[tex]\huge\underline\blue{✏ANSWER}[/tex]
(no answer found.)
(maybe can found on other apps?)
#BrainliestBunch
Answer:
12
Step-by-step explanation:
1) Vector AB (-2-(-6); -1-(-1))= (4; 0). Vector module is module AB=sqrt (4*4+0*0)= 4
2) The module of Vector BC is sqrt((-1-(-2))*(-1 - (-2))+ (-4-(-1))* (-4-(-1))= sqrt (9+1)= sqrt 10.
3) The module of AC is sqrt ((-1-(-6))*(-1-(-6))+ (-4-(-1))*(-4-(-1))= sqrt (25+9)= sqrt 34.
4) Having the triangle with the sides AB, BC, AC use the theorem of cos:
sqrt34*sqrt34= sqrt 10*sqrt 10 + 4*4- 2*sqrt10*4*cosB
34-10-16= -8 sqrt 10*cosB
c0sB= (-1)/ sqrt10
5) Find out sinB that is equal to Sqrt (1- ((-1)/sqrt 10)* ((-1)/sqrt10))= sqrt (9/10)= 3/sqrt10.
6)S= 4*sqrt10*3/sqrt10= 4*3=12. The area is equal to 12.
Overline MD cong overline LS additional information is necessary to show that triangle MTD cong triangle LGS by SSS?
Answer:
[tex]TD \cong GS[/tex]
Step-by-step explanation:
See comment for complete question
Given:
[tex]TM \cong GL[/tex]
[tex]MD \cong LS[/tex]
Required
The information that shows [tex]\triangle MTD \cong \triangle LGS[/tex] by SSS
By SSS implies that, the three sides of both triangles are congruent
Already, we have:
[tex]TM \cong GL[/tex]
[tex]MD \cong LS[/tex]
The third side of [tex]\triangle MTD[/tex] is [tex]TD[/tex]
The third side of [tex]\triangle LGS[/tex] is [tex]GS[/tex]
So, for both to be congruent by SSS, the third sides must be congruent
i.e.
[tex]TD \cong GS[/tex]
HELP PLEASE 50 POINTS DONT ANSWER IF YOU DONT KNOW
The ratio 2:3 means for every 2 inches on the original, the photocopy would be 3 inches.
3/2 = 1.5
The photocopied image is 1.5 times larger than the original.
Side BG on the original is side FG on the copy:
14 x 1.5 = 21 meters
FG = 21 meters
Answer:
FG = 21
Step-by-step explanation:
The ratio is 2:3
2 BC
----- = ----------------
3 FG
2 14
----- = ----------------
3 FG
Using cross products
2FG = 3*14
2FG = 42
Divide by 2
FG = 21
Which best explains why all equilateral triangles are similar?
O All equilateral triangles can be mapped onto each other using dilations.
O All equilateral triangles can be mapped onto each other using rigid transformations.
O All equilateral triangles can be mapped onto each other using combinations of dilations and rigid transformations.
O All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
Answer:
the correct answer is option 1.
The correct explanation is: All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
What are similar triangles?Those triangles look the same but are different in size.
And in similar triangles,
the corresponding sides are in proportion to each other and the corresponding angles are equal to each other.
In an equilateral triangle, all three sides are congruent, and all three angles are congruent.
Therefore, any equilateral triangle can be transformed into any other equilateral triangle through a combination of translations, rotations, and reflections, without changing the size or shape of the triangle.
Thus, all equilateral triangles are similar, with side lengths in a 1:1 ratio, since they have the same shape but may differ in size.
To learn more about similar triangles;
https://brainly.com/question/14926756
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someone pls help me tysm will give brainliest !!
Answer:
1. 22:24 and 33:36
2. Yes, because for every time x move two times y will move three times in a graph, just like if a ratio between boys and girls was 2:3 it would mean that for every 2 boys there are 3 girls.
Step-by-step explanation:
11:12 = 22:24 and 33:36
One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fasttt
Answer: [tex]864\ m^2,\ 24\ m[/tex]
Step-by-step explanation:
Given
Perimeter of the rhombus is [tex]120\ m[/tex]
Length of one of the diagonal is [tex]d_1=36\ m[/tex]
All the sides of the rhombus are equal
[tex]\Rightarrow 4a=120\\\Rightarrow a=30\ m[/tex]
Area of the rhombus with side and one diagonal is
[tex]\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}[/tex]
Insert the values
[tex]\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2[/tex]
Area with two diagonals length can be given by
[tex]\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m[/tex]
Thus, the area of the rhombus is [tex]864\ m^2[/tex] and the length of the other diagonal is [tex]24\ m[/tex]
Shilpa's gym membership includes a one-time fee of $20. She then pays a discounted fee of $5 for each visit. The function that shows her average cost after x visits is: Recall the general form of a rational function: Which statement defines the horizontal asymptote? m < n, so y = 0 is the horizontal asymptote. m = n, so y = am / bn is the horizontal asymptote. m = n, so y = 0 is the horizontal asymptote. m > n, so there is no horizontal asymptote.
Answer:
See explanation
Step-by-step explanation:
Given
[tex]Flat = 20[/tex]
[tex]Visit = 5[/tex]
Required
The function to represent x visits
This is calculated as:
[tex]f(x) = Flat + Visit * x[/tex]
So, we have:
[tex]f(x) = 20 + 5 * x[/tex]
[tex]f(x) = 20 + 5x[/tex]
The second question is incomplete; however, I will explain how to calculate the horizontal asymptote of a rational function.
For polynomials with the same degree (i.e. m = n), the horizontal asymptote is calculated by dividing the coefficients of the highest degrees.
e.g.
[tex]f(x) = \frac{6x^2 + 1}{3x^2 + 4}[/tex] ---the degrees of both is 2
So, the horizontal asymptote is:
[tex]y = 6/3[/tex]
[tex]y =2[/tex]
If the numerator has a higher degree, then there is no horizontal asymptote.
If the denominator has a higher degree, then the horizontal asymptote is:
[tex]y = 0[/tex]
Answer:
First one is B, Second is 5
Step-by-step explanation:
got it right on edge
what is the slope of a line that is perpendicular to the line shown? (3,3) and (-3,-1)
Answer:
-3/2
Step-by-step explanation:
Using the slope formula, we can find the slope of the line shown
m = ( y2-y1)/(x2-x1)
= ( -1-3)/(-3-3)
= -4/-6
= 2/3
A line that is perpendicular is the negative reciprocal
-1/ (2/3) = -3/2
Answer:
the slope is 0
Step-by-step explanation:
y2-y1/x2-x1=-1-3/-3-3
y=0
The total enclosed area is ____ square units. Round to the nearest tenths place (1 decimal place).
Answer: 47.6
Is this right?
Answer:
siis corretoed
Step-by-step explanation:
Solve: 3/x-4 >0
x < 4
x > -4
x > 4
x < -4
Answer:
x>4
Step-by-step explanation:
3/(x-4) >0
Divide each side by 3
3/(x-4) * 1/3 >0*1/3
1/(x-4) >0
We know if 1/(x-4) >0 then x-4 > 0
x-4>0
Add 4 to each side
x-4+4 >0+4
x>4
[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]
[tex]:\implies{\dfrac{3}{x-4}>0}\\\\:\hookrightarrow{\dfrac{3}{x-4}×\dfrac{1}{3}>0×\dfrac{1}{3}}\\\\:\longrightarrow{x-4>0}\\\\:\implies{x-4+4>0+4}\\\\ :\dashrightarrow{\sf{x>4}}[/tex]
HELP ASAP
1.
(8,4)
(-4,2)
(4,-8)
(-8,4)
2.
(6,6)
(12,-12)
(-12,12)
(12,12)
3.
(-2,6)
(-4,12)
(4,12)
(12,-4)
Answer:
A(-2,1)》A1(-8, 4)
B(-3,3)》B1(-12,12)
C(-1,3)》C1(-4,12)
HOPE IT HELPS....
I need help, I have no clue what the answer is
Answer:
1/27
Step-by-step explanation:
- substitute the variable with the given datas
[3^-5 * 3^4]^3 * [3^-4 * (-9)^3]^0
- use the properties of power
(3^-1)^3 * 1
3^-3
(1/3)^3
1/27
The answer is number 3 i.e. 1/27
Translate the sentence into an inequality.
Nine times the sum of a number and 22 is at most −15
HELP!!! THANKS YA'LL :))))))
Answer:
9(n + 22) ≤ -15
Step-by-step explanation:
9 times the sum of a number and 22 is at most −15
Let n = number
Times = multiplication
Sum = Addition
9 * n + 22
We must add parenthesis on the end on 22 and before n
We must do this because it says 9 times the sum of a number and 22 which means that 9 is being multiplied by both n and 22
We would have 9(n + 22)
9(n + 22) is at most -15
At most meaning that -15 is the highest number that 9(n + 22) can equal
Because it says at most 9(n + 22) can equal -15 or anything less than -15
So at most can be replaced with ≤
9(n + 22) ≤ -15
X and Y are in partnership with capital contributions of $50000 and $30000 respectively.
The partnership agreement provides that profits are to be shared in proportion to capital
contributions and each partner is entitled to 10% interest on capital.
Profit for the year was $37000.
What was the total amount credited to Y’s current account at the end of the year?
A $10875 B $13875 C $18125 D $23125
Answer:
The correct answer is B. $13,875.
Step-by-step explanation:
Since X and Y are in partnership with capital contributions of $ 50000 and $ 30000 respectively, and the partnership agreement provides that profits are to be shared in proportion to capital contributions and each partner is entitled to 10% interest on capital, and profit for the year was $ 37000, to determine what was the total amount credited to Y’s current account at the end of the year the following calculation must be performed:
50,000 + 30,000 = 80,000
80,000 = 100
30,000 = X
30,000 x 100 / 80,000 = X
37.5 = X
37,000 x 0.375 = X
13.875 = X
-2(5x + 1) > 49
Solve for the inequality and enter your solution
Answer:
x < -51/10
General Formulas and Concepts:
Pre-Algebra
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityStep-by-step explanation:
Step 1: Define
Identify
-2(5x + 1) > 49
Step 2: Solve for x
[Division Property of Equality] Divide -2 on both sides: 5x + 1 < -49/2[Subtraction Property of Equality] Subtract 1 on both sides: 5x < -51/2[Division Property of Equality] Divide 5 on both sides: x < -51/10Answer:
x < -51/10
Step-by-step explanation:
-10x -2 > 49
-10x > 51
x < -51/10
PLS HELP 19 POINTS!!!!!!!!
Answer:
Step-by-step explanation:
15. = 2.39
and jus use mathaway lma
Thank you so much, my friend
Answer:
Step-by-step explanation:
This is quite a doozy, my friend. We will set up a d = rt table, fill it in...and pray.
The table will look like this before we even fill anything in:
d = r * t
SUV
sedan
Ok now we start to pick apart the problem. Motion problems are the hardest of all story problems ever. This is because there are about 100 ways a motion problem can be presented. So far what we KNOW for an indisputable fact is that the distance from Georgetown to Greenville is 120 km. So we fill that in, making the table:
d = r * t
SUV 120
sedan 120
The next part is derived from the sentence "After an hour, the SUV was 24 km ahead of the sedan." This tells us the rate of the SUV in terms of the sedan. If the SUV is 24 km ahead of the sedan in 1 hour, that tells us that the rate of the sedan is r and the rate of the SUV is r + 24 km/hr. BUT we have other times in this problem, one of them being 25 minutes. We have a problem here because the times either have to be in hours or minutes, but not both. So we will change that rate to km/min. Doing that:
24 [tex]\frac{km}{hr}[/tex] × [tex]\frac{1hr}{60min}=.4\frac{km}{min}[/tex] So now we can fill in the rates in the table:
d = r * t
SUV 120 = r + .4
sedan 120 = r
They left at the same time, so now the table looks like this:
d = r * t
SUV 120 = r + .4 * t
sedan 120 = r * t
We will put in the time difference of 25 minutes in just a sec.
If d = rt, then the equation for each row is as follows:
SUV: 120 = (r + .4)t
sedan: 120 = rt
Since the times are the same (because they left at the same time, we will set the equations each equal to t. The distances are the same, too, I know that, but if we set the distances equal to each other and then solve the equations for a variable, the distances cancel each other out, leaving us with nowhere to go. Trust me, I tried that first! Didn't work.
Solving the first equation for time:
sedan: [tex]\frac{120}{r}=t[/tex] That's the easy one. Now the SUV. This is where that time difference of 25 minutes comes in from the last sentence. Let's think about what that sentence means in terms of the times of each of these vehicles. If the sedan arrived 25 minutes after the SUV, then the sedan was driving 25 minutes longer; conversely, if the sedan arrived 25 minutes after the SUV, then the SUV was driving 25 minutes less than the sedan. The latter explanation is the one I used in the equation. Again, if the SUV was driving 25 minutes less than the sedan, and the equations are solved for time, then the equation for the SUV in terms of time is
[tex]\frac{120}{r+.4}=t-25[/tex] and we solve that for t:
[tex]\frac{120}{r+.4}+25=t[/tex]
Again, going off the fact that times they both leave are the same, we set the equations equal to one another and solve for r:
[tex]\frac{120}{r+.4}+25=\frac{120}{r}[/tex]
I began by first multiplying everything through by (r + .4) to get rid of it in the denominator. Doing that:
[tex][r+.4](\frac{120}{r+.4}) +[r+.4](25)=[r+.4](\frac{120}{r})[/tex] which simplifies very nicely to
[tex]120+25(r+.4)=\frac{120}{r}(r+.4)[/tex] So maybe it's not so nice. Let's keep going:
[tex]120+25r+10=\frac{120r}{r}+\frac{48}{r}[/tex] and keep going some more:
[tex]130+25r=120+\frac{48}{r}[/tex] and now we multiply everything through by r to get rid of THAT denominator:
[tex]r(130)+r(25r)=r(120)+r(\frac{48}{r})[/tex] giving us:
[tex]130r+25r^2=120r+48[/tex] Now we have a second degree polynomial we have to solve by factoring. Get everything on one side and factor using the quadratic formula.
[tex]25r^2+10r-48=0[/tex]
That factors to
r = 1.2 and r = -1.6 and both of those rates are in km/minute. First of all, we cannot have a negative rate (this is not physics where we are dealing with velocity which CAN be negative) so we throw out the -1.6 and convert the rate of 1.2 km/minute back to km/hr:
[tex]1.2\frac{km}{min}[/tex] × [tex]\frac{60min}{1hr}[/tex] and we get
r = 72 km/h, choice B.
Wow...what a pain THAT was, right?!
Find it fast pleasee
Answer:
A
Step-by-step explanation:
Additive inverse is (5/3) and multiplicative inverse is (-3/5). Their product is (-1)
Inverse means the opposite of something.
In this case the opposite of -5/3 is 5/3.
So the answer is: 5/3
If you have seven dimes how much money do you have
Answer:
70 cents or 0.70 dollars
Step-by-step explanation:
one dime is 10 cents so if you have 7 than you have 70 cents
Solve these inequalities:
a) x + 14 < 4x + 2 < 3x + 11
b) x + 8 < 8x - 6 < 5x + 12
Answer:
A) 4.7 < x < -3
B) 1.14 < x < 1.09
Step-by-step explanation:
a)
x + 14 < 4x + 2 < 3x + 11
x + 14 < 4x
14 < 4x - x
14 < 3x
4.7 < x
2 < 3x + 11
2 - 11 < 3x
-9 < 3x
-3 < x
4.7 < x - 3 < x
4.7 < x < -3
b)
x + 8 < 8x - 6 < 5x + 12
x + 8 < 8x
8 < 8x - x
8 < 7x
1.14 < x
-6 < 5x + 12
12 < 5x + 6
12 < 11x
1.09 < x
1.14 < x 1.09 < x
1.14 < x < 1.09
−4/7 × 3/5 + 4/7 − 1/5 + 2/5 × −4/7
Pls Answer ASAP. Will Mark Brainliest.
Can you put picture, it is not clear
Find the H.C.F of these expressions.(2a²+6ac,4a²c+12ac²)
Answer:
Hello,
Answer 8a²c(a+3c) =8a³c+24a²c
Step-by-step explanation:
2a²+6ac=2a(a+3c)
4a²c+12ac²=4ac(a+3c)
H.C.F=2a(a+3c)*4ac=8a²c(a+3c)
Answer:
1st expression:2a×a+2×3×a×c
2nd expression:2×2×a×a+2×2×3×a×c×c
here,
2×a×a+2×3×a×c
2a^a+6ac
Instructions: Find the missing side. Round your answer to the nearest tenth.
24°
х
27
Answer:
x = 60.6 units
Step-by-step explanation:
Hi there!
In this right triangle, we're given the measure of an angle, the side opposite that angle and another side adjacent to that angle (that is not the hypotenuse). In this circumstance, we can use the tangent ratio to help us solve for the missing side:
[tex]tan\theta=\frac{opp}{adj}[/tex]
Plug in the given information:
opp = 27, adj = x, θ = 24
[tex]tan(24)=\frac{27}{x}\\x=\frac{27}{tan(24)} \\x=60.6[/tex]
Therefore, the length of the missing side is 60.6 units when rounded to the nearest tenth.
I hope this helps!
2. In the triangle below, NE and KL are perpendicular bisectors. Knowing that the sum of interior angles in
KLME is 360 degrees, find a.
Answer:
a = 60°
Step-by-step explanation:
From the picture attached,
In the given triangle,
NE and ML are the perpendicular bisectors of two sides of the triangle.
Therefore, m∠MEK = m∠MLK = 90°
Since, sum of interior angles of polygon KLME = 360°
m∠MEK + m∠MLK + m∠EML + m∠EKL = 360°
90° + 90° + 120° + a = 360°
a = 360° - 300°
a = 60°
SOMEONE HELP ME PLEASE
Answer:
26/35
Step-by-step explanation:
So we gotta add it together, so 1/7+0.6 or 1/7+3/5. Common denominator is 35, so the answer is 26/35
Which is the graph of y = log4(x+3)?
Edge 2021
Answer:
see graph
Step-by-step explanation:
The function that is shown below is the graph of the given function [tex]y = log_{4}(x+3)[/tex] .
What is a function?"A function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function."
The given function is:
[tex]y = log_{4}(x+3)[/tex]
For [tex]x = -2[/tex], [tex]y = log_{4}(-2+3) = log_{4}1 = 0[/tex]
For [tex]x = -1[/tex], [tex]y = log_{4}(-1+3) = log_{4}2 = 0.5[/tex]
For [tex]x = 0[/tex], [tex]y = log_{4}(0+3) = log_{4}3 = 0.793[/tex]
For [tex]x = 1[/tex], [tex]y = log_{4}(1+3) = log_{4}4 = 1[/tex]
For [tex]x = 2[/tex], [tex]y = log_{4}(2+3) = log_{4}5 = 1.161[/tex]
By putting the values of (x, y) in the graph, we get the graph of [tex]y = log_{4}(x+3)[/tex].
Learn more about a function here:
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Find the missing length of the following trapezoid with midsegment drawn
**You will earn 15 points for both of the problems**
Answer:
UV = 10
HG = 25
Step-by-step explanation:
UV = (11+9)/2 = 20/2 = 10
HG = (28+22)/2 = 50/2 = 25
Answer:
Below in bold.
Step-by-step explanation:
First problem:
The length of the mid segment is the mean of the 2 outer segments.
So it is (11+9)/2
= 20/2
= 10.
Second problem:
As above, it is (22+28) / 2
= 50/2
= 25.
Angles 4 and 6 are
because they are
angles.
Answer: Is this a question? Or statement Yes they can be angles
Step-by-step explanation:
For each relation, decide whether or not it is a function.
Answer:
Step-by-step explanation:
Relation 1 is a function
Relation 2 is not a function
Relation 3 is a function
Realation 4 is not a function
(06.04 MC) Dennis drew the line of best fit on the scatter plot shown below: What is the approximate equation of this line of best fit in slope-intercept form?
Answer:
Step-by-step explanation:
In order to write the equation of this line, we need to pick 2 points on the graph where the line goes right through the intersection of the grids. Actually, you only need 1 of these, because the line goes through at (0, 15). Another point then can be (6, 6). Locate this point so you know what I means when I say that the line goes right through where the grids intersect at x = 6 and y = 6 (as opposed to somewhere in the middle of one of these grids). Find the slope between these 2 points:
[tex]m=\frac{6-15}{6-0}=-\frac{9}{6}=-\frac{3}{2}[/tex]
Since there's only one choice with that slope, that is the choice you want.
please someone help mee
Answer:
4,1,-6
3,-3,-4
x-axis,5,0
2,-7,3
1,4,2
y-axis,0,-4
Step-by-step explanation: