An organization is planning to implement a VPN. They want to ensure that after a VPN client connects to the VPN server, all traffic from the VPN client is encrypted. Which of the following would BEST meet this goal?a. Split tunnelb. Full tunnelc. IPsec using Tunnel moded. IPsec using Transport mode

Answer:

Processor P2 has the highest performance expressed in instructions per second.

Explanation:

Given:

Processors:

P1

P2

Clock rate of P1 = 3 GHz

Clock rate of P2 = 3 GHz

Cycles per instruction = CPI of P1 = 1.5

Cycles per instruction = CPI of P2 = 1.0

To find:

which processor has the highest performance in instructions per second (IPS)

Solution:

Compute CPU time:

CPU time =  (Number of instructions * cycles per instruction) / clock rate

CPU time = (I * CPI) / R

We are given the CPI and clock rate. So

CPU time = (I * CPI) / R

 I / CPU time = R/CPI

Since

Instructions per second = Number of instructions (I) / execution time

                             IPS     = I / CPU time

So

Instructions Per Second = clock rate / cycles per instruction

IPS = R/CPI

Putting the values in above formula:

Instructions Per Second for P1 = IPS (P1)

                                                  = clock rate P1 / CPI (P1)

                                                  = 3 GHz / 1.5

                                     IPS (P1) = 2            

As 1 GHz = 10⁹ Hz

IPS (P1) = 2x10⁹

Instructions Per Second for P2 = IPS (P2)

                                                  = clock rate P2 / CPI (P2)

                                                  = 3 / 1.0

                                     IPS (P2) = 3

As 1 GHz = 10⁹ Hz

IPS (P2) = 3x10⁹

Hence processor P2 has the highest performance expressed in instructions per second i.e. 3x10⁹

Answer:

c. Cartography.

Explanation:

Cartography is the science and art of making an illustrated map or chart. Geographic information system (GIS) allows users to interpret, analyze, and visualize data in different ways that reveal patterns and trends in the form of reports, charts, and maps.

Basically, cartography is the science and art of depicting a geographical area graphically, mostly on flat surfaces or media like maps or charts. It is an ancient art that was peculiar to the fishing and hunting geographical regions. Geographic information system is an improved and technological form of cartography used for performing a whole lot of activities or functions on data generated from different locations of the Earth.

Answer:

C. Cartography

Explanation:

Answer:

x = 5, the data type is integer( integer data type is for whole numbers)

2. The data type is string

3. The data type is float (float data type is for decimals)

Explanation:

Answer:

Answered below

Explanation:

Deep packet inspection is a kind of data processing that thoroughly inspects data sent over a computer network and acts on it by rerouting, logging or blocking it. Uses of DPI include;

To ensure that data is in the correct format, internet censorship, to check for malicious code, and also eavesdropping.

DPI uses port mirroring and optical splitter to acquire packets for inspection. It combines the functionality of an intrusion detection system and intrusion prevention system with a traditional stateful firewall.

DPI is therefore helpful in perimeter security by keeping unauthorized users out and at the same time protecting authorized users from attack. Privacy concerns have been raised over the inspection of content layers of internet protocols such as in the case of censorship and government regulations and control.

Answer:

You'll need dual monitor cables and an adapter.

Explanation:

First Step

Position your monitors on your desk or workspace. Make sure the systems are off.

Second Step

Make sure your power strip is close by. Then plug your power strip and connect the first monitor to your PC via your HDMI

Use an adapter to do the same for the second monitor.

Turn the entire system on

Third Step

On your PC, right click on a blank place in your home screen and click on Display Settings.

If you want to have two separate displays showing the same thing, select Duplicate, but if you want to have the two displays independent of each other, select Extend Display.

Apply the settings and select Done.

Answer:

The technician should either provide a route from the user's IP scheme to the printer or change the user's IP scheme to be within the same scheme as the printer.

Explanation:

The most likely reason the user is unable to print to the printer is that the user's computer cannot path the current address to the address of the printer.  Without the printer being on the same subnet as the user's computer, the computer has no way of being able to tell where the printer is.

The two solutions to this are to either add a route to the user's computer explicitly telling the user's computer where to trace to find the printer or to change the user's computer to match the IP scheme of the printer.

Cheers.

