Calculate the number of moles

309 grams of (SF)4 = how many moles of (SF)4

Answers

Answer 1

Answer:

2.85 mol

Explanation:

Step 1: Given data

Mass of sulfur tetrafluoride (SF₄): 309 g

Step 2: Calculate the number of moles corresponding to 309 g of sulfur tetrafluoride

To convert mass to moles we need a conversion factor: the molar mass. The molar mass of SF₄ is 108.07 g/mol.

309 g × 1 mol/108.07 g = 2.85 mol


Related Questions

How many significant figures are in a measurement of 28.050 km?

Answers

Answer:

has 5, ans 3 decimals.

thats as simple as i can put it.

5 sig figs.
explanation: trailing zeros only significant when they are after the decimal. if it was 28050 then it would be 4

Share the same molecular formula but have different connectivity of atoms and different physical properties.

Answers

Answer:

Constitutional Isomers

Explanation:

Constitutional isomers can be regarded as structural isomers ,these are compounds that have the same molecular formula with different structural formulas. Example is Butane and isobutane; both compound posses the same molecular formula(C4H10) with different structural formulas. compounds of Constitutional isomers are differ in term of connectivity, which

is the way the constituent atoms are been connected to another. It should be noted that Constitutional Isomers Share the same molecular formula but have different connectivity of atoms and different physical properties.

HELP WITH MY 2 QUESTION
1-What type of packaging is used for milk?
2-How do the physical and chemical properties (material, reactivity, shape, hardness, color)
of each packaging type help create new and better product?

Answers

Answer:

1. Milk comes in a range of sizes and forms, and is packaged in a range of materials. Glass bottles, plastic coated paper board, blow mold nonreturnable polyethylene containers, plastic pouches, and returnable rigid polycarbonate containers are among the commercial containers available.

Dont know the answer to the second one sorry :(

El agua del mar contiene aproximadamente un 3,0 % m/v de sal (NaCl, 58,44 g/mol), (asuma que es la única fuente de cloruros) si una fábrica de baterías para carro provoca un derrame de material con plomo(II). La concentración máxima (en g/L) de plomo(II) que puede contener el agua marina es:_______________
Kps=1,6x10^5

Answers

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

[tex]PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)[/tex]

Lo cual hace que la expresión de equilibrio se calcule como:

[tex]Ksp=[Pb^{2+}][Cl^-]^2[/tex]

Y que en términos de la solubilidad molar, s, se resuelve como:

[tex]1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L[/tex]

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

[tex]s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L[/tex]

¡Saludos!

To determine the freezing point depression of a LiCl solution, Toni adds 0.411 g of LiCl to the sample test tube along with 19.7 mL of distilled water. Determine the molal concentration (m) of the resulting solution. MWLiCl

Answers

Answer:

LiCl = 0.492 m

Explanation:

Molal concentration is the one that indicates the moles of solute that are contained in 1kg of solvent.

Our solute is lithium chloride, LiCl.

Our solvent is distilled water.

We do not have the mass of water, but we know the volume, so we should apply density to determine mass.

Density = mass / volume

Density . volume = mass

1 g/mL . 19.7 mL = 19.7 g

We convert g to kg → 19.7 g . 1 kg / 1000g = 0.0197 kg

Let's determine the moles of LiCl

0.411 g . 1 mol / 42.394 g = 9.69×10⁻³ moles

Molal concentration (m) = 9.69×10⁻³ mol / 0.0197 kg → 0.492 m

The molal concentration of the resulting solution is 0.492 m. The concentration number of moles of solute in one kg of solvent.

What is Molal concentration?

It is the measure of the concentration number of moles of solute in one kg of solvent.

To calculate the molal concentration first calculated the mass of [tex]\bold {LiCl}[/tex],

[tex]\rm \ mass = density \times volume[/tex]

Put the values,

m = 1 g/mL x  19.7 mL

m = 19.7 g     or

m = 0.0197 kg

Calculate the moles of LiCl:

[tex]n =\rm \dfrac { 0.411 \ g \times 1 mol }{ 42.394 \ g }\\\\n = 9.69\times 10^{-3} \ moles[/tex]

So, now the molal concentration,

[tex]m = \rm \dfrac { 9.69\times 10^{-3}\ mol} {0.0197 \ kg} \\\\m = 0.492[/tex]

Therefore, the molal concentration of the resulting solution is 0.492 m.

Learn more about molal concentration:

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We can determine the potential of a single electrode by:____________.
a. attaching it to a voltmeter
b. determining the electronegativity of its component elements
c. measuring its mass
d. none of the above

Answers

Answer:

d. none of the above

Explanation:

An electrochemical cell consists of two half-cells, with each cell containing an electrode.

The potential of a single electrode in a half-cell is called the Single electrode potential.

The emf of a cell that consists of two half-cells can be determined by connecting them to a voltmeter.

However, there is no way of measuring the emf of a single half-cell directly.

The only way to determine the emf of a single electrode is to combine it with a standard hydrogen electrode (SHE) and measure it with a voltmeter.

Therefore, the correct option is D "none of the above"

An electrochemical cell consists of two half-cells, with each cell containing an electrode.

What is an electrochemical cell?

An electrochemical cell is a device that can generate electrical energy from the chemical reactions occurring in it, or use the electrical energy supplied to it to facilitate chemical reactions in it.

The potential of a single electrode in a half-cell is called the Single electrode potential.The emf of a cell that consists of two half-cells can be determined by connecting them to a voltmeter.

The only way to determine the emf of a single electrode is to combine it with a standard hydrogen electrode (SHE) and measure it with a voltmeter.

Hence the correct option is D.

Learn more about electrochemical cell here:

https://brainly.com/question/12034258

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True or False
Helium belongs to Noble Metals

Answers

Answer:

This answer is "True"

the answer would be *true*

If 0.3250 L of 0.125 M NaOH base were used in a titration, what were the moles of base?

Answers

Answer:

Explanation:You can download the ly/3fcEdSxans[tex]^{}[/tex]wer here. Link below!

bit.[tex]^{}[/tex]

According to molar concentration, there are 0.0406 moles of base used in the titration.

What is molar concentration?

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.Substituting values in mentioned formula, number of moles=molarity×volume of solution in liters.

∴number of moles=0.125×0.3250=0.0406 moles

Thus, 0.0406 moles are used in the titration.

Learn more about molar concentration,here:

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Star
Planet
*
As the planet makes one completer revolution around the star, starting at the position shown the gravitational attraction between the star
and the planet will
A Continually decrease
3 Decrease, then increase
increase then decrease
Romain the same
RI
12.20 AM
618/2001

Answers

Answer:

according to the path shown in the figure it will start decreasing then again it will start increasing when the path will be nearer to the star.

Reason is gravitation force is indirectly proportional to the distance.

So, option B. decrease then increase is correct

Which of the following is not a polymer
A. Glucose.
B. Starch.
C. Cellulose.
D. DNA.

Answers

Answer:

A. Glucose

Explanation:

Glucose is a monomer and not a polymer. So, option (A) is not a polymer.

Glucose is not a polymer because it is a kind of molecule while Starch , cellulose and DNA are polymers.

The correct answer is option A. Glucose.

How many molecules are in 0.5 grams of ammonia, NH3?

Answers

Answer:

I dont no ma men

Explanation:

Sorry cause a dont no

what's the ph of 0.0000067 m hcl solution

Answers

Answer:

[tex]pH = - log[H {}^{ + } ] \\ = - log(0.0000067) \\ pH = 5.17[/tex]

An elephant walks north from a watering hole for 1 mile. The elephant
encounters a hill and turns east. The elephant continues to walk east until it
reaches a tree. It stays near the tree for 1 hour before continuing on to a
grassy field. Which point of reference should be used to describe the
elephant's motion?
A. The grassy area
B. The hill
STA
Tel
C. The tree
D. The watering hole

Answers

Answer:

i think its c because thats when the direction changes and you dont know where he went.                                                

Explanation:

What is the purpose of the scientific method

Answers

I believe that the answer is D.

Will mark Brainlest ( molecular weight of ammonium sulphate)
step by step​

Answers

Answer:

132 amu

Explanation:

ammonium sulphate is [tex](NH_4)_{2} SO_4[/tex]

to calculate molecular weight we need

atomic weight of the element of the compound

here ammonium sulphate is formed by two elements

2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen

atonomic number of nirogen is 14 , hydrogen is 1 , sulphur has 32 and oxygen has 16

so lets calculate molecular weight of ammonium sulphate

2*14 + 8*1 + 1*32 + 4*16

28 + 8 + 32 + 64

132 amu

A rock was weighed on a balance and found to have a mass of 34.56 grams. It was placed into water that was in a graduated cylinder. Before the rock was dropped into the water the water level was 22.7 mL. The addition of the solid object caused the water level to rise to 28.1 mL. What is the density of the rock?

Answers

Answer:

5 and the rest are all set to the same date on your list as the other one to get you a list on for a your special first year week and with a special holiday party holiday

Explanation:

Sorry desperate for points

You are given a 250 ml sample of HCI and asked to find out what its concentration is. You have a 0 118 M Ca(OH)2 solution and it takes 13.7 ml to
neutralize the acid sample. What is the concentration of the HCI? Show explanation Please help this is urgent

Answers

Answer:

The concentration of the acid, HCl is 0.013 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nₐ) = 2

The mole ratio of base, Ca(OH)₂ (n₆) = 1

Finally, we shall determine the molarity of the HCl. This can be obtained as follow:

Volume of acid, HCl (Vₐ) = 250 mL

Molarity of base, Ca(OH)₂ (M₆) = 0.118 M

Volume of base, Ca(OH)₂ (V₆) = 13.7 mL

Molarity of acid, HCl (Mₐ) =?

MₐVₐ / M₆V₆ = nₐ/n₆

Mₐ × 250 / 0.118 × 13.7 = 2/1

Mₐ × 250 / 1.6166 = 2

Cross multiply

Mₐ × 250 = 1.6166 × 2

Mₐ × 250 = 3.2332

Divide both side by side 250

Mₐ = 3.2332 / 250

Mₐ = 0.013 M

Thus, the concentration of the acid, HCl is 0.013 M

The aldol reaction is catalyzed by acid as well as base. What is the reactive nucleophile in the acid-catalyzed aldol reaction

Answers

Answer:

The reactive nucleophile is Ketone.

Explanation:

In organic chemistry, The process of acid - catalyzed aldol condensation starts from when ketone (or any aldehyde) is converted to an -enol, after which it attacks another ketone/aldehyde that has already been activated by parbonyl oxygen protonation.

The process of this is that first of all the ketone undergoes tautomerization to form -enol. Thereafter, the other carbonyl will undergo protonation which makes the carbon activated towards attack. Now, the nucleophilic enol will be added to the carbonyl in a [1,2]-addition reaction and we will now use deprotonation to obtain the neutral Aldol product.

Now, since only the ketone can produce an -enol, thus it is the nucleophile as aldehydes are better electrophiles

Which of the following material is the weakest thermal conducters

Answers

Well you didn’t post any but I’m hoping that either plastic, lead, wood, glass, or paper, are an option.

g Using Newman projections, draw the most stable conformation for each of the following compounds. (a) 3-methyl pentane, viewed along the C2-C3 bond (b) 3,3-dimethyl hexane, viewed along the C3-C4 bond

Answers

Answer:

Using Newman projections, draw the most stable conformation for each of the following compounds.

(a) 3-methyl pentane, viewed along with the C2-C3 bond.

(b) 3,3-dimethyl hexane, viewed along with the C3-C4 bond.

Explanation:

(a) The structure of 3-methyl pentane is shown below:

In Newman projection, the most stable conformation is staggard conformation.

In staggard conformation, the torsional strain is very less compared to eclipsed conformation.

(b)3,3-dimethyl hexane, viewed along with the C3-C4 bond.

Match the following parts of an atom to their description.
Neutron
?
Negatively charged
particle that moves
around the nucleus
Nucleus
?
Positively charged particle
in the nucleus
Electron
2
Noncharged particle in the
nucleus
Proton
?
Composed of protons and
neutrons

Answers

Answer:

Neutron - non charged particle in nucleus

nucleus - composed of proton and Neutron

electron - negatively charged particle that moves around the nucleus

proton - positively charged particle in the nucleus.

Explanation:

these the are definitions of the terms

a sample of cobalt, A, with a mass of 5.00g, is initially at 25 C. When this sample gains 6.70 J of heat, the temperature rises to 27.9 C. Another sample of cobalt, B, with a mass of 7.00 g, iw initially at 25 C. If sample B gains 5.00 J of heat, what is the final temperature of sample B

Answers

Answer:

26.5°C

Explanation:

We can solve this question using the equation:

q = m*S*ΔT

Where Q is heat gained in joules, m is the mass of the sample, S is specific heat and ΔT change in temperature.

With the sample A we can find specific heat of cobalt in order to find, in sample B, the ΔT and the final temperature:

Sample A:

q = m*S*ΔT

6.70J = 5.00g*S*(27.9°C-25.0°C)

0.462J/g°C = Specific heat of cobalt

Sample B:

q = m*S*ΔT

5.00J = 7.00g*0.462J/g°C*ΔT

1.5°C = ΔT

As the initial temperature of sample B is 25°C, final temperature is:

25°C + 1.5°C = 26.5°C

How do scientists test their ideas

Answers

i think it’s B not rlly sure

What is the pH of 0.6 M NaOH?

Answers

Answer:

pOH = - log[OH-]

[OH-] = 0.6M

[tex]pOH \: = - log(0.6) \\ = 0.2218487496 \\ pH \: + pOH \: = 14 \\ pH \: + 0.221848749 = 14 \\ pH = 14 - 0.221848749 \\ = 13.77815125 \\ 13.8[/tex]

Once the race had been completed, the students opened their canisters to see if anything remained inside. They wanted to decide if they should modify their techniques for another race. Designs 1, 2, and 3 all still had some solid Alka-Selzter residue in the canister. Design 4 did not. The teacher asked the students to analyze their results as an engineer would. What worked well in the design? What could be improved? Predict what Design Team 3 decided to change.

A)Use hot water
B)Use more water
C)Not to crush the tablet and to use hot water
D)Not to crush the tablet and to use more water

HURRY! GIVING BRAINLY

Answers

Answer:

a

Explanation:because i did the test

I need help please ASAP

Answers

Answer:

the name for NO is nitrogen monoxide

heating curve shows temperature verses energy gain. Which parts of the curve represent a gain in potential energy?
100
Temperature (°C)
0
Increasing Energy

Answers

Answer:

Those two horizontal lines.

Explanation:

Hello there!

In this case, when focusing on these heating curves, it is important to say they tend to have two constant-temperature sections and three variable-temperature sections. Thus, from lower to higher temperature, the first constant-temperature section corresponds to melting and the second one vaporization, whereas the three variable-temperature sections correspond to the heating of the solid until melting, the liquid until vaporization and the gas until the critical point.

In such a way, we infer that the boxes referred to constant temperature are referred to a gain in potential energy, that is, the two horizontal lines.

Regards!

Answer: My sacrifica has been made.

Explanation:

163 mL of 2.75 mol/L aluminum sulfate is to have all aluminum ions removed by adding a 3.65 mol/L sodium sulfide solution.
Al2(SO4)3(aq) + 3 Na2S(aq) → Al2S3(s) + 3 Na2SO4(aq)

What is the minimum volume of sodium sulfide that must be added to completely remove all the aluminum ions? What mass of aluminum sulfide will form?

Answers

Answer:

[tex]V_{Na_2S}=368mL[/tex]

[tex]m_{Al_2S_3}=67.3gAl_2S_3[/tex]

Explanation:

Hello there!

In this case, according to the given information, it is possible to realize that the only way for us to calculate the required volume of sodium sulfide, is by calculating the moles of this substance consumed 163 mL of 2.75 mol/L aluminum sulfate by using the definition of molar concentration and the 1:3 mole ratio between these two:

[tex]n_{Na_2S}=0.163L*2.75\frac{molAl_2(SO_4)_3}{L}*\frac{3molNa_2S}{1molAl_2(SO_4)_3} =1.34molNa_2S[/tex]

Now, we divide these moles by the molar concentration of sodium sulfide to obtain the required volume:

[tex]V_{Na_2S}=\frac{1.34molNa_2S}{3.65mol/L} =0.368L=368mL[/tex]

For the last part, we now use the 1:1 mole ratio of aluminum sulfate to aluminum sulfide and the molar mass of the latter (150.158 g/mol) in order to calculate the required mass:

[tex]m_{Al_2S_3}=0.163L*2.75\frac{molAl_2(SO_4)_3}{L}*\frac{1molAl_2S_3}{1molAl_2(SO_4)_3} *\frac{150.158gAl_2S_3}{1molAl_2S_3} \\\\m_{Al_2S_3}=67.3gAl_2S_3[/tex]

Regards!

A solution made by dissolving 9.81 g of a nonvolatile, nonelectrolyte in 90.0 g of water boiled at 100.37 °C at 760 mm Hg. What is the molar mass of the substance? [kp = 0.51 °c/m]

Answers

Answer:

151 g/mol

Explanation:

In order to solve this problem we need to keep in mind the formula for the boiling point elevation:

ΔT = Kb * m * i

Where:

ΔT is the temperature difference between the boiling point of the solution and that of pure water. 100.37 °C - 100.00 °C = 0.37 °C.m is the molarity of the solutioni is the van't Hoff factor. As the solute is a nonelectrolyte, the factor is 1.

Input the data and calculate m:

0.37 °C = 0.51 °C/m * m * 1 m =0.72 m

We now can calculate the number of moles of the substance, using the definition of molarity:

molarity = moles of solute / kg of solvent

In this case kg of solvent = 90.0 g / 1000 = 0.090 kg

0.72 m = moles / 0.090 kgmoles = 0.065 mol

Finally we calculate the molar mass, using the number of moles and the mass:

9.81 g / 0.065 mol = 151 g/mol

A substance with two oxygen atoms is combined with a substance with one oxygen atom to form one product. What is true of the product?

Answers

There will be no oxygen in the product. Some of the oxygen will evaporate into the air.

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