By knowing the natural abundance of minor isotopes, it's possible to calculate the relative heights of M+ and M+1 peaks. If natural abundances are 12C - 98.9% and 13C - 1.10%, what are the relative heights, to the nearest 0.1%, of the M+ and M+1 peaks in the mass spectrum of cholesterol, C27H48O? Ignore the contributions of isotopes like 2H (deuterium; 0.015% natural abundance) and 17O (0.04% natural abundance) that are small. The relative heights are, in order of increasing mass: 100 to

Answers

Answer 1

Answer:

the relative height of M⁺ : M+1 is; 0.7418 : 0.2228

The relative heights are; In order of increasing mass 100 : 30

Explanation:

Given the data in the question;

The M⁺ peak comes from all ¹²₆C atoms

so, the probability in cholesterol, C₂₇H₄₈O is ( 98.9% )²⁷ = ( 0.989 )²⁷ = 0.7418

The M+1 peak comes from the isotopic carbon ¹³₆C.

so, the probability in cholesterol is ⇒ 1.10% × ( 98.9% )²⁶ = 0.011 × ( 0.989)²⁶

The probability for 27 carbons is ⇒  27 × 0.011 × ( 0.989)²⁶ = 0.2228

Therefore, the relative height of M⁺ : M+1 is; 0.7418 : 0.2228

The relative heights are; In order of increasing mass 100 : 30  


Related Questions

8. What does the term 'sustainable mean? *

Answers

Answer:

something that can be maintained over a period of time

Answer:

a balance between meeting today's needs.......

Explanation:

Given the data you collected for the volume of water displaced by 25.000 g of aluminum, what is the density of aluminum?
A. 3.38 g/cm
B. 13.5 g/mL
C. 2.70 g/cm
D. 0.637 g/mL

Answers

Answer:

C. 2.70 g/mL

Explanation:

Density is the ratio between the mass of a substance and the volume it occupies. Based on Archimedes' volume, the displaced volume of the aluminium is the volume it occupies. To solve this question we must find the difference in volume between initial volume of water = 30mL and final volume of water + aluminium = 39.26mL. This difference is the volume of the aluminium. With its mass we can find density:

39.26mL - 30mL = 9.26mL

Density = 25.00g / 9.26mL =

2.70g/mL

Right answer is:

C. 2.70 g/mL

The human body contains many elements from the periodic table. It is mostly composed of oxygen and carbon, but trace
elements also have a significant role. The table gives the mass, in kilograms, of some elements found in the human body, based
on a 70.0 kg person.
Atomic number
Element
Mass (kg)
8
oxygen
45.2
6
carbon
12.6
1
hydrogen
7.0
7
nitrogen
2.2
20
calcium
1.3
15
phosphorus
0.78
19
potassium
0.25
16
sulfur
0.18
others
0.60
total
70,0
Potassium makes up what fraction of the mass of the human body?

Answers

Potassium makes up 1/280 of the mass of the body.

From the question given above, the following data were obtained:

Oxygen = 45.2 Kg

Carbon = 12.6 Kg

Hydrogen = 7 Kg

Nitrogen = 2 Kg

Calcium = 1.3 Kg

Phosphorus = 0.78 Kg

Potassium = 0.25 Kg

Sulphur = 0.18 Kg

Others = 0.60 Kg

Total = 70 Kg

Fraction of potassium =?

We can obtain the fraction of potassium of the mass of the body as follow:

Potassium = 0.25 Kg

Total = 70 Kg

Fraction of potassium =?

Fraction of potassium = mass of potassium / Total

Fraction of potassium = 0.25 / 70

Fraction of potassium = 1/280

Therefore, the fraction of potassium in the body is 1/280

Learn more: https://brainly.com/question/14760859

A mixture of sulfuric acid and nitric acid will produce small quantities of the nitronium ion (NO2 ): The nitronium ion has a central nitrogen atom with a positive charge double bonded to two oxygen atoms on both sides. Each oxygen atom carries two lone pairs of electrons. Does the nitronium ion have any significant resonance structures

Answers

Answer:

A mixture of sulfuric acid and nitric acid will produce small quantities of the nitronium ion (NO2 ): The nitronium ion has a central nitrogen atom with a positive charge double bonded to two oxygen atoms on both sides. Each oxygen atom carries two lone pairs of electrons. Does the nitronium ion have any significant resonance structures?

Explanation:

The structure of nitronium ion is shown below:

Any molecule to exhibit resonance, it should have alternating double bonds.

Resonance is the phenomenon in which the structure of a molecule can be represented in two or more forms and each form is called canonical form.

The canonical forms do not differ in the position of atoms and they differ only in the position of double bonds.

For the given molecule, there are no alternating double bonds.

Hence, nitronium ion does not exhibit any significant resonance structures.

Using the formation of formaldehyde as a model, comment on photosynthesis and the formation of sugars using what we know about entropy and free energy.

Answers

Answer:

It produces free energy.

Explanation:

Photosynthesis is a process which is used by the plant for producing energy in the form of ATP. This energy is used by the plants in different activities which enables the plant to grow and develop successfully. There are some factors which causes change in the rate of photosynthesis means the production of energy for the plant body. If the environmental factors are suitable, more energy is produced through the process of photosynthesis.

Nitric acid (HNO3) reacts with ammonia (NH3) in aqueous solution. Use your knowledge of nitric acid to decide what type of reaction arrow(s) to use. $$ Part 2 (1 point) Sulfuric acid (H2SO4) reacts with ammonia in aqueous solution. Use your knowledge of sulfuric acid to decide what type of reaction arrow(s) to use. $$

Answers

Answer:

Both reactions are acid-base reactions

Explanation:

An acid base reaction is a reaction that occurs between an acid and a base. This reaction often leads to the formation of a salt in the process. The nature of the salt depends on the type of acid and base that reacted in the process.

Both HNO3 and H2SO4 are strong acids. However, ammonia is a weak base. The acid base reaction between ammonia and these strong acids is shown below;

HNO3(aq) + NH3(aq) ------>NH4NO3(aq)

H2SO4(aq) + 2NH3(aq) ----> (NH4)2SO4(aq)

Reaction Progression
Which statement best describes the diagram?
The pathway A-B-D involves a catalyst and is slower than A-C-D.
The pathway A-B-D involves a catalyst and is faster than A-C-D.
The pathway A-C-D involves a catalyst and is slower than A-B-D.
The pathway A-C-D involves a catalyst and is faster than A-B-D

Answers

the third one is right

H2C=CH2 + H2 решение?​

Answers

Answer:

[tex]CH _{3}CH _{3}[/tex]

Ethane

Ketone bodies are produced when a person what

Answers

Answer:

Ketones and ketoacids are alternative fuels for the body that are made when glucose is in short supply. They are made in the liver from the breakdown of fats. Ketones are formed when there is not enough sugar or glucose to supply the body's fuel needs. This occurs overnight, and during dieting or fasting.

Explanation:

True or false? An organism may play more than one role in a food web

Answers

Answer:

true

Explanation:

because an organism have many roles in food web

why is tin tin and aluminum the better choice for canned milk

Answers

Answer:

Well, they are very durable unlike other packaging food materials, they can be recycled. But, the internet says allumninum cans are much better. and it could be better because you can keep the canned milk cool (cold) for a long lasting time. (keep it in the fridge if you want it to stay cold even longer)

Choose the compound that exhibits hydrogen bonding as its strongest intermolecular force. Choose the compound that exhibits hydrogen bonding as its strongest intermolecular force. CH2Br2 CH3NH2 LiF C3H8 CF4

Answers

Answer:

The given molecules are:

CH2Br2

CH3NH2

LiF

C3H8

CF4.

Which compound consists of the hydrogen bond as the strongest intermolecular force.

Explanation:

The hydrogen bond is the electrostatic force of attraction that exists between the covalently bonded H-atom of one molecule and a high electronegative atom (N, O, F) of another molecule.

For example, H-bonding in water is represented below:

Among the given molecules,

CH2Br2 does not have H-bond because there is no either N or O or F atom in it.

In LiF also there is no H-atom and no hydrogen bond.

C3H8 also does not have H-bond in it.

CF4 also does not have H-atom or hydrogen bond in it.

The answer is CH3NH2(methylamine).

It has an intermolecular hydrogen bond in it as shown in the attachment.

The dashed line represents the H-bond.

how to calculate moles

Answers

Explanation:

First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.

For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.

Answer:

Number of moles : Mass (g) ÷ relative atomic mass

How do I balance this?
_CuC12 + _NaNO3 → _CU(NO3)2 + _ NaC1

Answers

[tex]CuCl_2+2NaNO_3 \rightarrow Cu(NO_3)_2 + 2NaCl[/tex]

What property can be easily measured in solids, liquids, and gases? (2 points)

Group of answer choices

The temperature of solids, liquids, and gases can be easily measured.

The texture of solids, liquids, and gases can be easily measured.

The color of solids, liquids, and gases can be easily observed.

The texture and temperature can be easily measured for solids, liquids, and gases.

Answers

Answer:

I think the answer is A

Explanation:

the temperature of solids , liquids and gases can be easily measured

When the following aqueous solutions are mixed together, a precipitate forms. Balance the net ionic equation in standard form for the reaction that occurs and determine the sum of the coefficients.

Sodium sulfide and silver nitrate - 3 or 4
Lead(II) nitrate and sodium chloride -3 or 4
Calcium nitrate and potassium carbonate - 3or 4
Barium nitrate and sodium hydroxide -3 or 4
Silver nitrate and sodium chloride -3 or 4

Answers

Answer:

For (a): The balanced net ionic equation is [tex]2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)[/tex] and the sum of coefficients is 4

For (b): The balanced net ionic equation is [tex]Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)[/tex] and the sum of coefficients is 4

For (c): The balanced net ionic equation is [tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex] and the sum of coefficients is

For (d): The balanced net ionic equation is [tex]Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)[/tex] and the sum of coefficients is 4

For (e): The balanced net ionic equation is [tex]Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)[/tex] and the sum of coefficients is 3

Explanation:

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

For (a): Sodium sulfide and silver nitrate

The balanced molecular equation is:

[tex]Na_2S(aq)+2AgNO_3(aq)\rightarrow 2NaNO_3(aq)+Ag_2S(s)[/tex]

The complete ionic equation follows:

[tex]2Na^{+}(aq)+S^{2-}(aq)+2Ag^+(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ag_2S(s)[/tex]

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)[/tex]

Sum of the coefficients = [2 + 1 + 1] = 4

For (b): Lead(II) nitrate and sodium chloride

The balanced molecular equation is:

[tex]2NaCl(aq)+Pb(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+PbCl_2(s)[/tex]

The complete ionic equation follows:

[tex]2Na^{+}(aq)+2Cl^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+PbCl_2(s)[/tex]

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)[/tex]

Sum of the coefficients = [2 + 1 + 1] = 4

For (c): Calcium nitrate and potassium carbonate

The balanced molecular equation is:

[tex]K_2CO_3(aq)+Ca(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+CaCO_3(s)[/tex]

The complete ionic equation follows:

[tex]2K^{+}(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2K^+(aq)+2NO_3^-(aq)+CaCO_3(s)[/tex]

As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex]

Sum of the coefficients = [1 + 1 + 1] = 3

For (d): Barium nitrate and sodium hydroxide

The balanced molecular equation is:

[tex]2NaOH(aq)+Ba(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Ba(OH)_2(s)[/tex]

The complete ionic equation follows:

[tex]2Na^{+}(aq)+2OH^{-}(aq)+Ba^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ba(OH)_2(s)[/tex]

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions

The net ionic equation follows:

[tex]Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)[/tex]

Sum of the coefficients = [2 + 1 + 1] = 4

For (e): Silver nitrate and sodium chloride

The balanced molecular equation is:

[tex]NaCl(aq)+AgNO_3(aq)\rightarrow NaNO_3(aq)+AgCl(s)[/tex]

The complete ionic equation follows:

[tex]Na^{+}(aq)+Cl^{-}(aq)+Ag^{+}(aq)+NO_3^{-}(aq)\rightarrow Na^+(aq)+NO_3^-(aq)+AgCl(s)[/tex]

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)[/tex]

Sum of the coefficients = [1 + 1 + 1] = 3

*
The crystal structure of salt is

Answers

quimica espero que si sea corecta

How many atoms of nitrogen are in Fe2(NO4)2?

Answers

the number of nitrogen atoms in the compound is two

What are the characteristics of ionic compounds?​

Answers

Answer:

the characteristics of ionic compounds are :

1.They form crystals.

2.They are hard and brittle.

Answer:

they form crystals.

they have high melting and boiling points.

they are hard and brittle.

they are good insulators.

when dissolve in water...they dissociate Into ions.

What is the right answer?

Answers

Answer:

equal to zero is the right answer

The student is now told that the four solids, in no particular order, are barium chloride (BaCl2), sugar (C6H12O6), butanoic acid (C3H7COOH), and sodium bromide (NaBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive.

Answers

Answer:

The student is now told that the four solids, in no particular order, are barium chloride (BaCl2), sugar (C6H12O6), butanoic acid (C3H7COOH), and sodium bromide (NaBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive.

Explanation:

The given substances are:

barium chloride(BaCl2),

glucose(C6H12O6),

butanoic acid (C3H7COOH) which is a weak acid,

sodium bromide (NaBr).

The conductivity of a solution is proportional to the number of ions present in a particular solution.

1mol. of BaCl2 in water produces a total three mol. of ions.

[tex]BaCl_2 (aq) -> Ba^2^+(aq) + 2Cl^-(aq)[/tex]

Gluocse is a covalent compound and it does not dissociate into ions in water.

So, it does not conduct electricity.

Butanoic acid is a weak acid. But due to the release of H+ ions it can conduct a very less amount of electricity.

NaBr is an ionic compound and in 1mol. of NaBr in water gives two mol. of ions.

NaBr (aq)  -> Na+ (aq)  + Br- (aq)

Hence, the order of conductivity among the given substances in aqueous solution is:

BaCl2 > NaBr > butanoic acid > glucose

what is electron configuration of oxygen in its excited state​

Answers

Answer:

[tex]1 {s}^{2} 2 {s}^{2} 2 {p}^{4} [/tex]

OR

[tex]2 : 6[/tex]

Answer:

If we look at the ground state (electrons in the energetically lowest available orbital) of oxygen, the electron configuration is [tex]1s^{2} 2s^{2} 2p^{4}[/tex] . If the element were to become excited, the electron could occupy an infinite number of orbitals. However, in most texts, the example will be the next available one. So for oxygen, it might look like this:  [tex]1s^{2} 2s^{2} 2p^{3}3s^{1}[/tex]  - where the valence electron now occupies the 3s orbital in an excited (i.e. not ground) state.

So, the electron configuration of oxygen in its excited state​ is [tex]1s^{2} 2s^{2} 2p^{3}3s^{1}[/tex].

Which of the following relations is correct for exothermic and endothermic reactions?

Answers

Answer:

pa helpppp

Explanation:

pleseee need answerrrr

The correct relations for exothermic and endothermic reactions from the given relations is  H Products > H Reactants in exothermic reactions. Hence, Option (D) is Correct.

What is Exothermic Reaction ?

In thermochemistry, an exothermic reaction is a "reaction for which the overall standard enthalpy change ΔH⚬ is negative." Exothermic reactions usually release heat.

Therefore, The correct relations for exothermic and endothermic reactions from the given relations is  H Products > H Reactants in exothermic reactions. Hence, Option (D) is Correct.

Learn more about reaction here ;

https://brainly.com/question/17434463

#SPJ2

during the process of photosynthesis, green plants produce...

Answers

Answer: photosynthesis

Explanation:

they use carbon dioxide and energy from the sun to make sugar molecules and oxygen

what is thermodynamics ???
don't explain .-. !!!​

Answers

Answer:

the scientific study of the relations between heat and other forms of energy

What should the coefficient for the diatomic oxygen (O2) be when this equation is correctly balanced

Answers

3

And then for Fe it should be 4 and for the products it should be 2!!

The reduced coenzymes generated by the citric acid cycle donate electrons in a series of reactions called the electron transport chain. The energy from the electron transport chain is used for oxidative phosphorylation.
a) Which compounds donate electrons to the electron transport chain?
b) Which of the following is the final electron acceptor?
c) Which of the following are the final products of the electron transport chain and oxidative phosphorylation?
1. H20
2. NADH
3. NAD+
4. ATP
5. ADP
6. O2
7. FADH2
8. FAD

Answers

Answer:

a. NADH and FADH₂ donate electrons to the electron transport chain

b. Molecular oxygen, O₂, is the final electron acceptor

c. The final products of the electron transport chain and oxidative phosphorylation are as follows: NAD+, FAD+, H₂O, and ATP

Explanation:

The citric cycle oxidize acetylCoA molecules to carbon dioxide and in the process produce the reduced coenzyme NADH and FADH₂. These reduced coenzymes then are able to donate their electrons to various complexes in the electron transport chain. The flow of these electrons through the electron transport chain is coupled to proton pumping out of the mitochondrial matrix into the intermembrane space. Ultimately, the energy of the proton motive force is used to drive synthesis of ATP from ADP and inorganic phospahte and the electrons are accepted by molecular oxygen to produce water. This process is known as oxidative phosphorylation.

Therefore, the answers to the given questions a, b and c are as follows:

a. NADH and FADH₂ donate electrons to the electron transport chain

b. Molecular oxygen, O₂, is the final electron acceptor

c. The final products of the electron transport chain and oxidative phosphorylation are as follows: NAD+, FAD+, H₂O, and ATP

CuCl2(aq) + KOH(aq)--------------->Cu(OH)2(aq) + KCl(aq)

Answers

Answer:

CuCl2 (aq) + 2 KOH (aq) → Cu(OH)2 (s) + 2 KCl (aq)

Explanation:

I did it.

Answer:

CuCl2 + 2KOH------------------>Cu(OH)2 + 2KCl

Explanation:

this is the right solution of equation

How does activation energy affect a chemical reaction?

Answers

Answer:

It determines how difficult it is to start the reaction.

Explanation:

A 24.803 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 79.733 g of water. A 10.560 g aliquot of this solution is then titrated with 0.1077 M HCl . It required 32.37 mL of the HCl solution to reach the methyl red endpoint. Calculate the weight percent NH3 in the aqueous waste.

Answers

Answer:

2.37 (w/w)% of NH3 in the fertilizer

Explanation:

The HCl reacts with NH3 as follows:

HCl + NH3 ⇄ NH4Cl

To solve this question we must find the  moles of HCl used in the titration = Moles NH3. With its molar mass we can find mass of NH3 and using the dilutions we can find weight percent as follows:

Moles HCl = Moles NH3

32.37mL = 0.03237L * (0.1077mol/L) =

Mass NH3 in the dilution -Molar mass: 17.031g/mol-

0.003486moles NH3 * (17.031g/mol) = 0.05937g NH3

Mass NH3 in the sample:

0.05937g NH3 * (79.733g + 24.803g) / 10.560g =

0.588g NH3

Weight percent:

0.588g NH3 / 24.803g * 100 =

2.37 (w/w)% of NH3 in the fertilizer

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