Answer:
[tex]\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & { 64.5} & {64-65} & {4} & {66.5 } & {66-67} & {4} & {68.5 } & {68-69} & {4} &{70.5 } & {70-71} & {5} & {72.5 } & {72-73} & {10} & {74.5 } & {74-75} & {4}\ \end{array}[/tex]
Using the frequency distribution, I found the mean height to be 70.1129 with a standard deviation of 3.2831
Step-by-step explanation:
Given
[tex]\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & { } & {64-65} & {4} & { } & {66-67} & {4} & { } & {68-69} & {4} &{ } & {70-71} & {5} & { } & {72-73} & {10} & { } & {74-75} & {4}\ \end{array}[/tex]
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:
[tex]M = \frac{1}{2}(Lower + Upper)[/tex]
Where
[tex]Lower \to[/tex] Lower class interval
[tex]Upper \to[/tex] Upper class interval
So, we have:
Class 64-65:
[tex]M = \frac{1}{2}(64 + 65) = 64.5[/tex]
Class 66 - 67:
[tex]M = \frac{1}{2}(66 + 67) = 66.5[/tex]
When the computation is completed, the frequency distribution will be:
[tex]\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & { 64.5} & {64-65} & {4} & {66.5 } & {66-67} & {4} & {68.5 } & {68-69} & {4} &{70.5 } & {70-71} & {5} & {72.5 } & {72-73} & {10} & {74.5 } & {74-75} & {4}\ \end{array}[/tex]
Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:
[tex]\bar x = 70.1129[/tex]
[tex]\sigma = 3.2831[/tex]
See attachment for result of 1-VarStats
Solving (c): Compare the calculated mean to the actual mean
The actual mean is missing from the question, so I will make assumptions in this part
Assume they are close
This means that the selected sample is a reflection of the actual population where the samples are selected.
Assume they are not close
This means that the selected sample does not reflect the actual population where the samples are selected.
Find z such that 97.5% of the standard normal curve lies to the left of z. (Enter a number. Round your answer to two decimal places.)
Answer:
z=1.96
Step-by-step explanation:
Using normal distribution table or technology, 97.5% corresponds to z=1.959964, generally denoted z=1.96, or 1.96 standard deviations above the mean.
(above value obtained from R)
Question 16 of 20
If a study estimated that 22% of students ride their bikes to school, and the
error range is +2%, what percentage of students might actually ride their bikes
to school?
O A. 22% -24%
O B. 2% - 22%
O C. 20% - 22%
ОО
D. 20% - 24%
SUBMIT
PREVIOUS
Answer:
D) 20%-24%
Step-by-step explanation:
The margin of error is ±2%, which means that the true proportion it can be 2% above the average proportion or 2% below the average proportion. Therefore, the percentage of students that might actually ride their bikes to school is 20%-24%.
Answer: A. 22%-24%
Step-by-step explanation: There's a +2% error range, so you just add 2% to the existing percentage to get your range of 22% (the original percentage) through 24% (the percentage you get after adding 2%)
GIVING BRAINLIEST!!!!!!
Answer:
B-2
Step-by-step explanation:
To find the constant of dilation take the lead of EF and divide it by the length of AB to get (6/3)=2
Bob can mow a yard in 5 hours and Jeff can mow the same lawn
in 3 hours. Which equation could be used to solve an equation to find the time
it would take to mow the yard if they both mowed the lawn at the same time? *
Answer:
2 hours
Step-by-step explanation:
because they work faster togetter and jeff mows faster
Crawling Crayfish!
Big Claw, the crayfish, challenged Flicker to a 60 em race. Since Big Claw is much
larger, he offered to give Flicker a 10 cm head start Flicker agreed and the race
began. After 5 seconds, Big Claw had crawled 6 cm and Flicker had crawled 4 cm.
If they continue at this rate, who do you predict will win the race? justify your
prediction
How many seconds have elapsed when Big Claw and Flicker are tied?
Answer: Crayfish, 25 s
Step-by-step explanation:
Given
The length of race is 60 cm
Flicker gets a 10 cm head-start
Cray fish covers 6 cm in 5 s i.e. its speed is
[tex]\Rightarrow \dfrac{6}{5}=1.2\ cm/s[/tex]
Flicker covers 4 cm in 5 s, its speed is
[tex]\Rightarrow \dfrac{4}{5}=0.8\ cm/s[/tex]
Time taken by Cray fish to cover the race is
[tex]\Rightarrow t_1=\dfrac{60}{1.2}\\\\\Rightarrow t_1=50\ s[/tex]
Time taken by flicker to cover race with 10 cm head start
[tex]\Rightarrow t_2=\dfrac{60-10}{0.8}\\\\\Rightarrow t_2=62.5\ s[/tex]
Time taken by crayfish is less. Hence, crayfish wins the race
When they both covers the same distance, they tied momentarily i.e.
[tex]\Rightarrow 1.2t=10+0.8t\\\Rightarrow 0.4t=10\\\\\Rightarrow t=\dfrac{10}{0.4}\\\\\Rightarrow t=25\ s[/tex]
After 25 s, they tied the race.
m.ng giúp mình về phần vector trong ma trận nha
Answer:
maybe if u translate it in English
Step-by-step explanation:
it wouldv been helpful if u mind?
Oliver is building a rectangular dog pen with an area of 18.9 square feet. If the length of the dog pen is 6.3 feet, what is the width?
Answer:
3 feet
Step-by-step explanation:
A = l x w Formula
18.9 = 6.3 x w Substitution
18.9/6.3 = w Division
3 = w Solution
PLS HELP! If m(x) = 2x3 – 3x + 12, what is the value of m(-2)?
Answer:
[tex]m(x) = 2 {x}^{3} - 3x + 12 \\ m( - 2) = 2 {( - 2)}^{3} - 3( - 2) + 12 \\ = 2[/tex]
What is the awnsers helppppp
Answer: 0.77
Step-by-step explanation:
Answer:
0.23
Step-by-step explanation:
the chart adds up to 1 as a whole so 23% chose football and there is a 23% chance the next person will also choose football.
What is the zero of the function represented by this graph?
Short Response
Shantelle wants to rent a mid-size car for one day. Value Rent-a-Car charges $20 a day plus $0.20 per
mile, and Best Rent-a-Car charges $30 a day plus $0.10 per mile for rental of the same mid-size car.
Part A) Write an equation in slope intercept form, y=mx+b, for each car:
Value Rent-a-Car: y=0.20x+20
Best Rent-a-Car: y=0.10x+30
Part B: Determine the mileage where the rental charges are the same.
9514 1404 393
Answer:
100 miles
Step-by-step explanation:
A. The answers shown are correct
__
B. Equate the values of y and solve for x.
0.20x +20 = 0.10x +30
0.10x = 10 . . . . . . . subtract (20+0.10x)
x = 100 . . . . . . . . divide by 0.10
The rental charges are the same for 100 miles.
How to solve problem?
Answer:
m<ADE = 57 degrees
Step-by-step explanation:
Angles of a quadrilateral add up to 360. We are already given 69 and 45, which can both be subtracted from 360, leaving us with 246. Since the two remaining angles are congruent, 246 can be divided by 2 to find the remaining measure(s). We are left with 123. However, m<ADE is supplementary to this. So we subtract 123 from 180. The final answer is 57 degrees.
How do I solve this math problem? The answer is: x = a^2/a-3
Answer:
I love algebra anyways
the ans is in the picture with the steps
(hope it helps can i plz have brainlist :D hehe)
Step-by-step explanation:
Will mark brainliest! Problem is in pic below, no links please. Thanks.
Answer:
0.6
Step-by-step explanation:
The third side of the triangle ABC is AB. Using the Pythagorean Theorem, its length is 12. [tex]12^{2} +16^2=20^2[/tex]
∠F is congruent to ∠C and so the sin(∠F) = sin(∠C)
The sin(∠C) = opposite/hypotenuse
= |AB| / |AC|
= 12/20
= 3/5
= 0.6
so the answer is 0.6
Bill can hit a bucket of 323 golf balls in 17 hours.
How many golf balls can Bill hit in 23 hours?
It take 6 Pounds of flour to make 36 cakes. How much flour is needed to make 9 cakes?
Answer:
54 pounds
Step-by-step explanation:
To find out how much flour is needed to make 9 cakes, we first need to find out how much much flour is needed to make 1 cake. For that, we need to divide 6 by 36. That will give you 6. Now that we know how much flour is needed to make 1 cake, we will just have to multiply 6 by 9 to find out how much flour is needed to make 9 cakes. That will give you 54 pounds, which is your final answer.
Find the value of x.
Answer:
20
Step-by-step explanation:
[tex]V_{right\: square \: pyramid} = \frac{1}{3} {a}^{2} h \\ \\ \therefore \: 1500 = \frac{1}{3} {(15)}^{2} (x)\\ \\ \therefore \: 1500 = \frac{1}{\cancel 3} \times \cancel {225} (x) \\ \\ \therefore \: 1500 = 75x \\ \\ \therefore \: x = \frac{1500}{75} \\ \\ \therefore \: x = 20[/tex]
The number of adults who attend a music festival, measured in hundreds of people, is represented by the function a(d)=−0.3d2+3d+10, where d is the number of days since the festival opened.
The number of teenagers who attend the same music festival, measured in hundreds of people, is represented by the function t(d)=−0.2d2+4d+12, where d is the number of days since the festival opened.
What function, f(d) , can be used to determine how many more teenagers than adults attend the festival on any day?
f(d)=−0.1d2+d+22
f(d)=0.1d2+d+2
f(d)=−0.1d2+7d+2
f(d)=0.1d2+7d+2
Answer:
f(d)=0.1d^2+d+2
Step-by-step explanation:
t(d)=−0.2d2+4d+12
a(d)=−0.3d2+3d+10
how many more teenagers than adults attend the festival on any day?
==>
f(d) = t(d) - a(d)
=0.1d^2+d+2
how do i solve this question.
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. y2(y2 − 4) = x2(x2 − 5) (0, −2) (devil's curve)
Answer:
Step-by-step explanation:
Given that:
[tex]y^2 (y^2-4) = x^2(x^2 -5)[/tex]
at point (0, -2)
[tex]\implies y^4 -4y^2 = x^4 -5x^2[/tex]
Taking the differential from the equation above with respect to x;
[tex]4y^3 \dfrac{dy}{dx}-8y \dfrac{dy}{dx}= 4x^3 -10x[/tex]
Collect like terms
[tex](4y^3 -8y)\dfrac{dy}{dx}= 4x^3 -10x[/tex]
[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]
Hence, the slope of the tangent line m can be said to be:
[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]
At point (0,-2)
[tex]\dfrac{dy}{dx}= \dfrac{4(0)^3 -10(0)}{4(-2)^3-8-(2)}[/tex]
[tex]\dfrac{dy}{dx}= \dfrac{0 -0}{4(-8)+16}[/tex]
[tex]\dfrac{dy}{dx}= 0[/tex]
m = 0
So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:
(y - y₁ = m(x - x₁))
y + 2 = 0(x - 0)
y + 2 = 0
y = -2
To find the constant vector C, we use the given initial condition v(0) = k, we also know that at t = 0, the general equation for v() i:s Comparing both equations for V(0) and solving for C, we have C = k. Substituting it back into the general equation, we have
V(t) = 4ti + 5tj + c = ______.
Answer:
4ti + 5tj + k
Step-by-step explanation:
Initial condition V(0) = k
at t = 0
general equation for v(t )
V(0) = 0i + 0j + c = k
when we compare V(0) and solve for c , c = k
back to general equation
V(t) = 4ti + 5tj + c = 4ti + 5tj + k
Use the graph to answer the question.
What is [tex]\frac{AD}{AB}[/tex] in simplest form?
A. [tex]\frac{10}{3}[/tex]
B. [tex]\frac{1}{3}[/tex]
C. [tex]\frac{17}{5}[/tex]
D. 3
Answer:
D. 3
Step-by-step explanation:
Distance between A and D = AD = 9 units
Distance between A and B = AB = 3 units
[tex] \frac{AD}{AB} = \frac{9}{3} [/tex]
Simplify by dividing
[tex] \frac{AD}{AB} = \frac{3}{1} [/tex]
[tex] \frac{AD}{AB} = 3 [/tex]
The answer is 3
please help me find the area
Answer:
17,290 yd2
Step-by-step explanation:
I rlly don't know how u were taught to solve it but what I did was multiply all the sides
if Tom had 78 apples and he gave to the shop for 80% and he put it on sale for another 10% what many apples would Tom get in the end?
Answer:
he has to many apples
Step-by-step explanation:
Never gonna give you up
Never gonna let you down
Never gonna run around and desert you
Never gonna make you cry
Never gonna say goodbye
Never gonna tell a lie and hurt you
X Y
-10 2
-15 3
-25 5
Determine whether y varies directly with x. If so, find the constant of variation and write the equation
Answer:
x = -5y
Step-by-step explanation:
x = ay
-10 = 2a
a = -5
x = ay
-15 = 3a
a = -5
x = ay
-25 = 5a
a = -5
Solve for X in the triangle. Round your answer to the nearest tenth
Answer:
[tex]\displaystyle x \approx 9.9[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityTrigonometry
[Right Triangles Only] SOHCAHTOA[Right Triangles Only] sinθ = opposite over hypotenuseStep-by-step explanation:
Step 1: Define
Identify variables
Angle θ = 64°
Opposite Leg = x
Hypotenuse = 11
Step 2: Solve for x
Substitute in variables [sine]: [tex]\displaystyle sin(64^\circ) = \frac{x}{11}[/tex][Multiplication Property of Equality] Multiply 11 on both sides: [tex]\displaystyle 11sin(64^\circ) = x[/tex]Rewrite: [tex]\displaystyle x = 11sin(64^\circ)[/tex]Evaluate: [tex]\displaystyle x = 9.88673[/tex]Round: [tex]\displaystyle x \approx 9.9[/tex]Sum of 5x^2+2x and 4-x^2
Answer:
4x^2 + 2x + 4
Step-by-step explanation:
5x^2 + 2x + 4 - x^2
4x^2 + 2x + 4
Answer:
2(2x^2 + x + 2)
Step-by-step explanation:
5x^2+2x + 4-x^2
Re arrange so like terms are next to each other
Keep the same symbol that is at the front of the term when moving it
5x^2 - x^2 + 2x + 4
We will just do the first part first
5x^2 - x^2
5x^2 - 1x^2 (is the same thing as above)
So because they are like terms (are both x^2)
We can just minus 1 from 5
5-1=4
So 4x^2
Now the equation is
4x^2 + 2x + 4
This is as small as it gets but you can also bring it to this
4, 2 and 4 all are divisible by 2 so
2(2x^2 + x + 2)
What is the initial value of the function represented by this table?
Answer:
2
Step-by-step explanation:
3+2=5 and 5+2 =7 and on x side just add 1
PLEASE HELP!!!
WILL MARK BRAINLIEST!!!
If the diameter of the circle shown below is 6ft and 0 is a right angle, what is the length of segment AB to the nearest foot?
Multiple choice!
Thank you!
Answer:
how old are you gghhjjzetstu9u
Answer:
4 ft
Step-by-step explanation:
let's find radius first
radius=diameter/2
=6/2
=3 ft
radii=3 ft
Now by using pythagoras theorem
a^2 + b^2 = c^2
3^2 + 3^2 =AB^2
9+9=AB^2
18=AB^2
[tex]\sqrt{18}[/tex] AB
4.24 =AB
4 ft =AB (after converting to nearest foot)
A force of 4 pounds is required to hold a spring stretched 0.4 feet beyond its natural length. How much work (in foot-pounds) is done in stretching the spring from its natural length to 0.6 feet beyond its natural length
Answer:
the work done in stretching the spring from its natural length is -1.8 ft.lb
Step-by-step explanation:
Given the data in the question;
From Hook's law, the magnitude of force applied on a spring is expressed as follows;
|F| = k|x|
where F is the force applied the spring, k is the spring constant, x is the length extension
Now, given that; F = 4 pounds = 4 lb and x = 0.4 ft
we substitute
4 = k × 0.4
k = 4 / 0.4
k = 10 lb/ft
Also, Hook's law can be expressed as follows;
F = -kx ---------- let this be equation 1
Now, work done by a force applied between two points is expressed as follows;
dW = Fdx ----------- let this be equation 2
substitute equation 1 into equation 2
dW = (-kx )dx
we integrate both side
∫(dW) = ∫((-kx )dx)
W = -k∫xdx
W = -k[tex]\frac{x^2}{2}[/tex]
w = -[tex]\frac{1}{2}[/tex]kx²
we substitute 10 lb/ft for k and 0.6 ft for x
w = -[tex]\frac{1}{2}[/tex] × 10 lb/ft × (0.6 ft)²
w = -[tex]\frac{1}{2}[/tex] × 10 lb/ft × 0.36 ft²
w = -1.8 ft.lb
Therefore, the work done in stretching the spring from its natural length is -1.8 ft.lb