21.5 sq. Cm
43 sq. Cm
100 sq. Cm
68.6 sq. Cm

Answer:

433 in.²

Step-by-step explanation:

Divide the figure into 2 rectangles

Area of the figure = area of the bigger rectangle + area of smaller rectangle

✔️Area of bigger rectangle = L*W

L = 29 in.

W = 13 in.

Area of the bigger rectangle = 29*13

= 377 in.²

✔️Area of the smaller rectangle = L*W

L = 7 in.

W = 8 in.

Area of the bigger rectangle = 7*8

= 56 in.²

✅Area of the figure = 377 + 56 = 433 in.²

The exact value of cos(13π/8) is 1/2 [tex]\sqrt{2-\sqrt{2} }[/tex].

Trigonometriic ratios are the ratios of the sides of a right angled triangle. sin , cos, tan, sec, cosec, cot are some of the trigonometric ratios. Sin is the ratio of perpendicular and hypotenuse, cos is the ratio if base and hypotenuse, tan is the ratio of perpendicular and base, secant is the ratio of hypotenuse and base, cosecant is the ratio of hypotenuse and perpendicular, cot is the ratio of base and perpendicular.

We have to find the value of cos (13π/8).

We have to use formula which is following:

cos[tex]Θ[/tex]=[tex]\sqrt{1/2(1+cos 2Θ}[/tex]

=[tex]\sqrt{1/2(1+cos(2*13 π/8)}[/tex]   (π=[tex]π[/tex])

=[tex]\sqrt{1/2(1+cos(3 π+π/4)}[/tex]

=[tex]\sqrt{1/2(1-cos(π/4)}[/tex]

=[tex]\sqrt{1/2(1-1/\sqrt{2} }[/tex]

=[tex]\sqrt{\sqrt{2}-1/2\sqrt{2} }[/tex]

=1/2[tex]\sqrt{2-\sqrt{2} }[/tex]

Hence the value of cos (13π/8) is [tex]1/2\sqrt{2-\sqrt{2} }[/tex].

Learn more about trigonometric ratios at https://brainly.com/question/24349828

#SPJ2

Answer:

4.2 hours

Step-by-step explanation:

Answer:

Y = -0.3587+0.09118X

92 %

Step-by-step explanation:

Using technology to fit the data between the variables, test score and hours of sleep; we obtain the linear model :

Ŷ = -0.3587+0.09118X

Where, x = test score ; y = hours of sleep

To obtain the test score of a student who sleep foe 8 hours using the model :

Y = 8

Ŷ = -0.3587+0.09118X

8 = -0.3587+0.09118X

8 + 0.3587 =0.09118X

8.3587 = 0.09118X

X = 8.3587 / 0.09118

X = 91.672515

X = 92 ( approximately)

Answer:

The answer is "Option B".

Step-by-step explanation:

Please find the complete question in the attached file.

The Horizontal stretch [tex]=(\frac{1}{6 \ x})\\\\[/tex]

Translation by 5 units right[tex]=( \frac{1}{6\ x})-5[/tex]

Answer:

its A i used his answer and got it wrong

Hey there!

I hope you have a great one too :)

Answer:

demographic

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the given information:

ΔG° = -30.5 kJ/mol

By applying the following equation to calculate the value of K.

ΔG° =-RT㏑K

making ㏑ K  the subject of the formula:

[tex]\mathtt{ In \ K} = \dfrac{\Delta G^0}{-RT}[/tex]

where;

Temperature at 25° C = (25 + 273)K

= 298K

R = 8.3145 J/mol.K (gas cosntant)

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-(8.3145 \ J/mol. K \times 298 \ K}[/tex]

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-2477.721 J/mol }[/tex]

㏑K = 12.309

[tex]K = e^{12.309}[/tex]

K = 221682.17

K = 2.22 × 10⁵

b) The reaction for the metabolism of glucose is given as:

[tex]C_6H_{12} O_6 + 6O_{2(g)} \to + 6CO_{2(g)} + 6H_2O_{(l)}[/tex]

From the above expression, let calculate the Gibbs free energy by using the formula:

[tex]\Delta G^0_{rx n }= \Delta G^0_{product}- \Delta G^0_{reactant}[/tex]

[tex]\Delta G^0_{rx n }= [6 \times \Delta G^0_{f}(CO_2) + 6 \times \Delta G^0_{f}(H_2O)] - [1 \times \Delta G^0_{f}(C_6H_{12}O_6) + 6 \times \Delta G^0_{f}(O_2)][/tex]

At standard conditions;

The values of corresponding compounds are substituted into the equation above:

Thus,

[tex]\Delta G^0_{rx n }= [6 \times (-394) + 6 \times (-237)] - [1 \times (-911) + 6 \times (0)] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= [-2364-1422] - [-911+0] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -3786 +911 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875000 \ J/mol[/tex]

Now, the no of ATP molecules generated = [tex]\dfrac{\Delta G^0 \text{of metabolism for glucose}}{\Delta G^0 \text{of hydrolysis for ATP}}[/tex]

= (-2875000 J/mol ) / -30500 J/mol

= 94.26

≅ 94 ATP molecules generated

Answer:

A) 60

Step-by-step explanation:

P = 5+5+11+9+(5+11)+(9+5)

P = 60

Answer:

A. 60 m

Step explanation:

Perimeter for the small cube

5+5+5+5=20

Perimeter for the rectangle

9+9+11+11=40

Add 20 plus 40 to find the perimeter for the whole shape

20+40=60

Hope this helps

Answer:

Step-by-step explanation:

Answer:

1865.16 m^2

Step-by-step explanation:

first let 's find radius of a circle

radius=diameter/2

=18/2

=9 m

area of a cylinder=2πrh+2πr2

=2*3.14*9*24 + 2*3.14*(9)^2

=1356.48 + 2*3.14*81

=1356.48 + 508.68

=1865.16 m^2

Answer:

1866.11 m²

Step-by-step explanation:

Formula = 2πrh + 2πr²

Surface area = 2 * 3.14 * 9 * 24 + 2*3.14* 81 ≈ 1866.11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

348 kiwis

Step-by-step explanation:

Jamie is packing Kiwie fruits into a tray

Each tray holds 58 kiwis

He can put 6 trays in a crate

Hence when the craye is full the number of kiwis it will contain can be calculated as follows

°= 58×6

= 348 kiwis

Answer:

y=179x

Y=105x+2046

Step-by-step explanation:

Answer:

[tex]\sqrt{x^2 + y^2}[/tex]

Step-by-step explanation:

to find diatance between AB

A(0 , 0) = (x1 , y1)

B(x , y) = (x2 , y2)

distance formula = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

=[tex]\sqrt{(x - 0)^2 + (y - 0)^2}[/tex]

=[tex]\sqrt{x^2 + y^2}[/tex]

Answer:

108

Step-by-step explanation:

c = b + 56

c + b = 160

Substitute for c

(b + 56) + b = 160

2b + 56 = 160

2b = 104

b = 52

c = 52 + 56 = 108

Answer:

−7.361097448

Step-by-step explanation:

That is the same as writing [tex]10\sqrt{30}[/tex]

======================================================

Explanation:

The diagram shows that

That must mean DC = AC-AD = 60-50 = 10

We'll use this to help find BD as shown below

AD/BD = BD/DC

AD*DC = BD*BD .... cross multiply

(BD)^2 = AD*DC

BD = sqrt(AD*DC) ..... geometric mean formula

BD = sqrt(50*10)

BD = sqrt(500)

----------------------

Now apply the pythagorean theorem to find AB. Focus on triangle ABD.

(AD)^2 + (BD)^2 = (AB)^2

(AB)^2 = (AD)^2 + (BD)^2

(AB)^2 = (50)^2 + (sqrt(500))^2

(AB)^2 = 2500 + 500

(AB)^2 = 3000

AB = sqrt(3000)

AB = sqrt(100*30)

AB = sqrt(100)*sqrt(30)

AB = 10*sqrt(30)

Hi there!  

»»————-　★　————-««

I believe your answer is:  

(-3, -1) and (1, 3)

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

See the graph attached.

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

[tex]{ \tt{y = x + 2 - - - (a)}} \\ { \tt{ {x}^{2} + {y}^{2} = 10 - - - (b) }} \\ substitute \: for \: y \: in \: (b) : \\ { \tt{ {x}^{2} + {(x + 2)}^{2} = 10 }} \\ { \tt{ {x}^{2} + {x}^{2} + 4x + 4 = 10 }} \\ { \tt{2 {x}^{2} + 4x - 6 = 0}} \\ { \tt{ {x}^{2} + 2x - 3 = 0 }} \\ { \boxed{ \bf{x = 1 \: and \: - 3}}} \\ in \: (a) : \\ y = x + 2 \\ { \boxed{ \bf{y = 3 \: and \: - 1}}}[/tex]

Answer:

[tex]95 - \frac{3}{4} [/tex]

[tex] = \frac{95}{1} - \frac{3}{4} [/tex]

[tex] = \frac{380}{4} - \frac{3}{4} [/tex]

[tex] = \frac{380 - 3}{4} [/tex]

[tex] = \frac{377}{4} [/tex]

[tex] = 376\frac{1}{4} [/tex]

Answer:

[tex]t - 3.2 \le 7.5\\[/tex]

Step-by-step explanation:

Given

Represent as inequality

Taking the statement one at a time

So, the inequality is:

[tex]t - 3.2 \le 7.5\\[/tex]

Answer:

1.33

Step-by-step explanation:

so mean is the average

so what you have to do is add the numbers for each person and then divide by the amount of numbers present. the question is asking for the difference so subtract the numbers for each from person.

mia's mean= 34.33

sophia's mean= 35.667

sophia-mia= 1.33

(check my work, and if you need help just comment)

Answer: The company will recognize commission expense in the amount of $2,400 in December

Step-by-step explanation:

Based on the information given in the question, the company will recognize commission expense in the amount of $2,400 in December.

A commission is regarded as a fee which is paid to a salesperson by a company in exchange for completing a sale.

It should be noted that in the accrual basis of accounting, commission should be recorded in the same period as when the sale generated was generated.

Answer:

b. The company will recognize commission expense in the amount of $2,400 in December.

Step-by-step explanation:

Based on the information given the statements that is true will be: THE COMPANY WILL RECOGNIZE COMMISSION EXPENSE IN THE AMOUNT OF $2,400 IN DECEMBER reason been that each salesperson were paid a commission in the amount of $800 for each cycle sold, which is 3 cycles during the month of December.

Calculation to determine the Commission Expense

Commission Expense=$800*3 cycles

Commission Expense=$2,400

Therefore The company will recognize commission expense in the amount of $2,400 in December.

Step 1: 360÷30(exterior angle)= 12 sides

Step 2: (12-2)×180= 1800 (sum of the interior angles of the polygon)

Test: 1800÷ 12 sides= 150 ( 1 interior angle)

i think the correct answer is 2 hours and 10 mins

Answer:

12 ft

Step-by-step explanation:

we know the areas of the 2 top squares.

the area of a square is simply the square of its side length.

=>

81 ft² means side length is 9 ft.

225 ft² means side length is 15 ft.

these are also 2 of the sides of the right triangle.

the third side we get by using Pythagoras :

c² = a² + b²

with c being the side opposite of the 90 degree angle.

so,

225 = 81 + x²

as x is also the third side of the triangle.

=> 144 = x²

x = 12 ft

Answer:

2821.51

73425.64

28124.24

4124.24

Step-by-step explanation:

Effective rate: .058/2 = .029

This question is kind of ambigous and I'll make the assumption that there is no payment at time 0

[tex]175000=x\frac{(1+.029)^{2*18}-1}{.029}\\x=2821.511[/tex]

interested earned:

175000-2821.51*36= 73425.64

2.)

Same assumption as question 1 (there is no payment at time 0)

effective rate: .063/12= .00525

[tex]400(\frac{(1+.00525)^{60}-1}{.00525})=28124.24[/tex]

Interest earned: 28124-400*60=4124.24

Answer:

First problem: monthly payment $2741.99; interest earned $76,288.36

Second problem: amount in account $28,271.90; interest earned $4271.90

Step-by-step explanation:

First problem:

You open an account with a deposit. The deposit is the first monthly payment. This means that this is an annuity in which you pay at the beginning of the pay period. That makes it into an "annuity due."

[tex] A = \dfrac{F}{\frac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

where A = periodic payment,

F = future value

i = interest rate per compounding period, n = number of compounding periods

[tex]A = \dfrac{175000}{\frac{(1 + \frac{0.058}{2})^{2 \times 18} - 1}{\frac{0.058}{2}} \times (1 + \frac{0.058}{2})}[/tex]

[tex] A = 2741.99 [/tex]

Interest earned:

[tex] 2 \times 18 \times 2741.99 - 175000 = 76288.36 [/tex]

Second problem:

Once again, the account starts with a deposit of the monthly payment, so this is also an annuity due, meaning the payments occur at the beginning of each compounding period. Here, we are given the monthly payment, an d we need to find the future value.

[tex] F = A \times \dfrac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

[tex] F = 400 \times \dfrac{(1 + \frac{0.063}{12})^{5 \times 12} - 1}{\frac{0.063}{12}} \times (1 + \frac{0.063}{12})} [/tex]

[tex] F = 28271.90 [/tex]

The interest earned is:

[tex] 28271.90 - 12 \times 5 \times 400 = 4271.90 [/tex]

Answer:

[tex]x^2 + y^2 = 52[/tex]

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Equation of a circle:

The equation of a circle with center [tex](x_0,y_0)[/tex] and radius r has the following format:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

Center at the origin;

This means that [tex]x_0 = 0, y_0 = 0[/tex]

So

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

[tex](x - 0)^2 + (y - 0)^2 = r^2[/tex]

[tex]x^2 + y^2 = r^2[/tex]

Passes through (4, 6)

The radius is the distance from this point to the center. So

[tex]r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]r = \sqrt{(4-0)^2+(6-0)^2}[/tex]

[tex]r = \sqrt{16+36}[/tex]

[tex]r = \sqrt{52}[/tex]

So

[tex]r^2 = 52[/tex]

Then

[tex]x^2 + y^2 = r^2[/tex]

[tex]x^2 + y^2 = 52[/tex]