxed{\bold{\green{2Cr(OH)_{3}+ 3H_{2}SO_{4} → Cr_{2}(SO_{4})_{3} + 6H_{2}O}}}[/tex]

When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.

g) aluminum metal plus chlorine gas

[tex]\boxed{\bold{\green{2Al(s) + 3Cl_2(g) \rightarrow 2AlCl_2 }}}[/tex]

When aluminum metal is added to chlorine gas Combination reaction takes place and forms aluminum chloride.

Answer:

[tex]\lambda=451nm[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the following equation, defined in terms of energy, Planck's constant, wavelength and speed of light:

[tex]E=\frac{hC}{\lambda }[/tex]

Thus, we solve for the wavelength as shown below:

[tex]\lambda=\frac{hC}{ E}[/tex]

And finally plug in the energy, Planck's constant and speed of light to obtain:

[tex]\lambda=\frac{6.6261 x 10^{-34} m^2 kg / s*3x10^8m/s}{4.405x10^{-19}m^2kg/s^2}\\\\\lambda=4.513x10^{-7}m*\frac{1nm}{10^{-9}m} \\\\\lambda=451nm[/tex]

Regards!

Answer:

The left side equation is:

[tex]Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}[/tex]

Explanation:

For the reaction of acetic acid HCH3CO2 with the water, The equilibrium constant equation is

[tex]HCH_{3}COO + H_{2}O \rightleftharpoons CH_{3}COO^{-} + H_{3}O[/tex]

The left side of this equilibrium constant equation will be written as shown below:

[tex]Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}[/tex]

Based on the expression given in the question, X is the effective nuclear charge, and it increases down a group.

Effective nuclear charge is the net nuclear charge that an electron in an atom experiences, after subtracting the nuclear charge shielded by other electrons.

The effective nuclear charge is denoted by Zeff and can be calculated by subtracting the number of shielding electrons from the atomic number.

Therefore, based on the expression given in the question, X is the effective nuclear charge, and it increases down a group.

Learn more about effective nuclear charge at: https://brainly.com/question/13664060

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Answer:

[tex]\Delta G=-541.4kJ/mol[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to write out the described chemical reaction as shown below:

[tex]H_2+F_2\rightarrow 2HF[/tex]

Now, we set up the expression for the calculation of the standard free energy change, considering the free energy of formation of each species, specially those of H2 and F2 which are both 0 because they are pure elements:

[tex]\Delta G=2\Delta G_f^{HF}-(\Delta G_f^{H_2}+\Delta G_f^{F_2})\\\\\Delta G=2*-270.70kJ/mol-(0kJ/mol+0kJ/mol)\\\\\Delta G=-541.4kJ/mol[/tex]

Regards!

Answer:

Explanation:

The reaction between 2 chloro- 2 methyl pentane and sodium iodide takes place through SN2 mechanism . iodide ion is the nucleophile which attacks the substrate . The rate of such reaction depends upon concentration of both the nucleophile and the substrate .

Hence rate of reaction will be increased by 2 x 2 = 4 times.

option D ) is correct.

Explanation:

The given reaction represents the reaction between a tertiary alkyl halide that is 2-chloro-2-methylpentane and a nucleophile that is NaI.

This reaction favors SN1 mechanism which has order one.

So, the given reaction follows first-order kinetics.

For a first-order reaction, the rate law is:

rate =k [A]

That means the rate of the reaction is dependent on the concentration of reactants.

So, when the concentration of the reactant is doubled then, the rate of the reaction is also doubled.

Among the given options the correct answer is option B) It would double the rate.

Answer:

Following are the responses to the given points:

Explanation:

For question 1:

Butanoic acid, butane, and butanone are also the three chemicals most dissolve in water. Its intermolecular force forces are produced by carboxylic acid functional groups with water.

For question 2:

Butanoic acid is a rancid buffer.

Methanoic acid is responsible for the stinging red ants

For question 3:

Methyl butanoate's chemical structure.

Explanation:

the carbon would be sp3 hybridized, and it doesn't matter which carbon, since either of them have a full octet

Answer:

2

Explanation:

Lead(|V) fluoride

Ammonium Nitrate

Lithium sulfide

For the rules, I don't know what you were taught. I just do it intuitively since I have done so much chemistry.

The first one the roman numerals represents the charge of the lead which much match the 4- charge from the 4 fluorides.

The second one is just two polyatomic ions which you just have to remember.

The last one is the typical ionic compound naming technique i guess.

Answer:

Pilot scale up

Explanation:

Preformulation studies are carried out on candidate drug molecules that show sufficient pharmacological promise in animal model(pharma approach).

It involves preliminary study of the properties of a drug which is considered a potentially active ingredient against a particular disease condition.

Scale-up is the term used to refer to the increase in the batch size of a product. This is only done after a drug has been proven successful against the target disease after extensive pilot studies.

Scale-up is the last operation carried out when a drug has passed through all stages. It is not included in preliminary preformulation studies

Answer:

Option A. 1:1

Explanation:

From the question given above, the following data were obtained:

Li => 1s² 2s¹

Cl => 1s² 2s²2p⁶ 3s²2p⁵

Lithium (Li) will form compound with Cl by losing 1 electron as shown below:

Li —> Li⁺ + e¯ ..... (1)

Cl on the other hand will accept 1 electron from Li to form the chloride ion, Cl¯ as shown below:

Cl + e¯ —> Cl¯ ...... (2)

Combining equation 1 and 2, we have:

Li + Cl + e¯ —> Li⁺ + Cl¯ +

Cancel e¯ from both side

Li + Cl —> Li⁺Cl¯

Thus, the ratio of metallic cation (+) to non-metallic anion (-) in the compound is 1:1

Answer: 0.085 (Ms)⁻¹

Explanation: Half life = 12 s

is the initial concentration = 0.98 M

Half life expression for second order kinetic is:

k = 0.085 (Ms)⁻¹

The rate constant for this reaction is 0.085 (Ms)⁻¹ .

Answer:

I think you can make 26, hope this helped.

Explanation:

Explanation:

The "baby" plant grows entirely from stored energy and food from the cotyledons until it reaches sunlight

Answer:

Alkenes, Markovnikov's, Alkenes, Alkyl halides, and less.

Explanation:

Alkenes must undergo addition because they have easily broken π bonds.

Markovnikov's rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom.

Alkenes are unsaturated hydrocarbons because they have fewer than the maximum number of hydrogen atoms per carbon.

Alkyl halides have good leaving groups and therefore readily undergo substitution and elimination reactions.

In hydroboration, the boron atom bonds to the less substituted carbon.

Answer: Mendeleev predicted elements that would later be discovered.

Answer:

0.147 mol

Explanation:

Step 1: Calculate the volumetric concentration (Cv)

We will use the following expression.

Cv = Cg × ρ

Cv = 98.0 g%g × 1.84 g/mL = 180 g%mL

Step 2: Calculate the molarity of sulfuric acid

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

M = 180 g / 98.08 g/mol × 0.100 L = 18.4 M

Step 3: Calculate the moles of solute in 8.00 mL of solution

8.00 × 10⁻³ L × 18.4 mol/L = 0.147 mol

Answer:

19.3 g of NaCl can be produced

Explanation:

We state the reaction:

Cl₂ (g) + 2NaI (s) →  2NaCl (s) + I₂ (s)

We need to determine limiting reagent:

15.4 g . 1mol /70.9g = 0.217 moles of chlorine

49.6 g . 1mol / 149.89g = 0.331 moles of NaI

Ratio is 1:2. 1 mol of chlorine reacts to 2 moles of NaI

0.217 moles may react to (0.217 . 2)/1 = 0.434 moles of NaI

It is ok to say the NaI is the limting reactant because we need 0.434 moles of it and we only have 0.331.

Ratio is 2:2.

0.331 moles of NaI can produce 0.331 moles of NaCl

We convert mass to moles: 0.331 mol . 58.45g /mol = 19.3 g

Answer:

Its atomic number is 14 and its atomic mass is 28. The most common isotope of uranium has 92 protons and 146 neutrons. Its atomic number is 92 and its atomic mass is 238 (92 + 146).

Answer:

2 concentrations

Explanation:

Gogle - " The half-life of a reaction is the time required for a reactant to reach one-half its initial concentration or pressure. For a first-order reaction, the half-life is independent of concentration and constant over time. "

Answer:

D. all of the above

Explanation:

A and C are verified by Keplar's laws of planetary motion.

B is verified by the equatorial and polar aces of the Planet.

Answer:

c

Explanation:

they dont have to orbit the sun specifically and are commonly more ovoid than spherical

Answer:

The answer is D. The energy possessed by an electron at a set distance from the nucleus.

Explanation:

Energy levels (also called electron shells) are fixed distances from the nucleus of an atom where electrons may be found. Electrons are tiny, negatively charged particles in an atom that move around the positive nucleus at the center.

Energy levels are the fixed amount of energy that a system described by quantum mechanics, such as a molecule, atom, electron, or nucleus, can have.

An energy level is the energy possessed by an electron at a set distance from the nucleus. Therefore, option D is correct.

Any discrete value from a set of total energy values for a subatomic particle constrained by a force to a finite space or for a system of such particles, such as an atom or a nucleus, is referred to as the energy level, also known as the energy state, in physics.

Since an electron's rotation in a shell is linked to a specific amount of energy. When it moves from one energy level to another, or when it jumps to another shell, the energy changes. As a result, a shell also indicates an electron's energy along with its location, and these are known as energy levels.

The shell or orbital that an electron is in with respect to the atom's nucleus is referred to as its primary energy level.

Thus, option D is correct.

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https://brainly.com/question/17396431

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Answer:

3: Lactone

Explanation:

Lactones are defined as carboxylic esters that contain the structure (−C(=O)−O−) which is essentially showing that an ester has now become part of the chemical structure of the ring.

Thus, looking at the question, it has the structure as defined in Lactones.

Thus, we can say that the compound is a Lactone.

Answer:

a

Explanation:

Beer-Lambert Law shows the relationship between the factors affecting the absorbance of a sample in relation to the concentration. These factors are:

the concentration c, path length (l), and the molar absorptivity (ε).

As a result, more radiation is assimilated as the concentration rises, and the absorbance rises as well. However, the longer the path length, the increase in the number of molecules and the higher the absorbance.

Thus, the straight-line equation for Beer-Lambert's law is:

A = εcl

From the above explanation, the option that doesn't relate to the deviations from linearity of Beer's law plot is in Option (a).

Answer:

[tex]Pb^{2+}(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+Pb(s)[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to write the complete molecular equation as shown below:

[tex]Pb(NO_3)_2(aq)+Ni(s)\rightarrow Ni(NO_3)_2(aq)+Pb(s)[/tex]

Now, we can separate the nitrates in ions as they are aqueous to obtain:

[tex]Pb^{2+}(aq)+2(NO_3)^-(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+2(NO_3)^-(aq)+Pb(s)[/tex]

And then, we cancel out the nitrate ions as the spectator ones, for us to obtain the net ionic equation:

[tex]Pb^{2+}(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+Pb(s)[/tex]

Best regards!

Answer:

3.07 Cal/g

Explanation:

Step 1: Calculate the heat absorbed by the calorimeter

We will use the following expression.

Q = C × ΔT

where,

Q = 37.60 kJ/°C × 2.29 °C = 86.1 kJ

According to the law of conservation of energy, the heat released by the candy has the same magnitude as the heat absorbed by the calorimeter.

Step 2: Convert 86.1 kJ to Cal

We will use the conversion factor 1 Cal = 4.186 kJ.

86.1 kJ × 1 Cal/4.186 kJ = 20.6 Cal

Step 3: Calculate the number of Cal per gram of candy

20.6 Cal/6.70 g = 3.07 Cal/g

Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together. After the salt compounds are pulled apart, the sodium and chloride atoms are surrounded by water molecules, as this diagram shows. Once this happens, the salt is dissolved, resulting in a homogeneous solution.

hope this helps you

have a nice day:)

D.22

is my answer than welcome

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