Using the table above. Which statement below is true?

Using The Table Above. Which Statement Below Is True?

Answers

Answer 1

9514 1404 393

Answer:

  (d)  45% play basketball; 55% play soccer

Step-by-step explanation:

You just need a little number sense here. The total number who play sports is the number in the lower right of the table: 120.

The fraction who are males playing basketball is 42/120. Comparing that to 45/100, we see it cannot be 45%. (a) is false.

The fraction who are males is 72/120, more than half, so cannot be 40%. (b) is false.

Looking at males who play basketball, we have already determined the fraction 42/120 is well below 65%. (c) is false.

The fraction who play basketball is 54/120 = 45%. (d) is true.


Related Questions

Find the slope of the line that passes through the two points 2,-4 & 4,-1

Answers

Answer:

Step-by-step explanation:

I have this saved on my computer in notepad b/c this type of question get asked sooo often :/

point P1 (-4,-2)  in the form (x1,y1)

point P2(3,1)  in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

My suggestion is copy that above and save it on your computer for questions like this

now use it

Point 1  , P1 = (2,-4)   in the form (x1,y1)

Point 2 , P2 = (4,-1)  in the form (x2,y2)

m = [ -1-(-4) ]  /  [ 4-2]

m =  (-1+4) / 2

m = 3 / 2

so now we know the slope is  3/2  :)  

The principle of redundancy is used when system reliability is improved through redundant or backup components. Assume that a​ student's alarm clock has a 15.3​% daily failure rate. Complete parts​ (a) through​ (d) below. a. What is the probability that the​ student's alarm clock will not work on the morning of an important final​ exam?

Answers

Answer:

[tex]Pr = 0.153[/tex]

Step-by-step explanation:

Given

[tex]p = 15.3\%[/tex]

Required

Probability of alarm not working

[tex]p = 15.3\%[/tex] implies that the alarm has a probability of not working on a given day.

So, the probability that the alarm will not work on an exam date is:

[tex]Pr = 15.3\%[/tex]

Express as decimal

[tex]Pr = 0.153[/tex]

g ) If it is raining, a home security system detects an intruder with probability 0.70. If it is NOT raining, the probability becomes 0.92. The probability of rain on any 2 given day is 0.25. To test the system on a randomly chosen day, the system technician pretends to be an intruder. Given that the technician will NOT be detected, what is the probability that it is NOT raining

Answers

Answer:

0.4444 = 44.44% probability that it is NOT raining

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Technician not detected.

Event B: Not raining.

Probability the technician is not detected:

0.3 of 0.25(raining).

0.08 of 0.75(not raining). So

[tex]P(A) = 0.3*0.25 + 0.08*0.75 = 0.135[/tex]

Probability the technician is not detected and it is not raining:

0.08 of 0.75. So

[tex]P(A \cap B) = 0.08*0.75 = 0.06[/tex]

Given that the technician will NOT be detected, what is the probability that it is NOT raining?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.135} = 0.4444[/tex]

0.4444 = 44.44% probability that it is NOT raining

For each of the following variables, identify the type of variable (categorical vs. numeric). (1) Temperature (in Fahrenheit) of an office building (11) Traffic congestion (e.g. light, medium, heavy)
1) (1) Numeric, and (II) Categorical
2) (1) Numeric, and (II) Numeric
3) (1) Categorical, and (II) Numeric
4) There is no correct match.
5) (1) Categorical, and (11) Categorical

Answers

Answer:

(a) Temperature: Numerical

(b) Traffic congestion: Categorical

Step-by-step explanation:

Required

Determine the variable type

(a) Temperature

Temperatures are measured in numeric values e.g. 22 degree Fahrenheit, etc.

Hence, the variable is numerical

(b) Traffic congestion

From the question, we understand that the traffic congestion are divided into three categories i.e. light, medium....

Hence, the variable is categorical

Find m∠GHIm∠GHI if m∠GHI=14x+6m∠GHI=14x+6, m∠QHI=130∘m∠QHI=130∘, and m∠GHQ=3x−3m∠GHQ=3x−3.

Answers

Answer:

m∠GHI = 160

Step-by-step explanation:

From the question given above, the following data were obtained:

m∠GHI = 14x + 6

m∠QHI = 130°

m∠GHQ = 3x – 3

m∠GHI =?

Next, we shall determine the value of x. This can be obtained as follow:

m∠GHI = m∠QHI + m∠GHQ

14x + 6 = 130 + (3x – 3)

14x + 6 = 130 + 3x – 3

Collect like terms

14x – 3x = 130 – 3 – 6

11x = 121

Divide both side by 11

x = 121 / 11

x = 11

Finally, we shall determine the value m∠GHI. This can be obtained as follow:

m∠GHI = 14x + 6

x = 11

m∠GHI = 14(11) + 6

m∠GHI = 154 + 6

m∠GHI = 160

Match the y coordinate with coo responding pairs of x

Answers

Answer:◎ See the attachment photo.

◎ Don't forget to thanks◎ Mark as brainlist.

A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50% of this population prefers the color green. If 14 buyers are randomly selected, what is the probability that exactly 12 buyers would prefer green

Answers

Answer:

The probability that exactly 12 buyers would prefer green

=0.00555

Step-by-step explanation:

We are given that

p=50%=50/100=0.50

n=14

We have to find the probability that exactly 12 buyers would prefer green.

q=1-p

q=1-0.50=0.50

Using binomial distribution formula

[tex]P(X=x)=nC_r p^r q^{n-r}[/tex]

[tex]P(x=12)=14C_{12}(0.50)^{12}(0.50)^{14-12}[/tex]

[tex]P(x=12)=14C_{12}(0.50)^{12}(0.50)^2[/tex]

[tex]P(x=12)=14C_{12}(0.50)^{14}[/tex]

[tex]P(x=12)=\frac{14!}{12!2!}(0.50)^{14}[/tex]

[tex]P(x=12)=\frac{14\times 13\times 12!}{12!2\times 1}(0.50)^{14}[/tex]

[tex]P(x=12)=91\cdot (0.50)^{14}[/tex]

[tex]P(x=12)=0.00555[/tex]

Hence, the probability that exactly 12 buyers would prefer green

=0.00555

Simplify the given expression below:
(4 + 21) – (1 – 71)

Answers

Hey there!

(4 + 21) - (1 - 71)

4 + 21 = 25

= 25 - (1 - 71)

1 - 71 = -70

= 25 - (-70)

= 25 + 70

= 95

Answer: 95

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Two cell phone companies charge a flat fee plus an added cost for each minute or part of a minute used. The cost is represented by C and the number of minutes is represented by t.
Call-More: C = 0.40t + 25 Talk-Now: C = 0.15t + 40

Answers

Answer:

The call more is cheaper than talk-now.

Step-by-step explanation:

The companies charge a flat fee plus an added cost for each minute or part of a minute used for two companies are as follows :

Call-More: C = 0.40t + 25 Talk-Now: C = 0.15t + 40

We need to find which company is cheaper if a customer talks for 50 minutes.

For call more,

C = 0.40(50) + 25 = 45 units

For talk-now,

C = 0.15(50) + 40 = 47.5 units

So, it can be seen that call more is cheaper than talk-now.

help? haha
solve the equation below:)
3x - 5 = 10 + 2x

Answers

Step-by-step explanation:

3x-2x=5+10 [taking variables on one side and constant on other]

x=15

soln:

3x-5= 2x+10

3x -5+5=2x+10+5 [ adding 5 on both side]

3x=2x+15

3x-2x=2x+15-2x [subtracting 2x on both side]

x=15

Ans=15

Answer:

[tex]x = 15[/tex]

Step-by-step explanation:

[tex]3x - 5 = 10 + 2x[/tex]

[tex]3x - 2x = 10 + 5[/tex]

[tex]1x = 15[/tex]

[tex]x = 15[/tex]

Hope it is helpful.....

Ed decided to build a storage box. At first, he was planning to build a cubical box with edges of length n inches. To increase the amount of storage, he decided to make the box 1 inch taller and 2 inches longer while keeping its depth at n inches. The volume of the box Ed built has a volume how many cubic inches greater than the box he originally planned to build?

Answers

Answer:

The new volume is 3n^2+2n inches greater.

Step-by-step explanation:

Volume of a cube = s^3 where s is side of cube

Original volume = n^3

Volume of a Rectangular Prism = LBH

New Volume = (n+1)(n+2)(n)= n^3+3n^2+2n

DIfference = New- original = 3n^2+2n

Verify that the equation is an identity.

Answers

Step-by-step explanation:

We need to prove that ,

cot x / csc x - csc x / cot x = - tan x sec x .

LHS :-

> cot x / csc x - csc x / cot x

> cos x / sin x ÷ csc x - sin x × csc x / cos x

> cosx - 1/ cos x

> cos² x - 1 / cos x

> - sin²x / cosx

> -sin x / cos x × sin x

> -tan x sin x

= RHS

Hence Proved !

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2. The numbers of tornadoes in different weeks are mutually independent. Calculate the probability that fewer than four tornadoes occur in a three-week period.

Answers

Answer:

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2

Three weeks, so [tex]\mu = 2*3 = 6[/tex]

Calculate the probability that fewer than four tornadoes occur in a three-week period.

This is:

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.0025[/tex]

[tex]P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.0149[/tex]

[tex]P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.0446[/tex]

[tex]P(X = 3) = \frac{e^{-6}*6^{3}}{(3)!} = 0.0892[/tex]

Then

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0025 + 0.0149 + 0.0446 + 0.0892 = 0.1512[/tex]

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

exponential function in the form y=ab^xy=ab
x
that goes through points (0, 13)(0,13) and (5, 416)(5,416).

Answers

Hello!

[tex]\large\boxed{y = 13(2)^x}}[/tex]

y = abˣ

We know that at x = 0, b = 1 because any number to the power of 0 = 1.

Therefore:

13 = a(1)

13 = a

Now, plug in this value to solve for b:

y = 13bˣ

Substitute in the next point:

416 = 13(b)⁵

Divide both sides by 13:

32 = b⁵

Take the 5th root of both sides:

2 = b

Rewrite:

y = 13(2)ˣ

Which of the following is the intersection of the line AD and line DE?

Answers

Answer:

Point D

Step-by-step explanation:

The intersection(s) of lines represents where they cross or intersect. We can see that lines AD and DE cross or intersect as Point D, hence the answer being Point D.

Answer: Point D

Step-by-step explanation: The intersection of two figures is the set of points that is contained in both figures. In the diagram shown, D is the intersection of lines AD and DE because D is the point contained by both line AD and DE.

If 19,200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the box.

Answers

Step-by-step explanation:

√19200cm²

=138.56cm

then the highest possible volume

=(138.56)³

=2660195.926cm³

The largest possible volume of the box is; V = 25600 cm³

Let us denote the following of the square box;

Length = x

Width = y

height = h

Formula for volume of a box is;

V = length * width * height

Thus; V = xyh

but we are dealing with a square box and as such, the base sides are all equal and so; x = y. Thus;

V = x²h

The box has an open top and as such, the surface are of the box is;

S = x² + 4xh

We are given S = 19200 cm². Thus;

19200 = x² + 4xh

h = (19200 - x²)/4x

Put (19200 - x²)/4x for h in volume equation to get;

V = x²(19200 - x²)/4x

V = 4800x - 0.25x³

To get largest possible volume, it will be dimensions when dV/dx = 0. Thus;

dV/dx = 4800 - 0.75x²

At dV/dx = 0, we have;

4800 - 0.75x² = 0

0.75x² = 4800

x² = 4800/0.75

x² = 6400

x = √6400

x = 80 cm

From h = (19200 - x²)/4x;

h = (19200 - 80²)/(4 × 80)

h = (19200 - 6400)/3200

h = 4 cm

Largest possible volume = 80² × 4

Largest possible volume = 25600 cm³

Read more at; https://brainly.com/question/19053087

a woman bought some large frames for 
$12 each and some small frames for $5
each. If she bought 20 frames for $156
find how many of each type she bought.

Answers

Answer:

8 pairs of large glasses and 12 pairs of small ones

Step-by-step explanation:

Let's say the number of large frames she buys is l, and the number of small frames is s. She buys 20 frames of assorted sizes, but they can only be small or large. Therefore, s + l = 20.

Next, the total cost of large frames is 12 dollars for each frame. Therefore, the total cost for the large frames is equal to 12 * l. Similarly, the total cost for the small frames is equal to 5 * s. The total cost of all frames is equal to 156, so

12* l + 5 * s = 156

s + l = 20

In the second equation, we can subtract l from both sides to get

s = 20 - l

We can then plug that into the first equation to get

12 * l + 5 * (20-l) = 156

12 * l + 100 - 5*l = 156

subtract both sides by 100 to isolate the variable and its coefficient

12 * l  -  5 * l = 56

7 * l = 56

divide both sides by 7 to isolate the l

l = 8

The woman buys 8 pairs of large glasses. The number of small glasses is equal to 20-l=20-8=12

Tyler and Elena are on the cross country team. Tyler’s distances and times for a training run are shown on the graph. Elenas distances and times for a training run are given by the equation y=8.5x, calculate Tyler’s pace per minute

Answers

Answer:

8.2 miles per minute

Step-by-step explanation:

Given

See attachment for graph

Required

The rate of Tyler's graph

This means that we calculate the slope (m) of the graph using:

[tex]m = \frac{y_1 - y_2}{x_1 - x_2}[/tex]

So, we have:

[tex](x_1 ,y_1) = (0,0)[/tex]

[tex](x_1 ,y_1) = (1,8.2)[/tex]

So, we have:

[tex]m = \frac{y_1 - y_2}{x_1 - x_2}[/tex]

[tex]m = \frac{0 - 8.2}{0 - 1}[/tex]

[tex]m = \frac{-8.2}{- 1}[/tex]

[tex]m = 8.2}[/tex]

What is the correct equation for the graph?

Answers

tan graph and its tax because tax=0

A sprinkler releases water st a rate of 150 liters per hour. If the sprinkler operated for 80 minutes how many liters of water will be released

Answers

200 liters for 80 minutes of run time

The amount of water released from the sprinkler for 80 minutes is 200 L

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the amount of water from the sprinkler for 80 minutes be = A

Now , the value of A is given by the equation

A sprinkler releases water st a rate of 150 liters per hour

So , 60 minutes = 150 Liters of water

80 minutes = 1/60 hours

80 minutes = 1.333 hours

The amount of water released for 1.333 hours A = 150 x 1.333

On simplifying the equation , we get

The amount of water released for 1.333 hours A = 200 L

Therefore , the value of A is 200 L

To learn more about equations click :

https://brainly.com/question/19297665

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The number of measles cases decreased by 7% to 606 cases this year. What was the number of cases prior to the increase? Express your answer rounded correctly to the nearest whole number.

Answers

Answer:

652 cases

Step-by-step explanation:

The formula for percentage increase is 100 times the final-initial/final value. If we plug the numbers in and calculate, we get 652 cases. Have a great day!

Find x so that B = 3x i +5j is perpendicular to is perpendicular to A=2i - 6j​

Answers

Answer:

5

Step-by-step explanation:

I'm going to call x, x1 because I want to use x as a variable.

So we have a ray with points (0,0) and (3x1,5) on it. This equation for this ray would be y=5/(3x1)×x.

We have another ray with points (0,0) and (2,-6). This equation for this ray would be y=-6/2×x or y=-3x.

We want these two lines' slopes to be opposite reciprocals. The opposite reciprocal of -3 is 1/3.

So we want to find x1 such that 5/(3x1)=1/3.

Cross multiply: 15=3x1

Divide both sides by 3: 5=x1

We want x1 to be 5 so that 5/(3×5) and -3 are opposite reciprocals which they are.

Another way:

If two vectors are perpendicular, then their dot product is 0.

The dot product of <3x,5> and <2,-6> is 3x(2)+5(-6).

Let's simplify:

6x-30.

We want this to be 0.

6x-30=0

Add 30 on both sides:

6x=30

Divide both sides by 6:

x=5

Which point is part of the solution of the inequality y ≤ |x + 4| − 3?

Answers

Answer:

Step-by-step explanation:

Pls help this is rlly important!! You’ll get branliest bc this is hard and I’m stuck.

Answers

the median of restaurant b's cleanliness ratings is 2.

the median of restaurant b's food quality ratings is 4.

the median of restaurant b's service ratings is 3.

:))

show that 43\2^4×5^3 will terminate after how many places of the decimal​

Answers

Answer:

4 places after the decimal.

the result is 0.0215

Step-by-step explanation:

I assume the expression is really

43 / (2⁴ × 5³)

this is the same as

(((((((43 / 2) / 2) / 2) / 2) / 5) / 5) / 5)

since the starting value is an odd number, the first division by 2 creates a first position after the decimal point, and it must be a 5, as the result is xx.5

the second division by 2 splits again the uneven end .5 in half, creating a second position after the decimal point again ending in 5, as the result is now xx.x5

the third division by 2 does the same thing with that last 5 and creates a third position after the decimal point ending again in 5, as the result is now xx.xx5

the fourth division by 2 does again the same thing, a fourth position after the decimal point is created ending in 5. now xx.xxx5

in essence, every division of the 0.5 part by 2 is the same as a multiplication by 0.5, which squares 0.5 leading to 0.5². the next division did the same thing leading to 0.5³.

and finally the fourth division to 0.5⁴.

0.5⁴ = (5/10)⁴ = 5⁴/10⁴

so, now we start to divide this result by 5. since the positions after the decimal point are divisible by 5 without remainder, as we have 5⁴ to work with.

every divisible by 5 takes one of these powers away.

so, we go from 5⁴/10⁴ to 5³/10⁴ to 5²/10⁴ to 5/10⁴.

all the time we maintain the 10⁴ in the denominator of the fraction. and that determines the positions after the decimal point.

so, after all the individual divisions we come to and end and are still limited to the 4 positions after the decimal point.

what is the complete factorization of 8x^2-8x+2

Answers

Answer:

2x(4x-4+1)

Step-by-step explanation:

i hope it will help you

Answer:

x=1/2

Step-by-step explanation:

press the calculator

8x²-8x+2=0

x=1/2

min,x=1/2

min,y=0

solve for s 9s+20=−16

Answers

Answer:

s = -4

Step-by-step explanation:

Your goal is to manipulate the equation so you can isolate s

9s + 20 = -16

Subtract 20 from both sides to get:

9s = -36

Divide both sides by 9 so s is alone

you end up with s = -4

Answer:

s  = -4

Step-by-step explanation:

9s+20=−16

Subtract 20 from each side

9s +20 -20 = -16 -20

9s = -36

Divide by 9

9s/9 = -36/9

s  = -4

Instructions: Solve the following linear
equation
4(n + 5) – 2(5 + 7n) = -70
n =

Answers

Answer:

Step-by-step explanation:

4*(n +5) - 2*(5 + 7n) = -70

4*n + 4*5 + 5*(-2) + 7n*(-2) = -70

4n + 20 - 10 - 14n = -70

4n - 14n + 20 - 10 = -70

- 10n + 10 = -70

Subtract 10 from both sides

-10n = -70 - 10

-10n = -80

Divide both sides by (-10)

n = -80/-10

n = 8

Step-by-step explanation:

sjbsbsbeekejebebheebebejekek

What is the solution set for |z+4|> 15

Answers

Answer:

I think that answer would be B.

Step-by-step explanation:

Consider this linear function:
y = 1/2x + 1
Plot all ordered pairs for the values in the domain.
D: {-8, -4,0, 2, 6)

Answers

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The attachment shows the ordered pairs (x, f(x)) and their graph.

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