The triangles are similar. If QR = 9, QP = 6, and TU = 19, find TS. Round to the nearest tenth.
A) 16
B) 12.7
C) 2.8
D) 28.5

Answer:

$15798.4

Step-by-step explanation:

We will have to use this formula A = Peᵃᵇ

A = Final amount

P = Initial amount (12,000)

e = Mathematical constant: 2.7183

a = Interest rate (5.5% or 0.055)

b = Years

So our equation will look like this

A = 12,000e⁵ ⁰·⁵⁵

A = 12,000(2.7183)·²⁷⁵

A = 12,000(1.316533)

A = 15798.396

Answer:

(a+b)(a-b)

Step-by-step explanation:

[tex]\\ \sf\longmapsto (a+b)(a-b)[/tex]

[tex]\\ \sf\longmapsto a(a-b)+b(a-b)[/tex]

[tex]\\ \sf\longmapsto a^2-ab+ba-b^2[/tex]

[tex]\\ \sf\longmapsto a^2-ab+ab-b^2[/tex]

[tex]\\ \sf\longmapsto a^2-b^2[/tex]

[tex]\large\bf{\orange{ \implies}} \: \tt \: {a}^{2} \: - \: {b}^{2} [/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: (a + b) \quad \: (a - b)[/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: a \: (a - b) \quad \: b \: (a - b)[/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: ab \: + \: ba \: - \: {b}^{2} [/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: ab \: + \: ab \: - \: {b}^{2} [/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: \cancel{ab} \: + \: \cancel{ab} \: - \: {b}^{2} [/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: {b}^{2} [/tex]

Answer:

Step-by-step explanation:

Triangular cross-section.

Answer:

it is a triangle cross-section

hope this answer helps you

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Answer:

9

Step-by-step explanation:

b = Brandon

4b=b+27

-b   -b

-------------

3b = 27

----   ----

3      3

b = 9

Brandon is 9 years old.

Answer:

4/10=2/5 therefore the answer to 2/5

Answer:

[19 -1 25 3.25]

Step-by-step explanation:

just take the elements from the resultant matrix and divide it by the corresponding elements in the given matrix to find the matrix that's being asked.

9514 1404 393

Answer:

Step-by-step explanation:

The highest degree term is -2v^3. Its degree is 3, so the degree of the polynomial is 3. Its coefficient is -2, so the leading coefficient is -2.

Answer:

gshwhsye

Step-by-step explanation:

gshshhshshshjsjsjsj

Answer:

-

Step-by-step explanation:

-

The probability will be the same for both clocks.

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

With one alarm clock, we have a 0.875 probability of being awakened.

The probability for the two clocks will be the same because both the clocks will ring at the same time.

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Answer:

First by "BODMAS" we will sove multiplication

81×81+68×68-2×81×68

now first we will solve addition

=6561+4624-11016

=11185-11016

=169

Step-by-step explanation:

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The triangles are similar due to SAS congruence postulate rule.

Similar Triangles are defined as two triangles with the same shape, equal pair of corresponding angles, and the same ratio of the corresponding sides. The triangles that like one another but may not be exactly the same size are said to be similar triangles. When two objects have the same shape but different sizes, they can be said to be similar. This indicates that identical shapes superimpose one another when enlarged. The term "Similarity" refers to this characteristic of like shapes.

Given triangles are similar due to SAS congruence postulate rule.

SAS or Side-Angle-Side Similarity Criterion,

According to the SAS similarity theorem, If any two of the first triangle's sides are exactly proportional to those of the second triangle, and if the angle created by these two sides of each individual triangle is equal, then the two triangles must be similar triangles.

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Answer:

[tex]\sqrt{8}+\sqrt{9}[/tex]

Step-by-step explanation:

By definition, the conjugate of a binomial is when you switch the operator (either + or -) in between the terms. For example, the conjugate of [tex]a+b\sqrt{c}=a-b\sqrt{c}[/tex] as we are just changing the addition symbol (+) to a subtraction symbol (-).

Therefore, the conjugate of [tex]\sqrt{8}-\sqrt{9}[/tex] occurs when we change the subtraction symbol to an additional symbol, hence the answer is [tex]\boxed{\sqrt{8}+\sqrt{9}}[/tex]

The angle of 30.283° in a degree-minute-second format will be 30° 16' 58". Then the correct option is C.

Unit modification is the process of converting the measurement of a given amount between various units, often by multiplicative constants that alter the value of the calculated quantity without altering its impacts.

The inclination is the separation seen between planes or vectors that meet. Degrees are another way to indicate the slope. For a full rotation, the angle is 360°.

The angle is given below.

