Assume the sample is a random sample from a distribution that is reasonably normally distributed and we are doing inference for a sample mean. Find endpoints of a t-distribution with 0.005 beyond them in each tail if the sample has size n

Answer:

im not sure about this one but my answer is 0.025.

Step-by-step explanation:

if there is a 1 out of 8 chance of getting a free burger,  convert that into 1/8. divide that by 5 and you get 0.025.

Answer:

n = 1

Step-by-step explanation:

Answer:

n = -4

Step-by-step explanation:

Let's solve your equation step-by-step.

−2(n − 6) = 20

Step 1: Simplify both sides of the equation.

−2(n − 6) = 20

(−2)(n) + (−2)(−6) = 20(Distribute)

−2n + 12 = 20

Step 2: Subtract 12 from both sides.

−2n + 12 − 12 = 20 − 12

−2n = 8

Step 3: Divide both sides by -2.

[tex]\frac{-2n}{-2} = \frac{8}{-2}[/tex]

n = -4

Hope this helps, please mark brainliest if possible. Have a great day.

[tex]30.87[/tex] ✅

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] \frac{926}{30} \\ = 30 \frac{26}{30} \\ ( \: or \: ) \\ = 30.8666 \\ = 30.87 [/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]

Answer:

[tex]Varianve = 3.842[/tex]

[tex]SD = 1.960[/tex]

Step-by-step explanation:

Given

See attachment for data

First, calculate [tex]\sum x^2[/tex]

[tex]\sum x^2 = 18^2 + 17^2 +20^2 + 19^2 + 20^2 + 16^2 + 16^2 + 15^2 + 18^2+14^2 +19^2 + 19^2+18^2+17^2 + 16^2+20^2+16^2+18^2+14^2+20^2[/tex]

[tex]\sum x^2 = 6198[/tex]

Calculate [tex]\sum x[/tex]

[tex]\sum x = 18 + 17 +20 + 19 + 20 + 16 + 16 + 15 + 18+14 +19 + 19+18+17 + 16+20+16+18+14+20[/tex]

[tex]\sum x = 350[/tex]

So, we have:

[tex]SS_x = \sum x^2 -\frac{(\sum x)^2}{n}[/tex]

[tex]SS_x = 6198 -\frac{350^2}{20}[/tex]

[tex]SS_x = 6198 -\frac{122500}{20}[/tex]

[tex]SS_x = 6198 -6125[/tex]

[tex]SS_x = 73[/tex]

Solving (a): The variance

[tex]Varianve = \frac{SS_x}{n-1}[/tex]

[tex]Varianve = \frac{73}{20-1}[/tex]

[tex]Varianve = \frac{73}{19}[/tex]

[tex]Varianve = 3.842[/tex]

Solving (b): The standard deviation

[tex]SD = \sqrt{Variance}[/tex]

[tex]SD = \sqrt{3.842}[/tex]

[tex]SD = 1.960[/tex]

Answer:

4/5 is ur answer

Step-by-step explanation:

ok just like the last one but this one is COS

ok so we know that COS is A/H

A= adjacent and ofc H= hypotenuse

so lets see its the COS of a which means it will be A/H

A= 4 and the H=5

Answer:

I. Radius, r = 2.90 cm

II. Height, h = 4.10 cm

Step-by-step explanation:

Given the following data;

Volume of cone = 24 cm³

To find the height and radius of the cup that will use the smallest amount of paper;

Mathematically, the volume of a cone is given by the formula;

[tex] V = \frac{1}{3} \pi r^{2}h[/tex]  ......equation 1

Where;

V is the volume of the cone.

r is the radius of the base of the cone.

h is the height of the cone.

Substituting into the formula, we have;

[tex] 36 = \frac{1}{3} \pi r^{2}h[/tex]

Multiplying both sides by 3, we have;

[tex] 108 = \pi r^{2}h[/tex]

Making radius, r the subject of formula, we have;

[tex] r^{2} = \frac {108}{ \pi h} [/tex]

Taking the square root of both sides, we have;

[tex] r = \sqrt { \frac {108}{ \pi h}} [/tex]

Mathematically, the lateral surface area of a cone is given by the formula;

[tex] LSA = \pi rl [/tex]  ......equation 2

Where;

r is the radius of a cone

l is the slant height of a cone.

To find the slant height, we would apply the Pythagorean' theorem;

[tex] l = \sqrt {r^{2} + h^{2}} [/tex]

Substituting r into the above equation, we have;

[tex] l = \sqrt {\frac {108}{\pi h} + h^{2}} [/tex]

Substituting the values of r and l into eqn 2, we have;

[tex] LSA = \pi * \sqrt { \frac {108}{ \pi h}} * \sqrt {\frac {108}{\pi h} + h^{2}} [/tex]

Simplifying further, we have;

[tex] LSA = \sqrt {108} * \sqrt { \frac {\pi h^{3} + 108}{\pi h}} [/tex]

[tex] LSA = \sqrt {108} * \sqrt { \frac {108}{ h^{2}} + \pi h}} [/tex]

Next, to find the value of h, we differentiate the above mathematical equation with respect to h;

[tex] \frac {dS}{dh} = \sqrt {108} * (\pi - \frac {216}{h^{3}}) * (\pi h + \frac {108}{h^{2}}) [/tex]

Limiting [tex] \frac {dS}{dh} [/tex] w.r.t 0;

[tex] \frac {dS}{dh} = 0 [/tex]

[tex] (\pi - \frac {216}{h^{3}}) = 0 [/tex]

Rearranging the equation, we have;

[tex] \pi = \frac {216}{h^{3}} [/tex]

We know that π = 3.142

[tex] 3.142 = \frac {216}{h^{3}} [/tex]

Cross-multiplying, we have;

[tex] 3.142h^{3} = 216 [/tex]

[tex] h^{3} = \frac {216}{3.142} [/tex]

[tex] h^{3} = 68.75 [/tex]

Taking the cube root of both sides, we have;

Height, h = 4.10 cm

Lastly, we find the value of r;

[tex] r = \sqrt { \frac {108}{ \pi h}} [/tex]

[tex] r = \sqrt { \frac {108}{3.142 * 4.10}} [/tex]

[tex] r = \sqrt { \frac {108}{12.88}} [/tex]

[tex] r = \sqrt {8.39} [/tex]

Radius, r = 2.90 cm

The height and radius of the cup that will use the smallest amount of paper is;

Radius = 2.52 cm

Radius = 2.52 cmHeight = 3.58 cm

Let us first state some relevant formulas;

Volume of a cone is;

V = ⅓πr²h

Surface area of a cone is;

S = πrL

Where L is Slant height and has a formula;

L = √(h² + r²)

We are told that the cone is to hold 24 cm³. Thus; V = 24 cm³

24 = ⅓πr²h

πr²h = 72

r = √(72/πh)

Putting √(72/πh) for r in the Slant height equation gives;

L = √(h² + (72/πh))

Thus;

S = π × √(72/πh) × √(h² + (72/πh))

Differentiating with respect to h gives;

dS/dh = √72 × (π - 144/h³) × 1/√(πh + 72/h²)

At dS/dh = 0,we will have;

(π - 144/h³) = 0

Thus;

h³ = 144/π

h = 3.58 cm

Thus, from r = √(72/πh);

r = √(72/(π × 3.58))

r = 2.52 cm

Read more at; https://brainly.com/question/4405937

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Answer:

  It satisfies both equations.

Step-by-step explanation:

The points on the graph of an equation are the values of the variables that satisfy the equation (make it true).

In a system of equations, you're generally looking for values of the variables that satisfy all of the equations in the system. That is, the solution will be a point on the graph of every equation in the system.

For a point to be on more than one graph, it must lie at a point of intersection of the graphs. If all of the graphs of a system go through the point of intersection, that point satisfies all of the equations, so is a solution of the system of equations.

Answer:

6 meters

Step-by-step explanation:

Area is length times width. If the width is 10 and the area is 60, then you would find 10 times ??? equals 60. Or 60 divided by 10. which is 6

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Answer:

  211

Step-by-step explanation:

Put the numbers where the variables are and do the arithmetic.

  b/2 +3c^2 = 38/2 +3(8^2) = 19 +3·64 = 211

Answer:

211

Step-by-step explanation:

given : b = 38 and c = 8

Evaluate :

= b/2 + 3c²

= 38 / 2 + 3 ( 8 )²

= 19 + 3 × 64

= 19 + 192

= 211

Answer:

-10

Step-by-step explanation:

See image below:)

Answer:

x = -10

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

Identify

-4/5x = 8

Step 2: Solve for x

9514 1404 393

Answer:

  30

Step-by-step explanation:

The sequence of square counts is ...

  170, 156, 142, 128

The differences from one row to the next are ...

  -14, -14, -14

We see that the differences are constant, so we know the sequence is an arithmetic sequence with first term 170 and common difference -14. This means the n-th term is ...

  an = a1 +d(n -1) . . . . . . for first term a1 and common difference d

  an = 170 -14(n -1)

For n=11, the number of squares is ...

  a11 = 170 -14(11 -1) = 30

There will be 30 squares in the 11th row.

Answer:

Invested at 11% : 3100

Invested at 6% : 3200

Step-by-step explanation:

let x= amount invested at 11%

let y= amount invested at 6%

we can write

Equation 1: x+y=6300

Equation2: .11x+.06y=533

Divide equation 2 by .06 to get

1.8333333x+y=8883.33333333

Subtract equation 2 from equation 1

.8333333x= 2583.33333333

x= 3100

Plug in x= 3100 into equation 1

3100+y= 6300

y= 3200

Answer:

The correct answer is - 332 pages.

Step-by-step explanation:

Given:

number of articles submissions - 75

number of pages in the yearbook on current plan = 156

pages required for two articles = 13 pages.

The number of pages to add = ?

Solution:

1 article takes pages in the yearbook = 13/2

= 6.5

the number of pages required for 75 articles = 75*6.5

= 487.5

The number of pages to add in the yearbook = 487.5 - 156

= 331.5 or 332.

Thus, the correct answer is - 332 pages.

Answer:

B)785.0 cubic inches

Step-by-step explanation:

amount of soup the pot can hold is equal to its volume

Volume of a cylinder is πr²h

π(5inches)²x 10inches

785.39816339744830

~785.0 cubic inches

Answer:

39

Step-by-step explanation:

Find the value of f(x) at both points

f(3) = 3(3)³ + 1 = 82

f(1) = 3(1)³ + 1 =  4

---------------------------

Average Rate of Change is just like slope

Divide the change in f(x) by the change in x

r = (82 - 4) / (3 - 1)

r = 78/2

r = 39

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Answer:

  103

Step-by-step explanation:

The sum of angles in a quadrilateral is 360°, so the measure of x° is ...

  x° = 360° -127° -90° -40° = 103°

  x = 103

Answer:

The measure of x is 103 °.

Step-by-step explanation:

Concept :- As we know that sum angles of quadrilateral is 360 ° so, to find the measure of x.

Firstly add all the angles that we have given and subtract from 360 ° and we get the vue of x.

We know that The sum angles of quadrilateral is 360 ° , Hence, value of x =

x + 127 ° + 90 ° + 40 ° = 360 °

x + 257 ° = 360 °

Subtract 257 ° from 360 °

x = 360 ° - 257 °

x = 103 °

Therefore, The measure of x is 103 °.

Answer:

y < [tex]\frac{1}{4} x+3[/tex]

Step-by-step explanation:

(-4, 2) (4, 4)

4 - 2 = 2

4 - - 4 = 8

slope = 1/4

y intercept is 3 because the inequality goes up 3 units

Answer:

30 cookies

Step-by-step explanation:

Reeba sells [tex]\frac{2}{3}[/tex] of [tex]3\frac{3}{4}[/tex] of 12 chocolate chip cookies.

Let us start by finding [tex]3\frac{3}{4}[/tex] of 12. We simply have to multiply the two numbers. However, it would be much easier if we had an improper fraction than a mixed number. Let us make [tex]3\frac{3}{4}[/tex]  an improper fraction first.

[tex]3\frac{3}{4} =\frac{15}{4}[/tex]

Ok! Let's multiply.

[tex]\frac{15}{4} *\frac{12}{1} =\\15*3\\=45[/tex]

Ok, Reeba baked 45 cookies in total. We know that she sells  [tex]\frac{2}{3}[/tex]  of her baked cookies, so we can again multiply the two numbers.

[tex]\frac{2}{3} *\frac{45}{1} =\\2*15=\\30[/tex]

Therefore, Reeba sold 30 cookies.

I hope this helps! Let me know if you have any questions :)

fine ,it is a A ok,I am sorry for using rude words on you

Answer:

hello

Step-by-step explanation:

a²+b²=c²

16²+b²=65²

256+b²=4225

b²=4225-256

b²=3969

[tex]b = \sqrt{3969}[/tex]

b=63

b=63 mi

have a nice day

Answer:

b = 63

Step-by-step explanation:

In a right angled triangle, hypotenuse squared is equal to the sum of the square of the other sides.

c² = a² + b² (where c is the hypotenuse, and a and b are the other two sides)

c =  65       , a = 16        b = ?

65² = 16² + b²

4225 = 256 + b²

4225 - 256 = b²

b² = 3969

b = [tex]\sqrt{3969}[/tex]

b = 63

check

c² = 16 ² + 63²

   = 256 + 3969

   = 4225

c = √4225

c = 65

Answer: 139.65 or 25.34.

Step-by-step explanation:

The revenue function will be:

= Price × Quantity

= P × (7,000 - 50p)

= 7000p - 50p²

The coat function is given as:

C = 2,000 + 25q

C = 2000 + 25(7000 - 50p)

C = 2000 + 175000 - 1250p

C = 177000 - 1250p

Then, we'll equate the revenue function to the cost function. This will be:

7000p - 50p² = 177000 - 1250p

-50p² + 7000p + 1250p - 177000 = 0

-50p² + 8250p - 177000 = 0

Divide through by -50

p² - 165 + 3540 = 0

Solving to get the value of P will then give us 139.65 or 25.34.

Answer: See explanation

Step-by-step explanation:

1. The average recovery time for all heart attack patients that the cardiologist has or will treat. = Parameter

2. All heart attack patients that the cardiologist has cared for or will care for in the future = Population.

3. The average recovery time for the 32 heart attack patients = Statistics

4. The 32 heart attack patients who were observed by the cardiologist = Sample

5. The list of all 32 heart attack patients' recovery times = Data

6. The recovery time for a heart attack patient. = Variable

Answer:

[tex]\% Low = 30 \%[/tex]

Step-by-step explanation:

Given

[tex]Total = 340g[/tex] -- missing

[tex]Low = 102g[/tex]

Required

% of sugar in Low

This is calculated as:

[tex]\% Low = \frac{Low}{Total} * 100\%[/tex]

So, we have:

[tex]\% Low = \frac{102g}{340g} * 100\%[/tex]

[tex]\% Low = \frac{102}{340} * 100\%[/tex]

[tex]\% Low = \frac{10200}{340} \%[/tex]

[tex]\% Low = 30 \%[/tex]

I hope this is help full to you

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Answer:

  (3)  12

Step-by-step explanation:

Let x represent the length of leg XY. Then the length of YZ is x/2 and the area  of the right triangle is ...

  A = 1/2bh

  A = 1/2(x)(x/2) = x²/4

  36 = x²/4 . . . . . use the given value for area

  144 = x² . . . . . . multiply by 4

  √144 = 12 = x . . . . . take the square root

The length of leg XY is 12 cm.

Answer:

67 f

Step-by-step explanation: