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[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\text{350 rounded to the nearest hundred is...}[/tex]

[tex]\huge\text{Rounding is basically is the}\\\huge\text{approximation of the given number.}[/tex]

[tex]\huge\bullet\huge\text{ So, when you are looking at 350, you are}\\\huge\text{asking yourself is it closer to 300 or 400.}\\\huge\text{If you are looking at the number correctly}\\\huge\text{you would see it is closer to \underline{\underline{400}} when you}\\\huge\text{rounded to NEAREST HUNDRED.}[/tex]

[tex]\huge\boxed{\textsf{Therefore, your ANSWER/RESULT is: \bf 400}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

[tex]f'(x)=1+\ln x[/tex]

Step-by-step explanation:

[tex]f'(x)[/tex] is notation for the first derivative of [tex]f(x)[/tex].

Recall the product rule:

[tex](f\cdot g)'=f'\cdot g+g'\cdot f[/tex]

Therefore, we have:

[tex]\displaystyle \frac{d}{dx}(x\ln x)=\frac{d}{dx}(x)\cdot \ln(x)+\frac{d}{dx}(\ln x)\cdot x[/tex]

Note that:

[tex]\displaystyle \frac{d}{dx}(x)=1,\\\\\frac{d}{dx}(\ln x)=\frac{1}{x}[/tex]

Simplify:

[tex]\displaystyle \frac{d}{dx}(x\ln x)=1\cdot \ln x+\frac{1}{x}\cdot x, \\\\\frac{d}{dx}(x\ln x)= \ln x+1=\boxed{1+\ln x}[/tex]

The derivative is:

[tex] \bold{f(x) \: = \: x \: \times \: (In(x))}[/tex]

[tex] \bold{f'(x) \: = \: \frac{d}{dx} (x \: \times \: In(x))}[/tex]

[tex] \bold{f'(x) \: = \: \frac{d}{dx} (x) \: \times \: In(x) \: + \: x \: \times \: \frac{d}{dx} (In(x))}[/tex]

[tex] \bold{f'(x) \: = \: 1In(x) \: + \: x \: \times \frac{1}{x} }[/tex]

[tex] \bold{f'(x) \: = \: In(x) \: + \: x \: \times \: \frac{1}{x} }[/tex]

[tex] \boxed{ \bold{f'(x) \: = \: In(x) \: + \: 1}}[/tex]

Answer:

1.69s^2h/3.

Step-by-step explanation:

New s = 1.3s

New volume = (1.3s)^2h /3

= 1.69s^2h/3.

Answer:

47

Step-by-step explanation:

8(4) + 2(6) + 3 = 47

32 + 12 + 3 = 47

Answer: Square root of negative 7 is greater than -3.12345

Step-by-step explanation: Since the square root of -7= 2.64575131 i (A positive number) Then it's greater, since the positive number is always greater than the negative numbers, because the negative numbers are further below zero than the positive number, if there is a number below the zero and a number above the zero, the one above the zero is greater,  because it's a positive number, the one below 0 is negative.

Patterns are set of rules that guide the creation of a dataset. The observation from the first three designs are as follows:

The pattern

The first three design show that, as the design number increases (i.e. 1, 2, 3), the number of tiles used also increases (i.e. 7, 12, 19)

The expressions for the number of tiles

The design number and the number of tiles is represented as follows

[tex]1 \to 7[/tex]

[tex]2 \to 12[/tex]

[tex]3 \to 19[/tex]

From the designs, we observe that some tiles are at the middle, while other tiles are at the sides.

Design 1 has 1 tile at the center and 6 tiles at either sides.

So, we have:

[tex]1 \to 1 + 6[/tex]

[tex]2 \to 4 + 8[/tex]

[tex]3 \to 9 + 10[/tex]

Expand

[tex]1 \to 1^2 + 6 \to 1^2 + 2 \times 3 \to 1^2 + 2 \times (1 + 2)[/tex]

[tex]2 \to 2^2 + 8 \to 2^2 + 2 \times 4 \to 2^2 + 2 \times (2 + 2)[/tex]

[tex]3 \to 3^2 + 10 \to 3^2 + 2 \times 5 \to 3^2 + 2 \times (3 + 2)[/tex]

Notice the pattern,

The number of tiles in design n will be:

[tex]Tiles = n^2 + 2 \times (n + 2)[/tex]

Open bracket

[tex]Tiles = n^2 + 2n + 4[/tex]

Hence, the expressions for number of tiles in design n are:

[tex]n^2 + 2(n + 2)[/tex] and [tex]n^2 + 2n + 4[/tex]

Technology to prove that both expressions are equivalent

To prove that [tex]n^2 + 2(n + 2)[/tex] and [tex]n^2 + 2n + 4[/tex] are equivalent using technology, the graphs of [tex]n^2 + 2(n + 2)[/tex] and [tex]n^2 + 2n + 4[/tex] can be plotted and then compared

The table and graph for the first 6 designs

The table entry for the first 6 designs is calculated as follows:

[tex]n = 1\ \ \ \ \ Tiles = 1^2 + 2 \times 1 + 4 = 7[/tex]        

[tex]n = 2\ \ \ \ \ Tiles = 2^2 + 2 \times 2 + 4 = 12[/tex]        

[tex]n = 3\ \ \ \ \ Tiles = 3^2 + 2 \times 3 + 4 = 19[/tex]        

[tex]n = 4\ \ \ \ \ Tiles = 4^2 + 2 \times 4 + 4 = 28[/tex]        

[tex]n = 5\ \ \ \ \ Tiles = 5^2 + 2 \times 5 + 4 = 39[/tex]        

[tex]n = 6\ \ \ \ \ Tiles = 6^2 + 2 \times 6 + 4 = 52[/tex]        

So, we have:

[tex]\begin{array}{cc}Design & {Tiles} & {1} & {7} & {2} & {12} & 3 & {19} & {4} & {28} & {5} & {39}& {6} & {52} \ \end{array}[/tex]

See attachment for the graph of the above table

All the points on the curve make sense in this scenario because all values are positive.

The pattern type

We have:

[tex]Tiles = n^2 + 2n + 4[/tex]

When an equation has a degree of 2, the equation is quadratic.

Hence, the pattern is quadratic.

The largest design that an empty sign of 10ft by 12ft can contain.

From the first three designs:

The number of tiles on a complete row and column are always the same.

Design 1 has 3 tiles in its complete row and column

Design 2 has 4 tiles in its complete row and column

Design 3 has 5 tiles in its complete row and column

The relationship between the design number (d) and the number of complete tiles (t) is:

[tex]d = t - 2[/tex]

For the 10ft by 12ft empty sign

[tex]t = 10[/tex] because [tex]10 < 12[/tex]

So, we have:

[tex]d = t - 2[/tex]

[tex]d = 10 - 2[/tex]

[tex]d = 8[/tex]

Hence, the largest design number is design 8

Read more about patterns at:

https://brainly.com/question/13382968

[tex]\\ \sf\Rrightarrow y-1=\dfrac{2}{3}(x+1)[/tex]

[tex]\\ \sf\Rrightarrow -3-1=\dfrac{2}{3}(a+1)[/tex]

[tex]\\ \sf\Rrightarrow -4=\dfrac{-2(a+1)}{3}[/tex]

[tex]\\ \sf\Rrightarrow -2(a+1)=-4(3)[/tex]

[tex]\\ \sf\Rrightarrow -2(a+1)=-12[/tex]

[tex]\\ \sf\Rrightarrow a+1=\dfrac{-12}{-2}[/tex]

[tex]\\ \sf\Rrightarrow a+1=6[/tex]

[tex]\\ \sf\Rrightarrow a=6-1[/tex]

[tex]\\ \sf\Rrightarrow a=5[/tex]

Answer:

6

Step-by-step explanation:

5:1

30:6

multiply by 6 so its 6

Step-by-step explanation:

w+z=1-5+2+4¡

w+z=-2+4¡

and if you mean w= 1-5¡ , z= 2+4¡

z+w= 1-5¡+2+4¡

z+w= 3-¡

Answer:

x > 2

Step-by-step explanation:

Distribute and cross-simplify 1/2 with parenthesis

4x + x + 2 > 12

Solve left side

5x + 2 > 12

Subtract 2 from both sides

5x > 10

Divide both sides by 5

x > 2

Answer:

-7

Step-by-step explanation:

The line (y-1)=(2/3)(x+1) contains point (a,-3)

=> (-3-1) = (⅔)(a+1)

-4 = (⅔)(a+1(

(a+1)= -4 ÷ ⅔

a + 1 = -4 × 3/2

a+ 1 = -6

a = -6-1

a = -7

The value of 'a' will be;

⇒ a = - 7.

To find the value of any one of the variables from one equation in terms of the other variable is called the substitution method.

Given that;

The equation of line is,

⇒ (y - 1) = (2/3) (x + 1)

And, The point on the line = (a, - 3)

Now,

Since, The point on the line = (a, - 3)

Hence, It satisfy the equation of line.

Substitute x = a and y = - 3, we get;

⇒ (y - 1) = (2/3) (x + 1)

⇒ (- 3 - 1) = (2/3) (a + 1)

⇒ - 4 × 3 = 2a + 2

⇒ - 12 - 2 = 2a

⇒ 2a = - 14

⇒ a = - 7

Thus, The value of a = - 7

Learn more about the substitution method visit:

https://brainly.com/question/26094713

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Answer:

1.5 hours / 90 minutes

Step-by-step explanation:

time = distance ÷ speed

Answer:

Step-by-step explanation:

[tex] \frac{ - 216}{144} \\ \\ = \frac{ - 3}{2} [/tex]

Answer:

Step-by-step explanation:

4+x-3*z(7+3+6)

4+x-3*z*16

4+x-3*16z

4+x-48z

x-48z+4

Answer:

Ada is correct.

Step-by-step explanation:

Problems with Naman:

Naman is supposed to follow PEMDAS, which is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Division

Addition

Subtraction

~

The mistake: Naman moved +6 to the left and added it to the 2 located on the left side of the expression. You cannot do that, as it breaks the law of PEMDAS. On the other hand, Ada did the correct thing, which was to distribute 2 to all terms within the parenthesis (as one term in the parenthesis has a variable, and the other is a constant, meaning that they cannot be combined). This leads to Naman not doing the rest of the question correct.

Next, Ada correctly combined the two constants, which resulted in 0. 0 means nothing, therefore the placeholder is not needed. Therefore, 8x is the final answer.

Answer:

You would shade the fourth quadrant (bottom right).

Step-by-step explanation:

Due to the domain and range sets, you're given the facts that x must be greater than or equal to 0, but y is less than or equal to zero. This gives you what quadrant the graph should be in. Since you're not given an equation to follow like y=ax+b, then I can not say that this will give you a line.

Answer:

11. [tex]x^{5}[/tex]

12. 5*[tex]x^{2}[/tex]

13. x+21

14. 2x-8

Step-by-step explanation:

Answer:

4.43

Step-by-step explanation:

4 3/7

~Turn into an improper fraction

31/7

~Divide

4.42885714286...

~Round

4.43

Best of Luck!

Answer:

since there is no value for the dimensions of the tennis ball. The tennis ball is a sphere with a Surface Area 4pir²

Step-by-step explanation:

if I understand the typed information here, we have

(-4 + 8x) + 3 > -4

so, I am looking at that :

-4 + 8x + 3 > -4

let's first add 4 on both sides

8x + 3 > 0

then subtract -3 on both sides

8x > -3

and finally divide both sides by 8

x > -3/8

since we never multiplied or divided by a negative number, the inequality sign stays the same.

so, this inequality is true for all x > -3/8

Answer:

5 * sqrt(3)

Step-by-step explanation:

The sine of 60 degrees is equal to x/10 because x is opposite to it and 10 is the hypotenuse. Since the sine of 60 degrees is equal to sqrt(3)/2, sqrt(3)/2 = x/10. Because 5sqrt(3)/10 = sqrt(3)/2, 5sqrt(3)/10 = x/10 and therefore 5sqrt(3) = x.

Answer:

Option 3

Step-by-step explanation:

If he burned off 400 calories from 1500 consumed calories, he has 1100 consumed calories.  1900 - 1100 = 800 calories left to consume.

While option 2 also says no, it's not the right reason.  

The calories left to consume for the day is 800 calories.

No, 1,100 will cause him to exceed 1,900.

Given,

Jace has consumed 1,500 calories so far today.

He has also burned off 400 calories at the gym.

He would like to keep his daily calorie total to 1,900 calories per day.

We need to find how many calories he has left to consume for the day.

And see which option is the best choice.

We have,

Calories consumed in a day = 1500

Burned calories = 400

Calories to keep in a day = 1900

Find the Calories left

= 1500 - 400

= 1100

Find how many calories need to be consumed to keep 1900 calories.

= Calories needed to keep in a day - calories remaining after burned

= 1900 - 1100

= 800

We see that the calories left to consume is 800 calories.

So 1100 is not a viable solution. It will cause him to exceed 1,900.

Thus,

The calories left to consume for the day is 800 calories.

No, 1,100 will cause him to exceed 1,900.

Learn more about finding the calories needed to consumed to keep daily calories here:

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Answer:

The answer is 8.8

Step-by-step explanation:

4/5 x 20/20 = 80/100

80/100 = .8

Step-by-step explanation:

[tex]8 + \frac{4}{5} = \frac{40 + 4}{5} \\ = \frac{44}{5} = 8.8 \\ thank \: you[/tex]

Answer:

C

Step-by-step explanation:

y and 67 are alternate exterior angles and are congruent , then

y = 67° → C

Answer:

x = -11

Step-by-step explanation:

To get to 49 by squaring, you need to square 7. Since x can only be negative, you need to get to -7.

-11 + 4 = -7

(-7)^2 = 49

Answer:

x = -11

Step-by-step explanation:

To get to 49 by squaring, you need to square 7. Since x can only be negative, you need to get to -7.

Answer: Yes, the set of real numbers is closed under addition.

Explanation:

Let x and y be two real numbers. Their sum x+y is some other real number. This is what it means when we say the set of real numbers is closed under addition. Taking any two numbers and adding them will get us some other real number.

There is no way to have x+y be nonreal while x,y are both real.

[tex]\\ \sf\longmapsto -7\dfrac{8}{45}[/tex]

[tex]\\ \sf\longmapsto \dfrac{45(-7)+8}{45}[/tex]

[tex]\\ \sf\longmapsto \dfrac{315+8}{45}[/tex]

[tex]\\ \sf\longmapsto \dfrac{323}{45}[/tex]

[tex]\\ \sf\longmapsto 7.1[/tex]