⇒ 30.283°

Convert 30.283° into a degree-minute-second format. Then we have

⇒ 30° (0.83 x 60')

⇒ 30° 16.98'

⇒ 30° 16' (0.98 x 60'')

⇒ 30° 16' 58"

The angle of 30.283° in a degree-minute-second format will be 30° 16' 58". Then the correct option is C.

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Answer:

Kindly check explanation

Step-by-step explanation:

The data table :

Use of SM _UK _China _ Russia _US _ col total

Yes ______480 __215 ___343 __640 _ 1678

No _______320 _ 285 ___357__ 360 _ 1322

Row Total__ 800 _500 __ 700_ 1000_ 3000

H0 : p1 = p2 = p3 = p4

H1 : p1 ≠ p2 ≠ p3 ≠ p4

Test statistic :

χ² = Σ(observed - Expected)² / Expected

Expected value of each cell = (Row total * column total) / N

N = grand total

Expected Values:

447.467 _279.667 _ 391.533 _ 559.333

352.533 _ 220.333 _ 308.467 _ 440.667

χ²=(2.36536+14.9527+6.01605+11.6337+3.00232 18.9793+7.63611+14.7665) = 79.352

Degree of freedom, df = (row-1)*(column-1) = (2 - 1) * (4 - 1) = 1 * 3 = 3

Using the Pvalue from Chisquare calculator :

Pvalue(79.352, 3) = 0.00000000001

Decision region :

Reject H0 ; If Pvalue < α

α = 0.05

Since 0.000000001 < 0.05 ; Reject H0 and conclude that not all population proportion are equal.

Sample proportion :

Phat = number of yes, x / total

For UK, Phat = 480/800 = 0.6

For China , Phat = 215/500 = 0.43

For Russia , Phat = 343/700 = 0.49

For US, Phat = 640/1000 = 0.64

Answer:

given

f(x).4x+5

fog(x).8x+13

now

fog(x):8x+13

4x+5(g(x)):: 8x+13

g(x):: 8x+13/4x+5

Answer:

g(x) = 2x + 2

Step-by-step explanation:

One is given the following information:

One is asked to find the following:

Remember, (f o g (x)) is another way of representing a composite function. A more visual way of representing this composite function is the following (f(g(x)). In essence, one substitutes the function (g(x)) into the function (f(x)) in places of the varaible (x). Thus, represent this in the form of an equation:

f(g(x)) = 8x + 13

Substitute the given infromation into the equation:

4(g(x)) + 5 = 8x + 13

Solve for (g(x)) in terms of (x). Remember to treat (g(x)) as a single parameter:

4(g(x)) + 5 = 8x + 13

Inverse operations,

4(g(x)) + 5 = 8x + 13

4(g(x)) = 8x + 8

g(x) = (8x + 8) ÷ 4

g(x) = 2x + 2

Answer:

answer is A

Step-by-step explanation:

option A is the answer

Answer:

405

Step-by-step explanation:

We can use a ratio to solve

3 infected           x infected

------------------ = ----------------

50 sampled     6750 population

Using cross products

3*6750 = 50x

Divide each side by 50

3*6750/50 = x

405

Answer:

Around 405 elk should be infected with the parasite.

Step-by-step explanation:

6,750/50=135

135 * 3 = 405

hope this helps :)

Answer:

option A

Step-by-step explanation:

Permutation is An arrangement of objects in an ORDER

but combination is the opposite.

Answer:

x11and x2. arevvvscores

In a trapezoid, the midline is the average of the two bases.

PW = (YZ + TM) / 2

29 = (23 + 11x + 2) / 2

58 = 23 + 11x + 2

58 = 25 + 11x

11x = 33

x = 3

Hope this helps!

The horizontal distance from the base of the skyscraper out to the ship is 349.8feet

The angle situated above the hill is known as  the angle of depression

Given the following parameters

Height of the harbor = 824 feet

Angle of depression = 67degrees

According to SOH CAH TOA identity:

tan 67 = opp/adj
tan 67 = 824/d

d = 824/tan67
d = 349.8 feet

Hence the horizontal distance from the base of the skyscraper out to the ship is 349.8feet

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[tex]\frac{11z}{z+3}=13-i,z\in\mathbb{C}[/tex]

First, multiply both sides by [tex]z+3[/tex],

[tex]11z=(13-i)(z+3)[/tex]

[tex]13z+39-iz-3i=11z[/tex]

Collect terms and put z on the left,

[tex]2z-iz=3i-39[/tex]

[tex]z(2-i)=3i-39[/tex]

[tex]z=\frac{3i-39}{2-i}[/tex]

Division of complex numbers is defined by multiplying both denominator and numerator with complex conjugate of the denominator,

[tex]z=3\frac{(i-13)(2+i)}{(2-i)(2+i)}[/tex]

Multiply out,

[tex]z=3\frac{2i-1-26-13i}{5}[/tex]

[tex]z=3\frac{-11i-27}{5}[/tex]

The result is,

[tex]z=-\frac{81}{5}-\frac{33}{5}i[/tex]

Hope this helps :)

Answer:

-2 would be right next to -3 because its negative and -1 would be right next to -2, 2 would be two points away from 0 bc its a whole number

Answer:

The answer is D.

[tex]3x {}^{2} - 10x - 1 = 0[/tex]

Step-by-step explanation:

[tex]x = \frac{5 + 2 \sqrt{7} }{3} [/tex]

Divide each term of 5+2√7 by 3 to get 5/3 + 2/3√7.

[tex]x = \frac{5}{3} + \frac{2}{3} \sqrt{7} [/tex]

[tex]x = \frac{2 \sqrt{7 + 5} }{3} [/tex]

or

[tex]x = 3.43[/tex]

Answer:

?

How did you simplify

Answer:

[tex]\displaystyle \left(\frac{-(m^{2}-1)\, x + 2\, m\, y - 2\, m \, c}{m^{2} + 1},\, \frac{(m^{2} - 1)\, y + 2\, m \, x + 2\, c}{m^{2} + 1}\right)[/tex].

Step-by-step explanation:

Consider the line that is perpendicular to [tex]y = m\, x + c[/tex] and goes through [tex](x,\, y)[/tex].

Both [tex](x,\, y)[/tex] and the reflection would be on this new line. Besides, the two points would be equidistant from the intersection of this new line and line [tex]y = m\, x + c[/tex].

Hence, if the vector between [tex](x,\, y)[/tex] and that intersection could be found, adding twice that vector to [tex](x,\, y)\![/tex] would yield the coordinates of the reflection.

Since this new line is perpendicular to line [tex]y = m\, x + c[/tex], the slope of this new line would be [tex](-1/m)[/tex].

Hence, [tex]\langle 1,\, -1/m\rangle[/tex] would be a direction vector of this new line.

[tex]\langle m,\, -1\rangle[/tex] (a constant multiple of [tex]\langle 1,\, -1/m\rangle[/tex] would also be a direction vector of this new line.)

Both [tex](x,\, y)[/tex] and the aforementioned intersection are on this new line. Hence, their position vectors would differ only by a constant multiple of a direction vector of this new line.

In other words, for some constant [tex]\lambda[/tex], [tex]\langle x,\, y \rangle + \lambda\, \langle m,\, -1 \rangle = \langle x + \lambda \, m,\, y - \lambda \rangle[/tex] would be the position vector of the reflection of [tex](x,\, y)[/tex] (the position vector of [tex](x,\, y)\![/tex] is [tex]\langle x,\, y \rangle[/tex].)

[tex]( x + \lambda \, m,\, y - \lambda )[/tex] would be the coordinates of the intersection between the new line and [tex]y = m\, x + c[/tex]. [tex]\lambda\, \langle m,\, -1 \rangle[/tex] would be the vector between [tex](x,\, y)[/tex] and that intersection.

Since that intersection is on the line [tex]y = m\, x + c[/tex], its coordinates should satisfy:

[tex]y - \lambda = m\, (x + \lambda \, m) + c[/tex].

Solve for [tex]\lambda[/tex]:

[tex]y - \lambda = m\, x + m^{2}\, \lambda + c[/tex].

[tex]\displaystyle \lambda = \frac{y - m\, x - c}{m^{2} + 1}[/tex].

Hence, the vector between the position of [tex](x,\, y)[/tex] and that of the intersection would be:

[tex]\begin{aligned} & \lambda\, \langle m,\, -1 \rangle \\= \; & \left\langle \frac{m\, (y - m\, x - c)}{m^{2} + 1},\, \frac{(-1)\, (y - m\, x - c)}{m^{2} + 1}\right\rangle \\ =\; &\left\langle \frac{-m^{2}\, x + m\, y - m\, c }{m^{2} + 1},\, \frac{-y + m\, x + c}{m^{2} + 1}\right\rangle \end{aligned}[/tex].

Add twice the amount of this vector to position of [tex](x,\, y)[/tex] to find the position of the reflection, [tex]\langle x,\, y \rangle + 2\, \lambda \,\langle m,\, -1 \rangle[/tex].

[tex]x[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & x + 2\, \lambda\, m \\ = \; & x + \frac{-2\, m^{2}\, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1} \\ =\; & \frac{-(m^{2} - 1) \, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].

[tex]y[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & y + (-2\, \lambda)\\ = \; & y + \frac{- 2\, y + 2\, m\, x + 2\, c}{m^{2} + 1} \\ =\; & \frac{(m^{2} - 1) \, y + 2\, m \, x + 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].