Both aldehydes and ketones contain a carbonyl group a functional group with a carbon oxygen double bond, hence the carbonyl in aldehydes and ketones forms sp²hybridization.

Answers

Answer 1

Answer:

Both aldehydes and ketones contain a carbonyl group a functional group with a carbon oxygen double bond, hence the carbonyl in aldehydes and ketones forms sp²hybridization.

Explanation:

The structure of carbonyl group is -C=O-

The hybridization of carbon can be identified by couting the number of surrounding atoms.

In carbonyl compounds, carbon is directly bonded with three atoms.

One is oxygen, and the other two are other carbons.

With oxygen carbon has a double bond.

Hence, this three corresponds to sp2 hybridization.

Thus, the given statement is correct.


Related Questions

if slowing down is the response to seeing a blinking yellow light is it conditioned or unconditioned?

Answers

Answer:

Conditioned

Explanation:

Naturally, you do not slow down when you see a yellow light. That response is learned, therefore it is a conditioned response.

PLS HELP!!
Compare and contrast an electrolytic cell with a voltaic cell. Provide one example where both are present in daily life.

Answers

Answer:

See explanation

Explanation:

An electrolytic cell functions by a non spontaneous chemical process. Energy is supplied in the form of electricity through a battery to drive the electrochemical process.

A voltaic cell functions by a spontaneous chemical process. Energy or work can be derived from a voltaic cell.

When iron is rusting, a natural voltaic cell is set and the iron is converted to hydrated iron III hydroxide. The set up used for the extraction of sodium metal from brine functions on the basis of electrolysis.

How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen atoms and 2 oxygen atoms

Answers

Answer:

What period is the atom in?

1.

What group is the atom in?

What is the name of this atom?

What other atom would have similar

properties to the atom?

Will this atom conduct electricity well

Explanation:

How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen

and 2 oxygen atoms


Can someone do a True or false for these

Answers

Answer:

all i can accurately say is that 2 and 4 are both true

Write a hypothesis to answer the lesson question
"How can electrolysis be used to separate a
compound into its components?"
If_____ (an electrical current, a salt, an electrode, or oxygen)?
is applied to water
containing an electrolyte, then the water will
decompose into____( water vapor, sodium gas, hydrogen gas, oxygen gas, hydrogen and oxygen gas)?
because____________?

Answers

Answer:

Electric current

Hydrogen and oxygen gas

Explanation:

Electrolysis is defined as a method of separation whereby an electric current is introduced into compounds to separate them . The electric current used here is a direct electric current (DC) and it makes the compound to be spit into its' component elements.

Now, in the case of water like it says in the question. Water is a mixture of hydrogen and oxygen gas. Thus, when electric current is passed through water which has an Electrolyte, it makes the water to decompose into its compound elements which are hydrogen and oxygen.

Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?

CSF + XeF6 → CsXeF7

Answers

Answer:

27.9 g

Explanation:

CsF + XeF₆ → CsXeF₇

First we convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles, using its molar mass:

Molar mass of CsXeF₇ = 397.193 g/mol73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇

As 1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.

Now we convert 0.184 moles of CsF to moles, using the molar mass of CsF:

Molar mass of CsF = 151.9 g/mol0.184 mol * 151.9 g/mol = 27.9 g

the sum of two numbers is 54 one exceed the other by 14 find the number​

Answers

Answer:

x=34

y=20

Explanation:

let the first number be 'x'

let the second number be 'y'

Equation 1:-

x + y = 54

Equation 2:-

x = y + 14  (Since one exceeds the other by 14)

Substituting Equation 2 in Equation 1:-

(y + 14) + y = 54

=> y + 14 + y = 54

=> 2y + 14 = 54

=> 2y = 54 - 14

=> 2y = 40

=> y = 40/2

=> y = 20

Now in Equation 1:-

x + y = 54

Substituting y=20,

x + 20 = 54

x = 54 - 20

x = 34

Balancing equations
1. __Na + __Oz -> __Na2O

Answers

Answer:

Balancing equations

1

[tex]4Na + O_{2} -> 2Na_{2}O[/tex]

True or false, In a neutral atom of an element, the number of protons always equals the number of electrons.

Answers

Answer:

true

Explanation:

As an atom with no charge have same number of proton and electrons

True ! The number of protons will always be the same as electrons :)

Ginger wanted to see how long it would take to get to Brownsville from Houston. If it is 570 kilometers (km) to Brownsville, how long would it take her if she could only drive an average speed of 60 km/hour

Answers

Answer:

9.5 hours/ 9 hours 30 mins

Explanation:

Distance = speed × time so

Time = Distance ÷ speed

= 570 ÷ 60

= 9.5 hours

How many moles of carbon are in the sample?

Answers

Answer:

12.01 grams per mole

Explanation:

theres no sample or example so if theres grams of Carbon, convert it to moles using 12.01g/mol

describe the formation of ionic bonds in potassium chloride compound (5 marks)

Answers

Answer:

When the two atoms are in contact, potassium readily transfers its outer electron to chlorine which readily accepts it, resulting in both atoms achieving a state of eight outermost electrons. With this electron transfer, the ionic bond in KCl is formed.

PLEASE HELP ASAP!!!!!!!!

Answers

Answer:

ouch......it's kinda a practical question..

Answer: ?

Explanation: what was the answer?

The table shows four reactions.
Reactions

Reaction Equation
1 C3H8 + 5O₂ → 3CO₂ + 4H₂O
2 C₂H4 + H₂ → C₂H6
3 AgNO3 + NaCl - AgCl + NaNO3
4 2Fe + O₂ → 2Feo

Which of the above reactions is an example of combustion of an organic substance?

a) 1
b) 2
c) 3
d) 4

Answers

Answer:its B

Explanation:

i have done this before! and i got 100 so i hope you got all the other questions right!

The table shows four reactions. The reaction That is an example of combustion of an organic substance is C₂H₄ + H₂ → C₂H₆. The correct option is b) 2.

What are combustion reactions?

Combustion reactions are those reactions in which the reactant reacts with oxygen and produces heat and light. An example is the burning of wood, it happens in the presence of oxygen.

Organic compounds are those compounds that are made by carbons. They are made by carbon-carbon or carbon-hydrogen bonds. They are naturally present in nature.

C₂H₄ + H₂ → C₂H₆

The equation above shows the reaction between methane and hydrogen, which is forming ethane in the presence of oxygen.

Thus, the correct option is b) 2. C₂H₄ + H₂ → C₂H₆.

To learn more about combustion reactions, refer to the link:

https://brainly.com/question/12172040

#SPJ5

How does fluorine (F)differ from iodine(I)

A. Fluorine (F) has 3 more energy shells than iodine (I).

B. Fluorine (F) has 1 less energy shell than iodine (I).

C. Fluorine (F) has 1 more energy shell than iodine (I).

D. Fluorine (F) has 3 less energy shells than iodine (I).

Answers

I believe your answer is D. Fluorine (F) had 3 less energy shells than iodine (I)
Fluorine has 2 energy shells while iodine has 5 energy shells.
Subtract 5-2=3

Fluorine (F) and iodine(I) are the halogen elements that belong to group 17. They differ from each other as fluorine has 3 fewer energy shells than iodine. Thus, option D is correct.

What are halogen groups?

Halogen is a nonmetallic element that belongs to group 17 and consists of six elements namely fluorine, bromine, tennessine, chlorine, astatine, and iodine.

They are diatomic and have 7 valence electrons in the outer shell, which makes them highly reactive and electronegative. The shielding effect is less in F than I due to the closer placement and attraction of the valence electron to the nucleus.

Fluorine differs from iodine as it has a smaller size with fewer energy shells than iodine. Iodine has five energy shells,  whereas fluorine has two energy shells that make the difference of three shells between them.

