A crane lifts a 10000 N load through a distance of 30mins in 40s calculate work done
Given,
Force = 10,000 N
Distance = 30 m
Time = 40 s
Work done = force × distance
Work = 10,000 × 30
Work = 300,000 J
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꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂
The work done on the object is equal to the power it experiences which is equal to 735 watts.
What is work done?Work done is defined as the product of force applied and the distance over which the force is applied on the object. Work is done on an object when a force is applied to an object and the object is moved through a particular distance.
The time rate of doing work is called as power, which is designated by the symbol P. It is measured in the units of watts, where one watt is equal to one joule energy applied per second time.
Work done on an object is equal to the force (F) multiplied by the distance d in the direction of the force. Where, time interval is Δt.
P = W/Δt = F × d/Δt = m × g × h/Δt = 100 × 9.8 × 30 / 40
Power = 735 watts
The power of the object is 735 watts.
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What symbols are these?
Answer:
the bottom one is wollsiegel
How does water temperature affect density?
2. What are the challenges of wind energy that causes decrease in the electrical production?
3. Give two solutions:
1. Modification in the structure of the turbine
2. Modification in the function of the turbine.
4. You must estimate the cost in each solution, and which one is more affordable and efficient for the municipality to go for.
5. You must make sure that there is minimal energy loss.
Levelized production cost is a big challenge in the production of wind energy.
The main challenge in the production of wind energy is the high production cost. It has to minimize the Levelized Production Cost (LPC) which is the ratio between energy production cost and economic lifetime. This problem can be solved by doing modification in the structure of the turbine as well as we must ensure minimal energy loss.
The modification in the structure can produce more electrical energy and reduce the energy loss also provides more profit to the company so we can conclude that levelized production cost is a big challenge in the production of wind energy.
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A guitar string has a fundamental frequency f. The tension in the string is increased by 1.70%. Ignoring the very small stretch of the string. How does the fundamental frequency change?
The characteristics of the speed of the waves in strings and the resonance allows to find the change in the fundamental frequency when changing the tension is:
The change in fundamental frequency is: f = 1.08 f₀
The speed of the chord wave is given by the relationship between the tension and the density of the medium.
[tex]v= \sqrt{\frac{T}{\mu } }[/tex]
Where v is the velocity of the wave, T the tension of the string and μ the density
In a rope held at the ends, a process of standing waves occurs, two at the point where it is attached we have a node and a anti-node in the center.
2L = n λ
Where L is the length of the chord and call the wavelength
Wave speeds are related to wavelength and frequency.
v = λ f
We substitute.
[tex]\sqrt{\frac{T}{\mu } } = \frac{2L}{n} \ \ f[/tex]
For the fundamental frequency n = 1
f₀ = [tex]f_o = \sqrt{\frac{T}{\mu } } \ \ \frac{1}{2L}[/tex]
They indicate that the tension increases 1.70%
T = T₀ + 0.17 T₀
T = 1.17 T₀
We substitute.
[tex]f = \sqrt{1.17 } \ \sqrt{\frac{T_o}{\mu } } \ \ \frac{1}{2L}[/tex]
f = ra1.17 f₀
f = 1.08 f₀
In conclusion, using the characteristics of the velocity of the waves in strings and the resonance we can find the change in the fundamental frequency when changing the tension is:
The change in fundamental frequency is: f = 1.08 f₀Learn more about string resonance here: brainly.com/question/16010929
