Answer:
I=Principle × Rate × Time so 1000×4.5/100 × 15yrs
I need assistance urgent
Which is the equation of the line with slope o passing through the point (-3,-1)?
9514 1404 393
Answer:
y = -1
Step-by-step explanation:
We assume you want the line with a slope of zero. That is a horizontal line, so y is a constant. In order to make the line go through the point with y=-1, the equation of the line is ...
y = -1
Find the distance given the coordinates (-2, -1) & (-8, 7) in the simplest form
O 72
072
O 10
O 100
Write out in words how to solve the following equation N/3+5-8=2
(n/3) + 5 - 8 = 2
First add the constants (+5 and -8) on LHS.
(n/3) - 3 = 2
Transfer -3 to RHS, by changing its sign.
n/3 = 2 + 3
Now add the constants (2 and 3) on RHS.
n/3 = 5
Transfer 3 to RHS by changing division to multiplication
n = 5 × 3
Finally multiply the constants (5 and 3) on RHS
n = 15
If ∠G measures 45°, ∠F measures 82°, and f is 7 feet, then find g using the Law of Sines. Round your answer to the nearest foot. triangle EFG with side e across from angle E, side f across from angle F, and side g across from angle g 4 feet 5 feet 6 feet 7 feet
The value of g across from angle G is 5feet
According to sine rule
[tex]\frac{e}{sinE}=\frac{f}{sinF}=\frac{g}{sinG}[/tex]
Given the following
∠G = 45°
∠F = 82°
f = 7feet
Required
side g
Substitute the given values into the formula
[tex]\frac{f}{sinF}=\frac{g}{sinG}\\ \frac{7}{sin82}=\frac{g}{sin45}\\\frac{7}{0.9903}=\frac{g}{0.7071}\\7.0686=\frac{g}{0.7071}\\g=7.0686*0.7071\\g=4.998\\g\approx5ft[/tex]
Hence the value of g across from angle G is 5feet
Learn more here: https://brainly.com/question/15018190
The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.
Let be [tex]EFG[/tex] a Triangle, whose expression derived from the Law of Sines is described below:
[tex]\frac{e}{\sin E} = \frac{f}{\sin F} = \frac{g}{\sin G}[/tex] (1)
Where:
[tex]e[/tex] - Measure of the line segment FG, in feet.
[tex]f[/tex] - Measure of the line segment EG, in feet.
[tex]g[/tex] - Measure of the line segment EF, in feet.
[tex]E[/tex] - Angle at vertex E, in sexagesimal degrees.
[tex]F[/tex] - Angle at vertex F, in sexagesimal degrees.
[tex]G[/tex] - Angle at vertex G, in sexagesimal degrees.
We can determine a missing length, by knowing the length of a neighboring side and two consecutive angles. If we know that [tex]f = 7\,ft[/tex], [tex]G = 45^{\circ}[/tex] and [tex]F = 82^{\circ}[/tex], then the measure of the line segment EF is:
[tex]g = f\cdot \left(\frac{\sin G}{\sin F} \right)[/tex] (2)
[tex]g = (7\,ft)\cdot \left(\frac{\sin 45^{\circ}}{\sin 82^{\circ}} \right)[/tex]
[tex]g\approx 4.998\,ft[/tex]
[tex]g \approx 5\,ft[/tex]
The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.
I don’t get it this ain’t make no sense
Answer:
65 m
Step-by-step explanation:
u = 6 m/s
v = 20 m/s
t = 5 s
[tex]s=\frac{1}{2} (6+20)5[/tex]
[tex]s=\frac{1}{2} (26)5[/tex]
[tex]s=(13)5[/tex]
[tex]s=65[/tex]
Hey there!
1/2(6 + 20)(5)
= 1/2 (26)(5)
1/2(26) = 13
= 13(5)
= 65
Therefore, your answer is most likely: 65m
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Please help will give brainliest
Complete the equation describing how
x and y are related.
x
0
1
2
3
4
5
у
1
-1
-3
-5
-7
-9
y = [ ? ]x + []
Enter the answer that belongs in [?].
Answer:
y=-2x+1
Step-by-step explanation:
The slope of the line is - 2. The y intercept is 1. Hence the equation is y=-2x+1
Given the following situation:
A cell phone company offers a data package by charging $20 a month plus $12 per gigabyte of data used. Write a linear equation
that relates the cost C, in dollars, to the amount of data used. Use it to determine the amount of data used if they charge you
$116.
9514 1404 393
Answer:
C = 20 +12g8 gigabytesStep-by-step explanation:
At $12 per gigabyte, the data charge will be 12g where g is the number of gigabytes. Then the total charge is ...
C = 12g +20
__
If C = 116, the value of g is found from ...
116 = 12g +20
96 = 12g . . . . . . . subtract 20
8 = g . . . . . . . . . . divide by 12
The amount of data used is 8 gigabytes if the charge is $116.
Please help me find limit
9514 1404 393
Answer:
-13/11
Step-by-step explanation:
Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...
[tex]\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}[/tex]
The area of a rectangle is 63 ft^2, and the length of the rectangle is 11 ft more than twice the width. Find the dimensions of the rectangle.
Which statement is true about a line plot? A. A line plot shows the frequency of an interval of values of any given data set. B. A line plot shows the first quartile, but not the second quartile of any given data set. C. A line plot shows the frequency of the individual values of any given data set. D. A line plot shows the mean of any given data set.
Answer:
D
Step-by-step explanation:
8x( 5 x 2 ) Pls give answer
Answer:
80x
Step-by-step explanation:
Bracket first
5 x 2 = 10
8x x 10 = 80x
(Unless the 'x' next to the 8 is the term for multiplying:
8 x 10 = 80)
Answer:
80
Step-by-step explanation:
8 x (5 x 2)
8 x 10
Answer = 80
Find the area of the shaded regions:
QUICKLY!!!!!
Answer:
[tex]41.89\ cm^2[/tex]
Step-by-step explanation:
[tex]We\ are\ given:\\In\ two\ concentric\ circles,\\OD=3\ cm\\BC=4\ cm\\\angle DOB=\angle AOC=120\\Now,\\We\ know\ that:\\Area\ of\ a\ sector\ with\ a\ central\ angle\ \theta\ and\ a\ radius\ r\ is:\\A=\frac{\theta}{360}* \pi r^2\\Here,\\Area\ between\ the\ sectors=Area\ of\ Larger\ Sector - Area\ of\ smaller\ sector=\frac{\theta}{360}*\pi(R^2-r^2),\ where\ R\ and\ r\ are\ radii\ of\ the\ respective\ circles\ and\\ \theta\ is\ the\ common\ central\ angle.\\Here,\\R=4+3=7\ cm\\r=3\ cm\\ \theta=120\\ Hence,[/tex]
[tex]Area\ of\ the\ shaded\ region=\frac{120}{360}*\pi(7^2-3^2)=\frac{1}{3}*\pi(49-9)=\frac{1}{3}*\pi(40) \approx 41.89\ cm^2[/tex]
Really need help and the answer on this one plz help.
Find the area of Parallelogram ABCD given M< A=30° AB=10in AD=6in A=
Answer:
30 in²
Step-by-step explanation:
Parallelogram height is,
6/2 (since it's a 30°-60°-90° triangle)
= 3
Area = base × height
= 10×3 in²
= 30 in²
Answered by GAUTHMATH
The quadratic equation x^2 + 3x + 50 = 0 has roots r and s. Find a quadratic equation whose roots are r^2 and s^2.
Answer:
x^2 + 91x + 2500
-----------------------------------------------------------------------------
x^2 + 3x + 50
(x-r)(x-s)
-> x^2-(r+s)x+rs
rs = 50, r + s = -3
-> (rs)^2 = 2500
(r+s)^2 = 9
-> r^2 + 2rs + s^2 = 9
-> r^2 + 2(50) + s^2 = 9
-> r^2 + s^2 + 100 = 9
-> r^2 + s^2 = -91
(x-r^2)(x-s^2)
-> x^2-(r^2+s^2)x+(rs)^2
-> x^2 - (-91)x + 2500
x^2 + 91x + 2500
Two boats are travelling at 30 miles/hr, the first going north and the second going east. The second crosses the path of the first 10 minutes after the first one was there. At what rate is their distance increasing when the second has gone 10 miles beyond the crossing point
Answer:
their distance is increasing at the rate of 41.6 miles/hr
Step-by-step explanation:
Given the data in the question;
first we determine the distance travelled by the first boat in 10 min when the second boat was crossing its path;
⇒ ( 30/60 ) × 10 = 5 miles
so as illustrated in the diagram below;
y² = x² + ( x + 5 )²
2y[tex]\frac{dy}{dt}[/tex] = 2x[tex]\frac{dx}{dt}[/tex] + 2(x+5)[tex]\frac{dx}{dt}[/tex]
y[tex]\frac{dy}{dt}[/tex] = ( 2x + 5 ) ][tex]\frac{dx}{dt}[/tex]
[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex] ------ let this be equation 1
Now, given that, [tex]\frac{dx}{dt}[/tex] = 30 miles/hr, when x = 10
so
y = √( 10² + 15² ) = √325
so from equation 1
[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex]
we substitute
[tex]\frac{dy}{dt}[/tex] = [( 2(10) + 5 ) / √325 ]30
[tex]\frac{dy}{dt}[/tex] = [ 25 / √325 ] × 30
[tex]\frac{dy}{dt}[/tex] = 41.6 miles/hr
Therefore, their distance is increasing at the rate of 41.6 miles/hr
Question 7 Multiple Choice Worth 1 points)
(01.01 LC)
Evaluate the expression 28 - 472 - 10-2
0 11
O 27
O 56
O 59
Product A sells 1.5 times more than Product B. Product B sells 70% less than Product C. Product C sold 34,000 units this month.
How many units of Product A were sold?
10,200
15,300 23,800 35,700 51,000
Answer:
15,300 units
Step-by-step explanation:
First, find how many units of Product B were sold:
34,000(0.3)
= 10,200
Find how many units of Product A were sold:
10,200(1.5)
= 15,300
So, 15,300 units of Product A were sold.
Product A sold 15,300 units that is 1.5 times more than product B
Given :
Product A sells 1.5 times more than Product B. Product B sells 70% less than Product C.
Product C sold 34,000 units this month
Product C sold = 34000
Product B is 70% less than product C
So, product B is 100-70% =30% of product C
[tex]Product B=\frac{30}{100} \cdot 34000\\Product B \; sold = 10200[/tex]
Lets find out product A sold
Product A sold = 1.5 times more than product B
[tex]Product A= 1.5 \cdot product B\\Product A=1.5 \cdot 10200=15300[/tex]
15,300 units of product A were sold.
Learn more : brainly.com/question/18958901
The distance a race car travels is given by the equation, [tex]d=v_{0} t+\frac{1}{2} at^{2}[/tex], where [tex]v_{0}[/tex] is the initial speed of the race car, a is the acceleration and t is the time traveled. Near the beginning of a race, the driver accelerates for 9 seconds at a rate of [tex]4m/s^{2}[/tex]. The driver's initial speed was 75 m/s.
Find the driver's average speed during the acceleration.
Step-by-step explanation:
here's the answer to your question
Solve: 5 + n > 2
Just let me know because I am stuck and need to know the answer for this test please let me know thank you ❤️
[tex]\\ \sf\longmapsto 5+n>2[/tex]
We have to find n Take 5 to right side sign will be changed[tex]\\ \sf\longmapsto n>2-5[/tex]
Simplify[tex]\\ \sf\longmapsto n>-3[/tex]
Which of the following graphs is the inverse of f(x) = x2 + 4?
Answer:
Step-by-step explanation:
Determine whether the following polygons are similar. If yes, type 'yes' in the Similar box and type in the similarity statement and scale factor. If no, type 'None' in the blanks. For the scale factor, please enter a fraction. Use the forward dash (i.e. /) to create a fraction (e.g. 1/2 is the same as 12
1
2
).
Given:
The figures of two polygons.
To find:
Whether the polygons are similar and then find the scale factor (if similar).
Solution:
From the given figures it is clear that both polygons are rectangles and their all interior angles are right angles.
The ratio of their longer sides:
[tex]\dfrac{32}{26}=\dfrac{16}{13}[/tex]
The ratio of their shorter sides:
[tex]\dfrac{18}{12}=\dfrac{3}{2}[/tex]
Since the ratio of their corresponding sides are not equal, therefore the two polygons are not similar.
Therefore the required solutions are:
Similar : No
Similarity statement : None
Scale factor : None
Find the percent notation of 2.2
Answer:
2.2 x 100 = 220%
Step-by-step explanation:
To convert from decimal to percent, just multiply the decimal value by 100. In this example we have: 2.2 × 100 = 220% (answer). ➥ The ease way: 1) Move the decimal point two places to the right: 2.2 → 22 → 220.
I hope this will help you
The graph is that of a fourth-degree polynomial function. Which of the following correctly shows three factors of the function? Image included, please help!
C.
Observe that the roots of polynomial are [tex]-3,2,5[/tex]
We have a polynomial in a factored form,
[tex](x+3)(x-2)(x-5)[/tex]
If you substitute x for any of [tex]-3,2,5[/tex] the product will always equal to zero that is these numbers are roots of polynomial.
Hope this helps :)
a swift can fly at 160km/h. what is the speed in m/s? show clearly how you worked out your answer.
Answer:
[tex]\huge\boxed{\sf Speed = 44.44 \ m/s}[/tex]
Step-by-step explanation:
Speed = 160 km / hr
To convert km/hr to m/s, we multiply it by [tex]\sf \frac{10}{36}[/tex]
Hence,
[tex]\displaystyle Speed = 160 \times \frac{10}{36} \ m/s\\\\Speed = \frac{1600}{36} \ m/s\\\\Speed = 44.44 \ m/s\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Peace!Alice and Bob each choose a number uniformly (and independently) from the interval [0, 10]. What is the probability that the absolute value of the difference between their two numbers is less than 1/4
Answer:
The probability is zero (0)
Step-by-step explanation:
Given;
interval of numbers to be chosen = 0, 1, 2, 3 , 4, 5, 6, 7, 8, 9 , 10
total possible outcome = 11
The possible numbers whose absolute difference is greater than ¹/₄ includes the following;
(0,1), (1,2), (2,3), (3,4), (4,5), (5,6), (6,7), (7,8), (8,9), (9,10), (10,0)
The probability of this = 11 / 11 = 1
The probability that the absolute value of the difference between their two numbers is less than 1/4
[tex]P(less \ than \ \frac{1}{4} ) = 1 - P(greater \ than \ \frac{1}{4} )\\\\P(less \ than \ \frac{1}{4} ) = 1 - 1 \\\\P(less \ than \ \frac{1}{4} ) = 0[/tex]
You decide to determine, once and for all, which chocolate brownies are best-- yours or your sister-in-law's Yolanda-- by devising a test of hypothesis. She is a superb baker and she mocks your baking as inferior. Undaunted, you decide to randomly select 100 names from the NYC phone book. You contact each selected individual and they agree to participate in your study. Then, you send your brownies with instructions for rating the taste and one week later you send Yolanda's brownies with the same instructions. Each group rates the brownies on a 10 point ordinal scale--10 implies exquisite and 1 implies inedible. True or False: This test is performed on paired or matched samples.
Answer:
Ture
Step-by-step explanation:
The rates of the same participatant are paired.
Zoe is a party planner. She orders cupcakes and sheet cakes from Creative Cakes whenever she needs beautiful cakes to serve. One sheet cake serves 24 people and 2 dozen cupcakes serve 24 people. For the Benson's bridal shower she ordered 8 dozen cupcakes and 3 sheet cakes and paid $160.81. For the Nygaard's 50th wedding anniversary she ordered 6 dozen cupcakes and 15 sheet cakes and paid $342.33. She is planning a graduation party for her niece's high school class. She wants the party to be nice but she offered to pay for the cakes herself so she wants to choose the most economical plan. Zoe estimates 250 people will attend the party.
Full question:
Zoe is a party planner. She orders cupcakes and sheet cakes from Creative Cakes whenever she needs beautiful cakes to serve. One sheet cake serves 24 people and 2 dozen cupcakes serve 24 people. For the Benson's bridal shower she ordered 10 dozen cupcakes and 4 sheet cakes and paid $186.44. For the Nygaard's 50th wedding anniversary she ordered 2 dozen cupcakes and 15 sheet cakes and paid $259.66. She is planning a graduation party for her niece's high school class. She wants the party to be nice but she offered to pay for the she wants to choose the most economical plan. Zoe estimates 250 people will attend the party
Select the most economical choice below:
Zoe should buy sheet cakes because they cost $12.38 for one sheet cake.
Zoe should buy sheet cakes because they cost $15.66 for one sheet cake.
Zoe should buy cupcakes because they cost $12.38 for one dozen cupcakes.
Zoe should buy cupcakes because they cost $15.66 for one dozen cupcakes.
Zoe should buy cupcakes because they cost $12.38 for two dozen cupcakes.
Answer:
Zoe should buy cupcakes because they cost $12.38 for two dozen cupcakes.
Explanation:
If there are 250 people attending the high school class graduation party, then 24 people each within 250 people in total would get 2 dozen cupcakes worth $12.38 each.
Therefore there are 250/24 = 10.41 groups (10 groups approximately or 10.41×2=20.82 dozens of cupcakes required)
Zoe would need to spend 10.41×$12.38= $128.88 to buy the cupcakes for the party
ANSWER ASAP CORRECT ANSWER WILL GET BRAINLIEST PLUS 78 POINTS
9514 1404 393
Answer:
C) 462
Step-by-step explanation:
The presenters can be chosen 11C6 = 462 different ways.
__
If the teacher were concerned about the order of the presentations, the number of possibilities goes up to 11P6 = 332,640 different ways.
