The amount of money A accrued at the end of
n years when a certain amount Pis invested at
a compound annual rate r is given by
A= P(1+r)". If a person invests $150 at 5%
interest compounded annually, find the
approximate amount obtained at the end of 5
years.
[A] $191
[B] $4500
[C] $1139
[D] $900

Step-by-step explanation:

hope it helps you and please mark it brainliest answer

Answer: 1/3

Step-by-step explanation:

On side of the smaller quadrilateral is 8, the same side on the larger one is 24. 8 times 3 is 24. So the scale factor from the smaller to the larger is 1/3.

Answer:

1/3

Step-by-step explanation:

similar means all sides are proportinal, in this case one side is 3x bigger in the 2nd figure, so the same must be true of the other fig.

Answer:

- 14x²y

Step-by-step explanation:

Given

- 7x² × 2y

= - 7 × 2 × x² × y

= - 14x²y

Answer:

Answer:

I believ the answer is 6/12 or 1/2

Step-by-step explanation:

2x3 = 6 and 4x3 = 12 and 6/12 simplified would be 1/2

Answer:

I believe the answer is 6/12 or 1/2

Step-by-step explanation:

Answer:

Step-by-step explanation:

The enlargement of a comic will be very similar to the original. Everything is larger but in the same proportion. The difference is if the original is enlarged so much that the individual pixel in the original comic becomes visible; causing the enlargement to be "pixelated."

If a comic is drawn using a grid, that may reduce pixelation because you can line up things with the grid.

If the comic's size is reduced, then again it will look similar but everything is smaller and in the same proportion. There will not be any pixelation effect.

Answer:

y = 4

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 45

Hypothenus = 4√2

Adjacent = y =?

The value of y can be obtained by using cosine ratio as illustrated below:

Cos θ = Adjacent / Hypothenus

Cos 45 = y / 4√2

Cross multiply

y = 4√2 × Cos 45

Recall

Cos 45 = 1 / √2

Therefore,

y = 4√2 × 1/√2

y = 4

Answer:

-19>t

Step-by-step explanation:

-6>t-(-13)

-6>t +(13)

Subtract 13 from each side

-6-13 > t+13-13

-19>t

Answer:

2440

Step-by-step explanation:

an=115

a=7

Sn=n/2(a+an) [Where n is no. of terms]

   = 40/2(7+115)

   = 20(122)

   = 2440

Answer:

90

Step-by-step explanation:

Use angle-arc relation,

For a and 45, Inscribed angle's relation can be utilized

Inscribed angle=Half the arc

45=1/2a

Therefore, a=90

Answer:

70+30i

Step-by-step explanation:

Answer:

Enterprises usually adopt some quality practices to control the product quality during the manufacturing process in order to assure the delivery of qualitative good products to customers. The quality practices or quality management systems adopted by industries will further evolve due to the changes of quality concepts as time goes by. This chapter discusses the change of quality concepts and the related revolution of quality management systems in the past century. The quality concepts were gradually changed from the achievement of quality standards, satisfaction of customer needs, and expectations to customer delight. Since merely satisfying customers is not enough to ensure customer loyalty, the enterprises gradually focus on customers’ emotional responses and their delight in order to pursue their loyalty. The emotion of “delight” is composed of “joy” and “surprise,” which can be achieved as the customers’ latent requirements are satisfied. Thus, the concept of “customer delight” and the means to provide the innovative quality so as to meet the unsatisfied customers’ latent needs are elaborated on. Finally, a framework of innovation creation is developed that is based on the mining of customer's latent requirements. This outline will manifest the essential elements of the related operation steps.

Answer:

x = [tex]-\frac{2}{3}[/tex]

Step-by-step explanation:

I used the FOIL method

[(2x + 3) (3x + 2)] − [(3x + 2) (2x− 3)] = 0

[tex](6x^{2} +4x+9x+6) - (6x^{2} -9x+4x-6)=0[/tex]

[tex](6x^{2} +13x+6) - (6x^{2} -5x-6)=0[/tex]

[tex](6x^{2} +13x+6) - 6x^{2} +5x+6=0[/tex]

combine like terms

[tex]6x^{2} -6x^{2} = 0[/tex]

[tex]13x+5x=18x[/tex]

[tex]6+6=12[/tex]

so, [tex]18x +12 = 0[/tex]

subtract 12 on both sides

[tex]18x=-12[/tex]

divide by 18 to isolate x

[tex]x=-\frac{12}{18}[/tex]

and simplifies to

[tex]x=-\frac{2}{3}[/tex]

Step-by-step explanation:

We reflect We triangle across both axis so the x and y values will both switch.

Our triangle is originally in the second quadrant but then go to the 4the after we reflect it.

Second Quadrant are

^;8+1—](

Answer:

a) [tex]n = 4 + 7\cdot i[/tex], [tex]\forall\, i \in \mathbb{N}_O[/tex], b) [tex]n = 2 + (i+1)^{2}[/tex], [tex]\forall \,i\in \mathbb{N}_{O}[/tex]

Step-by-step explanation:

a) The sequence is representative for an arithmetic sequence, whose key characteristic is that difference is between two consecutive elements is the same. In particular, the sequence has a difference of 7 between any two consecutive elements and the initial element is 4. Hence, we can derive the following formula:

[tex]n = n_{o} + r\cdot i[/tex], [tex]\forall\, i \in \mathbb{N}_O[/tex] (1)

Where:

[tex]n_{o}[/tex] - Initial element.

[tex]r[/tex] - Difference between two consecutive elements.

[tex]i[/tex] - Index.

If we know that [tex]n_{o} = 4[/tex] and [tex]r = 7[/tex], then the expression for the n-th term of the sequence is:

[tex]n = 4 + 7\cdot i[/tex], [tex]\forall \,i\in\mathbb{N}_{O}[/tex]

b) In this case, we have a geometric sequence described by the following equation:

[tex]n = 2 + (i+1)^{2}[/tex], [tex]\forall \,i\in \mathbb{N}_{O}[/tex]  (2)

The constant element ([tex]2[/tex]) represents the two extreme squares, whereas the second order binomial represents the total of squares in the middle ([tex](i+1)^{2}[/tex]) and emulates the area formula of the square.

Answer:

Step-by-step explanation:

?

Answer:

1,195,742.25 (final answer since instructions did not include rounding up or anything)

Step-by-step explanation:

n = 4

The given expression is:

9^8 ÷ 9n

USE PEMDAS order of operations and solve:

9^8 ÷ 9n

= 43046721 ÷ 9n

Substitue n with 4 and solve:

43046721 ÷ 9(4)

= 43046721 ÷ 36

= 1,195,742.25

Answer:

9^4

Step-by-step explanation:

We know that a^b ÷ a^c = a^ (b-c)

9^8 ÷ 9^4

9^(8-4)

9^4

Answer: [tex]\frac{\sqrt{5}}{6}[/tex]

==================================================

Work Shown:

[tex]\frac{\sqrt{10}}{3\sqrt{8}}\\\\\frac{\sqrt{10}*\sqrt{8}}{3\sqrt{8}*\sqrt{8}}\\\\\frac{\sqrt{10*8}}{3\sqrt{8*8}}\\\\\frac{\sqrt{80}}{3\sqrt{64}}\\\\\frac{\sqrt{80}}{3*8}\\\\\frac{\sqrt{16*5}}{24}\\\\\frac{\sqrt{16}*\sqrt{5}}{24}\\\\\frac{4*\sqrt{5}}{24}\\\\\frac{\sqrt{5}}{6}\\\\[/tex]

Note: In the second step, I multiplied top and bottom by [tex]\sqrt{8}[/tex] to rationalize the denominator.

Answer:

square root of 5 over 6 or 0.37267799…

Step-by-step explanation:

Multiply the numerator and denominator by the conjugate.

Solution :

Given data :

x = 65, n = 300

[tex]$\hat p = \frac{x}{n}[/tex]

  [tex]$=\frac{65}{300}$[/tex]

  = 0.2167

The hypothesis are :

[tex]$H_0: p \leq 0.3$[/tex]

[tex]$H_0: p> 0.3$[/tex]

The [tex]\text{level of significance}[/tex], α = 0.05

The test is right tailed.

The standard deviation is :

[tex]$\sigma = \sqrt{\frac{0.3(1-0.3)}{300}}$[/tex]

σ = 0.0265

The test statistics is :

[tex]$z=\frac{\hat p - p}{\sigma}$[/tex]

[tex]$z=\frac{0.2167 - 0.3}{0.0265}$[/tex]

  = -3.14

The critical value is 1.645

The rejection region is : If z > 1.645, then we reject [tex]H_0[/tex]

Decision :

Since the test statistics does not lie in the rejection, so we fail to . [tex]\text{reject the null hypothesis}[/tex].

P-value : [tex]$P(z > - 3.14)$[/tex]   = 0.9992

Therefore, the p-value is not less than the level of significance so we fail to [tex]\text{reject the null hypothesis}[/tex].

Answer:

z^2-3z-18

=(z^2+3z)+(-6z-18)

=z(z+3)-6(z+3)

=(z+3)(z-6)

Answer:

[tex]\sqrt[3]{x^{5}y} = x^{\frac{5}{3}}y^\frac{1}{3}[/tex]

Step-by-step explanation:

Given

[tex]\sqrt[3]{x^{5}y}[/tex]

Required

The equivalent expression

We have:

[tex]\sqrt[3]{x^{5}y}[/tex]

Rewrite as an exponent

[tex]\sqrt[3]{x^{5}y} = (x^{5}y)^\frac{1}{3}[/tex]

Open bracket

[tex]\sqrt[3]{x^{5}y} = x^{5*\frac{1}{3}}y^\frac{1}{3}[/tex]

[tex]\sqrt[3]{x^{5}y} = x^{\frac{5}{3}}y^\frac{1}{3}[/tex]

Answer:

In the real world, a consumer may purchase more then one commodity. Let us assume that a consumer purchases two goods X and Y. How does a consumer spend his fixed money income in purchasing two goods so as to maximize his total utility? The law of equi­-marginal utility tells us the way how a consumer maximizes his total utilit

Answer:

$17,000 at 14% and $9,000 at 2%

Step-by-step explanation:

Let x = amount invested at 14%.

Let y = amount invested at 2%.

x + y = 26000

0.14x + 0.02y = 2560

     -0.02x - 0.02y = -520

(+)    0.14x + 0.02y = 2560

-------------------------------------

       0.12x              = 2040

x = 17,000

x + y = 26000

17000 + y = 26000

y = 9000

Answer: $17,000 at 14% and $9,000 at 2%

Answer:

-p^4 + 4p^3 - 5p^2 + 8p - 6

Step-by-step explanation:

Distribute the -p^2 to the p^2 and the 2. Then distribute the 4p to the p^2 and the 2. Then distribute the -3 to the p^2 and the 2.

When we expand:

-p^4 - 2p^2

+ 4p^3 + 8p

-3p^2 - 6

Group, ordering from highest to lowest "degree" (exponent).

-p^4 + 4p^3 - 2p^2 - 3p^2 + 8p - 6

Combine like terms.

-p^4 + 4p^3 - 5p^2 + 8p - 6

Answer:

Step-by-step explanation:

The lateral surface area is:

[tex]\\ \tt\longmapsto SA=2\pi rh[[/te]

[tex]\\ \tt\longmapsto SA=2\times 22}{7}\times (2.5)(9.25)[/tex]

[tex]\\ \tt\longmapsto SA=145.23in^2[/tex]

[tex] \sf \: ( - 12 )\times( - 4) + (- 8 )+ (+ 3) \\ \sf \: = (- 12 \times - 4 )+ (- 8 + 3) \\ \sf \: = 48 - 5 \\ = 43[/tex]

Hope it helps.

RainbowSalt2222

Answer:

34 : 6800000

Step-by-step explanation: