Answer:
3rd triangle can be constructed with dimensions 2,6,7.
Step-by-step explanation:
sum of any two sides > third side.
difference of any two sides < third side
1.
8+5=13 not >14 (no triangle.)
2.
7+8=15 not >15 (no triangle)
3.
2+6=8>7
2+7=9>6
7+6=13>2
7-2=5<6
7-6=1<2
6-2=4<7
so it is a triangle.
4.
6+3=9 not >10 (not a triangle)
3^x= 3*2^x
solve this equation
Answer:
[tex] {3}^{x} = 3 \times {2}^{x} \\ x = \frac{ln(3)}{ln(3) -ln(2) } = \frac{1.09}{1.09 - 0.69} \\ x = 2.7[/tex]
I hope I helped you^_^
the length of a piece of steel is 10 metres and its width is 4 metres. What is the ratio of its length to width?
Answer:
10:4
or
5:2
Step-by-step explanation:
Scientists have steadily increased the amount of grain that farms can produce each year. The yield for farms in France is given by y=−2.73x2+11000x−11000000 where x is the year and y is the grain yield in kilograms per hectare (kg/ha).
What does the y-intercept of this function represent?
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Answer:
the yield in year 0
Step-by-step explanation:
The y-value is the yield for farms in France in year x. The y-value when x=0 is the yield for farms in France in year 0.
_____
Additional comment
The reasonable domain for this function is approximately 1843 ≤ x ≤ 2186. The function is effectively undefined for values of x outside this domain, so the y-intercept is meaningless by itself.
What is the 21st term of the sequence with a1 = -6 and d = 4?
a) 70
b) 74
c) -40
d) 78
Answer:
74
Step-by-step explanation:
for this question you have to use the formula of the nth term which is Tn=a+(n-1)d,
T21=-6+(21-1)4
=-6+(20)4
=-6+80
=74
I hope this helps
If a and b are positive numbers, find the maximum value of f(x) = x^a(2 − x)^b on the interval 0 ≤ x ≤ 2.
Answer:
The maximum value of f(x) occurs at:
[tex]\displaystyle x = \frac{2a}{a+b}[/tex]
And is given by:
[tex]\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b[/tex]
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are given the function:
[tex]\displaystyle f(x) = x^a (2-x)^b \text{ where } a, b >0[/tex]
And we want to find the maximum value of f(x) on the interval [0, 2].
First, let's evaluate the endpoints of the interval:
[tex]\displaystyle f(0) = (0)^a(2-(0))^b = 0[/tex]
And:
[tex]\displaystyle f(2) = (2)^a(2-(2))^b = 0[/tex]
Recall that extrema occurs at a function's critical points. The critical points of a function at the points where its derivative is either zero or undefined. Thus, find the derivative of the function:
[tex]\displaystyle f'(x) = \frac{d}{dx} \left[ x^a\left(2-x\right)^b\right][/tex]
By the Product Rule:
[tex]\displaystyle \begin{aligned} f'(x) &= \frac{d}{dx}\left[x^a\right] (2-x)^b + x^a\frac{d}{dx}\left[(2-x)^b\right]\\ \\ &=\left(ax^{a-1}\right)\left(2-x\right)^b + x^a\left(b(2-x)^{b-1}\cdot -1\right) \\ \\ &= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right] \end{aligned}[/tex]
Set the derivative equal to zero and solve for x:
[tex]\displaystyle 0= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right][/tex]
By the Zero Product Property:
[tex]\displaystyle x^a (2-x)^b = 0\text{ or } \frac{a}{x} - \frac{b}{2-x} = 0[/tex]
The solutions to the first equation are x = 0 and x = 2.
First, for the second equation, note that it is undefined when x = 0 and x = 2.
To solve for x, we can multiply both sides by the denominators.
[tex]\displaystyle\left( \frac{a}{x} - \frac{b}{2-x} \right)\left((x(2-x)\right) = 0(x(2-x))[/tex]
Simplify:
[tex]\displaystyle a(2-x) - b(x) = 0[/tex]
And solve for x:
[tex]\displaystyle \begin{aligned} 2a-ax-bx &= 0 \\ 2a &= ax+bx \\ 2a&= x(a+b) \\ \frac{2a}{a+b} &= x \end{aligned}[/tex]
So, our critical points are:
[tex]\displaystyle x = 0 , 2 , \text{ and } \frac{2a}{a+b}[/tex]
We already know that f(0) = f(2) = 0.
For the third point, we can see that:
[tex]\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(2- \frac{2a}{a+b}\right)^b[/tex]
This can be simplified to:
[tex]\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b[/tex]
Since a and b > 0, both factors must be positive. Thus, f(2a / (a + b)) > 0. So, this must be the maximum value.
To confirm that this is indeed a maximum, we can select values to test. Let a = 2 and b = 3. Then:
[tex]\displaystyle f'(x) = x^2(2-x)^3\left(\frac{2}{x} - \frac{3}{2-x}\right)[/tex]
The critical point will be at:
[tex]\displaystyle x= \frac{2(2)}{(2)+(3)} = \frac{4}{5}=0.8[/tex]
Testing x = 0.5 and x = 1 yields that:
[tex]\displaystyle f'(0.5) >0\text{ and } f'(1) <0[/tex]
Since the derivative is positive and then negative, we can conclude that the point is indeed a maximum.
Therefore, the maximum value of f(x) occurs at:
[tex]\displaystyle x = \frac{2a}{a+b}[/tex]
And is given by:
[tex]\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b[/tex]
what is an example of a quintic bionomial?
find the value of the trigonometric ratio. make sure to simplify the fraction if needed.
Answer:
36/39
Step-by-step explanation:
Cos(theta) = Base/Hypotenuse
Cos(X) = 36/39
YOU THE REAL OG
IF YOU CAN DO THIS FOR ME
YES IT IS HAIKU
How much would you need to deposit in an account each month in order to have $50,000 in the account in 8 years? Assume the account earns 4% annual interest compounded monthly.
THANK YOU TO ANY OG WHO CAN SOLVE THIS , BRAINLIEST GUARANTEE TO ANYONE WHO REALLY TRIES
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Answer:
$442.80
Step-by-step explanation:
The formula for the amount of an ordinary annuity is ...
A = P(12/r)((1 +r/12)^(12t) -1)
where payment P is made n times per year and interest is accrued at annual rate r.
Filling in the given values, we want ...
50,000 = P(12/0.04)(1 +0.04/12)^(12·8) -1) = 112.91854P
P = 50,000/112.91854 ≈ 442.80
You would need to deposit $442.80 each month for 8 years.
Answer by formula please
Answer:
Step-by-step explanation:
I honestly have no idea what you mean by answer by formula, but I'm going to give it my best. I began by squaring both sides to get:
(a² - b²) tan²θ = b² and then distributed to get:
a² tan²θ - b² tan²θ = b² and then got the b terms on the side to get:
a² tan²θ = b² + b² tan²θ and then changed the tans to sin/cos to get:
[tex]\frac{a^2sin^2\theta}{cos^2\theta}=b^2+\frac{b^2sin^2\theta}{cos^2\theta}[/tex] and isolated the sin-squared on the left to get:
[tex]a^2sin^2\theta=cos^2\theta(b^2+\frac{b^2sin^2\theta}{cos^2\theta})[/tex] and distributed to get:
***[tex]a^2sin^2\theta=b^2cos^2\theta+b^2sin^2\theta[/tex]*** and factored the right side to get:
[tex]a^2sin^2\theta=b^2(sin^2\theta+cos^2\theta)[/tex] and utilized a trig Pythagorean identity to get:
[tex]a^2sin^2\theta=b^2(1)[/tex] and then solved for sinθ in the following way:
[tex]sin^2\theta=\frac{b^2}{a^2}[/tex] so
[tex]sin\theta=\frac{b}{a}[/tex] This, along with the *** expression above will be important. I'm picking up at the *** to solve for cosθ:
[tex]a^2sin^2\theta=b^2cos^2\theta+b^2sin^2\theta[/tex] and get the cos²θ alone on the right by subtracting to get:
[tex]a^2sin^2\theta-b^2sin^2\theta=b^2cos^2\theta[/tex] and divide by b² to get:
[tex]\frac{a^2sin^2\theta}{b^2}-sin^2\theta=cos^2\theta[/tex] and factor on the left to get:
[tex]sin^2\theta(\frac{a^2}{b^2}-1)=cos^2\theta[/tex] and take the square root of both sides to get:
[tex]\sqrt{sin^2\theta(\frac{a^2}{b^2}-1) }=cos\theta[/tex] and simplify to get:
[tex]\frac{sin\theta}{b}\sqrt{a^2-b^2}=cos\theta[/tex] and go back to the identity we found for sinθ and sub it in to get:
[tex]\frac{\frac{b}{a} }{b}\sqrt{a^2-b^2}=cos\theta[/tex] and simplifying a bit gives us:
[tex]\frac{1}{a}\sqrt{a^2-b^2}=cos\theta[/tex]
That's my spin on things....not sure if it's what you were looking for. If not.....YIKES
What is the distance between (-5,-5) and (-9,-2)
Answer:
A (5)
Step-by-step explanation:
The distance is the slope/gradientIn the pythogaras theorem [tex]c^{2} = a^{2} + b^{2}[/tex],c represents the slope and a and b represent the two shorter sides of the right angled triangle ( x,y)
x = -9 - (-5 ) = -9 +5 = -4y = -2 - (-5) = -2 +5 = 3[tex]c^{2}[/tex] = [tex]-4^{2} + 3^{2}[/tex]
= 16 + 9
= 25,
therefore [tex]\sqrt{c^{2} }[/tex] = [tex]\sqrt{25}[/tex]
c = 5
Choose the expression that represents “divide 0.04 by n.”
Answer:
.04/n=4/100n or 4÷100n
Find 2
x
y у
30°
4√3
OA. 4/2
OB.22
0.8
D.4
Answer:
8
Step-by-step explanation:
The given is a special right triangle with angle measures
90-60-30 and side lengths represented by
2a-a[tex]\sqrt{3}[/tex]-a
x is the side length that sees angle measure 90 degrees so it's represented by 2a
and 4[tex]\sqrt{3}[/tex] is the side length that sees angle measure that sees 60 degrees so the value of a is 4
therefore x = 2*4 = 8
If two bags of popcorn and three drinks cost $14,
and four bags of popcorn and one drink costs
$18, how much does a drink cost?
Answer:
2dollars
Step-by-step explanation:
one bag of popcorn is 4 dollars so 4 bags of popcorn is 16 plus 1 drink which is 2 dollars equal 18.
The cost of each popcorn is $4 and the cost of each drink will be $2.
What is the solution to the equation?The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.
If two bags of popcorn and three drinks cost $14, and four bags of popcorn and one drink costs $18.
Let the cost of each popcorn be 'x' and the cost of each drink be 'y'. Then the equations are given as,
2x + 3y = 14 ...1
4x + y = 18 ...2
From equations 1 and 2, then we have
2x + 3(18 - 4x) = 14
2x + 54 - 12x = 14
10x = 40
x = $4
Then the value of the variable 'y' is calculated as,
y = 18 - 4(4)
y = 18 - 16
y = $2
The cost of each popcorn is $4 and the cost of each drink will be $2.
More about the solution of the equation link is given below.
https://brainly.com/question/545403
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Find the missing length indicated
Answer:
x = 960
Step-by-step explanation:
x=√{576×(576+1024)}
or, x = √(576×1600)
or, x = √576×√1600
or, x = 24×40
or, x = 960
Answered by GAUTHMATH
Answer:
Step-by-step explanation:
what’s the value of x? and what’s the measure of angel JHK?
Answer:
x = 14
JHK = 21
Step-by-step explanation:
The angles are vertical angles and vertical angles are equal
3x-21 = x+7
Subtract x from each side
3x-x -21 = x+7-x
2x-21 = 7
Add 21 to each side
2x-21+21 = 7+21
2x = 28
Divide by 2
2x/2 =28/2
x = 14
JHK = 3x-21 = 3(14) -21 = 42-21 = 21
Answer:
Because ∠GHI and ∠JHK are vertical angles, they're congruent. Therefore, set their angle measures equal to each other & solve for x.
[tex]x+7=3x-21\\x-3x=-7-21\\-2x=-28\\x=\frac{-28}{-2} =14\°[/tex]
Substitute in the value of x to find ∠JHK:
[tex]3x-21=3(14)-21=42-21=21\°[/tex]
Mrs. Gomez has two kinds of flowers in her garden. The ratio of lilies to daisies in the garden is 5:2
If there are 20 lilies, what is the total number of flowers in her garden?
Answer:
28
Step-by-step explanation:
5 : 2
since this is a simplified ratio, they have a common factor. let's say it is 'x'
so now :
5x : 2x
we know that 5x is lilies, and we also know that she has 20 lilies, so:
5x = 20
x = 4
the daisies would be 2x so 2*4 = 8
total flowers is 20 + 8
28
what is the decimal equivalent of 7/20
could anyone help me solve this? I’ve had several questions like this and I don’t understand how to solve it. I’ll give brainliest:)
Answer:
-2, - 1, - 2 and - 3
Step-by-step explanation:
As the graph depicts an odd function, it will follow the rule f(-x) = - f(x)
An airline charges the following baggage fees: $20 for the first bag and $40 for the second. Suppose 54% of passengers have no checked luggage, 25% have only one piece of checked luggage and 21% have two pieces. We suppose a negligible portion of people check more than two bags.
a) The average baggage-related revenue per passenger is: $___.
b) The standard deviation of baggage-related revenue is: $____.
c) About how much revenue should the airline expect for a flight of 120 passengers?
Vehicles that get more than 40 miles per gallon can cross one county’s new bridge for free. Which graph shows the fuel-use rate of vehicles that have to pay to cross the bridge?
Answer:
D
Step-by-step explanation:
More than 40 miles per gallon
Open circle at 40 and line goes to the left
Answer: the answer is C
Step-by-step explanation:
because it is a open circle going to the left
Write the quadratic equation whose roots are 2 and -4 and whose leading coefficient is 2
Answer:
2x^2+4x-16
Step-by-step explanation:
The quadratic can be written as
f(x) = a(x-z1)(x-z2) where z1 and z2 are the roots
f(x) = a (x-2)(x- -4)
a is the leading coefficient
f(x) = 2(x-2)(x+4)
= 2(x^2 -2x+4x-8)
= 2(x^2 +2x-8)
= 2x^2 +4x-16
Three numbers are in the ratio of 1:2:4. If 3 is added to the first and 8 is subtracted from the third, the new numbers will be the first and third terms of an A.P., whose second term is the second number. Find the original numbers.
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Answer:
5, 10, 20
Step-by-step explanation:
Suppose the three numbers are x, 2x, and 4x. Then they have the required ratios. After the transformation, we have ...
((x+3) +(4x -8))/2 = 2x . . . . . 2nd term is average of 1st and 3rd
5x -5 = 4x ⇒ x = 5
The original numbers are 5, 10, 20.
_____
After the adjustment, the arithmetic sequence is 8, 10, 12.
Clue is a board game in which you must deduce three details surrounding a murder. In the original game of Clue, the guilty person can be chosen from 66 people, and there are 66 different possible weapons and 99 possible rooms. At one point in the game, you have narrowed the possibilities down to 44 people, 55 weapons, and 77 rooms. What is the probability of making a random guess of the guilty person, murder weapon, and location from your narrowed-down choices, and the guess being correct
Answer:
The probability of making a correct random guess is 0.00053%.
Step-by-step explanation:
Since Clue is a board game in which you must deduce three details surrounding a murder, and in the original game of Clue, the guilty person can be chosen from 66 people, and there are 66 different possible weapons and 99 possible rooms, and at one point in the game, you have narrowed the possibilities down to 44 people, 55 weapons, and 77 rooms, to determine what is the probability of making a random guess of the guilty person, murder weapon, and location from your narrowed-down choices , and the guess being correct, the following calculation must be performed:
(1 / (44x55x77)) x 100 = X
(1 / 186,340) x 100 = X
0.0005366 = X
Therefore, the probability of making a correct random guess is 0.00053%.
b) An achievement test was administered to a class of 20,000 students. The mean score was 80 and the standard deviation was 11. If Lingard scored 72 in the test, how many students did better than him
Answer: 15328
Step-by-step explanation:
The following can be deduced from the information given:
N = 20000
μ = 80
σ = 11
P(X>72) = 1 - P (X<72)
= 1 - P(Z < 72-80/11)
= 1 - P(Z < -8/11)
= 1 - P(Z < 0.7272)
= 1 - 0.2336 = 0.7664
Therefore, the number of students that were better than Lingard n(X > 72) will be:
= 20000 × 0.7664
= 15328
What is the measure of 7 shown in the diagram below?
110°
O A. 74.5°
B. 32°
X
O C. 71°
Z
D. 35.5°
Answer:
c
Step-by-step explanation:
Answer:
the correct choice is B
Step-by-step explanation:
Only the top runners in the world can finish a marathon in close to 2 hours. This graph
shows the pace that one such runner followed in a race. What is the unit rate?
Marathon Pace
N
28
24
20
Distance (mi)
10
12
B
8
A
4
0
0 20 40 60 80 100120140
Time (min)
Answer:
the unit rate is 4mi per minute.
Step-by-step explanation:
if you find the slope between point A and point B, you see that the line rises at 4 mi (distance) per minute (time). thus the unit rate is 4mi per minute. please correct me if I'm wrong, I hope this answer helps.
Is interquartile range a measure of center or a measure of variation?
Answer:
The interquartile range is the middle half of the data that is in between the upper and lower quartiles. ... The interquartile range is a robust measure of variability in a similar manner that the median is a robust measure of central tendency.
Find the greatest common factor of 65a3b4 and 39a4b5.
Step-by-step explanation: Let's begin by finding the
greatest common factor for the numbers 65 and 39.
I would make a factor tree and break up 65 and 39.
So 65 is 13 x 5 and 39 is 13 x 3.
Since the 13's match up, the greatest
common factor between 65 and 39 is 13.
For the variables, we use the smallest power on each of them.
So we use a^3 and b^4 to get 13a^3b^4 as our GCF.
It is estimated that t months from now, the population of a certain town will be changing at the rate of 4+ 5t^2/3 people per month. If the current population is 10,000, what will the population be 8 months from now?
Answer:
240000
Step-by-step explanation:
Represent the exponential equation.
[tex]10000 (5 {t}^{ \frac{2}{3} } + 4) = [/tex]
Replace 8 with t
[tex]10000(5(8) {}^{ \frac{2}{3} } + 4)[/tex]
[tex]10000(5 \times 4 + 4) [/tex]
[tex]10000(24) = 240000[/tex]
The population of the town after 8 month will be 2,40,000.
What is exponential growth?
Exponential growth is a pattern of data that shows greater increases with passing time, creating the curve of an exponential function.
Let P be the population of the town after 8 months
According to the given question
The current population of the town = 10,000.
Also, the population of the town is changing at the rate of [tex]4+5t^{\frac{2}{3} }[/tex].
Therefore, the population of the town after 8 month is given by the exponential function
[tex]P = 10000(4+5t^{\frac{2}{3} } )[/tex]
Substitute t =8 in the above equation
⇒[tex]P = 10000(4 + 5(8)^{\frac{2}{3} } )[/tex]
⇒[tex]P = 10000(4 + 5(2^{3}) ^{\frac{2}{3} } )[/tex]
⇒[tex]P = 10000(4+5(4))[/tex]
⇒[tex]P = 10000(24)[/tex]
⇒[tex]P = 240000[/tex]
Hence, the population of the town after 8 month will be 2,40,000.
Find out more information about exponential growth here:
https://brainly.com/question/11487261
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Dos coches están separados por una distancia de 12000 m salen al encuentro uno del otro, el primero con una aceleración de 5,6 m/s2 el segundo con 10,4 m/s2 , calcula el tiempo y la distancia de encuentro.
Un bus parte del reposo con una aceleración de 3,2 m/s2 y en ese mismo momento a 2 km de distancia, sale otro en sentido opuesto, también partiendo del reposo pero con una aceleración de 6,5 m/s2. Calcular la distancia y el momento de encuentro.
Dos vehículos separados por 1300 m parten al encuentro en el instante t=0. El primero lo hace con una velocidad inicial constante de 15 km/h. El segundo parte desde el reposo y con una aceleración de 1,2 m/s2. ¿A qué distancia de la salida del primer vehículo se encuentran?
Un automóvil se desplaza por una carretera que es paralela a la vía de un metrotren. El automóvil se detiene ante un semáforo que está con luz roja en el mismo instante que pasa un metrotren con una rapidez constante de 14 [m/s]. El automóvil permanece detenido durante 8 s y luego parte con una aceleración constante de 2,5 [m/s2 ]. Determine:
a)El tiempo que emplea el automóvil en alcanzar al metrotren, medido desde el instante en que se detuvo ante el semáforo.
Un micro parte del reposo y acelera a razón de 1,4 m/s2 . En este instante un pasajero que desea abordarlo, se encuentra a 12 [m] por detrás de la puerta y corre con una velocidad constante de 5 m/s.
a) Determinar si el pasajero alcanza o no al micro
Salva mi trimestre
Answer:
la respuesta es la primera ( a )
Step-by-step explanation:
