at what angle in degrees will the 1st order bright fringe for green light (500nm) be on a screen that is 1 meter away from a single slit

Faraday's left hand rule gives us the direction of the force on the particles, then [tex]F^{\prime}=B q v\\[/tex] gives the size of the force.

What is direction?

Direction is characterized as the course that anything follows, the route that must be taken to go to a particular location, the direction in which something is beginning to take shape, or the direction you are facing. When you turn right instead of left, that is an illustration of direction.

If we use Faraday's left hand rule on each particle, we can determine the effect of the magnetic field on the particle. The diagram shows the direction of the fields and the "current" so we can apply the rule.

For the electron, the magnetic field will exert a force directed into the plane of the paper (or if travelling on the earth, this will be towards the earth).

For the proton, the magnetic field will exert a force out of the paper (or if travelling on the earth, this will be away from the earth).

The force on a particle of charge q moving in a magnetic field, B with a velocity v  is given by:

[tex]F=B q v[/tex]

Both proton and electron have a charge of [tex]1.6 \times 10^{-19} C\\[/tex]

For the electron

[tex]$$F=\left(190 \times 10^{-3}\right) \cdot\left(1.6 \times 10^{-19}\right) \cdot 575000=1.748 \times 10^{-14} N$$[/tex]

For the proton

[tex]$$F=\left(54.2 \times 10^{-6}\right) \cdot\left(1.6 \times 10^{-19}\right) \cdot 130000=1.127 \times 10^{-18} N$$[/tex]

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power of the bulb  = 40 watt

Briefing

Power: In physics, the term "power" refers to the rate at which a task is completed, or how much energy is used during the allotted time.

What is energy now?

In physics, energy refers to the ability to do a task. It may exist in different forms, including potential, kinetic, thermal, electrical, chemical, radioactive, and others.

Consequently, in light of the posed query:

2400 J of energy

60 seconds in a minute is time.

As a result, we know that Power = Energy/Time.

p = E/t p = (2400-/60) joules/sec

p=40 W

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There is a net flux going into the surface, the parallelepiped must have a net charge (negative charge). Additionally, without an external field, all lines would point at the slab.

Six parallelograms come together to form a three-dimensional shape called a parallelepiped (the term rhomboid is also sometimes used with this meaning). It is comparable to a parallelogram in the same way that a cube is comparable to a square. There are three similar descriptions of a parallelepiped. A prism with a parallelogram-shaped base, a hexahedron with three pairs of parallel faces, and a polyhedron with six faces, each of which is a parallelogram.

There are pairs of parallel and congruent faces. The parallelepiped has twelve (12) edges and eight (8) vertices. The edges of the parallelepiped can be split into three (3) sets of four (4) edges each, where the edges in each set are all parallel and the same length. The parallelepiped is also a zonohedron.

A parallelepiped is a three-dimensional object having six faces and a parallelogram-like design. It has 8 vertices, 6 faces, and 12 edges. The parallelepiped is also known by the names rhombic, cuboid, and cube.

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By simply creating more loops or pulleys, the pulley system's mechanical advantage can be accomplished.

Equation:

It is known that a pulley system can lift a crate with 90 newtons of force. Finding the pulley system's mechanical advantage is important if the input force is 15 newtons.

The force makes the distance longer as though it were working. Mechanical advantage is not greatly affected by the number of pulleys. This is only based on the amount of weight that needs to be lifted.

Therefore,

F1/F2 = 90/15

F1/F2 = 6

Given that the crate's weight is 90 N and the input force is 15 N, this makes sense.

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Answer: C

Explanation:

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A 59-kg person riding a bike puts all her weight on each pedal when climbing a hill. The pedals rotate in a circle of radius 18 cm.  the maximum torque she exerts is 104.07Nm.

given that :

mass ,m = 59 kg

radius , r = 18 cm

The force , F = mg

F = 59 × 9.8

F = 578.2 N

The torque is expressed as:

torque = force × radius

torque = 578.2 N × 0.18 m

torque = 104.07 Nm

Thus, if the mass is 59 kg and the radius is 18 cm then  maximum torque she exerts is the 104.07 Nm.

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If your friend's outstretched hands are at distance d = 1.50 m above the ground, (a) work Wg does the gravitational force do on the book as it drops to her hands 167J, b) -167J, c) 196J, d)29J, e)167J, f)-167J g)296J, and h) 129J

a)  Work = mg(Ac)

              = 2 × 9.8 × (10 - 1.5) = 167j

b) ΔU = Ubc - Uab = Mg(bc) - Mg(ab)

          = mg(bc - ab)

           = 2 × 9.8 (1.5 - 10) = -167j

c) Potential energy at reach point v = mg(AB) = 2 × 9.8 × 10 = 196J

d) Potential energy at reach point U = mg (bc) = 2 × 9.8 × 1.5 = 29.4j

e) Total work wg = mg (ac) = 2 × 9.8 × 3.5 = 167j

f) ΔU = -wg = - 167j

g) ui = mg × AB + 100 = 196 + 100 = 296j

h) uf = mg × bc + 100 = 29.4 + 100 = 129j

Given the possibility of motion, gravitational forces can sort phases of various densities. Although high temperatures are not anticipated for the early Earth, widespread melting is one possibility. Sorting in response to the outgassing of deeply buried ices is a more feasible scenario. Such processes would have altered the moment of inertia, necessitating an adjustment to the angular velocity. Friction opposes gravitational settling and prevents it from being conservative, which makes quantification dubious. The ensuing phase separation and angular momentum alterations would not need to be as extensive as commonly believed if an iron protocore existed.

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The voltage drops in terms of vb , i2 , i3 , the given resistances, and any other given quantities.ΣΔV = 0 = I3 ⋅ R3 - I2 ⋅ R2.

When applying Kirchhoff's second rule the loop rule we need to identify closed loops and decide whether to loop clockwise or counterclockwise. For example, in Figure 3 the loop was traversed in the same direction as the current.

Loop 1 is the full loop and Loop 2 is the small loop on the right. To apply the loop rule, add all those voltage changes. Kirchhoff's Second Law, also known as Kirchhoff's Voltage Law states that the sum of all voltages around the closed loop of any circuit must be zero. This is a result of charge conservation and energy conservation.

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The temperature of two main-sequence stars is the same. Star B is two times further away than star A if star A is four times more brilliant.

The temperature and brightness of a main-sequence star depend on its mass. Bigger is always hotter and brighter. A star with ten times the mass of the sun contains nuclear energy. The brightness is 3000 times that of the sun.

Even stars with the same temperature inevitably have different luminosities. As an illustration, consider stars A and E, which have the same temperature but differ in luminosity.

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Zach's apparent weight before the elevator starts breaking is 686 N.

Zach's apparent weight while the elevator starts breaking is 966 N.

Given that, mass of Zach = 70 kg

His weight W = mg = 70* 9.8 = 686 N

If the elevator is going down at a constant velocity then, acceleration is zero and the apparent weight before braking is 686 N.

v = u + a * t

where,

t = Time taken

u = Initial velocity

v = Final velocity

a = Acceleration

Making a as subject from the above equation,

Acceleration a = (v - u)/t = (0-12)/3 = -4 m/s²

While the elevator is braking it has acceleration -4 m/s².

W = m ( g - a) = 70 (9.8 - (-4)) = 70(9.8 + 4 ) = 966 N

The apparent weight of Zach is 966 N.

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The approximate distance that the smoke travels up from the furnace is 9metres.

Distance is described as a numerical or occasionally qualitative measurement of how far apart objects or points are. In the field of physics or everyday usage, distance is usually referred to a physical length or an estimation based on other criteria.

Parameters given:

Velocity = 1.5

time = 6 seconds

We know that distance = speed x time

Hence, distance = 1.5 x 6 seconds

distance = 9 meters.

Distance is a scalar quantity that refers to how much ground an object has covered in the course of its motion while we can describe displacement as a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

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Sand dunes form when  the mound grows in circumference and height due to subsequent sand build up in one place by wind.

A sand dune is a mass of loose sand grains that have accumulated due to wind movement. The mound will eventually get so massive that it will collapse under its own weight to form a sand dune as it increases in height and circumference as a result of additional sand deposits. A set of sand dunes is referred to as a sand dune complex or sand dune system by geologists.

On the other hand, depending on the quantity of vegetation present, vast clusters of sand dunes are referred to as sand seas or sand dune fields. Ergs are another name for sand seas.

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Your question is incomplete, but most probably the question was:

sand dunes form when _______ sand build up in one place  by wind.

Answer:

copy and complete this diagram so that the system is in equilibrium

Projectile launch is a kinematics application to the movement of objects near the earth's surface.

Since the acceleration is constant, the time it takes for the body to go up is equal to the time it takes to go down; thus, the time it takes to go up is half of the total time.

tu = ttotal/2

tu = 4.70 / 2

tu = 2.35 s

The height the ball reach

The point of maximum height where the vertical velocity is zero

vy = voy - gt

0 = voy - gt

voy = gt

= 9.8 x 2.35

= 23 m / s

By using the equation.

v²y = v²oy - 2gy

0 = v²oy - 2gy

y = v²oy/2g

y = 23²/2 x 9.8

y = 27 m

To find the initial velocity,

Initial vertical velocity = 23 m / s

vx = x/t

The throw range is 44m in time of 4.60 s

vₓ = 44 / 4.60

 v₀ =  [tex]\sqrt{v^{2}ox + v^{2}oy }[/tex]

 v₀ = [tex]\sqrt{9.56^{2}+23^{2} }[/tex]

 v₀ = 24.9 m / s

The launch angle is:

Let's use trigonometry

tan θ = voy/vox

θ = tan⁻¹ voy/vox

θ = tan⁻¹ 23/9.56  

θ = 67.4°

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Radon is a radioactive gas which has no smell, colour or taste.

When you breathe in radon gas, it decomposes into solid radioactive particles that can become trapped in your lungs. These particles release small energy bursts as they degrade further. Over the course of ones lifetime, this can cause lung tissue to deteriorate and result in lung cancer.

Lung cancer has radon as one of its main causes. Depending on the average radon level across the nation and the prevalence of smoking, radon is thought to be responsible for anywhere from 3% to 14% of all lung cancers. Smokers are more likely to develop lung cancer due to the interaction between radon and smoking cigarettes.

There are tried-and-true, long-lasting, and reasonably priced ways to keep radon out of new construction and reduce it in existing structures.

With a small passive detector, it is simple to measure the amount of radon indoors.

The amount of radon in the air is measured in “picocuries per liter of air,” or “pCi/L

Note that your information is incomplete and a overview was given.

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Suppose you are in mission control on the moon, in charge of launching a moon-orbiting communications satellite.

a) 2430 N.

b) 1.84 x 10^6 m.

c) F = m * v^2 / r

d) 2157 m/s

e) 2.87 x 10^4 s

f)1.17 x 10^-3 m/s^2

a. The weight of the satellite near the surface of the moon would be the mass of the satellite multiplied by the acceleration due to gravity on the moon. The acceleration due to gravity on the moon is about 1.62 m/s^2, so the weight of the satellite would be

1500 kg * 1.62 m/s^2 = 2430 N.

b. The radius of the orbit of the satellite would be the distance from the center of the moon to the altitude of the satellite. The radius of the moon is 1.74 x 10^6 m, so the radius of the orbit of the satellite would be

1.74 x 10^6 m + 100 km = 1.84 x 10^6 m.

c. The centripetal force is the force that is required to keep an object in circular motion. It is equal to the mass of the object times its velocity squared, divided by the radius of its orbit. To find the centripetal force on the satellite, we need to know its velocity. We can find this using the equation for the centripetal force, which is:

F = m * v^2 / r

where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the orbit.

d. To find the required orbital velocity for the satellite, we can rearrange the equation for the centripetal force to solve for v:

v = sqrt(F * r / m)

Plugging in the values, we get:

v = sqrt(2430 N * 1.84 x 10^6 m / 1500 kg) = 2157 m/s

e. The orbital period is the time it takes for an object to complete one orbit. It is equal to the circumference of the orbit divided by the velocity of the object. The circumference of the orbit is 2 * pi * r, where r is the radius of the orbit. The velocity of the object is the orbital velocity we calculated above. Plugging these values into the equation, we get:

T = 2 * pi * r / v

Plugging in the values, we get:

T = 2 * pi * 1.84 x 10^6 m / 2157 m/s = 2.87 x 10^4 s

f. Yes, the satellite is accelerating while in orbit. The direction of the acceleration is towards the center of the orbit, and the magnitude of the acceleration is the centripetal acceleration, which can be calculated using the equation:

a = v^2 / r

Plugging in the values, we get:

a = 2157 m/s^2 / 1.84 x 10^6 m = 1.17 x 10^-3 m/s^2

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1. The velocity of the center of mass of the two-block system is zero.

2. The magnitude of the acceleration of the left block is greater than that of the right block.

The center of mass, or balancing point, of a distribution of mass in space is the only location where the total of the weighted relative positions of the distributed mass equals zero. In order to accelerate linearly without also accelerating angularly, a force might be applied at this moment. Using the center of mass as a reference point simplifies calculations in mechanics quite a bit. To imagine how an object would move, one can imagine a hypothetical location where the object's total mass is concentrated. To apply Newton's equations of motion to a particular object, the center of mass is the particle equivalent of that thing.

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With respect to stellar spectra Doppler shifts in spectral lines give clues to the motions of stars.

The spectral lines of an element can be used by astronomers to determine the element's temperature as density within the star. The spectral line may also be used to display the star's electric flux. The width of the line may be used to gauge how rapidly the material is moving. We can learn something about stellar winds from this.

Dark bands in a broad band can be used to identify components, and it can also reveal an object's temperature: The spectrum has more green, blue, and violet hues as the temperature rises. The spectrum of relatively cool objects is dominated by deep red or red and yellow.

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5.00 × 10-3/K is the coefficient of thermal expansion of the material from which the rod is made as it increases its length to 2.0005m

The coefficient of thermal expansion explains how an object's size varies when temperature changes. In particular, it measures the fractional size change per degree change in temperature at constant pressure, where lower coefficients denote a reduced propensity for size change.

The propensity of matter to alter shape, volume, and area in reaction to a change in temperature is known as thermal expansion. The average molecular kinetic energy of a substance has a monotonic relationship with temperature.

Use the equation for linear thermal expansion ΔL=αLΔT Δ L = α L Δ T to calculate the change in length, ΔL .

Get your rod hot enough to achieve, say, 1% linear thermal expansion.

The rod's dimension has increased to 1.01 units.

The rod is 1.030301 times its original size, or 1.013 larger than it was before heating.

This equals 1.03 when rounded to three major figures. In other words, its volume is 3% higher than that of the cold specimen.

The linear expansion is tripled, or 3%, by the volumetric expansion.

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Complete question:

A rod has a length 2.0000 m at 20.0°C. The length of the rod increases to 2.0005 m when the temperature increases to 40.0°C. What is the coefficient of thermal expansion of the material from which the rod is made?

The magnitude of the resultant displacement A + B is 5.18 km. Displacement of A is 3.2 km. The magnitude of B is 4.07 km.

It can be seen that the resultant displacement and the other 2 displacements form a right angle triangle, with A + B as the hypotenuse, 3.2 km as the opposite and the displacement B as the adjacent.

By using Pythagoras theorem, the adjacent side of the triangle can be found.

(5.18)² = (3.20)² + B²

26.83 = 10.24 + B²

B² = 26.83 - 10.24

B² = 16.59

B = √16.59 = 4.07 km

Thus, the magnitude of B is 4.07 km.

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Maximum torque developed is (BIL²/4[tex]\pi[/tex]n).

Torque is a measure of force that can cause an object to rotate about an axis.

For any structure such as a solenoid, toroid, and circular arc, the magnetic field at a certain point of the structure is always proportional to the number of turns of the coil.

As we know magnetic field is (BIL²/4[tex]\pi[/tex]n)

2[tex]\pi[/tex]rn = L

r = (L/2[tex]\pi[/tex]n)

A = [tex]\pi[/tex]r²

A = (L²/4[tex]\pi[/tex]n²)

M = niA

M = (iL²/4n[tex]\pi[/tex])

Then Torque is Z = MBSin90°

The question is incomplete, the complete question is "a wire of length l is wrapped into a coil with n turns this coil is then placed in a magnetic field of strength b,  the maximum possible torque developed is?"

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The thickness of the oil is 0.327 m.

The bottom pressure of the tank is given by atmospheric pressure, pressure given by oil and pressure of water. It is mathematically given as,

P = Patm + ρoil g* t + ρwater g * h

Making 't' as subject, we have,

ρoil g* t = P - Patm - ρwater g * h

t = (P - Patm - ρwater g * h)/ρoil g -------(1)

Given that, Height of the tank h = 0.9 m

Pressure at the bottom of the tank P = 113 kPa

Patm = 1.013 * 10⁵ Pa

g = 9.8 m/s²

ρwater = 1000 kg/m³

ρoil = 900 kg/m³

Placing the values in the above equation,

t = (P - Patm - ρwater g * h)/ρoil g

t = (113* 10³ - 1.013 * 10⁵ - 10³* 9.8* 0.9 )/(900* 9.8)

⇒ (113* 10³ - 101.3* 10³ - 8.82* 10³)/(900* 9.8) = 2.88 * 10³/(900* 9.8)

⇒ 0.327 m

Thus, the thickness of the oil is found to be 0.327 m.

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When a ball of mass m elastically collides with mass 2m, momentum and kinetic energy are conserved.

We know that,

Momentum Conservation:

mv+ 0= m(va)+ 2m(vb)......(a)

m(v)=m(va+2vb)

=> v= va+ 2vb

We know that,(a+b)2=a2+b2+2ab

Then,

(va+2ab)2=va2+4ab2+4(va×vb)

Squaring both sides gives v2= va2+4vb2+4(va×vb).....(1)

Kinetic conservation of energy

mv2=mva2+2mvb2

v2=va2+2vb2.....(2

Subtracting 2 from 1 gives

vb=-2va

Substituting into (a), we get

v a=-v/3

v b=2v/3

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A block with mass 4 kg glides at a speed of 2 m/s across a horizontal, frictionless surface. By compressing a spring in its journey, it comes to rest.  The spring has a 0.2 m compress.

But when you exert force on the battery, the charged particles begin to function, transforming the potential energy into kinetic energy. Similar to this, when you turn on a light, the potential energy goes through your wiring and is transformed into light and heat, both of which are examples of kinetic energy.

Given that,

Block weight: 4 kg

Speed = 2 m/s.

400 N/m force constant; we must determine the distance.

The elastic potential energy of the spring is created from the kinetic energy of the block.

Kinetic energy and potential energy in relationship

1/2mv^2=1/2kx^2

x^2=mv^2/k

put the value into the formula

x^2= 4*2^2/400

x^2=.04

x= .2m

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Option E; The pump work, the power output of this plant is 335KW

Pressure. at turbine. inlet P1 = 10 Mpa.

Enthalpy at turbine inlet = h1=3625.84 KJ/kg.

Entropy at turbine inlet S1 =6.90 KJ/kg-K.

It is given that process performed acceording to ideal rankine cycle which is "Reversible adiabatic expansion' in case of turbine wor., Since it is reversible adiabatic expansion, entropy at turbine inlet and entropy at turbine outlet is constant. So quality at turbine outlet is evaluated by using this relation. S1 = S2.

Pressure at turbine outlet = 10 Kpa.

Enthalphy of steam = hg =2675.1 KJ/kg.

Enthaphy of liquid=hf =417.51 KJ/kg

Entropy of steam = Sg =7.3589 KJ/kg-K.

Entropy of liquid =Sf =1.302 KJ/kg-K.

We know S1 = S2 =6.090=1.302+x(7.3589 - 1.302).

Quality at turbine exit x =0.79.

Enthalphy at exit = h2 = 417.51+ 0.79*(2675.1 - 417.51) =2201 KJ/kg-K.

heat transfered= mass*(enthlphy at exit of condenser - enthalphy at turbine inlet), Since pump work negleted

At exit of condenser, steam gets converted into water at 10 Kpa pressure whose enthalphy is hf =417.51 KJ/kg.

800 = m(3625.84 - 417.51).

mass flow rate of steam = 0.24 Kg/sec.

Turbine work the power output of this plant is = m(h1 - h2) =0.24(3625.84 - 2201) = 335 KW.

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Tunneling is a variation of techniques used to achieve higher degrees of privacy for browsing on the internet. This is true.

The right to privacy is a fundamental component of human rights that also supports equality before the law and the freedoms of association, expression, and thought. But defining it is difficult. Different individuals and nations have various points of view. In general, the right to privacy includes the freedom from interference and invasion.

This acknowledges that each person has a domain of existence and activity that rightfully belonged to that person alone, where he or she ought to be unrestricted by coercion or even unwanted observation.

Packets can be moved between networks using tunneling. Encapsulation is how tunneling functions: A tunneling protocol in computer networks is a communication protocol that permits the transfer of data between networks. It entails using a technique called encapsulation to allow private network communications to be sent across a public network.

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Complete question

tunneling is a variation of techniques used to achieve higher degrees of privacy for browsing on the internet

true or false.

The minimum feeder ampacity of the given feeder with three motors with full load currents of 5A, 10A, and 15A is 18.75A.

Minimum Circuit Ampacity (MCA) is a value that specifies the minimum main power wire size. It is also used to decide the minimum wire size needed for a field-wired product.

This specification is needed to guarantee that the wiring will not overheat under the conditions that are operating. More accurately, we can say that the MCA is the highest steady-state electrical current that the unit can withstand when operating correctly.

MCA is found using the formula

MCA = 1.25 x Amperage value of feeder (here)

= 1.25× 15 A

= 18.75 A

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The new rotational inertia or final moment of inertia of the girl is I₀ / 4.

option D is the correct answer.

Rotational inertia is a property of any object which can be rotated.

Rotational inertia or moment of inertia of an object is a measure of the resistance of an object to changes in its angular velocity.

Based on the law of conservation of angular momentum, the formula for her new rotational inertia is given as;

I₀ω₀ = I₁ω₁

where;

The given parameters include,

initial angular velocity = ω₀

final angular velocity = 4ω₀

initial moment of inertia = I₀

The final moment of inertia of the girl is calculated as

I₁ = ( I₀ω₀ ) / (ω₁)

I₁ = ( I₀ω₀ ) / (4ω₀)

I₁ = I₀ / 4

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A 95% confidence interval for μA-μB is 0.025

If we want to make a 95% confidence interval estimate for an unknown population mean. This means that there is a 95% probability that the confidence interval will have the true population mean.

Thus, P( [sample mean] - margin of error < μ < [sample mean] + margin of error) = 0.95.

We have,

n1 = 12

s1 = 5000

mean x1 = 36300

n2= 12

s2 =6100

mean x2 =38100

We have to find 95%confidence interval for μA- μB

from 95% = 100 (1-α%)

     1-α = 0.95

    α = 1-0.95 =0.05

α/2 = 0.025

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The distance before it falls back to the earth is 8.5 * 103 km. Option B

We know that the escape velocity has to do with the velocity that has to be supplied to a material so that the material can be able to escape from the earth's gravitational pull. Let us recall that the whole earth is a large gravitational field. If we throw an object up then the object would have to certainly fall doen to the ground under the influence of gravity.

It is therefore clear that gravity is the force that draws any object that  goes upwards down back to the ground. Given that we have been told here that the speed is  one-half of the escape speed, then then the magnitude of the speed is 5590.3 m/s.

Given that;

v^2 = u^2 - 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

Then;

u^2 = 2gh

h = u^2/2g

h = ( 5590.3)^2/2 * 9.8

=  8.5 * 103 km

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