Therefore, F and I differ from each other.

Learn more about fluorine and iodine here:

https://brainly.com/question/2005537

#SPJ5

A 80°C la presion de vapor del benceno (C6H6) es de 1 atm. Calcula la cantidad de hexano (C6H14) que debemos añadir a 200g de benceno para que su presion de vapor sea de 700mm de Hg

Answers

Answer:

18,9g de hexano son necesarios

Explanation:

Basados en la ley de Raoult, la presión de vapor ejercida por una solución es:

P = P°*Xsolvente

Donde P es la presión de la solución deseada = 700mmHg, P° la presión de vapor de vapor del benceno = 1atm = 760mmHg y X es la fracción molar del solvente (Benceno).

Reemplazando:

700mm Hg = 760mmHg * X(Benceno)

0.9211 = X(Benceno)

La fracción molar de benceno se define como:

X = Moles benceno / Moles benceno + Moles hexano

Moles benceno -Masa molar: 78g/mol-

200g * (1mol/78g) = 2.5641 moles benceno

X = Moles benceno / Moles benceno + Moles hexano

0.9211 = 2.5641 moles benceno / 2.5641 moles benceno + Moles hexano

0.9211moles Hexano + 2.3618 = 2.5641

0.9211*Moles Hexano = 0.2023

Moles hexano = 0.2023/0.9211 = 0.2196 moles hexano.

Masa Hexano -Masa molar: 86g/mol-

0.2196 moles hexano * (86g/mol) =

18,9g de hexano son necesarios

La cantidad de hexano (C6H14) que se debe agregar a 200 g de benceno para permitir que la presión de vapor se convierta en 700 mm de Hg sería:

18.9 g

Usando la ley de Raoult, la presión de vapor que libera una solución se encuentra por:

P = P ° × X disolvente  

Donde (P) denota la presión de la solución deseada

P ° denota la presión de vapor del benceno y

X denota la fracción molar del disolvente (benceno).

En el caso dado,

(P) = 700 mmHg,

= 1atm = 760mmHg

Fracción molar de benceno = 0,9211           (∵ 700/760)

La fracción molar de benceno (X)  = Moles de benceno/Moles de benceno + Moles de hexano

Moles de benceno - Masa molar: 78g / mol -  200 g × (1 mol / 78 g)

= 2.5641 moles de benceno

X = Moles de benceno/Moles de benceno + Moles de hexano

0.9211 = 2.5641 moles Benceno/2.5641 moles Benceno + Moles de Hexano

⇒ 0,9211 × moles de Hexano + 2,3618 = 2,5641    

⇒ 0.9211 × moles de Hexano = 0.2023

Moles de Hexano = 0.2023/0.9211

[tex]= 0.2196 moles[/tex]

[tex]Hexane mass - Molar mass = 86g/mol - 0.2196 mole hexane[/tex] × [tex](86g/mole)[/tex]

[tex]= 18.9g[/tex]

Por tanto, 18,9 g es la respuesta correcta.

Learn more about "Benzene" here:

brainly.com/question/25798187

A student is asked to separate two liquids. Liquid A boils at 100°C
and liquid B boils at 65 °C. The student sets up a fractional distillation
experiment, and after a few minutes a clear liquid is collected from the
condenser. Explain which of the two liquids will be collected first.

Answers

Answer:

liquid  B

Explanation:

because B has a lower bp it needs less time and energy to turn into vapour and is collected into the condenser first

A vehicle is moving with a velocity of 20 m/s.how far does it moves in one hrs

Answers

Distance= Speed x Time

1hr=60mins

60mins=3600 secs

20 x 3600=72000

72000 is your answer.

I need answers to question 1,2,3

Answers

Answer:

1. 0.125 mole

2. 42.5 g

3. 0.61 mole

Explanation:

1. Determination of the number of mole of NaOH.

Mass of NaOH = 5 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mole of NaOH =?

Mole = mass /molar mass

Mole of NaOH = 5/40

Mole NaOH = 0.125 mole

2. Determination of the mass of NH₃.

Mole of NH₃ = 2.5 moles

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 2.5 × 17

Mass of NH₃ = 42.5 g

3. Determination of the number of mole of Ca(NO₃)₂.

Mass of Ca(NO₃)₂ = 100 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]

= 40 + 2[14 + 48]

= 40 + 2[62]

= 40 + 124

= 164 g/mol

Mole of Ca(NO₃)₂ =?

Mole = mass /molar mass

Mole of Ca(NO₃)₂ = 100 / 164

Mole of Ca(NO₃)₂ = 0.61 mole

If 46.3 grams of acetylene are required to run a carbide lamp for 8 hours, how many moles of water are required

Answers

Answer:

1.78 mol

Explanation:

Step 1: Write the balanced equation

CaC₂ + H₂O ⇒ C₂H₂ + CaO

Step 2: Calculate the moles corresponding to 46.3 g of C₂H₂

The molar mass of C₂H₂ is 26.04 g/mol.

46.3 g × 1 mol/26.04 g = 1.78 mol

Step 3: Calculate the moles of H₂O required to form 1.78 moles of C₂H₂.

The molar ratio of H₂O to C₂H₂ is 1:1. The moles of H₂O required are 1/1 × 1.78 mol = 1.78 mol.

What volume is occupied by 0.109 molmol of helium gas at a pressure of 0.98 atmatm and a temperature of 307 K

Answers

Answer:

2.8 L

Explanation:

From the question given above, the following data were obtained:

Number of mole (n) = 0.109 mole

Pressure (P) = 0.98 atm

Temperature (T) = 307 K

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

The volume of the helium gas can be obtained by using the ideal gas equation as follow:

PV = nRT

0.98 × V = 0.109 × 0.0821 × 307

0.98 × V = 2.7473123

Divide both side by 0.98

V = 2.7473123 / 0.98

V = 2.8 L

Thus, the volume of the helium gas is 2.8 L.

define hydroscopy in chemistry

Answers

Answer: A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption

Explanation:

an experiment was carried out and H2SO4 was collected resulting in a 92.0% yield. What mass of H2SO4 was collected from the experiment?

Answers

Answer:

The mass of H2SO4 collected is 92.0g assuming the theoretical yield of H2SO4 is 100g

Explanation:

Assuming the theoretical yield of the sulfuric acid, H2SO4, is 100g.

To solve this question we must use the equation of percent yield:

Percent yield = Actual yield / Theoretical yield * 100

Where percent yield = 92.0%, actual yield is the mass of H2SO4 produced and theoretical yield is 100g, the mass we are assuming

Replacing:

92.0% = Actual yield / 100g * 100

92.0g = Actual Yield

The mass of H2SO4 collected is 92.0g assuming the theoretical yield of H2SO4 is 100g


(Please Help)

1.What is the most common isotope for element X

2.Calculate the average atomic mass or element X

Answers

Answer:

1. Isotope 2 occurs most commonly

2. 39.02amu

Explanation:

1. Isotope 2 has a relative abundance of 78.68% i.e. 78.68 out of 100, hence, it is the isotope that occurs most commonly.

2. Isotope 1 = 9.67%, mass no: 38

Isotope 2 = 78.68%, mass no: 39

Isotope 3 = 11.34%, mass no: 40

Isotope 4 = 0.31%, mass no: 41

To find the average atomic mass of element X, we multiply each isotopes' relative abundance by its mass no and find the sum as follows:

We convert each percentage to decimal abundance:

Isotope 1 = 9.67% = 0.0967

Isotope 2 = 78.68% = 0.7868

Isotope 3 = 11.34% = 0.1134

Isotope 4 = 0.31% = 0.0031

(0.0967 × 38) + (0.7868 × 39) + (0.1134 × 40) + (0.0031 × 41)

3.6746 + 30.6852 + 4.536 + 0.1271

Average atomic mass = 39.02amu

Cuál o cuáles de las siguientes características son correctas para la mayoría de los compuestos del carbono?
I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc.
II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos
III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos
IV) El enlace covalente es característico de los compuestos del carbono

Todas son correctas
II
I y IV
I, III y IV

Answers

Answer:

Todas son correctas

Explanation:

I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc. VERDADERO. La mayoría de los compuestos de carbono son apolares, y basados en la regla: Similar disuelve similar, podemos presumir que la mayoría de compuestos de carbono se disuelven en solventes no polares.

II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos. VERDADERO. Al ser sustancias apolares, sus fuerzas electrostáticas son bajas. De la misma manera, como su masa atómica es pequeña, las fuerzas de Van der Waals son despreciables haciendo que sus puntos de fusión y ebullición sean bajos respecto a sustancias de estrucutra similar.

III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos. VERDADERO. Los gases (Como el gas natural) son combustibles usados para cocina. Los líquidos (Como la gasolina) son combustibles y bastante inflamables. Los sólidos (Como la madera) se usan como combustibles para hacer asados o son el combustible en incendios forestales.

IV) El enlace covalente es característico de los compuestos del carbono. VERDADERO. La polaridad del carbono es neutral haciendo que la mayoría de los enlaces que forma sean covalentes.

Todas son correctas

Can someone help me with this one :")

Answers

Answer:

i think is probably A

Explanation:

because at constant temperature, the product of the pressure and volume of a given mass of and ideal gass in a closed system is always constant

Answer:

I believe the answer is A or D

Explanation:

I hope this helps you out!

What is the balance equation for
_AI+_Pb(NO3)2—__Pb+__Ca(NO3)2

Answers

Answer:

2 Al + 3 Pb(NO3)2 > 2 Al(NO3)3 + 3 Pb

Explanation:

A toy plane has a mass of 2.5kg and is 18 m above the ground. It is moving 4.5 m/s.

how much mechanical energy does the toy have?
A. 416J
B. 441J
C. 466J
D. 491J

Answers

Answer:

466J (c)

Explanation:

Mechanical Energy= Kinetic+Potential

Potential energy= mgh

Plug in givens

mgh=2.5*18*9.8=441J

Kinetic Energy = 1/2mv^2

Plug in givens

1/2mv^2= 1/2(2.5)(4.5)^2= 25.3125J

Mechanical energy= 441J+25.3125J=466.3125J or 466J

Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?

CSF + XeF6 → CsXeF7

Answers

Answer: A mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.

Explanation:

Given: Mass of cesium xenon heptafluoride = 73.1 g

The molar mass of cesium xenon heptafluoride is 131.3 g/mol. So, moles of [tex]CsXeF_{7}[/tex] is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{73.1 g}{131.3 g/mol}\\= 0.556 mol[/tex]

According to the given equation, 1 mole of CsF yields 1 mole of [tex]CsXeF_{7}[/tex].

Hence, moles of CsF reacting will also be equal to 0.556 mol. As molar mass of CsF is 151.9 g/mol so its mass is calculated as follows.

[tex]Moles = \frac{mass}{molarmass}\\0.556 mol = \frac{mass}{151.9 g/mol}\\mass = 84.46 g[/tex]

Thus, we can conclude that a mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.

The partial pressure of carbon dioxide in air varies with the seasons. Would you expect the partial pressure in the Northern Hemisphere to be higher in the summer or winter

Answers

Answer:

It will be higher in the summer.

Explanation:

Usually, the winter season is more harsh a weather on leaves than summer because it is wet season and thus has less sunlight and this means there will be less photosynthesis reactions and therefore it means the partial pressure will be lesser here unlike in the summer when it is a more warm and dry weather with sunlight where photosynthesis reactions will be more favorable to occur.

Thus, CO2 which is a great component of photosynthesis is used more in the summer and as such the partial pressure in the summer will be higher.

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