assume a corporation has cumulative voting and there are two directors up for election. what is the maximum number of votes a shareholder who owns 100 shares can cast for candidate jones if there are a total of 5 candidates?

When solving arithmetic expressions, Oracle 12c resolves addition and subtraction operations first from left to right in the expression. This statement is true.

By following these rules, Oracle 12c is able to resolve arithmetic expressions accurately and efficiently. This is particularly important when dealing with large amounts of data, where the correct order of operations is critical to ensure that the correct result is obtained.

Oracle 12c is a database management system that is used to handle large amounts of data. It has a variety of features that enable it to manage and maintain data effectively.

Oracle 12c has a SQL engine that allows it to execute SQL statements and expressions to retrieve and manipulate data.

When performing arithmetic operations in Oracle 12c, the order of operations is critical. The order of operations is the set of rules that dictate the sequence in which arithmetic operations should be performed in a mathematical expression.

These rules are also known as the rules of precedence.In Oracle 12c, the rules of precedence dictate that arithmetic operations should be resolved from left to right in an expression. This means that addition and subtraction operations should be resolved before multiplication and division operations.

This is because addition and subtraction operations have a lower precedence than multiplication and division operations. As a result, Oracle 12c always resolves addition and subtraction operations first from left to right in an expression .This order of operations ensures that the correct result is obtained when performing arithmetic operations in Oracle 12c.

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Answer:2.4 inches

Step-by-step explanation:

if 6 is for 30 feet, we can use a proportional statement to find what the length of the line will be for a room that is 12 feet.

Confidence interval = (y ± t∗s/√n)g1 = y - t*s/√ng2 = y + t*s/√n Substituting the values, g1 = 26.22 - 1.860*(0.11)/√9 = 25.84g2 = 26.22 + 1.860*(0.11)/√9 = 26.59Therefore, the statistics g1 and g2 that will satisfy the required inequality are 25.84 and 26.59 respectively.

The formula for finding the confidence interval is as follows: n − 1, where t is the value of the t-distribution corresponding to the specified confidence level and the sample size minus one.

As per the given exercise 7.11, suppose that in the forest fertilization problem the population standard deviation of basal areas is not known and must be estimated from the sample.

If a random sample of n = 9 basal areas is to be measured, find two statistics g1 and g2 such that p(g1 ≤ (y - u) ≤ g2) = 90

To find the statistics g1 and g2 that will satisfy the required inequality

the following formula can be used: Confidence interval = [tex](y ± t∗s/√n)[/tex]

From the formula, we can see that the confidence interval depends on the values of y, s, t and n.

The value of y is the sample mean

the value of s is the sample standard deviation

And the value of n is the sample size.

The value of t depends on the confidence level desired and the degrees of freedom for the t-distribution. In this case, the confidence level is 90%, which means that we want to find the value of t that will give us a total area of 0.90 under the t-distribution curve with 8 degrees of freedom .Using the t-table, the value of t can be found to be 1.860, where the value for 90% and 8 degrees of freedom is 1.860.t = 1.860Now, we need to calculate the value of s, which is the sample standard deviation.

Since we do not have any information about the population standard deviation, we will use the sample standard deviation as an estimate of the population standard deviations = σ/√nσ = s*√nσ = 0.11*√9σ = 0.33Substituting the values in the confidence interval formula

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The wave is polarized parallel to the y-axis, and the magnetic field lines are parallel to the x-axis. Here option D is the correct answer.

The oscillating electric dipole along the z-axis creates an electromagnetic wave with electric and magnetic fields perpendicular to each other and to the direction of wave propagation. At a position on the y-axis far from the origin, the electric field will be parallel to the y-axis.

The polarization of the wave refers to the orientation of the electric field vector. Since the electric field is parallel to the y-axis, the wave is polarized parallel to the y-axis.

According to the right-hand rule, the direction of the magnetic field lines will be perpendicular to both the electric field and the direction of wave propagation, which is along the z-axis. Therefore, the magnetic field lines will be parallel to the x-axis.

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Answer:

45 yo

Step-by-step explanation:

Let's start by defining some variables to represent the ages of Ted and Rosie:

- Let's call Ted's current age "T"

- Let's call Rosie's current age "R"

From the problem statement, we know that:

- Ted is five times as old as Rosie was when Ted was Rosie's age. Written as an equation, this becomes:

T = 5(R - (T - R))

Simplifying this equation, we get:

T = 5(R - T + R)

T = 10R - 5T

- When Rosie reaches Ted's current age, the sum of their ages will be 72. Written as an equation, this becomes:

R + T = 72 - T

We now have two equations with two variables. We can use substitution to solve for T.

Substitute the second equation into the first equation to eliminate R:

T = 10R - 5T

T = 10(72 - T) - 5T

T = 720 - 15T

16T = 720

T = 45

Therefore, Ted's current age is 45.

The statement that gives the most reasonable description of the distribution of quiz scores is "A typical score is within 1 point of the mean." The correct answer is Option D.

The standard deviation (SD) is a measure of the variability of data in a population. Standard deviation is a measure of how much each value differs from the mean (average) value of the data set.

The difference between the highest and lowest values in a dataset is known as the range. It's a quick way to see the data's spread. If the range is big, it implies that the data is more diverse, while if it's small, it implies that the data is more consistent.

The first quartile (Q1) is the value that splits the lowest 25% of a data set from the rest of the data set. If we order the dataset from smallest to largest, the first quartile is the value at the 25th percentile.

The third quartile (Q3) is the value that splits the highest 25% of a data set from the rest of the data set. If we order the dataset from smallest to largest, the third quartile is the value at the 75th percentile.

The sum of all values in a dataset divided by the total number of values in the dataset is known as the mean. The mean, often known as the arithmetic mean, is one of the most basic measures of central tendency in statistics.

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Answer:x=33/4096=0.008

Step-by-step explanation: 1.1     16 = 24

(16)3 = (24)3 = 212

Equation at the end of step

1

:

 ((212 • x) -  1) -  32  = 0

STEP

2

:

Equation at the end of step 2

 4096x - 33  = 0

STEP

3

:

Solving a Single Variable Equation:

3.1      Solve  :    4096x-33 = 0

Add  33  to both sides of the equation :

                     4096x = 33

Divide both sides of the equation by 4096:

                    x = 33/4096 = 0.008

Regardless of the appearance of the normal distribution or the size of the standard deviation, approximately less than 2.98% of observations consistently fall within two deviations types (one high and one low).

The normal distribution, also known as the Gaussian distribution, is a probability distribution symmetrical about the mean, indicating that data near the mean occurs more frequently than data far from the mean. In graphical form, the normal distribution is represented by a "bell curve".

The normal distribution is important in statistics and is often used in the natural and social sciences to represent real-valued random variables whose distribution is unknown. Their importance is partly due to the central limit theorem. It states that in some cases the mean of many samples (observations) of a random variable with finite mean and variance is itself a random variable - whose distribution converges to a normal distribution as the size of the l sample increases. Therefore, physical quantities assumed to be the sum of many independent processes, such as measurement errors, tend to have a near-normal distribution.

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There will be a population of 2,097,152 rabbits after 5 years.

A form of growth known as exponential growth occurs when a quantity's rate of expansion is proportionate to its present value. In other words, a quantity expands more quickly the greater it is. A prime example of exponential expansion is the rabbit population, which doubles in size every three months.

Given that, population of rabbits is doubling every 3 months.

That is,

5 years = 5 x 12 = 60 months

Number of doublings = 60 / 3 = 20

For every doubling, the population will be twice as large.

Thus,

P = 2 x 2²⁰ = 2 x 1,048,576 = 2,097,152 rabbits

Therefore, there will be approximately 2,097,152 rabbits after 5 years.

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Answer:

The answer is Nitrogen

Hope this helps :)

Answer:

[tex]\frac{-1}{3}[/tex]

Step-by-step explanation:

Look at the red slope triangle that is drawn. If you start at the point on the left, you go down 1 unit and then to the right 3 units.  This would be represented by -1/3.  Down would be negative and going right would be positive.  The slope is the rise over the run.

Helping in the name of Jesus.

All of the measures of central tendency and spread for these data will need to be changed from the original computations in order to reflect the correct values.

In this case, the initial set of scores was 4, 5, 8, 9, 11, 13, 15, 18, 18, 18, and 20. The teacher initially computed the mean, median, standard deviation, and IQR and then discovered that one of the 18s should have been a 16.The mean is affected by any change in the data, so this measure will need to be changed to reflect the correct values. The new mean is 73.The median is also affected by any change in the data, so this measure must be recalculated to reflect the correct values.

The new median is 15.5.The standard deviation measures the spread of data from the mean, so this measure must also be changed to reflect the correct values. The new standard deviation is 1.4.Finally, the IQR measures the spread of the middle 50% of the data, so this measure must also be changed to reflect the correct values. The new IQR is 6. All of the measures of central tendency will need to be changed.

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As per the combination method, the number of tickets that we put in that are marked "outer" is 3 (option d).

In this case, we want to choose the number of tickets marked "outer." Let's call this number k. We know that we already put one ticket marked "inner" in the box, so the total number of tickets in the box is 2. Therefore, n = 2.

Now we need to determine k. We want to know how many tickets we need to put in that are marked "outer." We can represent this as a. So we have:

ᵃC₁ = a! / ((1!)(a-1)!) = a

We want to find the value of a that satisfies the condition that the probability of choosing an "inner" ticket is 1/3 and the probability of choosing an "outer" ticket is 3/2.

Since we already put in 1 ticket marked "inner," the probability of choosing an "inner" ticket is 1/2, which means the probability of choosing an "outer" ticket is also 1/2.

We know that the probability of choosing an "outer" ticket is 3/2, so we can set up the following equation:

ᵃC₁ / 2 = 3/2

Solving for a, we get:

a = 3

In conclusion, the answer is (d) 3.

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Answer:

9

Step-by-step explanation:

-5 + (-18) +32

-23 + 32

32 -23

The sample mean is 1450g/cm², the standard deviation is 44.3 g/cm² and  the probability that, for a random sample of n = 10 test pieces of paper, x is greater than 1400 g/cm2 is 0.8708

a) The sampling distribution of the sample mean of n = 10 test pieces of paper is approximately normal with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size:

mean of sample mean = mean of population = 1450 g/cm²

standard deviation of sample mean = standard deviation of population / square root of sample size

= 140 g/cm2 / √(10)

= 44.3 g/cm²

Therefore, the sampling distribution of the sample mean is approximately normal with mean 1450 g/cm2 and standard deviation 44.3 g/cm2.

b) To find the probability that, for a random sample of n = 10 test pieces of paper, x is greater than 1400 g/cm2, we need to standardize the sample mean using the sampling distribution calculated in part (a):

z = (x - mean of sample mean) / standard deviation of sample mean

= (1400 - 1450) / 44.3

= -1.13

Using a standard normal distribution table or calculator, we can find the probability that z is less than -1.13 and subtract that probability from 1 to find the probability that z is greater than -1.13:

P(z > -1.13) = 1 - P(z < -1.13)

= 1 - 0.1292

= 0.8708

Therefore, the approximate probability that, for a random sample of n = 10 test pieces of paper, x is greater than 1400 g/cm² is 0.8708.

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Answer:

Multiplying the second equation by 5, we get:

15x + 20y = 180

Now, we can add this equation to the first equation:

26x = 208

x = 8

Substituting x = 8 in the second equation:

3(8) + 4y = 36

4y = 12

y = 3

Therefore, the solution to the system is (8, 3).

We need to use mathematical logic to prove that the cardinality of the cross product of two sets is the cardinality of each individual set multiplied by each other.

     Let's take an example of two sets A and B.

      Let's say, A={a, b} and B={1, 2, 3}

      To find the cardinality of the cross-product of A and B, we need to make all possible ordered pairs with A and B.

             {(a, 1), (a, 2), (a, 3), (b, 1), (b, 2), (b, 3)}

 Counting the number of ordered pairs, we get six.

  So, the cardinality of the cross-product of two sets A and B equals the cardinality of each set multiplied by the other. Here,

           |A| = 2 and |B| = 3,

          so |A x B| = 2 x 3

                           = 6.

          Therefore, it is proved that the cardinality of the cross product of two sets is the cardinality of each individual set multiplied by each other.

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The upper bound of a + b can be found by adding the upper bounds of a and b.

For a = 5cm, the nearest whole number is 5. The upper bound would be the midpoint between 5 and 6, which is 5.5.

For b = 3cm, the nearest whole number is 3. The upper bound would be the midpoint between 3 and 4, which is 3.5.

So the upper bound of a + b is:

5.5 + 3.5 = 9

Therefore, the upper bound of a + b is 9cm.

Answer: 12.84

Step-by-step explanation:

if x = 3.2 and y = 6.1  and Z = 0.2

then plug in the numbers

(3.2)(0.2) + (6.1)(2)

0.64 + 12.2 = 12.84

Any variable next to a number means multiplication.

if I was wrong lmk

The length, in feet, of BC is the square root of  √242 and, The length, in feet, of CF is the square root of √363

Cube:

In geometry, a cube is a three-dimensional solid object bounded by six faces, facets, or square sides, with three points of intersection at each vertex. Seen from a certain angle, it is a hexagon and its canvas is often represented by a cross.

Cube is the only regular hexahedron and one of the five Platonic solids. It has 6 faces, 12 edges and 8 vertices. Cube is also a cube, an equilateral cuboid, a rhombus and a 3-sonohedron.

Three orientations are square prisms and four orientations are triangular trapezoids. A cube is twice as large as an octahedron. It has cubic or octahedral symmetry. Cube is the only convex polyhedron whose faces are square.

Then the length CB is given by the Pythagorean theorem as:

CB = √(AC² +AB²)

     = √{(2 cm)² + (√2 cm)²}

     = √(4 +2) cm

CB = √6 cm

Now,

The length, in feet, of BC is the square root of  

√242

And,

The length, in feet, of CF is the square root of  

√363

Complete Question:

A cube. The top face has points C, A, B, D and the bottom face has points G, E, F, H. Diagonals are drawn from B to C and from C to F. Side B F is 11 feet.

What are the exact lengths of BC and CF?

The length, in feet, of BC is the square root of

The length, in feet, of CF is the square root of

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Answer:

The length, in feet, of BC is the square root of

✔ 242

The length, in feet, of CF is the square root of

✔ 363

Step-by-step explanation:

Answer:

Proofs attached to answer

Step-by-step explanation:

Proofs attached to answer

The greatest time that the fourth runner can run for the team to reach its goal is 63.23 seconds.

To find the greatest time that the fourth runner can run for the team to reach its goal, we need to subtract the total time of the first three runners from the goal time of 4 minutes (240 seconds).

Total time of the first three runners = 57.38 seconds + 60.92 seconds + 58.47 seconds = 176.77 seconds

Greatest time the fourth runner can run = Goal time - Total time of the first three runners = 240 - 176.77 = 63.23 seconds

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As per unitary method, the number of months would take her to break - even on the points purchase is 128

To break even on the points purchase, Jessie needs to recoup the cost of the point through the savings in her monthly mortgage payments. In this case, the cost of the point is 1% of the loan amount, which is $1,350.

To calculate the break-even point, we can use the following formula:

Break-even point = Cost of point / Monthly savings

In this case, the monthly savings is the difference between the original mortgage payment ($766.51) and the new mortgage payment with the point ($755.96), which is $10.55 per month.

Substituting the values, we get:

Break-even point = $1,350 / $10.55

Break-even point = 128 months

Therefore, it would take Jessie 128 months, or just over 10 years, to break even on the points purchase.

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Answer:

37

Step-by-step explanation:

we know that:

C=?

c=17

b=26

a=14

using the law of cosine:

[tex]a^{2} +b^{2} -2ab Cosc=c^{2}[/tex]

[tex]14^{2} +26^{2} -2(14)(26)Cosc=17^{2} \\872-728Cosc=289\\-728Cosc=-583\\Cosc=\frac{-583}{-728} \\C=36.791\\C=37[/tex]

We have established that the answer to the equation,  [tex]x = 24/7[/tex] , is that the left side equals the right side.

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation [tex]3x + 5 = 14[/tex]  consists of the two equations  [tex]3x + 5[/tex] and 14, which are separated by the 'equal' sign.

The equation is as follows:

[tex]\frac{1}{2}\times (x-2)+ 1+2/3x-3[/tex]

This equation can be made simpler by first merging like terms:

[tex]\frac{1}{2}\times (x-2)+ 1+2/3x-3[/tex]

[tex]= 1/2x + 2/3x - 4[/tex]

[tex]= 7/6*x - 4[/tex]

As a result, the equation becomes [tex]7/6*x - 4 = 0.[/tex]

We can now get the value of x by multiplying both sides by 6/7 after adding 4 on both sides: [tex]7/6*x = 4 x = 24/7.[/tex]

We rewrite the original equation with x = 24/7 to confirm the solution:

[tex]1/2*(24/7-2)+1+2/3(24/7)-3[/tex]

[tex]= 1/2*(10/7)+1+16/21-3[/tex]

[tex]= 5/7+1-2/3[/tex]

[tex]= 6/7[/tex]

Therefore, 6/7 demonstrates the equality.

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They can present in 96 different orders. Given, there are five student groups to present in class and one group cannot go first because they need additional set-up time.

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

We have 5 positions to fill here.

First position: 4 ways (one of the rest 4 groups will present first)

Second position: 4 ways (one of the rest 3 groups and the group which could not present first, will present second)

Third position: 3 ways (one of the rest 3 groups will present third)

Fourth position: 2 ways (one of the rest 2 groups will present fourth)

Fifth position: 1 way (rest group will present last)

Total ways in which they can present = 4*4*3*2*1 = 96

Hence, the answer is 96.

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Answer:

Pretty sure its C

Step-by-step explanation:

To cut through y axis, x axis is always 0, So it would be (0, a) where a is any real number, not (a,0) as is given in reason.

In the given scenario, the average current produced within the loop is approximately 2.13 A.

We can begin by computing the change in magnetic flux across the loop as it expands to determine the average current generated within the loop.

The following equation provides the magnetic flux across a loop:

Φ = B * A * cos(θ)

ΔΦ = B * ΔA

ΔA = A₂ - A₁ = π * (1.00 m)² - π * (0.40 m)² = π * (1.00² - 0.40²) = π * (1.00 + 0.40)(1.00 - 0.40) = π * (1.40)(0.60) = 0.84π m²

So,

ΔΦ = B * ΔA = (24 mT) * (0.84π m²) = 20.25π m²·T

emf = ΔΦ / Δt = (20.25π m²·T) / (1.0 s) = 20.25π V

As:

emf = I * R

So, again

I = emf / R = (20.25π V) / (30 Ω) ≈ 2.13 A

Thus, the average current produced within the loop is approximately 2.13 A.

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Answer:

Step-by-step explanation:

You want the measures of AO and DO in a trapezium in which AB║CD, the diagonals intersect at O, and AB = 3 cm, CD = 6 cm, CO = 4 cm, OB = 3 cm.

Diagonal AC is a transversal to parallel lines AB and CD, so alternate interior angles BAO and DCO are congruent. Vertical angles AOB and COD are also congruent, so ∆ABO ~ ∆CDO by the AA similarity postulate.

This means the side lengths are proportional, so ...

  AB/CD = AO/CO = BO/DO

  3/6 = AO/4 = 3/DO   ⇒   AO = 2, DO = 6

The measures of AO and DO are 2 cm and 6 cm, respectively.

__

Additional comment

It can help to draw a diagram.

The error bound for the 95% confidence interval is (1.96 x Standard Deviation/√n), which in this case is (1.96 x 11/√50) = 2.56. This means that the true mean weight of newborn elephant calves lies within +/-2.56 pounds of the interval range.

The 95% confidence interval for the population mean weight of newborn elephants can be calculated using the sample mean of 244 pounds and the sample standard deviation of 11 pounds. The confidence interval is calculated using the following formula:
Confidence Interval = (Mean - (1.96 x Standard Deviation/√n)), (Mean + (1.96 x Standard Deviation/√n))
Where n is the sample size.
Therefore, the 95% confidence interval for the population mean weight of newborn elephants is (231.14, 256.86).
This can also be represented in a graph. The graph would have the x-axis representing the confidence interval, with a range from 231.14 to 256.86, and the y-axis representing the probability, which would be 0.95.

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