Answer: hey, i hope this hlps!~~~ Part of mental health is how well your mind processes and understands information and experiences. In contrast, emotional health involves your ability to manage and express the emotions that arise from what you have learned and experienced.
Explanation:
help please!!
From the following images shown, classify the interactions that occur and say between which bodies, according to the following criteria:
a) Contact forces
b) Non-contact forces
Answer:
B= 4 A=5
Explanation:
Si se aplic una fuerza de 150N en un área de de 0.4m2¿cual será la preciosa ejercida?
Answer:
P = 375 Pa
Explanation:
The question says that,"If a force of 150N was applied in an area of 0.4m², what will be the precious exerted?"
We have,
Force, F = 150 N
Area, A = 0.4m²
We need to find the pressure exerted. We know that,
Pressure = forece/area
So,
[tex]P=\dfrac{150\ N}{0.4\ m^2}\\\\P=375\ Pa[/tex]
So, the required pressure is equal to 375 pa.
the volume of vessel is 6 litres. convert it into ml
(b) During one day, 250 kg of water is pumped through
the solar panel. The température of this
water rises from 16°C to 38°C.
The water absorbs 25% of the energy incident on the solar panel. The
specific heat capacity
of water is 4200J/(kg °C).
Calculate the energy incident on the solar panel during that day.
Please explain how to find the incident energy
Answer: The energy incident on the solar panel during that day is [tex]9.24 \times 10^{7} J[/tex].
Explanation:
Given: Mass = 250 kg
Initial temperature = [tex]16^{o}C[/tex]
Final temperature = [tex]38^{o}C[/tex]
Specific heat capacity = 4200 [tex]J/kg^{o}C[/tex]
Formula used to calculate the energy is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat energy
m = mass of substance
C = specific heat capacity
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C[/tex]
As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.
[tex]\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J[/tex]
Thus, we can conclude that the energy incident on the solar panel during that day is [tex]9.24 \times 10^{7} J[/tex].
A certain capacitor, in series with a resistor, is being charged. At the end of 25 ms its charge is half the final value. The time constant for the process is about:
Answer:
τ = 36 10⁻³ s
Explanation:
The charge of a circuit Rc is given by the expression
q = q₀ (1 - [tex]e^{-t/ \tau }[/tex])
q / q₀ = 1 - e^{-t/ \tau }
in this exercise they indicate that
q / q₀ = ½
for a time t = 25 10⁻³ s
we substitute
½ = 1 - [tex]e^{- 25 \ 10^{-3} / \tau}[/tex]
e^{- 25 \ 10^{-3} / \tau} = 1 -½
- 25 10⁻³ /τ = ln 0.5
-25 10⁻³ / ln 0.5 = τ
τ = 36 10⁻³ s
A block slides down a smooth inclined surface and the gap between the block and the surface contains viscous fluid. Assume the velocity distribution in the gap is linear, and the area of the block in contact with the vicious fluid remains constant. If you increase the inclined angle, the terminal velocity will Group of answer choices
Answer:
The velocity increases as the inclination increases.
Explanation:
hen a block moves downwards along the inclined plane, the viscous property of the fluid between the block and the inclined acts and thus there is a friction between the block and surface.
When gravitational force acting along the plane provides the acceleration of the block.
When the angle of inclination increases, the acceleration along the plane increases and thus the velocity increases.
What is the gravitational potential energy of a 3.0-kg rock that is 12.4 m above the ground?
Answer:
Explanation:
PE = mgh where m is mass, g is the pull of gravity, and h is the height to which the object can possibly fall.
PE = 3.0(-9.8)(-12.4) so
PE = 360 J, rounded to the correct number of sig figs.
The gravitational potential energy of the rock is 362.4 joules.
What is gravitational potential energy?The gravitational potential energy of an object is given by the formula:
PE = mgh
where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity (which is approximately 9.81 m/s^2 near the surface of the Earth), and h is the height of the object above a reference point.
In this case, the mass of the rock is 3.0 kg, the height above the ground is 12.4 m, and the acceleration due to gravity is 9.81 m/s^2. Substituting these values into the formula, we get:
PE = (3.0 kg) x (9.81 m/s^2) x (12.4 m) = 362.4 J
Therefore, the gravitational potential energy of the rock is 362.4 joules.
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which material has more specific heat?
Answer:
SO
Explanation:
SI
Answer:
Explanation:
dynamic equilibrium
A rope horizontally pulls a massive object lying on a surface with friction with a constant
velocity. What describes the force on the rope?
Answer:
Equal to the frictional force
Explanation:
Question; The options given with regards to a similar question posted online are;
A. Equal (equivalent) to the frictional force
B. Larger than the frictional force
C. Equal to the object's weight
D. More than the object's weight
Explanation
According to Newton's first law of motion, every object shall remain at rest or continue moving with uniform (constant speed) motion unless there is a net force acting on the object
Given that the velocity of the massive block, lying on the surface that has friction, being pulled by the rope = Constant
Therefore;
The net force acting on the moving block while being pulled by the rope = 0
From which we have;
The pulling force = The resistive force
Where;
The pulling force = The (pulling) force (applied) on the rope
The resistive force = The frictional force of the surface which tends to prevent the motion of the block
Therefore, given that the net force acting on the block = 0
The force on the rope = The frictional force (of the surface)
The correct option is option A. Equal to the frictional force.
A man ran a 5 mile race. The race looped around a city park and back
to the starting line. What is the man's total displacement?
A. 0 miles
B. 2.5 miles
C. 5 miles
D. 10 miles
Answer:
How big the city because it could be a big all city
[tex]what \: is \: matter \: \: \: {?} [/tex]
Answer:
matter is any substance that has mass and takes up space by having volume.
Explanation:
Matter is anything that has a mass and it takes up space or has a volume .
matters are made up many atoms or molecules .
hope it is helpful to you
stay safe, happy and healthy
There is a bell at the top of a tower that is 45m high. The bell weighs 190N. The bell has ___________________ energy. Calculate it.
I NEED THE ANSWER PLEASE
Answer:
250mn
Explanation:
A sphere of diameter 3.0cm is mounted into a thin uniform wire of diameter 0.2mm calculate the length of the wire in meters
Answer:
Length of the wire in meters = 0.000628 meter (Approx.)
Explanation:
Given:
Diameter of wire = 0.2 mm
Find:
Length of the wire in meters
Computation:
Radius of wire = 0.2 / 2
Radius of wire = 0.1
Length of the wire = Circumference of circle
Circumference of circle = 2πr
Length of the wire = 2πr
Length of the wire = 2(3.14)(0.1)
Length of the wire = 0.628 mm (Approx.)
1 meter = 1,000 mm
So,
Length of the wire in meters = 0.000628 meter (Approx.)
a bell rings at a frequency of 75hz on a warm 25 degree evening. calculate the...
a. speed of the sound wave at this temperature.
b. wavelength of the sound wave
Answer:
Explanation:
We need 2 different equations for this problem: first the velocity of sound equation, then the frequency of the sound equation.
The velocity of sound is found in:
v = 331.5 + .606T
We need to find that first in order to fill it into the frequency equation which is
[tex]f=\frac{v}{\lambda}[/tex] where v is the velocity we will find the part a, f is frequency and lambda is the wavelength. Starting with the velocity of the sound:
v = 331.5 + .606(25) and
v = 331.5 + 15 and rounding correctly using the rules for sig fig when adding:
v = 347 m/s
Filling that into the frequency equation:
[tex]75=\frac{347}{\lambda}[/tex] and
[tex]\lambda=\frac{347}{75}[/tex] so
[tex]\lambda=4.6m[/tex]
what is parking orbit?
Answer:
A temporary orbit in which a spacecraft awaits the next phase of its mission .
Si un movil parte del reposo logrando una aceleracion de 5 metros por segundo al cuadrado durante 8 segundos calcular la velocidad final
Answer:
Velocidad final, V = 40 m/s
Explanation:
Dados los siguientes datos;
Aceleración = 5 m/s²
Velocidad inicial = 0 m/s (ya que comienza desde el reposo)
Tiempo = 8 segundos
Para encontrar la velocidad final, usaríamos la primera ecuación de movimiento;
[tex] V = U + at[/tex]
Dónde;
V es la velocidad final. U es la velocidad inicial. a es la aceleración. t es el tiempo medido en segundos.Sustituyendo en la fórmula, tenemos;
[tex] V = 0 + 5*8 [/tex]
[tex] V = 0 + 40 [/tex]
[tex] V = 40 [/tex]
Velocidad final, V = 40 m/s
If you were testing materials to see whether they conduct electricity using a circuit and bulbs, what variable would you be changing?
A. The strength of the battery
B. The number of bulbs
C. The material
D. The time it takes the electricity to complete the circuit
Answer: C. The material
Explanation:
In order to check whether a material conducts electricity, the first thing to do would be to design a circuit. Connect a positive wire to the batteries and then another wire from the battery to the bulb and then a wire from the bulb as well.
Then bring different materials to test for conductivity by connecting the wires to the material. If the bulb lights then it is a conductor and if it doesn't the material is not a conductor. The material is therefore the changing variable.
A 2 kg hammer is used to nail a 0.002 kg nail with a force of 10 N. How much force is applied to the hammer?
Answer:
10 N
Explanation:
Given that,
A 2 kg hammer is used to nail a 0.002 kg nail with a force of 10 N.
We need to find how much force is applied to the hammer.
We know that, every action has an equal and opposite reaction. Both the action and reaction occurs in two different objects.
Hence, the force applied to the hammer is equal to 10 N.
Multiplying a vector with another vector results in what type of answer.
A) a direction
B) a vector
C) either a vector or a scalar
D) a scalar
multiplication of two vectors yields a vector oroduy
Bones are composed of three main components, what are they? (Choose all that apply)
Answer:
funny bone and compact bone
Explanation:
your funny bone only reacts if you hit it against something the compact bone is the heaviest and strongest bone in your body and the bone marrow is soft sponge like tissue in the center if most bones that produces white and red blood cells
As Courtney switches on the TV set to watch her favorite cartoon, the electron beam in the TV tube is steered across the screen by the field between two charged plates. If the electron experiences a force of 3.0 * 10^6 N, how large is the field between the deflection plates?
Answer:
Explanation:
Force= (q1q2)/(4/\Ęr2)
3×10^6= (1.602×10^-19)^2/(r^2)
r^2=(2.27×10^-33)/(3×10^6)
r^2=8.55×10^-45
r= 9.25×10^-23
The metal wire in an incandescent lightbulb glows when the lights is switch on and stops glowing when switched off. This simple process is which kind of a change?
Answer:
When the metal wire in an incandescent lightbulb glows when the light is switched on and stops glowing when it is switched off, this is an example of resistance, which provides light and heat.
Explanation:
Opening or closing a circuit.
a man runs 1200m on a straight line in 4 min . find his velocity.
Answer:
5m/sec^2
Explanation:
Distance=1200m
Time=4 min
1=60sec
4=4 x 60
=240sec
Velocity=Distance/Time
Velocity=1200/240
Velocity=5m/sec^2
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The energy of an electromagnetic wave changes proportionally to which
other property?
O A Speed
O B. Shift
O c. Wavelength
O D. Frequency
Answer:
D. Frequency
Explanation:
The energy of an electromagnetic wave is proportional to frequency, mathematically it is expressed as;
E ∝ f
E = hf
where;
h is Planck's constant = 6.626 x 10⁻³⁴ Js
The equation above can also be expanded to;
[tex]E = hf = h \frac{c}{\lambda}[/tex]
where;
c is speed of light = 3 x 10⁸ m/s
λ is the wavelength of the electromagnetic wave
Since the speed of light is constant, we can conclude that the energy of the electromagnetic wave is directly proportional to its frequency and inversely proportional to its wavelength.
Therefore, the correct option for direct proportionality is FREQUENCY
A gas in a sealed container has a pressure of 50 kPa at 27°C. What will the pressure of the gas be if the temperature rises to 87°C?
Answer:
the final pressure of the gas is 60 kPa.
Explanation:
Given;
initial pressure of the gas, P₁ = 50 kPa = 50,000 Pa
initial temperature of the gas, T₁ = 27⁰ C = 27 + 273 = 300 k
final temperature of the gas, T₂ = 87⁰ C = 87 + 273 = 360 K
Let the final pressure of the gas = P₂
Apply pressure law;
[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} = \frac{50,000 \times 360}{300} = 60,000 \ Pa = 60 \ kPa[/tex]
Therefore, the final pressure of the gas is 60 kPa.
Orion Balatik Big Dipper Apparent Brightness Absolute Brightness Polaris Star Trail Malihe Gemini Buwaya 1. Local constellation that signifies the start of rainy season in the Philippines. 2. Local constellation that appears in the month of March. 3. It is seen in the Philippines during the months of April and May. 4. The constellation where we can find Merak and Dubhe. 5. It is the brightes star in the constelation Ursa Minor (Little Dipper). 6. It is a type of photograph that utilizes long-exposure times to capture the apparent motion of stars in the night sky due to the rotation of the Earth. 7. The star's brightness as seen from the Earth. 8. The brightness of the stars if they are at the same standard distance from Earth. 9. This constellation means hunter and is prominent in the night sky all over the world during winter. 10. The local constellation that appears on the month of February and signifies start of planting and setting of traps to protect the crops from animals.
the quantum theory of radiation reflects:
the principle of superposition
the electromagnetic theory of light
the special theory of relativity
the principle of the photoelectric effect
Answer:
The electromagnetic theory of light , that's the answer
Answer:
the electromagnetic theory of light
Explanation:
got it right on o.w
How is an ammeter connected in a circuit to measure current flowing through it?
Answer:
It is connected in series with the circuit
Explanation:
This is because to measure the current in the circuit, the current in the circuit has to flow through the ammeter. As such, the ammeter must be connected in series with the circuit so as to measure the current flowing through the circuit.
So, to measure the current flowing through a circuit with an ammeter, the ammeter must be connected in series with the circuit.
6.05 Infections and Health
Plese don't report me i am trying to get the assigment done
Introduction
Contaminated water is a health risk, and not all populations have access to clean water. You are going to use household items to design, test and revise a water filtration system. New technologies undergo testing and revision before they are released to the public. This lab will simulate how the scientific process is used to solve problems.
Purpose
The Purpose of your design is to filter dirt, sand and other sediment from “swamp” water. You do not need to make it drinkable during this design. You will begin with a water sample that has visible dirt, mud or other contaminants. You will design a way to filter the water and evaluate your design. You will not be able to test for microorganisms or to filter them out during this design process. Do not test the water by drinking it.
Important: Do NOT drink the water in your experiment.
Materials
“Swamp” water (You can get this from an outside source like a hole in the ground, puddle, lake, river or swamp. Or, you may add dirt and sediment to tap water.) The starting sample should have visible dirt or sediment.
You may use any household materials for your water filtration system. Here are some suggestions:
Cheesecloth
OId t-shirt
Coffee filters
Pantyhose
Cotton balls
Sock
Funnel
Water bottle
Data for Design One (6 points)
Describe the appearance and smell of the “swamp” water before and after filtration. Use complete sentences and detailed examples.
Skilled Scientist level from Rubric: Student gives thorough details about the appearance and smell of the water before and after the filtration for Design One and Design Two.
Water before filtration
Water after filtration
Description of appearance
Description of smell or other physical characteristics
Rate the visible cleanliness of the water on a scale of 1 to 10 with 10 being the cleanest.
Feedback ( 5 points)
Consulat a peer or a family member about ways your design could be improved. Describe the feedback and provide the name of the reviewer. These are only suggestions that you can use to plan for Design Two. Use complete sentences and detailed examples.
Skilled Scientist level from Rubric: Student thoroughly describes the feedback received from peer/family member, and it is clear a meaningful exchange about ways to improve the design took place.
List the name of peer/family member and relationship:
Describe the feedback given by your peer/family member. What changes do they suggest you make to your design in order to clean the water better?
Planning for DesignTwo (8 points)
Use this space to plan out how to improve your water filter. Based on the feedback you received, what part are you trying to improve? Why did you make the changes that you did? Use complete sentences and detailed examples. You may include sketches or diagrams.
Skilled Scientist level from Rubric: Student thoroughly explains the changes for the design and gives ample details about any improvements that were made.
List materials used:
Describe how Design Two will work:
What part of your design are you trying to improve?
Why did you make the changes you did?
Data for Design Two (6 points)
Use the data and feedback from your first design to make changes to your water filtration system. Test your new design. Record the appearance and smell of the “swamp” water before and after filtration. Use complete sentences and detailed examples.
Skilled Scientist level from Rubric: Student gives thorough details about the appearance and smell of the water before and after the filtration for Design One and Design Two.
Water before filtration
Water after filtration
Description of appearance
Description of smell or other physical characteristics
Rate the visible cleanliness of the water on a scale of 1 to 10 with 10 being the cleanest.
Conclusion (10 points)
Use your data from Design One and Design Two to answer the following questions. Use complete sentences and detailed examples.
Skilled Scientist level from Rubric: Student answers all questions using ample details and showing critical thinking skills to reflect on the design process.
Summarize the appearance and smell of the “swamp” water before and after the filtering process using Design One.
2. Describe the changes you made to your water filtration system.
3. What feedback helped you make changes to your water filtration system?
4. Summarize the appearance and smell of the “swamp” water before and after the filtering process using Design Two.
5. What did you learn about the process of planning, testing and revising a design?
The process of filtration of swamp water using a filtering material such as neat clothes will make the water clearer and remove any bad smell.
What is filtration?Filtration is a separation technique used to separate insoluble solids from a liquid.
Filtration is employed in water purification.
Water purification is done in water purification plants.
A locally designed purification process for swamp water will involve using materials such as:
A T-shirt Funnel Water bottleThe T-shirt is used filter out mud and sediments.
Repeated filtrations will make the water clearer and remove any bad smell.
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In Rutherford's model of the atom, the positive charge
A) occupies most of the space in the atom
B) is concentrated at the center of the atom
C) is distributed throughout the atom's volume
D) revolves about the nucleus in specific orbits
Answer:
the correct address is B
In Rutherford's model of the atom, the positive charge is concentrated at the center of the atom.
What is Rutherford's model?The model described the atom as a tiny, dense, positively charged core called a nucleus, in which nearly all the mass is concentrated, around which the light, negative constituents, called electrons, circulate at some distance, much like planets revolving around the Sun.
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