Answer:

A true

Explanation:

Speeding leads to an increase in the degree of crash severity, possibly resulting in more fatalities or injuries. More damage is caused to the vehicles involved at higher speeds, increasing likelihood vehicle will not be drivable after a crash.

The statement "Speeding is one of the most prevalent factors contributing to traffic crashes" is true.

Speeding causes crashes to be more severe, which could lead to more fatalities or injuries. Higher speeds result in more damage to the involved vehicles, increasing the risk that the vehicle won't be drivable following a collision. There are many accidents increasing because of high speed.

The term "speeding" refers to moving or traveling swiftly. He paid a penalty for speeding. For many American drivers, speeding has become the standard, whether it is going over the posted speed limit, driving too quickly for the road conditions, or racing. Nationwide, speeding contributes to road fatalities.

Therefore, the statement is true.

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Answer:

Communication

Collaboration

ICT literacy

Explanation:

These are some of the skills that are needed in the 21st century to compete and thrive in the information society.

To remain progressive, one needs to have good communication skills. These communication skills can include Active Listening and Passive Listening.

Collaboration is important because you'll have to work with other people as no man is an island, we need someone else so the skill of collaboration is necessary to compete and stay relevant in the information society in the 21st century.

IT literacy is also very important because one needs to have basic computer knowledge such as programming, computer essentials and applications, etc.

Answer:

1)

for(i = 0; i < NUM_VALS; ++i) {

  if(userValues[i] == matchValue) {

     numMatches++;  }    }

2)  

for (i = 0; i < NUM_GUESSES; i++) {

      scanf("%d", &userGuesses[i]);   }

  for (i = 0; i < NUM_GUESSES; ++i) {

         printf("%d ", userGuesses[i]);    }

3)

sumExtra = 0;

for (i = 0; i < NUM_VALS; ++i){

     if (testGrades[i] > 100){  

        sumExtra = testGrades[i] - 100 + sumExtra;    }       }

4)

for (i = 0; i < NUM_VALS; ++i) {

    if (i<(NUM_VALS-1))  

   printf( "%d,", hourlyTemp[i]);

    else  

    printf("%d",hourlyTemp[i]); }      

Explanation:

1) This loop works as follows:

1st iteration:

i = 0

As i= 0 and NUM_VALS = 4 This means for condition i<NUM_VALS  is true so the body of loop executes

if(userValues[i] == matchValue) condition checks if element at i-th index position of userValues[] array is equal to the value of matchValue variable. As matchValue = 2 and i = 0 So the statement becomes:

userValues[0] == 2

2 == 2

As the value at 0th index (1st element) of userValues is 2 so the above condition is true and the value of numMatches is incremented to 1. So numMatches = 1

Now value of i is incremented to 1 so i=1

2nd iteration:

i = 1

As i= 1 and NUM_VALS = 4 This means for condition i<NUM_VALS  is true so the body of loop executes

if(userValues[i] == matchValue) condition checks if element at i-th index position of userValues[] array is equal to the value of matchValue variable. As matchValue = 2 and i = 1 So the statement becomes:

userValues[1] == 2

2 == 2

As the value at 1st index (2nd element) of userValues is 2 so the above condition is true and the value of numMatches is incremented to 1. So numMatches = 2

Now value of i is incremented to 1 so i=2

The same procedure continues at each iteration.

The last iteration is shown below:

5th iteration:

i = 4

As i= 4 and NUM_VALS = 4 This means for condition i<NUM_VALS  is false so the loop breaks

Next the statement: printf("matchValue: %d, numMatches: %d\n", matchValue, numMatches);  executes which displays the value of

numMatches = 3

2)

The first loop works as follows:

At first iteration:

i = 0

i<NUM_GUESSES is true as NUM_GUESSES = 3 and i= 0 so 0<3

So the body of loop executes which reads the element at ith index (0-th) index i.e. 1st element of userGuesses array. Then value of i is incremented to i and i = 1.

At each iteration each element at i-th index is read using scanf such as element at userGuesses[0], userGuesses[1], userGuesses[2]. The loop stops at i=4 as i<NUM_GUESSES evaluates to false.

The second loop works as follows:

At first iteration:

i = 0

i<NUM_GUESSES is true as NUM_GUESSES = 3 and i= 0 so 0<3

So the body of loop executes which prints the element at ith index (0-th) index i.e. 1st element of userGuesses array. Then value of i is incremented to i and i = 1.

At each iteration, each element at i-th index is printed on output screen using printf such as element at userGuesses[0], userGuesses[1], userGuesses[2] is displayed. The loop stops at i=4 as i<NUM_GUESSES evaluates to false.

So if user enters enters 9 5 2, then the output is 9 5 2

3)

The loop works as follows:

At first iteration:

i=0

i<NUM_VALS is true as NUM_VALS = 4 so 0<4. Hence the loop body executes.

if (testGrades[i] > 100 checks if the element at i-th index of testGrades array is greater than 100. As i=0 so this statement becomes:

if (testGrades[0] > 100

As testGrades[0] = 101 so this condition evaluates to true as 101>100

So the statement sumExtra = testGrades[i] - 100 + sumExtra; executes which becomes:

sumExtra = testGrades[0] - 100 + sumExtra

As sumExtra = 0

testGrades[0] = 101

So

sumExtra = 101 - 100 + 0

sumExtra = 1

The same procedure is done at each iteration until the loop breaks. The output is:

sumExtra = 8

4)

The loop works as follows:

At first iteration

i=0

i < NUM_VALS is true as  NUM_VALS = 4 so 0<4 Hence loop body executes.

if (i<(NUM_VALS-1))   checks if i is less than NUM_VALS-1 which is 4-1=3

It is also true as 0<3 Hence the statement in body of i executes

printf( "%d,", hourlyTemp[i]) statement prints the element at i-th index i.e. at 0-th index of hourlyTemp array with a comma (,) in the end. As hourlyTemp[0] = 90; So 90, is printed.

When the above IF condition evaluates to false i.e. when i = 3 then else part executes which prints the hourlyTemp[3] = 95 without comma.

Same procedure happens at each iteration unless value of i exceeds NUM_VAL.

The output is:

90, 92, 94, 95

The programs along with their output are attached.

Answer:

Abstraction

Explanation: Abstraction is a software engineer terminology that has been found to be very effective and efficient especially as it relates to object-oriented computer programming. It has helped software engineers and other computer experts to effectively manage account objects without having a knowledge of the details with regards to the Implementation process of that account object.

Answer:

Pick up roller

Explanation:

you should first check the pickup roller component. This component is the part of the printer that picks paper up from the paper tray. The pickup roller links the printer and the paper. When the printer printer is running, the roller would take paper from the paper tray for the printer to print on. One of the issues it can have is Paper jam where the roller would stop turning so that it will no longer be picking papers up from the tray.

Answer:

Option A

Availability

Explanation:

The implementation of too many security protocols will lead to a reduction of the ease at which a piece of information is accessible.  Accessing the piece of information will become hard even for legitimate users.

The security protocols used should not be few, however, they should be just adequate to maintain the necessary level of confidentiality and integrity that the piece of information should have, While ensuring that the legitimate users can still access it without much difficulty.

Answer:

Here is the function same_person that takes two instances of Person as arguments i.e. p1 and p2 and returns True if they are the same Person, False otherwise.

def same_person(p1, p2):  #definition of function same_person that takes two parameters p1 and p2

   if p1.GTID==p2.GTID:  # if the two instances of Person have same GTID

       return True  #returns true if above condition evaluates to true

   else:  #if the two instances of Person do not have same GTID

       return False #returns false when two persons have different GTID

Explanation:

person1 = Person("David Joyner", 30, 901234567)  #first instance of Person

person2 = Person("D. Joyner", 29, 901234567)  #second instance of Person

person3 = Person("David Joyner", 30, 903987654)  #third instance of Person

print(same_person(person1, person2))  #calls same_person method by passing person1 and person2 instance of Person to check if they are same

print(same_person(person1, person3)) #calls same_person method by passing person1 and person3 instance of Person to check if they are same

The function works as follows:

For function call print(same_person(person1, person2))

The GTID of person1 is 901234567 and that of person2 is 901234567

If condition if p1.GTID==p2.GTID in the function same_person checks if the GTID of person1 is equal to the GTID of person2. This condition evaluates to true because GTID of person1 = 901234567 and GTID of person2 = 901234567

So the output is:

True

For function call print(same_person(person1, person3))

The GTID of person1 is 901234567 and that of person3 is 903987654

If condition if p1.GTID==p2.GTID in the function same_person checks if the GTID of person1 is equal to the GTID of person3. This condition evaluates to false because GTID of person1 = 901234567 and GTID of person2 = 903987654 and they are not equal

So the output is:

False

The complete program along with its output is attached in a screenshot.

Answer:

It allows for departmentalization and managerial control. Simple and easy to understand and use. Easy to manage due to the rigidity of the model – each phase has specific deliverables and a review process. Phases are processed and completed one at a time.

Explanation:

Answer:

Explanation:

Bit stuffing Framing Method

In the given situation, the beginning casing is shown by 6 sequential ones followed by 2 zeroes.

The beginning casings are generally known as the flags.which are utilized for demonstrating the beginning and end of the edges. Essentially utilized for the synchronization between the sender and the reciever.

Along these lines here the beginning and end banners are 11111100(this is on the grounds that the end banner is same as the beginning banner).

To enable us understand how this question plays out, let us understand the rule for Stuffing and De-stuffing .

The standard for stuffing is :

At whatever point there are 5 successive ones supplement one zero in the casing which is an information. The embedded zero piece is known as the stuffed bit.The principle reason behind stuffing somewhat after 5 back to back ones is to evade the distortion of information (data) as flag. If the reciever misconstrues the information as end banner then he would quit recieving the information where the entire information sent by the sender will be left and lost causing an error-prone information.

The rule for destuffing :

The standard/rule for destuffing is only inverse as stuffing. After recieving the bitstuffed information (data), at the reciever's end zero after each 5 continuous ones will be evacuated and the rest of the information will be considered as the genuine information.

In the given situation, the beginning casing is demonstrated by 6 back to back ones followed by 2 zeroes.

the beginning casings are normally known as the flags.which are utilized for showing the beginning and end of the edges. Essentially utilized for the synchronization between the sender and the receiver.

In this way here the beginning and end banners are 11111100(this is on the grounds that the end banner is same as the beginning banner).

where the bolded/underlined digits represents the stuffed bits

cheers i hope this helps

Answer:

The file can be read only by a user with the decryption key

Explanation:

The way encryption works is it scrambles the data in a file following the rules of the encryption algorithm using a certain key to tell it how to scramble everything.

Without the key, the computer doesn't know how to decrypt it.

This is true no matter who has access to the file, be it a system administrator, a hacker, or even a legitimate user who has somehow lost access to the key

Strictly speaking, encryption can be broken, but, especially with modern encryption, that's a matter of centuries, and isn't really feasible

The statement that is true of an encrypted file is that The file can be read only by a user with the decryption key.

A decryption key is known to be a key that is given to Customers by a specific Distributor.

This key allows Customers to open and access the Software that they bought. The decryption key is a  mechanism that  permit  that a file can be read only by a user.

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Answer:

Polymorphism

Explanation:

If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.

The information regarding the polymorphism is as follows:

Therefore we can conclude that If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.

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Answer:

AZAX is key sentence for without reloading page.

Explanation:

AJAX is also known as XHR. If some one wants to send the file without reloading then look ahead at the search function and prompt the users by auto saving the documents. This request is sent to the server. The server return the data to your network. Whenever you have seen the file form, some action on the page. You will see some request from AJAX server request on your functional area. AJAX is called a reloading file without page. AZAX is stands for Asynchronous java scripts And XML. AJAX is used to send an email. AZAX is not used in front end, it is used from back end process.

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Answer:

E-Government Act of 2002.

Explanation:

The E-Government Act of 2002 is a statute of the United States of America which was enacted by the 107th U.S Congress on the 17th of December, 2002. The E-Government Act of 2002 was signed into law to facilitate the management and promotion of the US government processes and services, as well as enhance transparency and accountability between the government and the public through the application of internet-based information technology.

Under the E-Government Act of 2002, federal agencies must;

1. Review their IT systems for privacy risks.

2. Post privacy policies on their websites.

3. Post machine-readable privacy policies on their websites.

4. Report privacy activities.

Answer:

Complete the program with the following code segment

for(int i =0;i<=3;i++)

{

cout<<offsetAmount[i]+origList[i]<<" ";

}

return 0;

}

Explanation:

The following line is an iteration of variable i from 1 to 3; It iterates through elements of origList and offsetAmount

for(int i =0;i<=3;i++){

This adds and prints the corresponding elements of origList and offsetAmount

cout<<offsetAmount[i]+origList[i]<<" ";

}  The iteration ends here

Answer:

def power(base, expo):

   if expo == 0:

       return 1

   else:

       return base * power(base, expo-1)

Explanation:

*The code is in Python.

Create a method called power that takes base and expo as parameters

Check if the expo is equal to 0. If it is return 1 (This is our base case for the method, where it stops. This way our method will call itself "expo" times). If expo is not 0, return base * power(base, expo-1). (Call the method itself, decrease the expo by 1 in each call and multiply the base)

Answer:

The definition of the subject in question is presented in section elsewhere here.

Explanation:

The total value of almost all of the quantities mostly on unique die features will indeed be:  

⇒  [tex]1+2+3+4+5+6[/tex]

⇒  [tex]21[/tex]

The number of the 4 lateral sides throughout the first tossing will be 15, therefore determines the total of both top and bottom features would be:

⇒  [tex]21-15[/tex]

⇒  [tex]6[/tex]

The compositions including its {top and bottom} current valuations that give a total of Six include {1, 5}, {5, 1}, {2, 4}, as well as {4, 2}. Consequently, because neither of those variations includes Six, it indicates that six doesn't really feature on the very first toss mostly on high or low hand.  

And then let's look at second tossed situation. Throughout this particular instance, the total amount obtained would be 12.

Which means it has to be the number of top and bottom:

⇒  [tex]21-12[/tex]

⇒  [tex]9[/tex]

{4, 5},{5, 4}, {6, 3}, and {3, 6} seem to be the {top, bottom} facial variations that provide a total of Nine.  

Currently regarding all the tosses, {6, 3} and perhaps {3, 6} have been the only situations wherein the 6 emerge towards top or bottom. Then the value of the unique die mostly on face identical to 6 must've been 3.

Answer:

Explanation:

Hello friend !!!!!!!!!!!!

The answer is school zone

Hope this helps

plz mark as brainliest!!!!!!!

Children walking on the sidewalk, a person sitting in a parked car, and a parking lot with vehicles entering and exiting indicate a school zone (Option C).

In conclusion, children walking on the sidewalk, a person sitting in a parked car, and a parking lot with vehicles entering and exiting indicate a school zone (Option C).

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Answer:

Selection control structure

Explanation:

This is often referred to as if-conditional statement;

This condition tests for a condition and performs a sequence of operation depending on the result of the condition;

Take for instance, the following program written in python

x = int(input("enter any number: "))

if x < 0:

  print("Yes")

else

  print("No")

The above checks if the input number is less than 0,

If the condition is true, it prints Yes

If otherwise, it prints No

Answer:

#include <stack>

#include<iostream>

#include<fstream> // to read imformation from files

#include<string>

using namespace std;

int main() {

   stack<string> data;

   ifstream inFile("postfix.txt");

   string content;

   if (!inFile) {

       cout << "Unable to open file" << endl;

       exit(1); // terminate with error

   }

   while (getline(inFile, content)) {

       data.push(content);

   }

   inFile.close();

   return 0;

}

Explanation:

You were very close. Use the standard <stack> STL library, and make sure the stack elements are of the same type as what you're trying to add, i.e., std::string.

Answer:

Yes, badlion is safe. The further explanation is given below.

Explanation:

Answer:

Following are the code to this question:

var id= document.createElement('script');//defining id varaible that uses the createElement method  

ld.src = "https://code.jquery.com/jquery-3.5.1.min.js";//defining id varaible with src that holds the source link

alert("The loaded Script is: ");//defining alert box that print Script loaded.

Explanation:

In the above-given code, an id variable is defined that uses the createElement method, which helps to create the specified name with the Element Node, and in the next line, it uses the src with the id variable, that store the link, it also helps to loads the 3rd party script, which is displayed in an alert msg box.

Answer:

"Object-oriented" would be the correct choice.

Explanation: