Answer:
$4,562.5
Step-by-step explanation:
The amount Arvin has to invest, P = $10,000
The interest paid on the investment in the term deposit = 5%/year
The interest paid om the investment in Canada savings bonds = 3.4%/year
The amount Arvin earned at the of the year as simple interest, A = $413
Let, x, represent the amount Arvin invested in the term deposit and let, y, represent the amount he invested in Canada savings bonds, we can get the following system of equations
x + y = 10,000...(1)
0.05·x + 0.034·y = 413...(2)
Making y the subject of equation (1) and substituting the value in equation (2), we get;
From equation (1), we get, y = 10,000 - x
Plugging the above value of y in equation (2) gives;
0.05·x + 0.034 × (10,000 - x) = 413
∴ 0.05·x - 0.034·x + 340 = 413
x = (413 - 340)/(0.05 - 0.034) = 4,562.5
Therefore, the amount Arvin invested in the term deposit at 5%, x = $4,562.5
(y = 10,000 - x
∴ y = 10,000 - 4,562.5 = 5,437.5
The amount Arvin invested in Canada savings bonds, y = $5,437.5.)
I'LL GIVE BRAINLIEST !!! FASTERR !
Answer:
Option A, 86°
Step-by-step explanation:
each diagonals of a rhombus divides the angles at half, so a+b+c+d = 360°/2 = 180°
now, a+b+c+d-94° = 180°-94° = 86°
Answer:
D 266°
Step-by-step explanation:
a+b+c+d-94°
90°+ 90°+ 90°+ 90° -94°
360°-94°
266°
The slope of two lines are - 3/2 and 18/a. Determine the value of α that will make the lines:
a) parallel
b) perpendicular
Answer:
a) a=-12
b) a=27
Step-by-step explanation:
a) parallel lines have = slopes SO
-3/2 = -3/2
-3/2 = 18/a
-3a/2 = 18
-3a = 18 * 2 = 36
a = -12
b) perpendicular lines have negative inverse slopes SO
- 3/2 ---> 2/3
2/3 = 18/a
2a/3 = 18
2a = 18 * 3 = 54
a = 54/2 = 27
NOW ASAP I NEED HELP ON THIS FAST PLEASEEEEEEEEEEEEE
Answer:
fourth time ...
same problem...
the red line crosses a corner of a box at (4,20) and (2,10)
20/4 = 5
and
10/2 = 5
the slope , constant, gradient for this relationship is "5"
Step-by-step explanation:
What is the estimated value of 2v12 . 3V5 / V30 . V36
Answer:
the correct answer is b and I know this because I just had it
find the derivative of y=x²+3x
Answer:
[tex]\frac{dy}{dx}[/tex] = 2x + 3
Step-by-step explanation:
Differentiate each term using the power rule
[tex]\frac{d}{dx}[/tex] (a[tex]x^{n}[/tex] ) = na[tex]x^{n-1}[/tex]
y = x² + 3x
[tex]\frac{dy}{dx}[/tex] = 2[tex]x^{(2-1)}[/tex] + 3[tex]x^{(1-1)}[/tex]
= 2x + 3[tex]x^{0}[/tex]
= 2x + 3
Solve the following given problem
Answer:
The radius is 3.5cm
Step-by-step explanation:
Given
[tex]V = 192.5cm^3[/tex]
[tex]h = 5cm[/tex]
Required
The volume (V)
The volume of the vase is:
[tex]V = \pi r^2h[/tex]
So, we have:
[tex]192.5 = 22/7 * r^2 * 5[/tex]
Divide by 5
[tex]38.5 = 22/7 * r^2[/tex]
Multiply by 7/22
[tex]12.25= r^2[/tex]
Take positive square roots
[tex]r = 3.5[/tex]
Write an equation in standard form of the line that passes through the given point and has the given slope (-8,0); m= -4 PLEASE HELP NEED DONE ASAP WILL GIVE BRAINLIEST
Answer:
4x+y=-32
Step-by-step explanation:
given,
slope (m) = -4
point: (-8,0)
as we know the slope intercept form of the line is, y=mx+b, b=y-mx, now we put x=-8, y=0 to find b [because the point is given (-8,0) so it must satisfy the equation]
so,
b = 0-(-4)×(-8) = -32
y=mx+b
or, y=-4x-32
or, 4x+y=-32
(this is the standard form of the line)
Using the equation y - y1 = m(x - x1)
y - 0 = -4(x - (-8))
y = -4(x + 8)
y = -4x - 32
one class collects 8 1/4 pounds of recyclable materials. Another class collects 1 1/2
Step-by-step explanation:
what to find then??.........
What does x equal? Dpsewbskdye
Answer:
x = 7
Step-by-step explanation:
27 = 7x + 6 - 4x (Given)
27 = 3x + 6 (Simplify)
27 - 6 = 3x + 6 - 6 (Subtract 6 on both sides)
21 = 3x (Simplify)
21/3 = 3x/3 (Divide 3 on both sides)
7 = x (Simplify)
-x/c=6.5
I need to solve for x first then c
Answer:
[tex]x = -6.5c[/tex]
[tex]c = -\frac{x}{6.5}[/tex]
Step-by-step explanation:
In both cases, you are simply isolating the variable you are trying to solve for:
[tex]\frac{-x}{c} = 6.5[/tex]
Solve for x. Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. First, multiply c to both sides, and then divide -1 from both sides:
[tex]\frac{-x}{c} = 6.5\\\frac{-x}{c} * c = 6.5 * c\\-x = 6.5c\\\frac{-x}{-1} = \frac{6.5c}{-1}\\x = -6.5c[/tex]
Solve for c. Isolate the variable, c. Note the equal sign, what you do to one side, you do to the other. Multiply -1/x to both sides of the equation:
[tex]\frac{-x}{c} = 6.5\\\frac{-x}{c}(c)) = 6.5(c) \\-x = 6.5c\\\frac{-x}{6.5} = \frac{6.5c}{6.5}\\c = -\frac{x}{6.5}[/tex]
Answer:
x = -6.5c
-x/6.5 = c
Step-by-step explanation:
-x/c=6.5
Multiply each side by -c
-x/c * -c=6.5*-c
x = -6.5c
-x/c=6.5
Multiply each side by c
-x/c *c=6.5*c
-x = 6.5c
Divide each side by 6.5
-x/6.5 = 6.5c/6.5
-x/6.5 = c
Can anyone plz solve this question step by step ASAP!
Answer:
40√3 cm²Step-by-step explanation:
Step 1
Find the height:
h² = 8² - (12 - 8)²h² = 64 - 16 = 48h = √48 = 4√3Step 2
Find the area:
A = 1/2(a + b)hA = 1/2(12 + 8)(4√3) = 40√3 cm²Find the perimeter of the polygon
Answer:
Answer 60
Step-by-step explanation:
The distance from an exterior point to the incircle is equal to the tangent length in both cases.
So the 19 is made up of 9 and 10.
The length of the other portion of the tangent from the end of 19 to the tangent point on the right is also 10.
By a similar argument the lower length of the line to the tangent point is 11.
So you have
9 + 9 + 10 + 10 + 11 + 11
18 + 20 + 22 = 60.
Solve the square of this equation with explanation as I don’t understand please
===========================================================
Explanation:
Cut the x coefficient (10) in half to get 10/2 = 5. Then square this to get 5^2 = 25.
We'll add 1 to both sides so that the "24" turns into "25", thereby completing the square
x^2 + 10x + 24 = 0
x^2 + 10x + 24+1 = 0+1
x^2 + 10x + 25 = 1
Notice on the left hand side we have something of the form A^2+2AB+B^2 where A = x and B = 5. We can factor this into (A+B)^2, which is the whole reason why we completed the square. You can use the FOIL rule to see how (A+B)^2 expands out into A^2+2AB+B^2. Factoring reverses this process.
This means x^2+10x+25 factors to (x+5)^2 and we now have these steps
(x+5)^2 = 1
x+5 = sqrt(1) or x+5 = -sqrt(1)
x+5 = 1 or x+5 = -1
x = 1-5 or x = -1-5
x = -4 or x = -6 are the two solutions
------------------
Let's check x = -4 to see if it works or not
x^2 + 10x + 24 = 0
(-4)^2 + 10(-4) + 24 = 0
16 - 40 + 24 = 0
-24 + 24 = 0
0 = 0
We get a true equation. That confirms x = -4 is a solution.
If we tried x = -6, then,
x^2 + 10x + 24 = 0
(-6)^2 + 10(-6) + 24 = 0
36 - 60 + 24 = 0
-24 + 24 = 0
0 = 0
That x value is confirmed as well.
Evaluate Equation
Please Help Me!!
Answer:
C
Step-by-step explanation:
7+(-4x^2) where x=0, 7+0=7
Answer:
C. 7
Step-by-step explanation:
[tex]7+(-4x^2)[/tex]
Replace x with 0
[tex]7+(-4(0)^2)[/tex]
0 squared is 0. -4 times 0 is also 0.
7+0=7
I hope this helps!
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!
Answer:
a. (0,-5)
Step-by-step explanation:
10.
Define an operation ★ on the set of real numbers as follows:
a ★ b = 0.5ab
If 0.1 ★ b = 10, then evaluate bb.
a. 500
b. 200
c. 20
d. 50
Please explain how you got your answer.
If a ★ b = 0.5ab, then
0.1 ★ b = 0.5 (0.1) b = 0.05b = 10
==> b = 10/0.05 = 200
if x^2=y^2+z^2
what does x equal?
Answer:
[tex]\displaystyle x = \sqrt{y^2 + z^2}[/tex]
General Formulas and Concepts:
Pre-Algebra
Equality PropertyAlgebra i
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle x^2 = y^2 + z^2[/tex]
Step 2: Solve for x
[Equality Property] Square root both sides: [tex]\displaystyle x = \sqrt{y^2 + z^2}[/tex]Please help simple alebgra! Write an equation representing the translation of f(x) = 7x + 3 down 4 units.
Will mark brainliest!
9514 1404 393
Answer:
g(x) = 7x -1
Step-by-step explanation:
The y-coordinate of a function tells how many units the function value lies above the x-axis. Translating that value down 4 units is the same as subtracting 4 from the function value.
g(x) = f(x) -4
g(x) = 7x +3 -4
g(x) = 7x -1
simple geometry problem i cant understand
Answer:
23.5
Step-by-step explanation:
m∠Y = (m∠RTS - m∠VTX)/2
m∠Y = ((180 - m∠RTV) - (180 - m∠VTX))/2
m∠Y = ((180 - 95) - (180 - 142))/2
m∠Y = (85 - 38)/2
m∠Y = 47/2
m∠Y = 23.5
Heyyy could someone please help me out?? Would appreciate it. Thanks in advance!!^^
Answer:
Below,...
Step-by-step explanation:
They are saying that if you add a odd number + a odd number than you'd get a even number,... odd + even = odd,... odd x even = even,... and so on,...
Hope it helps,... Chow!
3. JK is tangent to circle L. Find JL to two decimal places.
Answer:
14.32
Step-by-step explanation:
Since this is a right triangle, we can us the Pythagorean theorem
a^2 + b^2 = c^2
3^2 + 14^2 = JL ^2
9+196 = JL ^2
205 = JL ^2
Taking the square root of each side
sqrt(205) = JL
14.31782106 = JL
To 2 decimal places
14.32
Solve for the measure of angle QSR, given b=136.
The calculated measure of the angle QSR is 68 degrees
How to solve for the measure of angle QSRFrom the question, we have the following parameters that can be used in our computation:
Angle b = 136 degrees
The measure of angle QSR can be calculated using
QSR = 1/2 * Angle b
substitute the known values in the above equation, so, we have the following representation
QSR = 1/2 * 136 degrees
Evaluate
QSR = 68 degrees
Hence, the measure of angle QSR is 68 degrees
Read more about angles at
https://brainly.com/question/31898235
#SPJ1
Martina bought 19 pounds of sugar for $10. How many pounds of sugar did she get per dollar?
Answer:
1.9 poundsStep-by-step explanation:
To solve this divide the amount of sugar by the number of dollars:
19 pounds / 10 dollars = 1.9 pounds per dollarPer 10dollar she brought=19pounds
Per dollar
[tex]\\ \sf\longmapsto \dfrac{19}{10}[/tex]
Write in decimals[tex]\\ \sf\longmapsto 1.9pounds[/tex]
7.
Explain why the equation 6|x| + 25 = 15 has no solution.
When one solves, they arrive at a step where |x| is equal to a fraction that may not be represented as an integer. Since | x| must be an integer, there is no solution.
When one solves, they arrive at a step where x is equal to a negative number. Since x can never be negative inside of the absolute value bars, there is no solution.
When one solves, they arrive at a step where |x| is equal to a negative number. Since | x| can never be negative, there is no solution.
The statement is false. There is a solution.
Answer:
When one solves, they arrive at a step where |x| is equal to a negative number. Since | x| can never be negative, there is no solution.
Step-by-step explanation:
6|x| + 25 = 15
Subtract 25 from each side
6|x| + 25-25 = 15-25
6|x| = -10
Divide by 6
6|x| /6 = -10/6
|x| = -5/3
There is no solution because the absolute value must be greater than or equal to zero. This equation has it negative.
the product of 7 and the quotient of 40 divided by 5 is
The quotient of 40 and 5
40÷5=8
=> Product of that number with 7 and 8
So number to find is : 7x8=56
The product of 7 and the quotient of 40 divided by 5 is 56.
What is the quotient?The quotient is the result which is derived by the division of two numbers.
For example, the quotient of 30 divided by 3 is 10.
What is the product of two numbers?The product is the multiplication of two numbers which is written as a*b.
For example, the product of 8 and 9 is 72.
Here given we have to calculate the product of 7 and the quotient of 40 divided by 5.
The quotient of 40 divided by 5 is 40/5= 8
The product of 7 and The quotient of 40 divided by 5= 7*8= 56
Therefore the product of 7 and the quotient of 40 divided by 5 is 56.
Learn more about quotient
here: https://brainly.com/question/673545
#SPJ2
Please Help
The students in a high school are being randomly split into focus and accountability groups that meet each morning for the first fifteen minutes of the school day. Each group contains four students, selected regardless of gender or grade level.
In order to explore the composition of the groups with regard to grade level, you have decided to conduct a simulation using colored discs. Since the number of students in each grade level is about the same, you put the same number of four different colored discs in a bag: red, blue, green, and yellow. You decide that red (r) represents the freshmen, blue (b) represents the sophomores, green (g) represents the juniors, and yellow (y) represents the seniors.
Next, you randomly select one disc from the bag, record the color, and put the disc bag in the bag. You do the same thing three more times to represent one group. Then, you complete this entire process twenty-five times, as shown below.
Based on the results of the simulation, the chances of a group having at least one senior is:
likely
unlikely
neither unlikely or likely
19/25 which is likely
count the ones with y and put that over 25
Same promblem as first but different angles
If two parallel lines are intersected by a transversal, then internal opposite angles are equal.
So, x° = 61°
=> x = 60
Because they are internal opposite angles.
f(x) = Square root of quantity x plus seven. ; g(x) = 8x - 11 Find f(g(x)). (1 point)
f(g(x)) = 2 Square root of quantity two x plus one
f(g(x)) = 8 Square root of quantity x plus seven - 11
f(g(x)) = 8 Square root of quantity x plus four
f(g(x)) = 2 Square root of quantity two x minus one
Answer:
2 sqrt(2x-1)
Step-by-step explanation:
f(x) = sqrt(x+7)
g(x) = 8x-11
f(g(x))=
Place g(x) in for x in the function f(x)
f(g(x)) = sqrt( 8x-11 +7)
= sqrt( 8x -4)
Factor out 4
= sqrt( 4(2x-1)
= 2 sqrt(2x-1)
[tex]\\ \sf\longmapsto f(x)=\sqrt{x+7}[/tex]
[tex]\\ \sf\longmapsto g(x)=8x-11[/tex]
g(x) will be put on the place of x[tex]\\ \sf\longmapsto f(g(x))=\sqrt{8x-11+7}[/tex]
[tex]\\ \sf\longmapsto f(g(x))=\sqrt{8x-4}[/tex]
[tex]\\ \sf\longmapsto f(g(x))=\sqrt{4(2x-1)}[/tex]
[tex]\\ \sf\longmapsto f(g(x))=2\sqrt{2x-1}[/tex]
HELPPPPPPPPP!!!!!!!!!!!!!!!!
Answer:
they are not similar. their one angle is only equal
Convert 75 mg into gram
Answer:
[tex]{ \tt{1 \: mg = 1 \times {10}^{ - 3} \: g}} \\ { \tt{75 \: mg = (75 \times 1 \times {10}^{ - 3} ) \: g}} \\ { \bf{ = 75 \times 10 {}^{ - 3} \: grams}} \\ { \bf{ = 0.075 \: grams}}[/tex]
